The number of students attending summer school at a local community college has been decreasing each year by 7%. If 847 students currently attend summer school at this rate continues, find the number of students attending summer school in 4 years.

Answer:

y = x - 3

Step-by-step explanation:

Slope = Rise / run

Slope = 4/4 = 1

y-intercept = -3

y = x - 3

Answer:

1.30

2. 0 im pretty sure

Step-by-step explanation:

if im wong sry

Answer:  x = 6/4

Step-by-step explanation:  

4x + 2 = 8

4x = 6

x = 6/4 or 1 1/2

Hope this helped :)

Answer:

x = 1.5, 1 1/2

Step-by-step explanation:

4x + 2 = 8

4x = 6

4x/4 = 6/4

x = 1.5

1.5 = 1 1/2

Have a nice day! :-)

Answer:

true

Step-by-step explanation:

Answer:

The answer is (A) decreases

Answer:

C:4 cm, 8 cm, 5 cm

Step-by-step explanation:

sum of length of any two sides of a triangle will be larger than the third side.

Answer:

Step-by-step explanation:

i dont know sorry

Answer:

a) section c

b) at a constant rate

c) below

A. 3m/s^2

B. 0 m/s^2

C. -3m/s^2

D. 1 m/s^2

Step-by-step explanation:

a) This graph models the change in velocity of time. Since when the velocity decreases over time, the acceleration is negative. This relationship is modeled in the interval from the 9th to 11th seconds which is section c.

b) If the graph is flat, it means the car is traveling at the same amount of meters per second. This means the car is traveling at a constant rate during section b.

c) During section A, the velocity in second 0 to second 4 increases by 12m/s. So, the acceleration is 3m/s^2. This is identical to finding the slope.

During section B, the velocity does not change at all, so the acceleration(and slope) is 0 m/s^2

During section C, over 2 seconds, from 9 to 11, the velocity goes from 12 m/s to 6 m/s, which is a change of -6 m/s. Therefore, the acceleration is -3m/s^2

During section D, over a span of 4 seconds(11 - 15), the velocity changes from 6 m/s to 10 m/s. That means a change of 4 m/s and the acceleration would be 1 m/s^2.

Answer:

I'm sorry I just need points

Step-by-step explanation:

Answer:

hope this will help you more

Answer:

1. 0

2. a/ a + b

3. a + b/ a - b

Answer:

[tex]S_{10} = 682[/tex]

Step-by-step explanation:

Given

[tex]a_1 = 6; r = 2[/tex]

Required

[tex]S_{10[/tex]

This is calculated as:

[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex]

So, we have:

[tex]S_{10} = \frac{6 * (2^{10} - 1)}{10 - 1}[/tex]

[tex]S_{10} = \frac{6 * (1024- 1)}{9}[/tex]

[tex]S_{10} = \frac{6 * 1023}{9}[/tex]

[tex]S_{10} = 682[/tex]

Answer:

2xˆ2-x-13=0

Step-by-step explanation:

Answer:

Below.

Step-by-step explanation:

2x^2 - 13 = x

Subtract x from both sides:

2x^2 - x - 13 = 0 is the standard form.

Answer:

[tex](g\ o\ f)=-20x+10[/tex]

Step-by-step explanation:

One is given the following functions:

f(x) =5x + 2

g(x) = 4x + 2

One is asked to find the following:

[tex](g\ o\ f)(x)[/tex]

One can rewrite this operation as the following:

g(f(x))

In essence, one substitutes in function (g) in place of the parameter (x), and solves to find the new function formed.

[tex]g(f(x))\\\\=g(-5x+2)\\\\=4(-5x+2)+2[/tex]

Simplify, distribute, multiply every term in the parenthesis by the term outside of it, then simplify,

[tex]=-20x+8+2\\\\=-20x+10[/tex]

Answer:

Step-by-step explanation:

Y= 320(1.5)^x-1

In this exercise we have to use the data informed in the text and perform the assembly of an equation in this way we find that:

[tex]Y=320(0.5)^X-1[/tex]

Some data were informed in the text for this equation to be written, so:

Now writing the equation representing the given information is:

[tex]Y=320(0.5)^X-1[/tex]

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Answer:

y=-32, 0, -16, -4, 16

Step-by-step explanation:

y=4(-6)-8= -32

y=4(2)-8 = 0

y=4(-2)-8 = -16

y=4(1) -8 = -4

y=4(6) -8= 16

For the given equation of the line, the complete table is attached below.

Use the concept of the equation of line defined as:

A line has length but no width, making it a one-dimensional figure. A line is made up of a collection of points that can be stretched indefinitely in opposing directions. Two points in a two-dimensional plane determine it.

The given equation of a line is,

y = 4x - x

To complete the table:

Put x = -6 in this equation,

y =  (-4)(-6) - 8

y = 16

Put x = 2 in the equation,

y =  (-4)(2) - 8

y = -16

Put x = -2 in the equation,

y =  (-4)(-2) - 8

y = 0

Put x = 1 in the equation,

y =  (-4)(1) - 8

y = -12

Put x = 6 in the equation,

y =  (-4)(6) - 8

y = -32

The complete table is attached below.

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9514 1404 393

Answer:

  θ = 60°

Step-by-step explanation:

The angle is more than 45° and less than 90°. The only viable choice is ...

  θ = 60°

__

We can only read the x-coordinate of the point on the terminal ray. It is 1/2, which is the cosine of 60°. The angle must be 60°.

Answer:

The radius is equal to 6.5 feet.

Step-by-step explanation:

To solve this we need to know that circumference equals 2πr (where "r" is the radius). Therefore, we can make the following equation...

2πr = 40.82

πr = 20.41

3.14r = 20.41

r = 6.5

Now we know that the radius is equal to 6.5 feet.

