Points that two lines pass through are given in the table. Match each point of intersection to the correct pair of lines.
(2, 0)
(-1, 3)
(1, 0)
(-1, -3)
(0, 2)
(-3, -1)

Answer:

It's 3[tex]x^{2}[/tex]/86

hope this helps:)

Answer:

43.2857142857

plz mark me as brainliest

Answer:

476.142857143

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The probability is 1/3

Answer:

Step-by-step explanation:

1. Write the question.

17 - 2x = -11

2. Subtract 17 from both sides

-17          -17

    - 2x = -28

3. Negatives cancel

      2x = 28

4. Divide both sides by 2

        /2     /2

        x = 14

5. Check the answer, write the equation.

17 - 2x = -11

6. Substitute x with the value

17 - 2(14) = -11

17 - 28 = -11

-11 = -11

The answer is correct!

Hope this helped,

Kavitha

Answer: (4+1)*5=25; (25+1)*5=130; (130+1)*5=655.

Step-by-step explanation:

Answer:

375

Step-by-step explanation:

500-125(25% of 500)=375

Answer:

-3 + 8 = 5

Step-by-step explanation:

When we have a "minus a negative", it's a positive. So the - -8 is the same as + 8.

LMK if you have questions.

-3 + -8 = -11

is that a nice one or something

Answer:

The theoretical probabilty of the coin landing on tails is 50/50 so their is a 50% chance of it landing on tails so theoretically it would land on tails 15 out of 30 times

Step-by-step explanation:

Answer:

circle area = 50.24 units²

Step-by-step explanation:

circle area = πr² = 3.14(4²) = 3.14(16) = 50.24 units²

Answer:

Similar by: SAS

ΔPKM ~ ΔLQM

Yes, the triangles PMK and LMQ are similar by SAS similarity statement.

A triangle is a three-sided polygon that consists of three edges and three vertices.

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

The triangles PKM and triangle LMQ are the similar triangles.

If two sides and the included angle in one triangle are congruent to two sides and the included angle in another triangle, then the two triangles are congruent

Both the triangles have a common angle M and two sides are proportional

∠LMQ = ∠PMK

The sides are proportional

LM/PM = QM/KM

The triangles are similar

ΔPKM ~ ΔLQM

Hence, Yes the triangles PMK and LMQ are similar by SAS similarity statement.

To learn more on Triangles click:

https://brainly.com/question/2773823

#SPJ2

Answer:

√89

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(9 - 1)² + [-6 - (-1)]²

√(8)² + (-5)²

√64 + 25

√89

Answer without Explanation:

B

Answer:

A vertical line

Answer:

m∠R = 123°

m∠S = 91°

Step-by-step explanation:

The measure of an inscribed angle is 1/2 the measure of the intercepted arc

m of arc QRS = 2 m∠P = 2(57) = 114

Now m of arc SPQ = 360 - 114 = 246

So, m∠R = 1/2(246) = 123

m of arc RSP = 2 m∠Q = 2(89) = 178

m of arc PQR = 360 - 178 = 182

m∠S = 1/2(182) = 91

50. 150 divided by 3

Answer:

x = 0

Step-by-step explanation:

hi there!

im not sure if the x between the 2's is a x as in a variable or if it is multiplication sign. im going to solve the problem as if it is a multiplication sign but if that is wrong then please let me know!

2 * 2 + x - 4 = 0

is our equation that we are working with ^

first step is, following the pemdas we multiply *2 with its self

( ^ parentheses, exponents, multiplication/ division making sure to solve it left to right, addition and subtraction still making sure to follow the left to right rule )

2 * 2 + x - 4 = 0

2 * 2

= 4 + x - 4 + 0

then we add positive 4 and negative 4 together, canceling eachother out the giving us the answer of  x = 0

4 + x - 4 + 0

4 + - 4 = 0

x = 0

i hope this helps you! have a good rest of your day :)

Answer:

B is the correct answer

Step-by-step explanation:

Answer:

−1+1.732051i

Step-by-step explanation:

Answer:

The circumference would be 25.12 mm

Step-by-step explanation:

[tex]c = 2\pi r[/tex]

[tex]c = 6.28 \times 4[/tex]

