Sqrt -1+2 using a+bi

The probability that you pull a card from a standard deck of 52 and then pull a second card without replacing the first card is 2%

The given parameters are:

Cards = 52

Face card = 12

Ace = 4

The probability of selecting a face card is:

P(Face card) = 12/52

Now, there are 51 cards.

The probability of selecting an ace is:

P(Ace) = 4/51

The required probability is:

P = 12/52 * 4/51

Evaluate

P = 0.0181

Express as percentage

P = 1.81%

Approximate

P = 2%

Hence, the probability is 2%

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Answer:

4/5

Step-by-step explanation:

First, we know that we have 5 envelopes. So the denominator of the probability is going to be x/5. We then realize that only one envelope has the car, so the probability of that is 1/5. If we subtract 1/5 from the probability of choosing an envelope (5/5), we get 5/5-1/5=4/5.

The ratio of the number of squares to the number of triangles is 5 : 2

The number of triangles that should be added to make the ratio is 6

Ratio expresses the relationship between two or more numbers. It is the number of times that one value is contained in another number.

Ratio of the number of squares to the number of triangles = number of squares : number of triangles

10 : 4

5 : 2

The number of triangles that should be added to make the ratio 1 : 1 - 10 - 4 = 6

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The area of this hub cap is about  510.44625 cm².

The area of circle is pi times the square of the radius.

Area of circle =π r²

Circumference (C) = 2π r

80.07 = 2 (3.14) r

76.87/ (2x 3.14) =r

r = 12.75 cm

now, Area be

=π r²

= 3.14*12.5*12.75

=510.44625 cm²

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Using the distance formula, the length of WX is approximately: 8.5.

Distance formula is, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex].

Given the endpoints:

W(5,-3) = (x1, y1)

X(-1,-9) = (x2, y2)

Plug in the values:

WX = √[(−1−5)² + (−9−(−3))²

WX = √[(−6)² + (−6)²]

WX = √72

WX ≈ 8.5

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Answer:

6 2 with the little check mark line in the midddle

Step-by-step explanation:

multiply the height x the length x the width to find the volume of a room (or another 3d object)

719ft

office area=12(20)=240ft

storage=(20-12)(40-(12+15)=8(13)=104ft

home theater=25(15)=375ft

total area= 240+104+375=719ft

Answer:

x > 8

Step-by-step explanation:

14 - 2(x + 1) < - 4 ← distribute parenthesis and simplify left side

14 - 2x - 2 < - 4

12 - 2x < - 4 ( subtract 12 from both sides )

- 2x < - 16

divide both sides by - 2 , reversing the symbol as a result of dividing by a negative quantity.

x > 8

Answer:

h = -5

Step-by-step explanation:

1) Subtract 7th from both sides

6h = 7h + 5

6h - 7h= 7h + 5 - 7h

2) Simplify

- Combine like terms

6h - 7h = 7h + 5 - 7h

-h = 7h + 5 - 7h

- Combine like terms

-h = 7h + 5 - 7h

-h = 5

3) Divide both sides by the same factor

-h = 5

-h/-1 = 5/-1

4) Simplify

Cancel terms that are in both the numerator and denominator

h/-1 = 5/-1

h = 5/-1

Divide the numbers

h = 5/-1

h = -5

Answer:

The answer is H=-5

Step-by-step explanation:

Answer:

A=πr^2

Step-by-step explanation:

A=π*r^2

Where, A is area of circle

r is radius of circle

π is constant

.

Hope it's help and I think I have give brainleist answer

Answer:

πr^2

Step-by-step explanation:

it's just πr^2.

easy

Answer:

Polynomial

Step-by-step explanation:

⇒ It cannot be option 1 as y does not vary with an exponent

⇒ It cannot be option 2 as y does not relate to any logarithmic values of x

⇒ It cannot be a option 4 as there no irrational numbers under a root

⇒ Therefore it is a polynomial, as it is written in the form : y = ax³ + bx² + cx + d (cubic polynomial)

Answer:

(a)  128 ft

(b)  4 s

(c)  Vertex:  (1, 144)

Step-by-step explanation:

Given information:

The height of the projectile at launch is the value of h(t) when t = 0 (the y-intercept).

