ANSWER: B
Explanation:
Answer:
B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
Explanation:
on edg... good luck!!
Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4?
A. 1.15 × 10^23
B. 1.84 × 10^24
C. 4.61 × 10^23
D. 7.87 × 10^23
Answer:
B. 1.84 × 10^24
Explanation:
[tex]75.0 g H2SO4(\frac{1 mol H2SO4}{98.1 g})(\frac{4 mol O}{1 mol H2SO4})(\frac{6.023 x 10^23 atoms}{1 mol O} )[/tex] = 1.84 x 10^24 atoms
2 M n O 2 + 4 K O H + O 2 + C l 2 → 2 K M n O 4 + 2 K C l + 2 H 2 O , there are 100.0 g of each reactant available. Which reactant is the limiting reagent?
Answer:
The limiting reactant is KOH.
Explanation:
To find the limiting reactant we need to calculate the number of moles of each one:
[tex]\eta = \frac{m}{M}[/tex]
Where:
η: is the number of moles
m: is the mass
M: is the molar mass
[tex] \eta_{MnO_{2}} = \frac{100.0 g}{86.9368 g/mol} = 1.15 moles [/tex]
[tex] \eta_{KOH} = \frac{100.0 g}{56.1056 g/mol} = 1.78 moles [/tex]
[tex] \eta_{O_{2}} = \frac{100.0 g}{31.998 g/mol} = 3.13 moles [/tex]
[tex] \eta_{Cl_{2}} = \frac{100.0 g}{70.9 g/mol} = 1.41 moles [/tex]
Now, we can find the limiting reactant using the stoichiometric relation between the reactants in the reaction:
[tex]\eta_{MnO_{2}} = \frac{\eta_{MnO_{2}}}{\eta_{KOH}}*\eta_{KOH} = \frac{2}{4}*1.78 moles = 0.89 moles[/tex]
We have that between MnO₂ and KOH, the limiting reactant is KOH.
[tex]\eta_{O_{2}} = \frac{\eta_{O_{2}}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{1}{1}*1.41 moles = 1.41 moles[/tex]
Similarly, we have that between O₂ and Cl₂, the limiting reactant is Cl₂.
Now, the limiting reactant between KOH and Cl₂ is:
[tex]\eta_{KOH} = \frac{\eta_{KOH}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{4}{1}*1.41 moles = 5.64 moles[/tex]
Therefore, the limiting reactant is KOH.
I hope it helps you!
Answer:
KOH is the limiting reactant
Explanation:
Step 1: Data given
Mass of MnO2 = 100 grams
Mass of KOH = 100 grams
Mass of O2 = 100 grams
Mass of Cl2 = 100 grams
Molar mass of MnO2 = 86.94 g/mol
Molar mass of KOH = 56.11 g/mol
Molar mass of O2 =32.0 g/mol
Molar mass of Cl2 = 70.9 g/mol
Step 2: The balanced equation
2MnO2 + 4KOH + O2 + Cl2 → 2 KMnO4 + 2KCl + 2H2O
Step 3: Calculate moles
Moles = mass / molar mass
Moles MnO2 = 100 grams / 86.94 g/mol
Moles MnO2 =1.15 moles
Moles KOH = 100 grams / 56.11 g/mol
Moles KOH = 1.78 moles
Moles O2 = 100 grams / 32.0 g/mol
Moles O2 = 3.125 moles
Moles Cl2 = 100 grams / 70.9 g/mol
Moles Cl2 = 1.41 moles
Step 4: Calculate the limiting reactant
For 2 moles MnO2 we need 4 moles KOH and 1 mol O2 and 1 mol Cl2 to produce 2 moles KMnO4, 2 moles KCl and 2 moles H2O
KOH is the limiting reactant. It will completely be consumed (1.78 moles). The other reactants are in excess.
There will react:
MnO2: 1.78/ 2 = 0.89 moles
O2: 1.78/4 = 0.445 moles
Cl2: 1.78/4 = 0.445 moles
There wil remain:
MnO2: 1.15 - 0.89 = 0.26 moles
O2: 3.125 - 0.445 = 2.68 moles
Cl2: 1.41 - 0.445 = 0.965 moles
KOH is the limiting reactant
Please help(15 points)
Why aren’t granite, copper, or petroleum found everywhere on Earth’s surface?
Answer: because they take a lot of tie to form
4) A solution has a pH of 2.0. What is true about this solution? *
The [H+] is greater than the [OH-].
The poH is 7.
