Answer:
3
Step-by-step explanation:
Answer:
2 tickets
Step-by-step explanation:
a + c = 5
9a + 4c = 30
let a = 5-c
substitute:
9(5-c) + 4c = 30
45 - 9c + 4c = 30
45 - 5c = 30
-5c = -15
c = 3
a = 2
There are two jars with marbles. The first jar contains 3 red, 4 green, and 5 blue marbles. The second jar contains 4 red, 2 green, and 6 blue marbles. What is the probability of the randomly drawing a green marble from the first jar and blue marble from the second jar
Answer:
both jars contain 12 marbles
for the first jar the probability is 4/12 which is 33%
for the second jar the probability is 6/12 which is 50%
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
theres 12 mables in each jar in this situation.
Drag each tile to the correct box. Amanda, Derrick, and Todd attend the same high school. Each student works as the cashier one night a week at the school's concession stand. The number of items sold at the concession stand to the first 20 customers on three different nights is represented on the dot plots below. Find the interquartile range, IQR, for each dot plot. Then, place the students in order from greatest to least IQR.
Answer:
Amanda > Todd > Derrick
Step-by-step explanation:
Amanda's IQR- 3.5
Derrick's IQR- 2
Todd's IQR- 3
The solution is, ordering the IQR in descending order :
Emma, Sally, Olivia
What is IQR?The interquartile range (IQR) contains the second and third quartiles, or the middle half of your data set. Whereas the range gives you the spread of the whole data set, the interquartile range gives you the range of the middle half of a data set.
here, we have,
Writing out the points obtained from the dot plot, and applying the relevant formula, the Interquartile range of each dot plot is given below ;
Writing out each score on the dot plot to calculate the statistical values :
Emma's Scores:
6 , 7 , 8 , 8 , 9 , 9 , 9 , 10 , 10 , 11 , 11 , 11 , 11 , 11 , 12 , 13 , 13 , 13 , 13 , 14
Q1 = 1/4(n+1)th term
Q1 = (5th + 6th) terms
Q1 = (9 + 9) / 2 = 9
Q3 = 3/4(n+)th term
Q3 = (12 + 13) ÷ 2 = 12.5
IQR = Q3 - Q1
IQR = 12.5 - 9 = 3.5
Sally's Scores:
6 , 6 , 6 , 7 , 7 , 8 , 8 , 8 , 9 , 9 , 10 , 10 , 10 , 10 , 10 , 10 , 11 , 11 , 12 , 12 , 14
Q1 = 1/4(n+1)th term
Q1 = (7 + 8) ÷ 2 = 7.5
Q3 = 3/4(n+1)th term
Q3 = (10 + 11) ÷ 2 = 10.5
IQR = Q3 - Q1
IQR = 10.5 - 7.5 = 3
Olivia's Scores:
6 , 6 , 7 , 7 , 7 , 8 , 8 , 8 , 8 , 9 , 9 , 9 , 9 , 9 , 10 , 10 , 12 , 12 , 13 , 14
Q1 = 1/4(n+1)th term
Q1 = (7 + 8) ÷ 2 = 7.5
Q3 = 1/4(n+1)th term
Q3 = (10 + 10) ÷ 2 = 10
IQR = Q3 - Q1
IQR = 10 - 7.5 = 2.5
Therefore, ordering the IQR in descending order :
Emma, Sally, Olivia
Learn more on IQR :
brainly.com/question/18006476
#SPJ3
complete question:
Drag each tile to the correct box.
Emma, Sally, and Olivia play for the school basketball team. The dot plots show the number of points each of them scored in 20 games.
Find the interquartile range, IQR, for each dot plot. Then, place the basketball players in order from greatest to least IQR.
Given b=4, c=1, A=120° for a triangle with sides a, b, c and angles A, B, C. What is the area of the triangle? Round to the nearest hundredth.
Answer:
1.73 units
Step-by-step explanation:
The area of a triangle with sides a, b, c and angles A, B, C is given as
Area = 1/2 bc sin A
Given that b=4, c=1, A=120° for a triangle with sides a, b, c and angles A, B, C then the area
= 1/2 * 4 * 1 * sin 120
= 2 sin 120
= 2 * √3/2
= √3
= 1.732
To the nearest hundredth = 1.73
I NEED HELP ASAP IM TRYING TO STUDY FOR MY STAAR TEST TOMORROW *NO LINKS ALLOWED*
Answer:
C
Step-by-step explanation:
equations for each:
A) y - x = 25
B) y = 25x
C) x = 25y
D) y = 25 + x
HELPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
[tex]16[/tex]
Step-by-step explanation:
[tex] {x}^{2} - 8x + c[/tex]
[tex] {x}^{2} + c - 8x[/tex]
To find the c value [tex]c = ( \frac{b}{2})^{2} [/tex] , divide the coefficient of x by 2 and square the result.
[tex]( - 1 \times 4 {)}^{2} [/tex]
[tex]( - 4 {)}^{2} [/tex]
[tex]16[/tex]
Hope it is helpful....Consider the geometric sequence 8,4,2,1,...
Answer:
Its A for the function that represents the geomertric sequence