Select the correct answer
If h is a function and -7 is an element in its domain, then which of the following statements correctly describes the expression (-7)?
The expressiurhit-7). represents the output of h corresponding to the input of -7.
The expression (-7) represents that -7 is the only element in the domain of h.
The expression h(-7) represents the input of h corresponding to the output of -7.
The value of h should be multiplied by -7 to evaluate the expression
Reset
Submit

Answer:

7 seconds

Step-by-step explanation:

1820/260=7.

Answer:

7m/sec

Step-by-step explanation:

Answer:

1/12

Step-by-step explanation:

1/6 divided by 2 = 1/12

Answer:

[tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

General Formulas and Concepts:

Alg I

Terms/CoefficientsFactorExponential Rule [Dividing]: [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]

Pre-Calc

[Right Triangle Only] Pythagorean Theorem: a² + b² = c²

a is a legb is a legc is hypotenuse

Trigonometric Ratio: [tex]\displaystyle sec(\theta) = \frac{1}{cos(\theta)}[/tex]

Trigonometric Identity: [tex]\displaystyle tan^2\theta + 1 = sec^2\theta[/tex]

TI: [tex]\displaystyle sin(2x) = 2sin(x)cos(x)[/tex]

TI: [tex]\displaystyle cos^2(\theta) = \frac{cos(2x) + 1}{2}[/tex]

Calc

Integration Rule [Reverse Power Rule]:                                                                [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

IP [Addition/Subtraction]:                                                             [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

U-Substitution

U-Trig Substitution: x² + a² → x = atanθ

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int {\frac{dx}{(81x^2 + 4)^2}}[/tex]

Step 2: Identify Sub Variables Pt.1

Rewrite integral [factor expression]:

[tex]\displaystyle \int {\frac{dx}{[(9x)^2 + 4]^2}}[/tex]

Identify u-trig sub:

[tex]\displaystyle x = atan\theta\\9x = 2tan\theta \rightarrow x = \frac{2}{9}tan\theta\\dx = \frac{2}{9}sec^2\theta d\theta[/tex]

Later, back-sub θ (integrate w/ respect to x):

[tex]\displaystyle tan\theta = \frac{9x}{2} \rightarrow \theta = arctan(\frac{9x}{2})[/tex]

Step 3: Integrate Pt.1

[Int] Sub u-trig variables:                                                                                 [tex]\displaystyle \int {\frac{\frac{2}{9}sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                           [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4tan^2\theta + 4]^2}} \ d\theta[/tex][Int] Factor:                                                                                                      [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4(tan^2\theta + 1)]^2}} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4sec^2\theta]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{16sec^4\theta} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{72} \int {\frac{sec^2\theta}{sec^4\theta} \ d\theta[/tex][Int] Divide [ER - D]:                                                                                         [tex]\displaystyle \frac{1}{72} \int {\frac{1}{sec^2\theta} \ d\theta[/tex][Int] Rewrite [TR]:                                                                                            [tex]\displaystyle \frac{1}{72} \int {cos^2\theta} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{1}{72} \int {\frac{cos(2\theta) + 1}{2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{144} \int {cos(2\theta) + 1} \ d\theta[/tex][Int] Rewrite [Int Prop - A/S]:                                                                          [tex]\displaystyle \frac{1}{144} [\int {cos(2\theta) \ d\theta + \int {1} \ d\theta][/tex]  

Step 4: Identify Sub Variables Pt.2

Determine u-sub for trig int:

u = 2θ

du = 2dθ

Step 5: Integrate Pt.2

[Ints] Rewrite [Int Prop - MC]:                                                                       [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {2cos(2\theta) \ d\theta + \int {1 \theta ^0} \ d\theta][/tex][Int] U-Sub:                                                                                                     [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {cos(u) \ du + \int {1 \theta ^0} \ d\theta][/tex][Ints] Integrate [Trig/Int Rule - RPR]:                                                             [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(u) + \theta + C][/tex][Expression] Back Sub:                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(2 \theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Rewrite [TI]:                                                                                           [tex]\displaystyle \frac{1}{144} [\frac{1}{2}(2sin(\theta)cos(\theta)) + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [sin(\theta)cos(\theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Back Sub:                                                                                             [tex]\displaystyle \frac{1}{144} [sin(arctan(\frac{9x}{2}))cos(arctan(\frac{9x}{2})) + arctan(\frac{9x}{2}) + C][/tex]

Step 6: Triangle

Find trig values:

[tex]\displaystyle tan\theta = \frac{9x}{2}[/tex]

[tex]\displaystyle \theta = arctan(\frac{9x}{2})[/tex]

tanθ = opposite / adjacent; solve hypotenuse of right triangle, determine trig ratios:

sinθ = opposite / hypotenuse

cosθ = adjacent / hypotenuse

Leg a = 2

Leg b = 9x

Leg c = ?