Answer:

The company must replace 0.0042 = 0.42% of packages.

Step-by-step explanation:

For each screw, there are only two possible outcomes. Either it is defective, or it is not. The probability of an screw being defective is independent of any other screw. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

It is known that screws produced by a certain company will be defective with probability 0.01.

This means that [tex]p = 0.01[/tex]

The company sells the screws in packages of 10

This means that [tex]n = 10[/tex]

That is, the package would have to be replaced if greater or equal to 2 screws are defective. What proportion of packages sold must the company replace?

This is:

[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]

In which:

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.01)^{0}.(0.99)^{10} = 0.9044[/tex]

[tex]P(X = 1) = C_{10,1}.(0.01)^{1}.(0.99)^{9} = 0.0914[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.9044 + 0.0414 = 0.9958[/tex]

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9958 = 0.0042[/tex]

The company must replace 0.0042 = 0.42% of packages.

9514 1404 393

Answer:

  10.  A) 120°

  11.  D) 40°

  12.  D) 54°

  13.  A) 101°

Step-by-step explanation:

The applicable rules of angles and arcs are ...

__

10) Angles C and L intercept the same arc (DE) so will have the same measure.

  15x = 16x -4

  4 = x . . . . . . . . add 4-15x

  arc DE = 2(15x) = 30(4) = 120 . . . degrees

__

11) Arc VW is twice the measure of angle X, so ...

  9x +8 = 2(5x)

  8 = x . . . . . . . . . subtract 9x

  ∠VXW = 5x = 5(8) = 40 . . . degrees

__

12) Arc EFG is twice the measure of angle W, so ...

  70° +FG = 2(88°)

  FG = 106° . . . . . . . . . subtract 70°

Arc FGW is twice the measure of angle E, so ...

  106° +GW = 2(80°)

  GW = 54° . . . . . . . . . . subtract 106°

__

13) Arc ST is twice the measure of angle R. The sum of arcs is 360°.

  RS +ST +TR = 360°

  119° +2(70°) +TR = 360°

  TR = 101° . . . . . . . . subtract 259°

Answer:

The standard error of the sample proportion is 0.0993.

The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is 0.0951.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

73% of voters support it.

This means that [tex]p = 0.73[/tex]

Sample of 20 voters

This means that [tex]n = 20[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.73[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.73*0.27}{20}} = 0.0993[/tex]

The standard error of the sample proportion is 0.0993.

The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is

12/20 = 0.6, so this is the p-value of Z when X = 0.6.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0.6 - 0.73}{0.0993}[/tex]

[tex]Z = -1.31[/tex]

[tex]Z = -1.31[/tex] has a p-value of 0.0951.

So

The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is 0.0951.

The standard error of the sample proportion is 0.0098.

The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is 0.0951

Given that,

Suppose that there is a school bond referendum in Greensboro, and 73% of voters support it.

You randomly ask 20 Greensboro voters whether they support the bond referendum.

We have to determine,

The standard error of the sample proportion is.

The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is .

According to the question,

There is a school bond referendum in Greensboro, and 73% of voters support it.

20 Greensboro voters whether they support the bond referendum.

[tex]standard \ deviation = \sqrt{\dfrac{p(1-p)}{n}}[/tex]

Where, p = 73% = 0.73

And n = 20

Therefore,

[tex]Standard \ deviation = \sqrt{\dfrac{p(1-p)}{n}}\\\\ Standard \ deviation = \sqrt{\dfrac{0.73(1-0.73)}{20}}\\\\Standard \ deviation = \sqrt{\dfrac{0.73\times 0.27}{20}}\\\\Standard \ deviation = \sqrt{\dfrac{0.19}{20}}\\\\Standard \ deviation = 0.0098[/tex]

The standard error of the sample proportion is 0.0098.

[tex]\dfrac{12}{20 }= 0.6[/tex]

 This is the p-value of Z when X = 0.6.

Therefore,

[tex]Z = \dfrac{X-\mu}{\sigma}\\\\Z = \dfrac{0.6-0.73}{0.993}\\\\Z = -1.31\\\\[/tex]

Z = -1.31 has a p-value of 0.0951.

Hence, The probability that 12 or fewer people (out of 20) in your sample support the bond referendum is 0.0951.

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Answer:

3/7 is greater than 2/5

Step-by-step explanation:

If you convert the fractions into decimals:

3/7=0.42

2/5=0.4

0.42 is greater than 0.4

Answer:

$7.5

Step-by-step explanation:

4 bottles cost = $5

Then 1 bottle costs:

$5/4 = $1.25

Then 6 bottles cost:

$1.25*6 = $7.5

Answer:

Choice B

A = b x h

Step-by-step explanation:

In other words the area of a parallelogram is the base times height

Answer

around $250 per month

Step-by-step explanation:

Answer:

Area of the figure = 25.7 units²

Step-by-step explanation:

Area of the given figure = Area of rectangle ABCD - Area of the semicircle with diameter CD

Area of the rectangle ABCD = Length × Width

                                               = BC × AB

                                               = 8 × 4

                                                = 32 units²

Area of the semicircle = [tex]\frac{1}{2}\pi r^{2}[/tex]

Here, r = radius of the semicircle

r = [tex]\frac{\text{Diameter}}{2}[/tex]

r = [tex]\frac{1}{2}(CD)[/tex]

r = [tex]\frac{4}{2}[/tex]

r = 2 units

Therefore, area of the semicircle = [tex]\frac{1}{2}\pi (2)^2[/tex]

                                                       = 2π

                                                       = 6.28 units²

Area of the given figure = 32 - 6.28

                                         = 25.72 units²

                                         ≈ 25.7 units²