Answer:
the MTTF of the transceiver is 50.17
Explanation:
Given the data in the question;
failure modes = 0.1 failure per hour
system reliability = 0.85
mission time = 5 hours
Now, we know that the reliability equation for this situation is;
R(t) = [ 1 - ( 1 - [tex]e^{-0.1t[/tex] )³] [tex]e^{-t/MTTF[/tex]
so we substitute
R(5) = [ 1 - ( 1 - [tex]e^{-0.1(5)[/tex] )³] [tex]e^{-5/MTTF[/tex] = 0.85
[ 1 - ( 1 - [tex]e^{-0.5[/tex] )³] [tex]e^{-5/MTTF[/tex] = 0.85
[ 1 - ( 0.393469 )³] [tex]e^{-5/MTTF[/tex] = 0.85
[ 1 - 0.06091 ] [tex]e^{-5/MTTF[/tex] = 0.85
0.9391 [tex]e^{-5/MTTF[/tex] = 0.85
[tex]e^{-5/MTTF[/tex] = 0.85 / 0.9391
[tex]e^{-5/MTTF[/tex] = 0.90512
MTTF = 5 / -ln( 0.90512 )
MTTF = 50.17
Therefore, the MTTF of the transceiver is 50.17
In your opinion, should a marketing plan be created for each and every product under a single brand should the marketing be for the brand itself? Explain your answer
Answer:
Both of them
Explanation:
When creating a marketing plan you need to think of the objective or goals that you have, you should probably always have a running campaign to help the brand itself to be constantly seen by the audience, while at the same time having specific campaigns for the products that you want to push or to promote the most. For example, not all of Nike's ads are aimed to sell more sneakers or sports clothing, some of them are just to keep them on the conversation and growing their brand, while the hype up campaign for the release of a new pair of sneakers or collection is done at the same time. So you should always go for both.
A wooden pallet carrying 540kg rests on a wooden floor. (a) a forklift driver decides to push it without lifting it.what force must be applied to just get the pallet moving.
Answer:
The appropriate solution is "1481.76 N".
Explanation:
According to the question,
Mass,
m = 540 kg
Coefficient of static friction,
[tex]\mu_s[/tex] = 0.28
Now,
The applied force will be:
⇒ [tex]F=\mu_s mg[/tex]
By substituting the values, we get
[tex]=0.28\times 540\times 9.8[/tex]
[tex]=1481.76 \ N[/tex]
Air enters a two-stage compressor operating at steady state at 520ºR, 14 lbffin 2 The overall pressure ratio across the stages is 12 and each stage operates isentropically. Intercooling occurs at constant pressure at the value that minimizes compressor work input as determined in Example 9.10, with air exiting the intercooler at 520°R. Assuming ideal gas behavior, with k = 1.4. Determine the work per unit mass of air flowing for the two-stage compressor, in Btu per lb of air flowing.
Answer:
106.335 Btu/Ib
Explanation:
Given data :
T1 = 520°R = 288.89K
P1 = 14 Ibf/in^2 = 96526.6 pa
r = 12
k = 1.4
R = 287 J/kg-k
Calculate work done per unit mass of air flowing ( two-stage compressor )
we will apply the equation below
W = 2k / K-1 * ( RT₁ ) * [tex][ r^{\frac{k-1}{2k} } - 1 ][/tex]
input values into equation above
W = 247.336 KJ/kg = 106.335 Btu/Ib
Some_____
include peanut butter, bacon, and chocolate.
Snap traps baits
Glue boards
Catchalls
IGRs
Bait stations
Answer:
it’s IGS
Explanation:
because i read
Answer:
snap trap baits
Explanation: its kind of obvi, but i took the test and got it right.
(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compare to the experimental values of 70.58 and 3.90, respectively.
(2) Estimate the specific volume in cm3/g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the compressibility factor charts and compare to the experimental values2 of 70.58 and 3.90, respectively.
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
Determine the specific volume in cm^3
V = 70.66 cm^3
b) comparing the specific volumes to the experimental values
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
What is a SAFETY CHECK
Answer:
Safety check is defined as rounding to make sure that the patients and the milieu (patients living quarters) is secured and free of harmful items that can be used to hurt someone.
