[tex]5x2 + 2x - 3=0[/tex]

Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

Step-by-step explanation:

0.13,1/2,1/8,and 7/8

hope it is helpful to you

Answer:

1. 3

2. 1

3. 2

4. 4

5. 5

Step-by-step explanation:

Answer:

The two triangles are similar.

What is the value of x?

Enter your answer in the box.

x=

The value of x is 7 units.

Two triangles are said to be comparable if their two sides are in the same ratio as the two sides of another triangle and their two sides' angles inscribed in both triangles are equal.

Given :

AD = 6 units , BD = 8 units, m∠ABC = m∠DBE = 90° and              

∠DEB ≅ ∠ACB

Now, AB = AD + BD

              = 8 + 6 = 14 units

Now, In ΔABC and ΔDBE,

∠DBE = ∠ABC ( Each of 90° )

∠DEB = ∠ACB ( given )

So, By using AA postulate of similarity of triangles , ΔABC ~ ΔDBE

Now, proportion of the corresponding sides will be equal.

AD/ DB= BC/ BE

14/8 = 3x/ 2x-2

4x= 28

x= 7

Hence, the value of x is 7 units.

Learn more about similarity of Triangle here:

https://brainly.com/question/11923416

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Answer: 52

Step-by-step explanation:

81 + 47 is 128.

180 - 128 =52 degrees.

:)

Answer:

m anglw ABD answers is 50 degree

Answer:

I've attached the Answer

Answer:

a = - 2

Step-by-step explanation:

Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.

Find a :

Equation : 5x + 2y = - 4

                5 ( a ) + 2 ( 3) = - 4

                5a + 6 = - 4

                 5a + 6 - 6 = - 4 - 6               [ subtracting both sides by 6 ]

                 5a  + 0 = - 10

                   5a = - 10

                    a = - 2                               [ dividing both sides by 5]

[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4

                                                                    5(-2) + 2( 3 ) = - 4

                                                                   - 10 + 6 = - 4

                                                                         - 4 = - 4 ]

Given:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex].

To find:

The least common multiple of given expressions.

Solution:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex]. The factor forms of these expressions are:

[tex](x+1)=1\times (x+1)[/tex]

[tex](x-1)=1\times (x-1)[/tex]

[tex](x^2-1)=(x-1)(x+1)[/tex]                 [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

The least common multiple is the product of all distinct factors with its highest degree. So,

[tex]L.C.M.=1\times (x+1)\times (x-1)[/tex]

[tex]L.C.M.=(x+1)(x-1)[/tex]

[tex]L.C.M.=x^2-1^2[/tex]                [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

[tex]L.C.M.=x^2-1[/tex]

Therefore, the least common multiple of given expressions is [tex]x^2-1[/tex].

Answer:

Tn = 75+25n

Step-by-step explanation:

The balance are in arithmetic progression

$100, $125, $150...

The formula for calculating the nth term of the sequence is expressed as;

Tn = a+(n-1)d

a =100

d = 125 - 100 = 150 - 125

d = 25

n is the number of terms

Substitute

Tn = 100+(n-1)*25

Tn = 100 + 25n-25

Tn = 75+25n

Hence the nth term of the sequence is Tn = 75+25n

Answer:

a line and a plan are considered parallel if they have no points in common if two parallel planes are cut by a third plane then the lines of intersection are parallel

Answer:

Step-by-step explanation:

Since all 3 of these angle come off a straight line, they all add up to equal 180. Thus,

2j + 32 + 6j - 2 + 30 = 180 and

8j + 60 = 180 and

8j = 120 so

j = 15

Answer:

x     -1      1    3

y      -2    -4   2

Step-by-step explanation:

y=x^2-x-4

when x=-1

y=(-1)^2-(-1)-4

y=1+1-4

y=-2

when x=1

y=(1)^2-(1)-4

y=1-1-4

y=-4

when x=3

y=(3)2-(3)-4

y=9-3-4

y=9-7

y=2

Answer:

t-6=7 .................

Answer:

t - 6 = 7

Step-by-step explanation:

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

Answer:

14. 13x+5x

=18x

180(angles on a st. line)= 18x

180/18

=10

RSU=13*10=130

UST=5*10=50

Answer:

[tex]b = \frac{y-12x}{12}[/tex]

Step-by-step explanation:

subtract 12x from both sides, then divide by twelve.

Answer:

55

Angle C is a inscribed angle of the of Arc Ba.

CA is the diameter so that means Arc BA equal 110 becuase

110+70=180.

