A second-degree polynomial takes the form
[tex]f(x) = ax^2 + bx + c[/tex]
for some constants a, b, and c. Such a function is continuous and differentiable everywhere in its domain.
Differentiating f(x) with respect to x gives
[tex]\dfrac{df}{dx} = 2ax + b[/tex]
We're told that
• f(x) is increasing on [0, 8]
• f(x) is decreasing on ]-10, 0]
and since df/dx is continuous, this tells us that df/dx = 0 when x = 0. It follows that b = 0, and we can write
[tex]f(x) = ax^2 + c[/tex]
We're also given that the curve passes through the point (-8, 4), which gives rise to the constraint
[tex]f(-8) = 64a - 8b + c = 4 \implies 64a + c = 4[/tex]
Since f(x) is decreasing on ]-10, 0], we have df/dx < 0 when x = -8, so
[tex]2ax+b < 0 \implies -16a < 0 \implies a > 0[/tex]
This means f(x) is minimized when x = 0, with min{f(x)} = c, so the co-domain of f(x) is the set {f(x) ∈ ℝ : f(x) ≥ c}.
Without another condition, that's all we can say about the co-domain. There are infinitely many choices for the constants a and c that satisfy the given conditions. For example,
a = 1, c = -60 ⇒ f(x) = x² - 60 ⇒ f(-8) = 4
⇒ co-domain = {f(x) ∈ ℝ : f(x) ≥ -60}
a = 2, c = -124 ⇒ f(x) = 2x² - 124 ⇒ f(-8) = 4
⇒ co-domain = {f(x) ∈ ℝ : f(x) ≥ -124}
etc.
This list shows the lengths in feet of the 25 longest bridges in the United States.
1010
1470
1600
2000
2800
1053
1495
1632
2150
3500
1200
1596
1750
2150
3800
1207
1600
1800
2300
4200
1380
1600
1850
2310
4260
Jamie made a frequency table of the bridge data.
U.S. Bridges
Length (ft)
Tally
Frequency
(first interval)
|||| ||
7
(last interval)
||
2
Based on the tallies and frequencies for the first and last intervals, how many intervals of what length did Jamie use?
a.
4 intervals of 1000 feet
c.
6 intervals of 500 feet
b.
5 intervals of 1000 feet
d.
7 intervals of 500 feet
Please select the best answer from the choices provided
A
B
C
D
The length of the intervals of the given frequency table is
500 ft.
The given list shows the lengths in feet of the 25 longest bridges in the United States.
we have to determine the median and mode of the bridge data.
The median is the middle number of the data set arranged in ascending order.
1010, 1053, 1200, 1207, 1380, 1470, 1495, 1596, 1600, 1600, 1600, 1632, 1750, 1800, 1850, 2000, 2150, 2150, 2300, 2310, 2800, 3500, 3800, 4200, 4260.
The median is 1750.
Mode is the number that appears most often in the data set.
1010, 1053, 1200, 1207, 1380, 1470, 1495, 1596, 1600, 1600, 1600, 1632, 1750, 1800, 1850, 2000, 2150, 2150, 2300, 2310, 2800, 3500, 3800, 4200, 4260
The mode is 1600.
Therefore the correct option is Median: 1750, Mode: 1600
So the length of the intervals of the given frequency table is
500 ft.
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0.00002165 in scientific notation.
Answer:
2.165 × 10⁻⁵
Step-by-step explanation:
Move the decimal -5 places to the right. For every scientific notation, 10 is the default number you are multiplying the decimal by. The exponent is the number of places you moved the decimal point. The exponent is positive when moving left, negative when moving right.
Hope it helps!
Which of the following points could be the initial point of vector v if it has a
magnitude of 10 and the terminal point (-3,3) ?
(-9,-5)
(-13,-7)
(0,2)
(-0.3,0.3)
The initial point of vector v if it has a magnitude of 10 and the terminal point (-3,3) is option B (-9,-5).