3Px=y−y2p2
first order higher dgree
Answer:
the order higher is 3p79g5t88=yv5379
A s100 N m torque is applied to a 1-m-long, solid round steel shaft. Design it to limit its angular deflection 2°, if shear modulus of elasticity 80 GPa and to determine the fatigue strength of the material.
Answer:
assuming factor of safety of 2
Se = 118.858 MPa
Explanation:
Torque = ± 100 N m
length of solid round steel shaft = 1-m
Angular deflection = 2°
shear modulus of elasticity = 80 GPa
Calculate Fatigue strength of material
apply Von-miss effective stress rule to determine the Von mises stress
max torque = 100 + 0
assuming a factor of safety of 2
Se(fatigue strength of material ) = Von mises stress * Fs
= 59.429 * 2 = 118.858 MPa
An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people
$255 per hour
Explanation:Total number of employed people = 16
(i) 5 people earn $15 per hour
That means that the total amount earned by those 5 is;
5 x $15 = $75 per hour
(ii) 4 people earn $17 per hour
That means that the total amount earned by those 4 is;
4 x $17 = $68 per hour
(iii) The remaining people earn $16 per hour.
There are 7 people remaining. i.e
16 - 5 - 4 = 7
That means that the total amount earned by those remaining (7) is;
7 x $16 = $112 per hour
The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e
Total = $75 + $68 + $112
Total = $255
Therefore, the total hourly wage earned by all 16 people is $255
A TRF receiver is to be designed with a single tuned circuit using an 8.2 uH inductor. If the frequency is to be tuned from 55 kHz to 1600 kHz, find the BW that results at 550 kHz if there is exactly 10 kHz BW at a frequency of 1050 kHz.
a. 105 kHz
b. 15.24 kHz
c. 5.24 kHz
d. 10 kHz
Answer:
[tex]Bw_1=5.24kHz[/tex]
Explanation:
From the question we are told that:
Induction [tex]L=8.2uH[/tex]
Resonant Frequencies
[tex]F_1=550kHz\\\\\F_2=1050kHz[/tex]
Generally the Bandwidth & Frequency equation is mathematically given by
[tex]\frac{F-1}{Bw_1}=\frac{F_2}{Bw_2}[/tex]
Therefore
[tex]Bw_1=\frac{500}{1050}*10[/tex]
[tex]Bw_1=5.24kHz[/tex]
A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.
Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
Technician A says that the distributor cap provides a connection point between the rotor and each individual cylinder plug wire. Technician B says that distributor caps cannot be repaired and have to be replaced when needed. Who is correct
Answer:
Neither a or b.
Explanation:
The distributor cap is cover which protects internal parts and holds contact between internal rotor and spark plug wires. When inspecting distributor caps there should be some carbon tracking which looks like bright white grease trails.
In a creep test, increasing the temperature will (choose the best answer) A. increase the instantaneous initial deformation B. increase the steady-state creep rate
Answer:
All of the above
Explanation:
firstly, a creep can be explained as the gradual deformation of a material over a time period. This occurs at a fixed load with the temperature the same or more than the recrystallization temperature.
Once the material gets loaded, the instantaneous creep would start off and it is close to electric strain. in the primary creep area, the rate of the strain falls as the material hardens. in the secondary area, a balance between the hardening and recrystallization occurs. The material would get to be fractured hen recrstallization happens. As temperature is raised the recrystallization gets to be more.
froce and motion worksheet
Answer:
The following description of the problem is provided.
Explanation:
If somehow the system seems to be in movement it'll still relax, and it becomes moving whether it sits. An externality is a cost, that either affects or threatens that can modify the bodily condition.The phenomenon of anything changing their position, altering or completely replacing. Whenever moment anything keeps moving, several components are found.Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. Knowing that the average normal stress must not exceed 210 MPa in the bolts and 145 MPa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design.
Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
A cylindrical specimen of some metal alloy having an elastic modulus of 124 GPa and an original cross-sectional diameter of 4.2 mm will experience only elastic deformation when a tensile load of 1810 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.46 mm.
