Read the excerpt from the story Winter Driving:

(3) "Yes, that's a good idea," Mina replied. "You have a long drive ahead of you, and it looks like the snow is not going to stop anytime soon. You don't want to get stuck anywhere on the roads, that would be even worse," Mina said worriedly as she walked Jesper to the door and handed him his jacket, which had been hanging on the coat rack.

(4) "Thank you so much for your hospitality, Mina. Keep in touch, and I will see you again soon." He hugged her goodbye and waved to the rest of the group before heading out the door. He took the elevator down to the main floor of the apartment building and walked to his car.

How do the events in paragraphs 3 and 4 contribute to the reader's understanding of Mina's feelings toward Jesper?

A By saying to Jesper that the snow isn't going to stop for a long time, Mina shows that she thinks Jesper is being silly by driving in the bad conditions.

B By walking him to the door and saying that they shouldn't wait so long to get together again, Mina shows that she enjoyed the visit with Jesper.

C By saying that Jesper has a long drive and that the snow isn't going to stop for a long time, Mina shows that she wants Jesper to stay longer.

D By walking him to the door and saying that they shouldn't wait so long to get together again, Mina shows that she hopes Jesper doesn't come back.

Answers

Answer 1
B or C I’m thinking but my guess is most likely C because they didn’t really say “they shouldn’t wait so long to get together again” they just said they’ll keep in touch
Answer 2

Answer:

C

Explanation:

So Sry if im wrong

But if im right pls mark me as brainiest

~~~~Stay Safe~~~~


Related Questions

Show an example of how to evaluate a trigonometric function using reference
angle (without a calculator/ you may use left hand rule or unit circle)

Answers

Answer:

[tex]\cos(150) = -\frac{\sqrt 3}{2}[/tex]

Explanation:

An example is as follows;

Using reference angle, evaluate [tex]\cos(150)[/tex]

Solution:

We have: [tex]\cos(150)[/tex]

150 degrees is in the second quadrant, and it makes 30 degrees (i.e. 180 - 150) with the x-axis.

This implies that, cos(150) has the same magnitude as cos(30);

The only difference in the values is the sign; because

30 degrees is in the first quadrant where all functions are positive150 degrees is in the third quadrant where all cosine is negative

So, we have:

[tex]\cos(150) = -\cos(30)[/tex]

-----------------------------------------------

[tex]\cos(30) = \frac{\sqrt 3}{2}[/tex]

-----------------------------------------------

[tex]\cos(150) = -\frac{\sqrt 3}{2}[/tex]

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