It is a basic solution.
It has a [OH-] of 0.01.
Answer:
A is correct
Explanation:
The pOH is 12
It is acidic
OH- is actually .0000000001
- Hope that helps! Please let me know if you need further explanation.
When will the simping end
Answer:
Nvr XD
Explanation:
Answer:
the world may never know
Explanation:
How many moles of O2 are needed to react completely with 35.0 mol of 10 points
FeCl3? *
4FeCl3 + 302 — 2Fe2O3 + 3Cl2
A) 26.3 mol
B) 46.7 mol
C) 23.3 mol
D) 10.0 mol
a solution contains 29.1g per litre of aluminium sulphate.calculate the number ofsulphate ions in 350cm^3 of the solution(Al=27,S=32,O=16)
Answer:
it is 0.24 M
Explanation
Find the molarity of all ions in a solution that contains 0.165 moles of aluminum chloride in 820. ml solution. " Answer: [Al 3+1= 0.201 M. (CI) = 0.603M. ... 2) Find the molartiy of each ion present after mixing 27 ml of 0.25 M HNO3 with 36 ml of ... of each ion and the mass of any precipitate when a 0.300 mole of aluminum.
What is the molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl?
Answer:
The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 [tex]\frac{moles}{L}[/tex]
Explanation:
Molarity is a unit of concentration based on the volume of a solution and is defined as the number of moles of solute per liter of solution. Then, the molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution.
[tex]Molarity (M)=\frac{number of moles of the solute}{volume of the solution}[/tex]
Molarity is expressed in units ([tex]\frac{moles}{liter}[/tex]).
Then you must know the amount of moles of the NaCl solute. For that it is necessary to know the molar mass. Being:
Na: 23 g/moleCl: 35.45 g/molethe molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole
Then a rule of three applies as follows: if 58.45 grams are present in 1 mole of NaCl, 10 grams in how many moles will they be?
[tex]moles=\frac{10 grams*1 mole}{58.45 grams}[/tex]
moles= 0.171
So you know:
number of moles of solute= 0.171 molesvolume= 50 mL= 0.05 LReplacing in the definition of molarity:
[tex]Molarity (M)=\frac{0.171 moles}{0.05 L}[/tex]
Solving:
Molarity= 3.42 [tex]\frac{moles}{L}[/tex]
The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 [tex]\frac{moles}{L}[/tex]
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.5 kJ/mol; and H2 O(g): Hf = –241.82 kJ/mol. How much heat is released by the combustion of 2 mol of methane? Use .
Answer:
The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol
Explanation:
The chemical reaction of the combustion of methane is given as follows;
CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)
Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor
Where:
CH₄ (g): Hf = -74.6 kJ/mol
CO₂ (g): Hf = -393.5 kJ/mol
H₂O (g): Hf = -241.82 kJ/mol
Therefore, the combustion of 1 mole of methane releases;
-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol
Hence the combustion of 2 moles of methae will rellease;
2 × -802.54 kJ/mol or 1,605.08 kJ/mol.
Answer: answer is C
Explanation:
Just took the test
How many times more acidic is a pH of 2 than a PH of 7?
Answer: 10 times more
Explanation:
Copy the sentences below. Correcting the five mistakes.
In a displacement reaction, a less reactive metal pushes out a more reactive metal from its compound. For example, iron displaces aluminium from aluminium oxide.
Answer:
In a displacement reaction, a more reactive metal pushes out a less reactive metal from its compound. For example, aluminium displaces iron from iron oxide.
Explanation:
Because aluminium is more reactive than iron, it displaces iron from iron(III) oxide. The aluminium removes oxygen from the iron(III) oxide: iron is reduced.
...
Hope this answer can help you. Have a nice day!
In a displacement reaction, a more reactive metal pushes out a less reactive metal from its compound. For example, aluminium displaces iron from iron oxide.
What is a compound?Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:
1)Molecular compounds where in atoms are joined by covalent bonds.
2) ionic compounds where atoms are joined by ionic bond.
3)Inter-metallic compounds where atoms are held by metallic bonds
4) co-ordination complexes where atoms are held by co-ordinate bonds.
They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.
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Given the equation representing a solution equilibrium: BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq)
What occurs when Na2SO4(s) is added to this system, increasing the concentration of SO4 2- (aq)?
1) The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases
2)The equilibrium shifts to the left, and the concentration of Ba2+(aq) increases
3)The equilibrium shifts to the right, and the concentration of Ba2+(aq) decreases
4)The equilibrium shifts to the right, and the concentration of Ba2+(aq) increases
Answer:
The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases
Explanation:
Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.