Answer:
the maximum length of the specimen before deformation is 0.4366 m
Explanation:
Given the data in the question;
Elastic modulus E = 124 GPa = 124 × 10⁹ Nm⁻²
cross-sectional diameter D = 4.2 mm = 4.2 × 10⁻³ m
tensile load F = 1810 N
maximum allowable elongation Δl = 0.46 mm = 0.46 × 10⁻³ m
Now to calculate the maximum length [tex]l[/tex] for the deformation, we use the following relation;
[tex]l[/tex] = [ Δl × E × π × D² ] / 4F
so we substitute our values into the formula
[tex]l[/tex] = [ (0.46 × 10⁻³) × (124 × 10⁹) × π × (4.2 × 10⁻³)² ] / ( 4 × 1810 )
[tex]l[/tex] = 3161.025289 / 7240
[tex]l[/tex] = 0.4366 m
Therefore, the maximum length of the specimen before deformation is 0.4366 m
Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.
a. True
b. False
Answer:
True
Explanation:
Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true
Find Ic(t),
If Vs(t)=8sin(4t+180°) V
3
د3
lic
62.5met
O 2.5cos(4t+53.1) A
O scos(4x+53.1°) A
O 2.5cos(4t+143°) A
Oscos(4t+143) A
Answer:
the answer is equal to 2.5cos(4t +53.1)
The walls of a refrigerator are typically constructed by sandwiching a layer of insulation between sheet metal panels. Consider a wall made from fiberglass insulation of thermal conductivity ki = 0.046 W/m K and thickness Li = 50 mm and steel panels, each of thermal conductivity kp = 60 W/m K and thickness Lp = 3 mm. If the wall separates refrigerated air at TX, i = 4 degree C from ambient air at T infinity, 0 = 25 degree C, what is the heat gain per unit surface area? Coefficients associated with natural convection at the inner and outer surfaces may be approximated as hi = h0 = 5 W/m2 K.
Answer:
q" = 14.122 W/m²
Explanation:
We are given;
Thermal conductivity of Fibre glass; k_i = 0.046 W/m.K
thickness of Fibre glass; L_i = 50 mm = 0.05 m
Thermal conductivity of steel panels; k_p = 60 W/m.K
Thickness of steel panels; L_p = 3 mm = 0.003 m
refrigerated air temperature; T∞_i = 4° C
Ambient air temperature; T∞_o = 25° C
h_i = h_0 = 5 W/m².K
Formula to calculate the heat gain per unit surface area in this case is;
q" = (T∞_o - T∞_I)/((1/h_o) + (L_p/k_p) + (L_i/k_i) + (L_p/k_p) + (1/h_i)
Where; ((1/h_o) + (L_p/k_p) + (L_i/k_i) + (L_p/k_p) + (1/h_i) is thermal resistance (R_th)
Plugging in the relevant values;
q" = (25 - 4)/((1/5) + (0.003/60) + (0.05/0.046) + (0.003/60) + (1/5))
q" = 14.122 W/m²
Please help!!!!! Thank u
Answer:
which class is this. I don't know sry
Air enters an adiabatic gas turbine at 1590 oF, 40 psia and leaves at 15 psia. The turbine efficiency is 80%, and the mass flow rate is 2500 lbm/hr. Determines:
a) The work produced, hp.
b) The exit temperature, oF.
Answer:
a) 158.4 HP.
b) 1235.6 °F.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:
[tex]m_{in}h_{in}=W_{out}+m_{out}h_{out}[/tex]
Whereas the mass flow is just the same, which means we have:
[tex]W_{out}=m_{out}(h_{out}-h_{in})[/tex]
And the enthalpy and entropy of the inlet stream is obtained from steam tables:
[tex]h_{in}=1860.7BTU/lbm\\\\s_{in}= 2.2096BTU/lbm-R[/tex]
Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:
[tex]s_{out}= 2.2096BTU/lbm-R[/tex]
Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.
Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:
[tex]h_{out}=1659.15BUT/lbm[/tex]
Then, the isentropic work (negative due to convention) is:
[tex]W_{out}=2500lbm/h(1659.15BUT/lbm-1860.7BUT/lbm)\\\\W_{out}=-503,875BTU[/tex]
And the real produced work is:
[tex]W_{real}=0.8*-503875BTU\\\\W_{real}=-403100BTU[/tex]
Finally, in horsepower:
[tex]W_{real}=-403100BTU/hr*\frac{1HP}{2544.4336BTU/hr} \\\\W_{real}=158.4HP[/tex]
Regards!