How to find the vector component?If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The magnitude of 10 and the terminal point (-3,3).
v = ai + bj
v = [tex]\sqrt{a^2 + b^2}[/tex]
10 = [tex]\sqrt{a^2 + b^2}[/tex]
AB = (-3 - a)i + (3 - b)j
If we put (-9,-5)then
AB = (-3 - a)i + (3 - b)j
AB = (-3 + 9)i + (3 + 5)j
AB = 6i + 8j
Put the value in the vector magnitude
10 = [tex]\sqrt{a^2 + b^2}[/tex]
= [tex]\sqrt{6^2 + 8^2}\\\\\sqrt{36+ 64}\\\\\sqrt{100}[/tex]
10 = 10
Thus, The correct option is B (-9,-5).
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At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering.
The probability that a student is a female or major in civil engineering is 62%
Complete questionAt a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?
How to determine the probability?Let A represent Female and B represents civil engineering.
The above representation means that the given parameters are:
P(A) = 49%P(B) = 21%P(A and B) = 8%The required probability is calculated as:
P(A or B) = P(A) + P(B) - P(A and B)
This gives
P(A or B) = 49% + 21% - 8%
Evaluate
P(A or B) = 62%
Hence, the probability that a student is a female or major in civil engineering is 62%
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willams bought piece of woods that is 3 feet long.he cuts it in to two pieces.one piece is 14 in long how long is the other piece
Answer:
22 inches
Step-by-step explanation:
3 feet = 36 inches
36-14=22
The other half is 22 inches long
Help me with the problem please!!
Step-by-step explanation:
Scale factor red to blue meaning 42 to 7
42÷7=6
Scale factor is 6
Perimeter of the blue quadrilateral = ?
If perimeter of red = 204
Then we use this following proportion
[tex]204 \div 42 = x \div 7[/tex]
[tex] \frac{204}{42} = \frac{x}{7} [/tex]
Then we cross multiply
42x=7×204
42x=1428
x=34
Area of the blue quadrilateral = ?
If area of the red quadrilateral = 2880
Then we use the following proportion
[tex]2880 \div 42 = x \div 7[/tex]
[tex] \frac{2880}{42} = \frac{x}{7} [/tex]
Then we cross multiply
42x=2880×7
42x=20160
x=480
[tex]\frac{1}{2} (5x - 9 ) = 2 (\frac{1}{3} + 6 )[/tex]
Answer: 103/15
Step-by-step explanation:
We can simplify the right-hand side to be [tex]2 \left(\frac{1}{3}+6 \right)=2 \left(\frac{19}{3} \right)=\frac{38}{3}[/tex].
This means we need to solve:
[tex]\frac{1}{2}(5x-9)=\frac{38}{3}\\5x-9=\frac{76}{3}\\5x=\frac{103}{3}\\x=\boxed{\frac{103}{15}}[/tex]
Please help me with this!
Answer:
Yes, x = 0 is a solution to the given equation
Step-by-step explanation:
[tex]1^3+1(1-1)=1-x^2[/tex] (Given)[tex]L.H.S.=1^3+1(1-1)[/tex] [tex]= 1 +1(0)[/tex] [tex]= 1+0 [/tex] [tex]=1[/tex] [tex]R.H.S. =1-x^2[/tex] [tex]=1-(0)^2[/tex] (Plug x = 0)[tex]=1-0[/tex] [tex]=1[/tex] [tex]\implies L.H.S. = R.H.S.[/tex]Thus, x = 0 is a solution to the equation [tex]1^3+1(1-1)=1-x^2[/tex]Hi Student!
The goal of this question is to determine x = 0 is a solution of the expression that was provided. The first step that we must take is input 0 into all of the x's that we have in the expression. Then we just simplify both sides and determine if the end expression is true and if it is then x = 0 is a solution.
Plug in the values
[tex]1^3 + 1(1 - 1) = 1 - x^2[/tex][tex]1^3 + 1(1 - 1) = 1 - (0)^2[/tex]Simplify both sides
[tex]1^3 + 1(0) = 1 - 0[/tex][tex]1 + 0 = 1[/tex][tex]1 = 1[/tex]Looking at the final expression, we can see that 1 is indeed equal to 1 and since the expression is true, we can say that x = 0 is a solution of the expression that was provided in the problem statement.
Without calculating the cubes find 1 cube+2cube+2(4) cube+(-5)cube+(-6)cube .
