what cause a mass defect?
○A. The mass of a nucleus is larger than it should be.
○B. The mass of a nucleus cannot be accurately measured.
○C. Mass is converted to the energy binding a nucleus together.
○D. Mass is lost when a particle is released in a reaction.​

Answer:

d- The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.

Explanation:

The reaction between potassium hydroxide and hydrochloric acid of equal volume and equal concentration yields a solution of pH 7 at equivalence point. We must note that KOH is a strong base while HCl is a strong acid. This fact influences the pH of the system at equivalence point.

Owing to the fact that the acid is exactly neutralized by the base; at the equivalence point of such titration, it is expected that hydrogen ions(H+) and hydroxide ions (OH-) must have reacted to form water, this leads to a final pH of 7.  

Explanation:

Facilitar el movimiento y desplazamiento de objetos pesados reduciendo el rose del objeto contra el suelo, Obtener un movimiento circular por efecto de la fuerza de un liquido, en el caso de contadores, molinos, centrales hidroeléctricas y turbinas.

Transmitir el movimiento de un eje a otro como en el caso de las lavadoras, bicicletas y neveras. Reducir drásticamente el esfuerzo necesario para elevar y mover objetos, como en casos de pozos de agua y ascensores Transformar movimientos giratorios en otros movimientos o viceversa. ,

Answer:

Eukaryotic cells have a true nucleus, which means the cell's DNA is surrounded by a membrane. Therefore, the nucleus houses the cell's DNA and directs the synthesis of proteins and ribosomes, the cellular organelles responsible for protein synthesis.

Ribosomes are the sites in a cell in which protein synthesis takes place. ... Within the ribosome, the rRNA molecules direct the catalytic steps of protein synthesis — the stitching together of amino acids to make a protein molecule.

Answer:

When blood is too basic, carbonic acid can ionize to bicarbonate and H+ ions, adding H+ ions to the blood.

When blood becomes too acidic, bicarbonate combines with extra H+ ions to form carbonic acid, removing H+ ions from the blood.

Carbonic acid can raise or lower the pH of blood.

Explanation:

A buffer is a solution that resists changes to its pH when small quantities of acids or bases are added to it. The human blood serves as a buffer as it contains a buffer of carbonic acid (H2CO3) and bicarbonate anion (HCO3-) which serves to maintain blood pH between 7.35 and 7.45. Other buffering systems in blood exist such as the Hydrogen ion and oxygen gas which affects oxygen binding to haemoglobin, however the carbonic-acid-bicarbonate buffer is the most important buffer for maintaining acid-base balance in the blood.

A buffer solution is made up of an acid and its conjugate base or a base and its conjugate acid. For carbonic acid-bicarbonate buffer, carbonic acid serves as the acid while bicarbonate serves as the base. When a little quantity of a base as hydroxide ions is added to a buffer, the acid reacts with it and remove it from the solution. On the other hand, when a little quantity of an acid as hydrogen ions are added to a buffer, the conjugate base reacts with it and remove it from the solution, thus keeping the pH of the solution fairly constant.

In the carbonic acid-bicarbonate buffer:

When blood is too basic, carbonic acid can ionize to bicarbonate and H+ ions, adding H+ ions to the blood.

When blood becomes too acidic, bicarbonate combines with extra H+ ions to form carbonic acid, removing H+ ions from the blood.

Thus, carbonic acid can raise or lower the pH of blood.

Carbonic acid work to maintain blood pH as follows:

This means that, carbonic acid works to maintain blood pH as follows:

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Answer:

True

Explanation:

Answer:

B, No reaction will occur

Explanation:

Copper as compared to lead is less reactive. This is the reason when  lead is added to copper nitrate solution, it replaces the copper and itself combines with nitrate to form lead nitrate aqueous solution

Lead + Copper(II) nitrate → Copper + Lead (II) nitrate

The same is not the case when the reaction is revered i.e Cu is added to Pb NO3 solution.

Hence, option B is correct

Answer:

Atoms are kind of like building blocks.