Therefore, from inspection of the graph, the y-intercept is (0, 128).

So the height of the projectile at launch is 128 ft.

The length of time it took for the projectile to land is the time from the beginning (when t = 0) to when the height is 0 (the x-intercept).  

From inspection of the graph, the x-intercept is (4, 0)

So the length of time it took for the projectile to land is 4 s.

The vertex is the turning point (minimum/maximum point).

Therefore, from inspection of the graph, the vertex is (1, 144).

The vertex represents the time and height at which the projectile was at its maximum.  So at the time of 1 second, the projectile was at its maximum height of 144 ft.

Answer:

[tex]\textsf{A)} \quad 5u^3-2u^2+5u+8[/tex]

Step-by-step explanation:

Given expression:

[tex](-2u^3+5u-1)+(7u^3-2u^2+9)[/tex]

Remove parentheses:

[tex]\implies -2u^3+5u-1+7u^3-2u^2+9[/tex]

Collect like terms:

[tex]\implies -2u^3+7u^3-2u^2+5u-1+9[/tex]

Combine like terms:

[tex]\implies 5u^3-2u^2+5u+8[/tex]

Option A

Answer:

Step-by-step explanation:

Remark

x/(x+1) - 1/2 = -1 /(x + 1) is the equation to be solved. Add 1/(x + 1 to both sides

x/(x+1) + 1/(x+1) - 1/2 = -1/(x + 1) + 1/(x + 1)              Combine

x/(x+1) + 1/(x + 1) - 1/2 = 0                                      Combine x/(x+1) + 1/(x+1)

(x + 1)/(x + 1) - 1/2 = 0                                            Cancel (x+1)/(x+1) = 1

1 - 1/2 = 0                                                              No solution

Answer: No solution

Answer:

-17, -10, -6, -5, 3, 8 only change is between 3 and 8

Answer:

1029 minutes or 17.15 hours

Step-by-step explanation:

25+0.06M=86.74

0.06M=61.74

M=61.74/0.06=1029

Answer:

-1/5

Step-by-step explanation:

To find the slope, the formula is y2-y1/x2-x1

1-2/3-(-2) = -1/5

Answer:

Step-by-step explanation:

hope this helps!!!!

Applying the Pythagorean theorem and the trigonometric ratios, the perimeter of triangle ABC is: 68.8 units.

The perimeter of a triangle = sum of its 3 sides.

Given the following:

Use the Pythagorean theorem to find AD considering triangle ADB as a right triangle:

AD = √(15² - 9²)

AD = 12 units

Use the trigonometric ratios to find DC and AC:

sin 30 = AD/AC

sin 30 = 12/AC

AC = 12/sin 30

AC = 24 units

tan 30 = AD/DC

tan 30 = 12/DC

DC = 12/tan 30

DC ≈ 20.8 units

BC = BD + DC = 9 + 20.8

BC = 29.8 units.

Perimeter of triangle ABC = BC + AB + AC

Perimeter of triangle ABC = 29.8 + 15 + 24

Perimeter of triangle ABC = 68.8 units.

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Answer:

See below

Step-by-step explanation:

Each 32 feet of depth is 1 more atmosphere of pressure on the diver  

The mean, median, standard deviation, and interquartile range for each data set is given below.

When arranged from lowest to highest, the IQR represents the central 50% of values.

Find the median (middle value) of the lower and higher half of the data to get the interquartile range (IQR).

These are the quartile 1 (Q1) and quartile 3 (Q3) values (Q3). The difference between Q3 and Q1 is the IQR.

Using the statistical tool, the following were arrived at:

Using the statistical tool, the following were arrived at:

See the respective Histograms attached.