12.simplify the following expression
21q + 5/2(3/2) + 4q -5
Answer:
i think the answer is 25q - 5 / 4
Donovan is paying for gym classes. Each type of class has its own weekly fee. He signed up for x weeks of yoga classes and y
weeks of kickboxing classes. He paid a total of $136. The equation below describes the relationship between the number of weeks
of yoga classes and the number of weeks of kickboxing classes Donovan signed up for.
8x + 12y
-
136
The ordered pair (5,8) is a solution of the equation. What does the solution (5.8)
Considering the given function, the ordered pair (5,8) means that the signed up for 5 weeks of yoga classes and 8 weeks of kickboxing classes.
What does the function represent?
The function that represents the relationship between the number x of yoga classes that Donovan signs up for and the number y of kickboxing classes is given by:
8x + 12y = 136.
Hence the ordered pair (5,8) means that the signed up for 5 weeks of yoga classes and 8 weeks of kickboxing classes.
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congruent figures someone please help
Volume of a cube with a side length of 18.8m
Answer:
[tex]6644.672~ m^3[/tex]
Step-by-step explanation:
[tex]\text{Volume} = (18.8)^3~ m^3 = 6644.672~ m^3[/tex]
What are the domain and range of g(x)= √x-3?
A. D: [3, ∞) and R: [0, ∞)
B. D: [–3, ∞) and R: [0, ∞)
C. D: (–3, ∞) and R: (–∞, 0)
D. D: (3, ∞) and R: (–∞, 0)
Answer:
I guess, A is the wanted answer, but
A and D together are the really correct answer.
Step-by-step explanation:
if I understand this correctly, then
g(x) = sqrt(x - 3)
the domain of a function is the definition of all valid x (input) values.
the range of a function is the definition of all valid y (result) values.
well, the content (the arguments) of a square root cannot be negative (at least not while dealing with real numbers).
so, the answer options B and D are automatically out, because the domain contains values that would make the arguments of the square root negative.
I guess your teacher wants to focus only on the positive results of the square root, so A is the correct number.
BUT formally, without designated restrictions, a square root has always 2 solutions : a positive and a negative one.
because (-x)² = (x)² = x².
so, I would have to say that the really correct answer is
A + D, because the range contains both, the positive and the negative numbers.
What is the square root of 121 ?
Answer:
√121 = 11
Explanation:
11 × 11 = 121
Answer:
11
Step-by-step explanation:
The square root of 121 is 11.
= 11*11 = √(121)
= 121 = 11
done
nth term formula? maths quickly
[tex]\text{Nth term of an arithmetic series} = a +(n-1)d \\\\\text{Nth term of an geometric series}= ar^{n-1}\\\\\text{where,}\\\\\text{a = first term.}\\\\\text{d = common difference.}\\\\\text{r = common ratio.}[/tex]
Given Segment AC with point B contained on the segment, as shown below.
Write a complete two-column proof for following information:
Given: Segment AB = x + 16, Segment BC = 4x + 11
Segment AC = 77
Prove: AB = 26
It is true that the line segment AB equals 26
How to prove that line segment AB = 26?The given parameters are:
AB = x +16
BC = 4x + 11
AC = 77
The two-column proof is as follows:
AC = AB + BC Line segment formula
77 = x + 16 + 4x + 11 Substitution property of equation
77 = 5x + 27 Addition property of equation
5x = 50 Subtraction property of equation
x = 10 Division property of equation
AB = 10 +16 Substitution property of equation
AB = 26
Hence, the line segment AB has been proved to equal 26
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You plan to build a house that is 1 ½ times as long as it is wide. You want the land around the house to be 20 feet wider than the width of the house, and twice as long as the length of the house, as shown at the right.
The total area with land based on the information given is 3x² + 60x.
How to find the area?Let the width = x
Let the length = (1.5 × x) = 1.5x
Area = 1.5x × x = 1.5x²
The area along with land:
Width = x + 20
Length = 3 × x = 3x
The total area with land:
= Length × Width
= 3x(x + 20)
= 3x² + 60x.
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In which table does yvary directly with x?
The table in which y varies directly with x is table C.
What is direct variation?
When a variable varies directly with another variable, it means that as one variable increases, the other variable also increases.
