This is slopes. — what is ( -12, -7 ) - ( 19, -4 ) ?

Answer:

A constant rate of change is accomplished when the change in one situation constantly results in changing another. In the scenario of a booster club constantly selling raffle tickets, the more tickets they sold the more the club raises.

Have an amazing day friend! <3

Answer:

95m

Step-by-step explanation:

312 - 61 - 61 = 190

190/2 = 95

Answer:

yes

7164 is divisible bt 6

Answer:

Yes

Step-by-step explanation:

Any number will be divisible by 6 if they be divisible by 2 & 3

- we know 7164 is divisible by 2

- also any number which sum of their digits are divisible by 3, the number will be divisible by 3

in this case (7164) 7+1+6+4=18 & 18 is divisible by 3 so 7164 is divisible by 3 as well.

so 7164 is divisible by 6

Step-by-step explanation:

[tex]f(x) = 2. {2}^{x} [/tex]

[tex]f( - 2) = 2. {2}^{ - 2} [/tex]

[tex]f( - 2) = 2. \frac{1}{ {2}^{2} } [/tex]

[tex]f( - 2) = \frac{2}{4} [/tex]

[tex]f( - 2) = 0,5[/tex]

The answer is D.

The value of f(x) = 2*[tex]2^{x}[/tex] when x = -2 is 0.5

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that a function,  f(x) = 2*[tex]2^{x}[/tex]

f(-2) = 2*[tex]2^{-2}[/tex]

= 2*1/2²

= 2/4

= 0.5

Hence, The value of f(x) = 2*[tex]2^{x}[/tex] when x = -2 is 0.5

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The equations take a linear form and are as follows; Part A.

Part B: It takes 5 Hours of work for the total costs to be the same.

The point at which the total costs are the same for both electricians is at;

h = 5hours.

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Answer:

Step-by-step explanation:

[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]

[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]

Hope it helps.

Do comment if you have any query.

Answer:

18

Step-by-step explanation:

3/6 =1/2

1/2 of 36 is 18

Answer:

z

Step-by-step explanation:

hqvqhqvw karrar ras wallah a part

Answer:

Step-by-step explanation:x

inproper fraction form:

[tex]x=\frac{11}{8}[/tex]

Decimal form:

[tex]x=1.375[/tex]

Mixed number form:

[tex]x=1\frac{3}{8}[/tex]

Hope this helps :)

Answer:

1.375 = x  or  1.4 = x

If you need to round it then it would be 1.4 = x

Step-by-step explanation:

Divide both sides by -8

[tex]\frac{-11}{-8}[/tex] = [tex]\frac{-8x}{-8}[/tex]

You end up with 1.375 = x

Answer:

10 + 28 / 35

= 38 / 35

= 1.0875

(Me, going to answer the easy questions because hard ones give me headaches)

Alright, listen up.

Steps:

First step: 60 is Lenny's lizard weight. Since it said 6 pounds less than double the lizard weight, we are going to multiply 60 by 2, therefore it would be 120.

Next step: Now 6 pounds less, so we are going to subtract 6 from that 120. 120 - 6 = 114.

Last step...: Label/answer: Lenny's lizard weight is 114 pounds.

Answer:

Laura’s lizard weights 33 pounds

Step-by-step explanation:

Let 2x be Laura’s lizard and

Let 2x - 6 be Lenny’s lizard

We know Lenny’s lizard is 60 pounds. Now to find Laura’s , equate( 2x - 6 )to 60 and solve for x

60 = 2x - 6

x =33

Therefore 33 is the answer

Answer:

im not sure

Step-by-step explanation:

Answer:

The equation to represent number of years in score is 5x = 1005x=100,

The number of years in score is 20

Step-by-step explanation:

CAN YOU GIVE ME BRAINliEST

Answer:

2x+y=s

2x\2+y\2=s\2

therefore x= s\2-y\2

Answer:

a) 2 * 3 = 6.

b) 123 is odd but contains an even digit (2).

Step-by-step explanation:

Answer:  

The difference between the longest and shortest sides of the triangle is 4 cm.

Explanation:

Step Number One:

Let the shortest side of the triangle have a length of x.

The middle side of the triangle has a length that is half of 3 times the length of the shortest side. This can be written as 1/2*3x, which equals 3/2x.

The longest side of the triangle has a length that is 2 centimeters longer than the length of the middle side. This can be written as 3/2x + 2.

Step Number Two:

The perimeter of the triangle, which can be found by adding the lengths of all of the sides of the triangle, is 18 centimeters. This can be shown by the following equations:

Shortest Side + Middle Side + Longest Side = Perimeter

x + 3/2x + 3/2x + 2 = 18

4x + 2 = 18

4x = 16

x = 16/4

x = 4

Step Number Three:

This means that the shortest side of the triangle has a length of 4 centimeters and the longest side of the triangle has a length of 8 centimeters.

8 cm - 4 cm = 4 cm

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Are you still confused? Not feeling confident in your ability to solve these types of problems? Some helpful topics to practice are listed below!

Still confused on ...

Step 1 - Practice equation solving!

Step 2 - Practice perimeter!

Step 3 - Practice addition and subtraction!

Remember: Certain problems may be tricky, but practice makes perfect!

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Answer by Math_Is_Me_123         

Answer: 70.4÷11 = 6.4

Step-by-step explanation:

__6.4__

11/70.4

-66 |

04 4

- 4 4

_____

=0

Answer:

x=g-c

Step-by-step explanation:

Answer:

1 inch = 4 feet

Step-by-step explanation:

[tex]\frac{2 inches}{8 feet} = \frac{1 inch}{4 feet}[/tex]

If we divide the given numbers by two (dividing on both sides keeps the equation true), we get 1 inch/4 feet. This tells us that on the scale, one inch is representative of four feet.

Answer:

approx 149.85 cm^2

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]