Sub variables [PT]:                                                                                         [tex]\displaystyle 2^2 + (9x)^2 = c^2[/tex]Evaluate exponents:                                                                                      [tex]\displaystyle 4 + 81x^2 = c^2[/tex][Equality Property] Square root both sides:                                                  [tex]\displaystyle \sqrt{4 + 81x^2} = c[/tex]Rewrite:                                                                                                           [tex]c = \sqrt{81x^2 + 4}[/tex]

Substitute into trig ratios:

[tex]\displaystyle sin\theta = \frac{9x}{\sqrt{81x^2 + 4}}[/tex]

[tex]\displaystyle cos\theta = \frac{2}{\sqrt{81x^2 + 4}}[/tex]

Step 7: Integrate Pt.3

[Exp] Sub variables [TR]:                                                                               [tex]\displaystyle \frac{1}{144} [\frac{9x}{\sqrt{81x^2 + 4}} \cdot \frac{2}{\sqrt{81x^2 + 4}} + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{18x}{81x^2 + 4} + arctan(\frac{9x}{2}) + C][/tex][Exp] Distribute:                                                                                             [tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

Answer:

It won't let me see the picture

Step-by-step explanation:

Multiply 5 or d. Dhbsjvbdnd

Answer:

0.192 hour

Step-by-step explanation:

41$ / 8 = 0.192 hours = 11.703 minutes

Answer: 36.56

Step-by-step explanation:

Answer: The answer is 18

Answer:

[tex] - 3 + 5 + 7 - 18 + 36 \\ - 3 + 12 - 18 + 36 \\ - 21 + 36 \\ = 15 \: \: \: ans.[/tex]

Answer:

Option (1)  ;   y = 7x

Step-by-step explanation:

(1) reads y = 7x, a line with slope 7, therefore the rate of change in this is 7

(2) says that y increases 12 units every time that x increases 4 Then the rate of change is: (increase in y / increase in x = 12/4 =3

(3) shows a table from which we can see that an increase of y in 8 corresponds to an increase of x in 2:  rate of change = (8 - 0) , (2 - 0) = 4

(4) shos a line with slope (rate of change) given by:  (12 - 0) / (2 - 0) = 12/2 = 6

Therefore, the greatest rate of change is shown by the first expression  

y = 7 x

Answer:

5 kilos

Step-by-step explanation:

55:11

5:1 ratio

Answer:

4

Step-by-step explanation:

44 yeah yeah what about the other

Answer:

Step-by-step explanation:

d=20t+1/3, b=30t

20t+1/3=30t

10t=1/3

t=1/30 hr

t=(1/30)60=2 min

Answer:

He can buy 10 cds

Step-by-step explanation:

125-30=95

95 divided by 9 = 10.5555555556

Answer: It would be  2 1/2 liters

Step-by-step explanation:

There can be 2 and a half litres of water will be filled in 1 bottle.

What is division?

Division is breaking a number up into an equal number of parts.

Given that,  3 litres of water can fill 1 ⅕ bottles,

Since, there are 3 litres in 6/5 bottles

so, 1 litre = 6/5×3 = 2 ¹/₂

Hence, There can be 2 and a half litres of water will be filled in 1 bottle.

For more references on division, click;

https://brainly.com/question/21416852

#SPJ2

Answer:

15/2

Step-by-step explanation:

5/1 * 3/2 = 15/2

1 - 0.082 = 0.918
Multiply by 0.918

Answer:

Rhombus

Step-by-step explanation:

The diagonals of Rhombus bisect each other and form 4 right triangles. Since they are right triangles, they measure 90 degrees so the diagonals are perpendicular.