The equation that is used to represent direct variation is:
y = kx
Where y is the constant of proportionality
In table c, k is equal to 26
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Multiply:
(x+y)by (x+y)
a+b by a^2-b^2
(a+5) by (a^2-2a-3)
(a^2-ab+b^3) by (a+b)
Answer:
Multiply:
[tex](x+y)by (x+y)[/tex]
[tex] : \implies(x + y)(x + y)[/tex]
[tex] : \implies \: x(x + y) + y(x + y)[/tex]
[tex] : \implies {x}^{2} + xy + xy + {y}^{2} [/tex]
[tex] : \implies{x}^{2} + 2xy + {y}^{2} [/tex]
Multiply:
[tex]a+b \: by \: a^2-b^2[/tex]
[tex]: \implies( {a}^{2} + {b}^{2} ) \times (a + b)[/tex]
[tex]: \implies \: {a}^{2} (a + b) - {b}^{2} (a + b)[/tex]
[tex]: \implies \: {a}^{3} + {a}^{2} b - {ab}^{2} - {b}^{3} [/tex]
Multiply:
[tex](a+5) by (a^2-2a-3)[/tex]
[tex]: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }[/tex]
[tex]: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)[/tex]
[tex]: \implies(a \times {a}^{2} - a \times 2a - a \times 3) + (5 \times {a}^{2} - 5 \times 2a - 5 \times 3)[/tex]
[tex]: \implies{a}^{3} - {2a}^{2} - 3a + 5 {a}^{2} - 10a - 15 [/tex]
[tex]: \implies{ {a}^{3} + {3a}^{2} - 13a - 15}[/tex]
Multiply:
[tex](a^2-ab+b^3) by (a+b)[/tex]
[tex]: \implies{(a + b) \times ( {a}^{2} - ab + {b}^{3} )}[/tex]
[tex]: \implies \: a( {a}^{2} - ab + {b}^{3}) + b( {a}^{2} - ab + {b}^{3} ) [/tex]
[tex]: \implies {a}^{3} - {a}^{2} b + a {b}^{3} + {a^2b} - {ab}^{2} + {b}^{4} [/tex]
[tex]: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4} }[/tex]
Step-by-step explanation:
[tex] \blue{ \frak{Seolle_{aph.rodite}}}[/tex]
Calculate the area of the alarm clock.
Given the diameter of the surface of the clock, the area of the surface of the alarm clock is 3846.5cm².
What is the area of the alarm clock?Note that: Area of a circle is expressed as;
A = πr²
Where r is radius and π is constant pi ( π = 3.14 )
Given that;
Diameter d = 70cm Radius r = d/2 = 70cm/2 = 35cmArea = ?A = πr²
A = 3.14 × ( 35cm )²
A = 3.14 × 1225cm²
A = 3846.5cm²
Therefore, given the diameter of the surface of the clock, the area of the surface of the alarm clock is 3846.5cm².
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If the population is highly skewed, the sample size needed for the central limit theorem to apply usually has to be ______ that when the population is not highly skewed a. different from b. the same as c. larger than d. smaller than
Answer:
2
Step-by-step explanation:
the same as...
(2) is the answer
If the population is highly skewed, the sample size needed for the central limit theorem to apply usually has to be the same as that when the population is not highly skewed.
What is the central limit theorem?The central limit theorem states in probability theory that, in many instances, when independent random variables are added together, their correctly normalized sum tends toward a normal distribution, even if the original variables are not normally distributed.
If the population is highly skewed, the sample size needed for the central limit theorem to apply usually has to be the same as that when the population is not highly skewed.
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Which is an x-intercept of the continuous function in the table ? (0, - 6); (3, 0); (- 6, 0) O (0, 3)
An x-intercept of the continuous function in the table is (-1, 0)
Intercept of a lineThe x-intercept of a line is the point where the line crossed the x-axis or the point where the value of y is zero.