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Answer:

a= 2x-3 b= 2x+5

ab= (2x-3)(2x+5)

= 2x*2x+ 2x*5- 3*2x- 3*5

= 4x+ 10x- 6x- 15

= 14x- 6x- 15

= 8x -15

x= 2

= 8(2)- 15

= 16-15

= 1

The balance of the account which earns annual simple interest of $250 at 4% for 1 year is $260

Simple interest = principal × rate × time

= 250 × 4% × 1

= 250 × 0.04 × 1

= $10

Balance = Principal + Simple interest

= $250 + $10

= $260

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The equation for the relationship between the thickness and number of weeks is y = 3.8 - 0.2x

Ice lost at 7 weeks = 7(0.2) = 1.4 meters

Total thickness of ice before loss = Ice remaining after 7 weeks + Ice lost at 7 weeks

= 2.4 + 1.4

= 3.8 meters

The equation:

y = Total thickness of ice before loss - (Ice lost per week × Number of weeks)

= 3.8 - (0.2 × x)

y = 3.8 - 0.2x

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[tex]sin60 = \frac{opp}{hyp} \\ sin60 = \frac{y}{12 } \\ \frac{ \sqrt{3} }{2} = \frac{y}{12} \\ 2y= 12 \sqrt{3} \\ y = 6 \sqrt{3} [/tex]

[tex]cos60 = \frac{adj}{hyp} \\ cos60 = \frac{x}{12} \\ \frac{1}{2} = \frac{x}{12 } \\ 2x = 12 \\ x = 6[/tex]

Hope it helps

Please give brainliest

The range of name lengths is equal to 8.

In Mathematics and Statistics, a range can be defined as the difference between the highest number and the lowest number contained in a data set.

In Mathematics and Statistics, the range of a data set can be calculated by using this mathematical expression;

Range = Highest number - Lowest number

From the given data set, we have:

Highest number = 10.

Lowest number = 2.

By substituting, we have:

Range = 10 - 2

Range = 8.

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The number of ways can the committee be organized will be 2220075. Then the correct option is 3.

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

The prom committee is made up of 8 boys and girls.

If there are 12 boys and 15 girls in the group to pick the committee from.

Then the number of ways can the committee be organized will be

Then the number of ways is given by the combination formula. Then we have

Number of ways = ¹²C₀ x ¹⁵C₈ + ¹²C₁ x ¹⁵C₇ + ¹²C₂ x ¹⁵C₆ + ¹²C₃ x ¹⁵C₅ + ¹²C₄ x ¹⁵C₄ + ¹²C₅ x ¹⁵C₃ + ¹²C₆ x ¹⁵C₂ + ¹²C₇ x ¹⁵C₁ +¹²C₈ x ¹⁵C₀

Number of ways = 6435 + 77220 + 330330 + 660660 + 675675 + 360360 + 97020 + 11880 + 495

Number of ways = 2220075

Thus, the correct option is 3.

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Answer: y=2x+7

(this is a rearranged version of y-2x=7 from question)

Step-by-step explanation:

4x=5-2y

y-2x=7

i would rearrange the 2nd value into y intercept form y=mx+b

so move the -2x to the other side of the = sign by doing the opposite, +2x on both sides to isolate the y

y=2x+7

you didn't give any options for "correct answer" so i can't give

you A B C or D answers

Answer:

Step-by-step explanation:

SOH CAH TOA

we have the (opposite) --> 325
we have the (adjacent) --> 296

so do the inverse tan of opposite over adjacent...
[tex]tan^{-1} (\frac{325}{296} ) = 47.67[/tex] degrees

Parameterize S by the vector function

[tex]\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle[/tex]

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

[tex]\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle[/tex]

The integral of the field over S is then

[tex]\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}[/tex]

Answer:

Hi,

Step-by-step explanation:

directrix: x=-8

focus=(8,0)

[tex]x=\dfrac{(y-0)^2}{2*(8+8)}+\dfrac{8-8}{2}\\\\\boxed{x=\dfrac{y^2}{32}}[/tex]