if its diameter is 9, that means its radius is half that, or 4.5.
[tex]\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=4.5 \end{cases}\implies \begin{array}{llll} SA=4\pi (4.5)^2\implies SA=81\pi \\\\\\ SA\approx 254.47~in^2 \end{array}[/tex]
The surface area of the basketball with diameter of 9 in will be 254.34 in².
What is surface area?The surface area of a solid object is a measure of the total area that the surface of the object occupies.
Given that, a basketball has a diameter of 9 inches we need to find its surface area,
Since, the basketball is in the shape of the sphere and the surface area of the sphere = 4π×radius²
Therefore, the surface area of the basketball =
= 4×3.14×(9/2)²
= 4×3.14×4.5×4.5
= 254.34 in²
Hence the surface area of the basketball with diameter of 9 in will be 254.34 in².
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Anyone know the answer
Step-by-step explanation:
-2g(1+g)
-2g - 2g²
(-2)g - (2)g²
please help me im just really slow
If sin Q = 4/5, cos P + cos Q
The value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
What is trigonometry?Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
We know that:
P + Q are complementary, which means that
P+Q = 90°
Then R is a right angle, i.e. it measures 90°.
sin(90-x) = cos (x)
cos(90-x) = sin (x)
Then sinQ = 4/5
cos(90-Q) = cosP = 4/5
Now sin²(P) + cos²(P) = 1
sin²(P) = 1 - cos²(P)
sin²(P) = 1 -[4/5]² =9/25
sin(P) = 3/5
cos(Q) = sin(P) = 3/5
cos(P) + cos(Q) = 4/5 + 3/5 = 7/5
Thus, the value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
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