From the table, the x-intercept are all the point where the value of f(x) is zero. Hence the Which is an x-intercept of the continuous function in the table is (-1, 0)
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The solution for which of the following is neither a interger nor a fraction 4x+7=x+2 ,5x-8=x+4, 3x+2=5x+2, none of the above
Answer:
none of the above
Step-by-step explanation:
4x + 7 = x + 2
4x - x + 7 = x - x + 2
3x + 7 = 2
3x + 7 - 7 = 2 - 7
3x = -5
3x / 3 = -5 / 3
x = -5 / 3 = -1.667
5x - 8 = x + 4
5x - x - 8 = x - x + 4
4x - 8 + 8 = 4 + 8
4x = 12
4x / 4 = 12 / 4
x = 3
3x + 2 = 5x + 2
3x - 5x + 2 = 5x - 5x + 2
-2x + 2 = 2
-2x + 2 - 2 = 2 - 2
-2x = 0
x = 0
Integers, As a whole number that can be written without a remainder,
x = 3
x = 0
(Mixed) Fraction
x = -5 / 3 = -1.667
17.
select the correct answer
what is the equation of the problem shown with its focus on this graph?
Options are in photo!
Answer:
B
Step-by-step explanation:
Tasty Goodies Bakery recorded the desserts that were recently sold.
chocolate croissants 1
cookies 1
brownies 10
slices of pie 12
Considering this data, how many of the next 78 desserts sold should you expect to be slices of pie?
slices of pie
Answer:
36
Step-by-step explanation:
possibility of slices of pie is 12/24, = 1/2
78 desserts, how much i expect is slices of pie
78*(1/2) = 36
We should expect about 39 of the next 78 desserts sold to be slices of pie.
What is an expression?An expression contains one or more terms with addition, subtraction, multiplication, and division.
We always combine the like terms in an expression when we simplify.
We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.
Example:
1 + 3x + 4y = 7 is an expression.com
3 + 4 is an expression.
2 x 4 + 6 x 7 – 9 is an expression.
33 + 77 – 88 is an expression.
We have,
Out of 24 desserts sold, 12 were slices of pie.
Therefore, the proportion of slices of pie sold is 12/24 = 1/2.
To estimate the number of slices of pie in the next 78 desserts sold, we can multiply the proportion of slices of the pie by the total number of desserts sold:
(1/2) x 78 = 39
Therefore,
We should expect about 39 of the next 78 desserts sold to be slices of pie.
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Please help we’re stuck
Answer:
Divide 12 by -6
The graph of a logarithmic function is shown below.
On a coordinate plane, a curve starts at y = negative 2 in quadrant 4 and curves up into quadrant 1 and approaches y = 2.
What is the domain of the function?
x < 0
x > 0
x < 1
all real numbers
The domain of the function is x > 0.
The correct option is (B)
What is domain of function?Domain of a function is defined by the set of x-values of the graph of a function.
as, domain of a function is defined by the set of x-values of the graph of a function.
From the graph we can see that,
x-values are starts from x > 0 [Since x ≠ 0]
Also, moves towards infinity,
Hence, domain of the function be, (0, ∞) or x > 0
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Answer:
B
Step-by-step explanation:
Find the probability that a randomly
selected point within the circle falls
in the red shaded area.
r = 4 cm
[?]%
Round to the nearest tenth of a percent.
Enter
Answer:
[tex]31.8\%[/tex]
Step-by-step explanation:
The area of the circle is [tex]A=\pi r^2=\pi(4)^2=16\pi[/tex]
The area of the triangle is [tex]A=\frac{bh}{2}=\frac{8*4}{2}=\frac{32}{2}=16[/tex]
Hence, the probability of a randomly selected point within the circle falls in the red shaded area is [tex]\frac{16}{16\pi}=\frac{1}{\pi}\approx0.318\approx31.8\%[/tex]
Here are two fractions.
7/6
6/7
Work out which of the fractions is closer to 1
You must show your working.
Here are two fractions.
The correct answer is 6 / 7 as it is closer to 1.
What is a fraction?The fraction is defined as the division of the whole part into an equal number of parts.
The number near 1 will be calculated as:-
7/ 6 = 1.1666
6 / 7 = 0.8571
Difference of the first ratio from one.
1.1666 - 1 = 0.1666
Difference of the second ratio:-
1 - 0.8571 = 0.1429
So the difference of 6 / 7 is lower than the difference of the fraction 7 / 6 from one.
Therefore the correct answer is 6 / 7 as it is closer to 1.
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