In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;
BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.
This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.
1) The equilibrium shifts to the left, and the concentration of [tex]Ba^{2+}[/tex](aq) decreases
Conditions for equilibrium:Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in the solution decreases significantly.
In this case, both BaSO₄ and Na₂SO₄ both possess the [tex]SO_4^{2-}[/tex] anion. Hence [tex]SO_4^{2-}[/tex] anion is the common ion.
Given the equilibrium;
[tex]BaSO_4(s) < = > Ba^{2+} (aq) + SO_4^{2-} (aq)[/tex],
The addition of Na₂SO₄ will decrease the solubility of BaSO₄ due to the presence of a common [tex]SO_4^{2-}[/tex] anion compared to pure water.
This implies that the equilibrium will shift to the left, (more undissociated BaSO₄ ) hence decreasing the [tex]Ba^{2+}[/tex]aq) concentration.
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mention two instruments that could be used to transfer sodium hydroxide solution into conical flask
Answer:
Pipette and Burettes
Explanation:
The two instruments that can be used for
a) Pipette – It is used to dispense measured volume of any liquid into any other equipment. Pipette works on the concept of creating a partial vacuum to take in the liquid and then release the volume to dispense the liquid.
b) Burettes – It has a stopcock that regulate the release of liquid. It is larger than the pipette and works as a graduated cylinder.
The element hydrogen has the highest specific heat of all elements. At room temperature, hydrogen's specific heat is 14.30 J/g •°C. If the temperature of a 340.0 g sample of hydrogen is to be raised by 30°C, how much energy will have to be added to the hydrogen?
Answer:
THE ENERGY NEEDED TO BE ADDED TO RAISE THE TEMPERATURE BY 30°C IS 145, 860 J
Explanation:
The energy needed can be calculated by using the heat formula, which is;
Heat = m c ΔT
m = mass of the hydrogen = 340 g
c = specific heat capacity of hydrogen at room temperature = 14.30 J/g°C
ΔT = change in temperature = 30°C
Heat =?
So therefore,
Heat = 340 * 14.30 * 30
Heat = 145860 J
The energy needed to be added to the hydrogen to bring the mass of 340 g to an increased temperature of 30°C is 145, 860 J or 145.86kJ
Which is the molar mass of Calcium?
Answer:
40.078 u
Explanation:
Which is not a reason that water is used to store spent fuel rods from nuclear power plants?
Water increases the speed of the chain reaction in the fuel rods.
Water protects nuclear power plant workers from the high temperature and radiation of the fuel rods.
Water acts as a radiation shield to reduce the radiation levels.
Water cools the spent rods.
Answer:
I believe the answer would be A
Unlike an acid, an aqueous solution of a base A) causes some indicators to change color B) conducts electricity C) contains more H+ ions than OH– ions D) contains more OH– ions than H+ ions
Answer:
D) contains more OH– ions than H+ ions
Explanation:
Bases have high concentration of hydroxides (OH-) and acids have high concentration of (H+) ions
Like an acid the aqueous solution of a base should be option D) contains more OH– ions than H+ ions.
What is aqueous solution of a base?An aqueous solution refers to the solvent when it should be dissolved in the liquid water. It is considered to be the solute ions or the dissolved ions also the molecules should be surrounded by the water molecules and it should be incorporated when the network of the bond should lies within the water.
Also, the base contains high concentration of hydroxides (OH-) and acids have high concentration of (H+) ions
Hence, the option d is correct.
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The chemical formulas for the following-
Copper (II) and Iodine
Potassium and Fluorine
Barium and Fluorine
Lithium and Oxygen
Copper (II) and Sulfur
Silver sulface
Lithium hydroxide
Barium phosphate
Ammonium sulfide
Magnesium fluoride
Sodium Chloride
aluminum phosphide
copper (I) oxide
im so sorry, i need help as soon as possible, this is due like right now and my dad is yelling at me
Which of the following is the correct definition of conduction?
A.
the transmission of heat across empty space
B.
the electromagnetic radiation from the surface of an object which is due to the object's temperature
C.
the transfer of heat by currents within a liquid or gas
D.
the transmission of heat across matter
Answer:
the transmission of heat across matter
Explanation:
Conduction is the transmission of heat across matter. Even though heat flows across matter during conduction, the matter itself does not flow.
In ΔDEF, the measure of ∠F=90°, FE = 16, DF = 63, and ED = 65. What ratio represents the tangent of ∠E?
Answer:
63/16
Explanation:
tanE=
adjacent
opposite
=
16
63
Answer:
63/16
Explanation:
this for delta math?
Which type of plant used light, feathered seeds?
What would a zebra be?
consumer
decomposer
producer
Answer:
Zebra- consumer
Tiger- consumer
Worm- decomposer
Tree-Producer
Molded bread- decomposer
Plant- producer
Answer:
Type of plant - Dandelion .Zebra is a Consumer .Explanation:
Dandelion plant produces light and feathery seeds .
Zebra consumes / eats grass so it is a consumer .
What is a covalent bond
if the [H+] = 0.01 M, what is the pH of the solution, and is the solution a strong acid, weak acid, strong base, or weak base?
12, strong base
2, weak acid
12, weak base
2, strong acid
Answer:
2, strong acid
Explanation:
Data obtained from the question. This includes:
[H+] = 0.01 M
pH =?
pH of a solution can be obtained by using the following formula:
pH = –Log [H+]
pH = –Log 0.01
pH = 2
The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.
Since the pH of the above solution is 2, it means the solution is a strong acid.
Can someone help me with this?
Answer:
D) condensing C) boiling
You are given the reaction Cu + HNO3 Cu(NO3)2 + NO + H2O complete the final balanced equation based on half-reactions
The balanced equation based on half-reactions is 2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O.
How to determine the balanced equation based on half-reactionsTo complete the balanced equation for the given reaction Cu + HNO3 -> Cu(NO3)2 + NO + H2O using half-reactions, we need to break down the overall reaction into separate oxidation and reduction half-reactions.
1. Oxidation Half-Reaction:
Cu -> Cu2+ + 2e-
In this step, copper (Cu) is oxidized, losing two electrons to form copper(II) ions (Cu2+).
2. Reduction Half-Reaction:
HNO3 + 3H+ + 2e- -> NO + 2H2O
In this step, nitric acid (HNO3) is reduced, gaining two electrons to form nitric oxide (NO) and water (H2O).
Now, to balance the half-reactions, we need to make sure that the number of electrons gained in the reduction half-reaction is equal to the number of electrons lost in the oxidation half-reaction. In this case, we can achieve this by multiplying the oxidation half-reaction by two.
Balanced Half-Reactions:
Oxidation: 2Cu -> 2Cu2+ + 4e-
Reduction: HNO3 + 3H+ + 2e- -> NO + 2H2O
Finally, we can combine the balanced half-reactions to obtain the balanced equation for the overall reaction:
2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O
Therefore, the balanced equation based on half-reactions is 2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O.
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5. How is a cell wall different from a cell membrane?
A balloon containing N2 has 1.70 moles and occupies 3.80L. What will the volume be if the number of moles is increased to 2.60moles?
Help me please
Answer:
5.81L
Explanation:
N1 = 1.70 moles
V1 = 3.80L
V2 = ?
N2 = 2.60 moles
Mole - volume relationship,
N1 / V1 = N2 / V2
V2 = (N2 × V1) / N1
V2 = (2.60 × 3.80) / 1.70
V2 = 9.88 / 1.70
V2 = 5.81 L
The volume of the gas is 5.81L
what is the compound of scI2
Answer:
sulfur dichloride
Explanation:
SCl2 is the chemical formula for sulfur dichloride. This compound is made of only two elements, so it is a binary compound.
Atom X contains seven protons and seven neutrons. Atom Z contains seven and eight neutrons. Which of the following statemenats correctly describes the two atoms?
A.They are isotopes
B.They are radioactive
C.They are atims of different elements.
D. They have the same mass number
Piz help!!!!
Answer:
A. They are isotopes.
Explanation:
An isotope is an element with the same number of protons but different number of neutrons resulting in a varied mass number/molecular weight.
Which statement is true about the total mass of the reactants during a chemical change?
Answer:
Equal to the total mass
Explanation:
just took the test
Relative and average atomic mass both describe properties of an element related to its different isotopes. Out of these two Relative atomic mas is more accurate. Therefore, the correct option is option C.
What is mass?Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope. In chemistry relative mass is equal to the mass of one-twelfth the mass of C-12 isotope .
Average atomic mass = (mass of first isotope× percent abundance of first isotope)+(mass of second isotope× percent abundance of second isotope)
The total mass of the reactants during a chemical change is equal to the total mass of the product.
Therefore, the correct option is option C.
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