Answer:

2=72 4=148  6=222  10=370 15=555 16=592

sorry about the second part i didnt see it

Answer:

148, 3 , 740, 1110, 8.

Step-by-step explanation:

Miles: 148 + 740 + 1,110 = 1,998

Gallons: 2 + 4 + 3 + 10 + 15 + 8 = 42

Answer:

the correct choice would be the last choice!

Step-by-step explanation:

Answer:

D) 23.5

Step-by-step explanation:

First solve for x² + y³, which inserting the numbers would be 4² + 5³. This is also 16 + 125 or 141. Now solve for the bottom: 2 + x or 2 + 4 to get 6. Divide 141/6 to get 23.5.

Hope it helps!

Answer:

$22.5

Step-by-step explanation:

You will pay $22.5 for a item with original price of $30 when discounted 25%.

Answer:

Refer to explanation

Step-by-step explanation:

The screenshot you put is the correct answer, here's another method to get the same answer:

Find what 25% is.

100% = 30

1% = 30 ÷ 100 = 0.30

25% = 0.30 x 25 = 7.50

Find the price after the 25% discount.

100 - 25 = 75

75% = 30 - 7.50 = 22.50 or 0.30 x 75 = 22.50 (Both solutions give the same answer)

Answer:

2.55     2.56    2.57

Step-by-step explanation:

Answer:

2.51, 2.52, 2.59

Step-by-step explanation:

Ay yo whats good bro

a. x= 11/5
b. x= 6
c. x= -12/2
d. x= 6/5

Answer:

Your answer is "H"

Step-by-step explanation:

The answer is the answer is H

Answer:

11

Step-by-step explanation:

i don't know

Answer:

the twelve pack

Step-by-step explanation:

12 pack = $10.08 if u get the 6 pack for $5.34 and want to buy two pack it equals $10.68 if you want to save change buy the 12 pack

The 6 pack is the better buy because the cost per soda would be about $1.12, vs with the 12 pack the cost per soda would be about $1.19

9514 1404 393

Answer:

  60 cm

Step-by-step explanation:

The model ship will be x feet long, where ...

  x/100 = 1/50

  x = 100/50 = 2

In meters, that is ...

  2(0.3 m) = 0.6 m

A meter is 100 cm, so the length in centimeters is ...

  (0.6)(100 cm) = 60 cm

So the sum of both deserts is 30000000 and one is 9 times more than the other, it’s a 1:9 ratio. 9+1 is ten and 30000000/10 is 3,000,000. That’s the area of the smaller desert. You multiply 3 million by 9 and get 27,000,000 sq miles for the larger desert. Hope that makes some sense! :)

Answer:

Number of moles Aluminium sulfide

1 mole of sulfide contains 150 g

Therefore; 16.2/150  

              = 0.108 moles  

The mole ratio of Al2S3 : Al(OH)3 is 1:2

Therefore; moles of Aluminium hydroxide will be;

 = (0.108 × 2)

 = 0.216 moles  

But, 1 mole of  Al(OH)3 contains 77 g

Therefore, the mass of aluminium hydroxide is

  0.216 moles × 77

=  16.632 g

Step-by-step explanation:

Given:

The geometric sequence is

[tex]4, -12, 36,...[/tex]

To find:

The sum of first 8 terms of the given geometric sequence.

Solution:

We have,

[tex]4, -12, 36,...[/tex]

Here, the first term is 4 and the common ratio is

[tex]r=\dfrac{-12}{4}[/tex]

[tex]r=-3[/tex]

The sum of first n terms of a geometric sequence is

[tex]S_n=\dfrac{a(r^n-1)}{r-1}[/tex]

Where, a is the first term and r is the common ratio.

Putting n=8, a=4 and r=-3, we get

[tex]S_8=\dfrac{4((-3)^8-1)}{-3-1}[/tex]

[tex]S_8=\dfrac{4(6561-1)}{-4}[/tex]

[tex]S_8=-6560[/tex]

Therefore, the sum of first 8 terms is -6560.

Answer:

8

Step-by-step explanation:

12 times 1/2=6

(-4(1/2))= -2

6-(-2)

6+2

=8

Answer:

i am gessing to divide

Step-by-step explanation: