What is the solution for x In the inequality -3x+4<16

Answer:

21

Step-by-step explanation:

: P

Answer:

21

Step-by-step explanation:

umm that's kindergarten math-

Answer:

$45000

Step-by-step explanation:

Given data

Net income =$50,400

Let the prior year income be x

12/100*x +x= 50400

0.12x+x= 50400

1.12x= 50400

x= 50400/1.12

x= $45000

Hence the prior year income is $45000

Answer:

5 + 2 = 27

Step-by-step explanation:

Answer:

let's take s as student

let's take p as problem

sp as student that has gotten a problem

1s × 5p + 1s × 5p + 1s × 5p + 1s × 5p + 1s × 5p

5sp + 5sp + 5sp + 5sp + 1s × 5p + 2p

20sp + 1s × 7p

20sp + 7sp

27sp

Answer:

the exact answer is 314.159265359

Step-by-step explanation:

but it simplifies to 314.16

Answer:

the corect answer for this question is (-x,y)

Answer:

y = x +5

Step-by-step explanation:

2x +4 + 1-x = x +5

hope this helps

Answer:

1 ladrillo cuesta 1 dólar.    1 brick costs 1 dollars.

1 kg de cemento cuesta 3 dólares: 1 kg cement costs 3 dollars

1 kg de arena cuesta $ 16: 1 kg sand costs $ 16

Step-by-step explanation:

Spanish

Deje que los ladrillos, la arena y el cemento se denoten por b, sy c. Luego, de acuerdo con la condición dada

20b + 5s + 10c = $ 130 --- ecuación 1

1c = 3b ------ ecuación 2

1s = 4c + 4b ------ ecuación 3

Poniendo la ecuación 2 en la ecuación 3

1s = 4 (3b) + 4b

1s = 16b ---------- ecuación 4

20b + 5s + 10 (3b) = $ 130

50b + 5s = 130 --- ecuación 5

Poniendo la ecuación 4 en la ecuación 5

50 b + 5 (16b) = 130

50 b + 80b = 130

130 b = 130

b = 130/130 = $ 1 ------- ecuación a

1 ladrillo cuesta 1 dólar.

Poner el valor de costo de 1 ladrillo en estas ecuaciones

1c = 3b ------ ecuación 2

1s = 4c + 4b ------ ecuación 3

1c = 3 (1) = $ 3 -------- ecuación b

1 kg de cemento cuesta 3 dólares

1s = 4c + 4b

1 s = 4 (3) + 4 (1)

1 s = 12 + 4

1s = $ 16 ------ ecuación c

1 kg de arena cuesta $ 16

Poner valores de la ecuación a, b, c en la ecuación 1

20b + 5s + 10c = $ 130

20 (1) + 5 (16) + 10 (3) = 130

20 + 80 + 30 = 130

130 = 130 ------------ por lo tanto probado

English

Let the bricks , sand and cement be denoted by b, s and c. Then according to the given condition

20b+ 5s+ 10c= $130--- equation 1

1c= 3b------ equation 2

1s= 4c+4b------ equation 3

Putting equation 2 in equation 3

1s= 4(3b) + 4b

1s= 16b---------- equation 4

20b+ 5s+ 10(3b)= $130

50b + 5s= 130--- equation 5

Putting equation 4 in equation 5

50 b + 5 (16b) = 130

50 b+ 80b= 130

130 b= 130

b= 130/130= $1------- equation a

1 brick costs 1 dollars.

Putting the cost value of 1 brick in these equations

1c= 3b------ equation 2

1s= 4c+4b------ equation 3

1c= 3(1)= $3-------- equation b

1 kg cement costs 3 dollars

1s= 4c+4b

1s= 4(3) + 4(1)

1s= 12+4

1s= $16 ------ equation c

1 kg sand costs $ 16

Putting values from equation a, b, c in equation 1

20b+ 5s+ 10c= $130

20 (1) + 5 (16) + 10 (3)= 130

20 + 80 + 30 = 130

130 = 130   ------------ hence proved

Answer:

The Answer is gonna be 66-11y

EXPLANATION :

11 (6 - y)

11x6=66

11(y)=11y

So we will get 66-11y

Answer:

9 and 2: 1

10 and 4: 2

Step-by-step explanation:

9: 1, 3, 9

2: 1, 2

Answer: 1

10: 1, 2, 5, 10

4: 1, 2, 4

Answer: 2

Answer:

73.5

Step-by-step explanation:

Part/whole=percent/100

?/500=2.1%/100

500 divided by 100 is 5, so 2.1% times 5 is 10.5, which is the amount of interest made per year.

So, 10.5 times 7 is 73.5

Answer:

2 and 3

Step-by-step explanation:

30 is 20% of 150

I hope this helps

Have a great day

PLEASE SHOW THE PROBLEM WE CANT SEE

Answer:

False

Step-by-step explanation:

Answer: In the two similar triangles, Angle 1 and Angle 4 are alternate interior angles.

Vertical angles prove that Angle 3 is congruent to angle 6.

The triangles are similar because alternate interior angles are congruent.

Step-by-step explanation:

Step-by-step explanation:

Mam nice drawing at your backside Mam nice drawing at your backside

Answer:

The sum is Rs 1,250 and Rs 650

Step-by-step explanation:

Let the amounts be represented as $x and $y

The sum of both is 1900

Thus;

x + y = 1,900 •••••(i)

Mathematically, the interest on the amount borrowed is;

I = PRT/100

where p is the principal, representing the amount borrowed

R is the rate

T is the time

for the first amount of $x ; we have interest as;

I = (x * 5 * 4)/100 = 20x/100

for the second, we have

I = (y * 9 * 4)/100 = 36y/100

The sum of both is 580

Thus;

20x/100 + 36y/100 = 580

20x + 36y = 58000 •••••(ii)

From equation i;

x = 1,900 - y

Substitute this into equation ii

We have this as;

20(1900-y) + 36y = 58,000

38000 - 20y + 36y = 58,000

16y = 58000 - 38000

16y = 20,000

y = 20,000/16

y = 1250

From equation 1;

x + y = 1900

x = 1900-y

x = 1900-1250

y = 650

Answer:

C. Subtraction property of equality

Step-by-step explanation:

Answer:

the answer is D

you would end up with 14% and 14 is in between 12 ns 18

Step-by-step explanation:

Answer:

314

Step-by-step explanation:

Answer:

314

Step-by-step explanation:

R= half of d

d= 20

20/2= 10

r=10

Plug into formula:

3.14(10)^2

= 314

Answer:

(a) Domain: All real numbers except -2

(b) [tex]f(x) > -4[/tex]

Step-by-step explanation:

Given

See attachment for f(x)

Solving (a): The domain

From the attached image, we have:

[tex]f(x) = -x - 2, x <-2[/tex]

[tex]f(x) = -x^2, -2 < x < 0[/tex]

[tex]f(x) = x, x \ge 0[/tex]

To get the domain, we consider the inequalities attached to each of the piece-wise function

[tex]x < -2[/tex]

This implies that the values of x is less than -2 i.e.

[tex]x = \{.......,-4,-3\}[/tex]

[tex]-2< x<0[/tex]

This implies that x is greater than -2 and less than 0 i.e.

[tex]x = \{-1\}[/tex]

[tex]x \ge 0[/tex]

This implies that x is greater than or equal to 0 i.e.

[tex]x =\{0,1,2,3,....\}[/tex]

If these values of x are merged, we have:

[tex]x = \{.......,-4,-3,-1,0,1,2,3.....\}[/tex]

[tex]x = \{-\infty,..,-4,-3,-1,0,1,2,3,...,\infty\}[/tex]

-2 is not included in the above values of x.

Solving (b): The range

From the attached image, we have:

[tex]f(x) = -x - 2, x <-2[/tex]

[tex]f(x) = -x^2, -2 < x < 0[/tex]

[tex]f(x) = x, x \ge 0[/tex]

Substitute the greatest value of x in each piece-wise function.

[tex]f(x) = -x - 2, x <-2[/tex]

[tex]x=-2[/tex]

So;

[tex]f(-2) = -2-2 = -4[/tex]

[tex]f(x) = -x^2, -2 < x < 0[/tex]

[tex]x = -2[/tex]

So:

[tex]f(-2) = -2^2 = -4[/tex]

[tex]f(x) = x, x \ge 0[/tex]

[tex]x = \infty[/tex]

So;

[tex]f(\infty) = \infty[/tex]

We have:

[tex]f(-2) =-4[/tex]

[tex]f(-2) =-4[/tex]

[tex]f(\infty) = \infty[/tex]

The smallest value of f(x) is -4

Hence, the range is:

[tex]f(x) > -4[/tex]

Answer:

Domain is

B)

(-infinity, -2) U (-2, infinity)

Range is (-4, infinity)

Step-by-step explanation:

go it correct

edge2022

The Answer Is 9-6i

have an amazing day <3

Answer:      9-6i

Step-by-step explanation:

Answer:

yur

Step-by-step explanation:

Answer:

yeah it's a decimal so yes

Answer:

C≈37.7in

Step-by-step explanation:

Answer:

Hello!

Area: 113.04

Circumference: 37.68

Hope this helps

Answer:

2/8 of the fifth graders are not in band

Step-by-step explanation:

To find how many fifth graders are not in band, subtract the # of fifth graders in band. Your difference is the amount of fifth graders that are not in band. To check your answer add 2/8 + 6/8 which should be equal to 8/8 or a whole ( 1 ).