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and gauge pressure of 300 kPa. The gas is heated, and the gauge pressure at the final state is 367 kPa. Determine the final temperature, in °C. The local atmospheric pressure is 1 atm.
Answer:
the final temperature is 77.1 °C
Explanation:
Given the data in the question;
Initial temperature; T₁ = 27°C = ( 27 + 273)K = 300 K
Initial absolute pressure P₁ = 300 kPa = ( 300 + 101.325 )kPa = 401.325 kPa
Final absolute pressure P₂ = 367 kPa = ( 367 + 101.325 )kPa = 468.325 kPa
Now, to calculate the final temperature, we use the ideal gas equation;
P₁V/T₁ = P₂V/T₂
but it is mentioned that the rigid tank is closed,
so the volume is the same both before and after.
Change in volume = 0
hence;
P₁/T₁ = P₂/T₂
we substitute
401.325 kPa / 300 K = 468.325 kPa / T₂
T₂ × 401.325 kPa = 300 K × 468.325 kPa
T₂ = [ 300 K × 468.325 kPa ] / 401.325 kPa
T₂ = 140497.5 K / 401.325
T₂ = 350.08 K
T₂ = ( 350.08 - 273 ) °C
T₂ = 77.1 °C
Therefore, the final temperature is 77.1 °C
can you solve this question
Answer:
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How should an organization balance its resources between pursuing its primary mission for existence and striving to meet social responsibility goals?
Answer:
The main reason for the existence of an organization is to generate profits, but it is increasingly required through the legal and social obligation that companies are not only profitable entities, but promoters of the well-being and development of society.
Therefore, the balance between the resources for its financial goals and objectives and social responsibility goals will be achieved through the adoption of processes that include environmental and social management as an integral and important part of the general administration, which is not an exclusion for generation profitability, but a tool that will help achieve organizational goals and objectives.
Environmental and social management through certifications, programs and management systems, provides policies and procedures that help companies reduce their costs, eliminate waste, improve productivity, generate stakeholder satisfaction and several other benefits that promote continuous improvement and consequently the improvement in the company's positioning in the market.
Essence of check line in chain surveying
Answer:
Following are the description on the chain surveying:
Explanation:
The checking which is also called a beginning of the test is indeed a line uniting the summit of a triangular with other fixed locations from both sides of a triangle. To verify the overall precision of a framework, the check-line is measured. When assessed mostly on the ground, every length of an examination line should match its height. It also is called a proof line that connects the top of the triangle with any fixed location in the contrary direction. It is utilized for verifying the preciseness of a work.
Who certifies master electricians
Answer:
The state you live in
Ferrous metals contain ____ (ferrite) so most have ________ properties. Ferrous metals are vulnerable to _____ when exposed to_______, except for ____________ and wrought iron.
Answer:
Iron
Magnetic properties
Rust
Moisture
Stainless steel
Explanation:
Ferrous materials are those that contain iron. Now iron is a magnetic material and this makes ferrous materials to possess magnetic properties.
Since they contain iron, when they are exposed to moisture they react with oxygen in oxidation to form iron oxide which is reddish and gets worse over time which forms a rusty surface.
- Apart from Wrought iron that resists corrosion,another ferrous metal that does that is Stainless steel because it contains chromium, which is an element that protects it from rust.
Find the dryness fraction, specific volume and internal energy of steam at 7bar nd enthalpy 2600kj/kh. (0.921,0.2515m³/kg , 2420kj/kg)
Answer:
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Explanation:
Karen just checked her bank balance and the balance was 1111.11. She is kind of freaking out and saved the receipt, thinking that it must mean something. Karen is probably just suffering from
Answer:
chronic stoner syndrome
Explanation:
"the universe just sends us messages sometimes mannnn, you just have to be ready to listen to them" lol
What is FOLLOWING PROCEDURES
Answer:
When employees follow procedures, they perform tasks correctly and provide consistent customer service. This enhances the quality of your organization's products and services. And, in turn, improves your company's reputation. Employees can know they are fulfilling their roles and take pride in their work.