[tex]c = 25.12[/tex]

Answer:

c = [tex]\sqrt{58}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

c² = 7² + 3² = 49 + 9 = 58 ( take the square root of both sides )

c = [tex]\sqrt{58}[/tex]

Answer:

Step-by-step explanation:

According to Pythagoras Theorem:

[tex] {7}^{2} + {3}^{2} = {c}^{2} [/tex]

Hence,

[tex] = > {c}^{2} = {7}^{2} + {3}^{2} [/tex]

[tex] = > {c}^{2} = 49 + 9[/tex]

[tex] = > {c}^{2} = 58[/tex]

[tex] = > c = \sqrt{58} [/tex]

So,

[tex]c = \sqrt{58} [/tex]

Is the answer.

8 x 7s = 56s

8 x (-2) = -16

so 8(7s - 2) = 56s - 16

Answer:

20 people chosen to March

Step-by-step explanation:

The sample can be explained as a random subset of the population. It is a given number of draws or selection made usually at Random from the entire or larger population set. The sample is usually smaller Than the population and if done randomly will be representative of the population set. The entire spectator attending the baseball game is the population of interest while the 20 selected from the entire pool to March in the victory parade is the sample data obtained from the population set.

Answer:

(a) His speed when he runs from C to A is [tex]4.\overline {285714}[/tex] m/s

(i) The bearing of B from A is approximately 127.18°

(ii) The bearing of A from B is approximately 307.18°

Step-by-step explanation:

(a) The given parameters are;

The distance from A to B = 120 m

The speed with which Olay runs from A to B, v₁ = 4 m/s

The distance from B to C = 180 m

The speed with which Olay runs from B to C, v₂ = 3 m/s

The distance from C to A = 150 m

His average speed for the whole journey = 3.6 m/s

We find

The total distance of running from A back to A, d = 120 m + 180 m + 150 m = 450 m

The time it takes to run from A to B, t₁ = 120 m/(4m/s) = 30 seconds

The time it takes to run from B to C, t₂ = 180 m/(3m/s) = 60 seconds

Let t₃ represent the time it takes Olay to run from C to A

We have;

The total time it takes to run from A back to A = t₁ + t₂ + t₃

Therefore;

[tex]Average \ velocity = \dfrac{Total \ distance }{Total \ time} = \dfrac{d}{t_1 + t_2 + t_3}[/tex]

Substituting the known values for the average velocity, 'd', 't₁' and 't₂'  gives;

[tex]Average \ velocity = 3.6 \, m/s = \dfrac{450 \, m}{30 \, s + 60 \, s + t_3}[/tex]

3.6 m/s × (30 s + 60 s + t₃) = 450 m

3.6 m/s × 30 s + 3.6 m/s × 60 s + 3.6 m/s × t₃ = 450 m

108 m + 216 m + 3.6 m/s × t₃ = 450 m

∴ 3.6 m/s × t₃ = 450 m - (108 m + 216 m) = 126 m

t₃ = 126 m/(3.6 m/s) = 35 s

The speed with which Olay runs from C to A, v₃ = Distance from C to A/t₃

The speed with which he runs from C to A = 150 m/(35 s) = 30/7 m/s =[tex]4.\overline {285714}[/tex] m/s

(i) The given bearing of C from A = 210°

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

∴ cos(A) = (b² + c² - a²)/(2·b·c)

Where;

a = The distance from B to C = 180 m

b = The distance from C to A = 150 m

c = The distance from A to B = 120 m

We find;

cos(A) = (150² + 120² - 180²)/(2 × 150 × 120) = 0.125

A = arccos(0.125) ≈ 82.82°

The bearing of B from A ≈ 210° - 82.82° ≈ 127.18°

The bearing of B from A ≈ 127.18°

(ii) The angle, θ, formed by the path of the bearing of A from B is an alternate to the supplementary angle of the bearing of B from A

Therefore, we have;

θ ≈ 180°- 127.18° ≈ 52.82°

The bearing of A from B = The sum of angle at a point less θ

∴ The bearing of A from B = 360° - 52.82° ≈ 307.18°

The bearing of A from B ≈ 307.18°.

Answer:

i am unsure

Step-by-step explanation:

I HEART POINTS