Angle C is half of Arc BA so Angle C is

[tex]55[/tex]

Answer:

A) x + 5y = 20

B) x + 3y = 14

Multiplying A) by -1

A) -x -5y = -20 then adding B)

B) x + 3y = 14

-2y = -6

y = 3

x = 5

Step-by-step explanation:

Answer:D - mean>median

Step-by-step explanation:

There are no repeating variables to have a mode so median and mean are the only options. The mean of this data set is 7.4 and the median is 6. Therefore mean greater than median

Answer:

(Altitude)^2+(Base)^2=(Hypotenuse)^2

Answer: 28

Step-by-step explanation: 5(4)-4(-2) which is 20+8 and that is 28.

Answer:

LM = 24.3

Step-by-step explanation:

In terms of similar shapes, we know that the ratio of the value of one side to its corresponding side value is equal to another. In other words, we know that LK and HG are corresponding sides by looking at the quadrilaterals. The ratio of LK to HG is equal to the ratio of another pair of corresponding sides, such as LM and IH.

Therefore, the ratio of LK and HG (LK/HG) is equal to the ratio of LM and IH (LM/IH) . Make sure to keep the same quadrilateral's sides on top/bottom. In this example, LM and LK are on the same quadrilateral, and are therefore both on top. Similarly, IH and HG are of the same quadrilateral and are both on bottom. We can write this as

LK / HG = LM / IH

34/7 = LM / 5

Multiply both sides by 5

34*5/7 = LM

LM ≈ 24.2857

Rounding to the nearest tenth, LM = 24.3

Answer:

24.3

Step-by-step explanation:

Answer:

a2+a3=78

a2 and a3 must both be positive numbers that add up to 78

so a2 = a3 = 39

a1=102, a2=39, a3=39

Step-by-step explanation:

a1=102

a1+ a2 + a3=180 (all interrior angles of a triangle add up to 180)

a2+a3=78

a2 and a3 must both be positive numbers that add up to 78

Step-by-step explanation:

Hey there!

Given;

Distance (d) = 450 km = 450*1000 = 450000 m

Time(t) = 5 hours = 5*60*60 = 18000s

Now;

Speed (s) = Distance (d) /Time(t)

Or, s = 450000/18000

Or, s = 25m/s.

Therefore, the speed is 25m/s.

Hope it helps!

Answer:

The car has a velocity of 25 m/s.

Step-by-step explanation:

There are two ways to solve this problem.

First way :

450km = 450.000m

5h = 5x 3.600s =18.000s

v = s/t = 450.000 / 18.000 = 25m/s

Second way :

Velocity = speed/time = 450 / 5 = 90 km/h

90/3.6 = 25 m/s

Either way, the car has a velocity of 25 m/s.

Answer:

(f+g)(x) = 60x + 400

Step-by-step explanation:

Given :

Amount in account A:

f(x) = 20x + 100

Amount in account B :

g(x) = 40x + 300

Total amount in Account A and B:

f(x) + g(x) = (20x + 100) + (40x + 300)

(f+g)(x) = (20x + 40x) + (100 + 300)

(f+g)(x) = 60x + 400

Answer:

Step-by-step explanation:

The equation of blue line A is x = 1.

That of blue line B is y = 4.

Answer:

1st entry: 41

3rd entry: 17

Step-by-step explanation:

The 1st and 3rd entry are incorrect.

We will use the following for the 1st and 3rd:

[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]

[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]

where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.

Let's do part 1 now)

25+4+2(6)

29+12

41

Let's do part 3 now)

25+4-2(6)

29-12

17

Answer:

Step-by-step explanation:

Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is

J + M = 230. The second equation is

J + K = 130. The third equation is

M = 3K. Sub that 3K into the first equation and get

J + 3K = 230. Now take th second equation and solve it for J:

J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:

130 - K + 3K = 230 and

2K = 100 so

K = 50

Kevin has $50

Answer:

10010110

Step-by-step explanation:

A binary number is basically a number in base 2. So, each place represents a power of two. The ones place represents 1 or 2^0, the tens represents 2 or 2^1, the hundreds represents 4 or 2^2 and so on. To find the highest place needed to make in the number in binary, we find the greatest power of two that is below 150. In this case, it is 128. We can start by writing 128 in binary:

10000000

Now, we subtract 128 from 150 and find the largest power of two that is smaller than the difference. The largest power of 2 smaller than 22 is 16, so we put a one in the place for 2^4:

10010000

We can subtract 16 from 22 to get what is leftover to continue the process. We get 6, and the largest power of 2 smaller is 4. We can place a one in the hundreds place to represent it:

10010100

What is left is 6-4 or 2, which is just 2^1, so we can place it in the tens place:

10010110

Given:

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

To find:

The quadrant in which [tex]\theta[/tex] lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.

In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.

In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.

We have,

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.

Therefore, the correct option is D.