Explanation:

Think of atoms as kind of like a mix between paint pigments and legos. The more legos that you have, the bigger the molecule but keep in mind that there are many different kinds of legos that all can come together to build numerous things. I hope that I answered your question and i apoligize if I didn't.

Answer:

Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

Answer:

The molecules in gasoline (octane, the chemical formula shown) contain chemical energy. This energy is transformed into kinetic energy that allows a car to race on a racetrack.

Answer:

5.01 x 10^-6 M

Explanation:

PH= -log [H+]

[H+] = 10^-PH

Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g

Answer:

Any element in group 18 has eight valence electrons (except for helium, which has a total of just two electrons

Explanation: they could be grouped by how they reproduce or they can be grouped by if there hetero or autotrophic

Answer:

D. 331 mm Hg

Explanation:

We can solve this problem by keeping in mind the law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of its components.

In other words:

We input the given data:

And calculate the pressure of the nitrogen:

Answer:

high use of mineral resources

Explanation:

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Answer:

the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).

Answer:

81.65 g CO2

Explanation:

Answer: proton and neutron

Explanation:

They both have the mass of 1

Answer:

Explanation:

Answer:

number of moles of (N) = 0.794 moles

Explanation:

From the given information:

no of moles of nitrogen (N) = (unknown)???

mass of nitrogen = 13.5 g

molar mass of NH3 = 14 +( 1 × 3) = 17 g/mol

To calculate the no of moles of N, we have:

number of moles of (N) = mass of N/molar mass

number of moles of (N) = 13.5 g/17 g/mol

number of moles of (N) = 0.794 moles

Answer:

Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water

Explanation:

To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:

Molarity of stock (M₁) = 0.0405 mM

Volume of diluted (V₂) = 100 mL

Molarity of diluted solution (M₂) = 0.001 mM

Volume of stock solution needed (V₁) =?

M₁V₁ = M₂V₂

0.0405 × V₁ = 0.001 × 100

0.0405 × V₁ = 0.1

Divide both side by 0.0405

V₁ = 0.1 / 0.0405

V₁ = 2.47 mL

Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.

Answer: [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Explanation:

Moles of  [tex]CO[/tex] = 0.35 mole

Moles of  [tex]H_2O[/tex] = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of [tex]CO[/tex] = [tex]\frac{0.35mol}{1.00L}=0.35M[/tex]

Initial concentration of [tex]H_2O[/tex] = [tex]\frac{0.40mol}{1.00L}=0.40M[/tex]

Equilibrium concentration of [tex]CO[/tex] = [tex]\frac{0.19mol}{1.00L}=0.19M[/tex]

The given balanced equilibrium reaction is,

                      [tex]CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)[/tex]

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

[tex]K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}[/tex]

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56[/tex]

Thus [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Answer:

B

Explanation:

I'm gonna guess E on this one, but I think you should choose either E or A

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45° Celsius

Formula (113°F − 32) × 5/9 = 45°C

Answer:d

Explanation:

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.

Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

Charge on the left side = -1

Charge on the right side = -1+0+0 = -1

As the charge on the electron antineutrino,  [tex]{\bar{\nu }}[/tex] e and the tau neutrino,  [tex]\nu\tau[/tex] are zero each.

Thus, charge on left side = charge on right side

Or, the equation is in accordance with charge conservation.

Lapton number of left side = 1

Laptop number of right side = 1-1+1 = 1

This is because, lapton number of the particles involved are,

Tau lapton, [tex]\tau[/tex]-1 = 1,

Electron, e-1 = 1,

Electron antineutrino,  [tex]{\bar{\nu }}[/tex]e = -1,

Tau neutrino, [tex]\nu\tau[/tex]= 1,

Thus, lapton number of left side = lapton number of right side

So, the equation obeys lapton number conservation.

2.

The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:

Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.

Just simply multiply 3 quarks by the number of nucleons:

So, 3 (quarks) x 4 (nucleons) = 12 quarks

Therefore, there are 12 quarks in 4 nucleons.

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