use [tex] a^2-b^2=(a+b)(a-b)[/tex]
to get [tex] (\cos^3A-\sin^3A)(\cos^3A+\sin^3A)[/tex]
then use [tex] a^3+b^3=(a+b)(a^2+b^2-ab)[/tex]
and [tex]a^3-b^3=(a-b)(a^2+b^2+ab)[/tex]
also, [tex] \sin^2\theta+\cos^2\theta=1[/tex]
to get [tex](\cos A-\sin A)(1+\sin A\cos A)(\cos A+ \sin A)(1-\sin A\cos A)[/tex]
then again use the first identity In both pairs, i.e.
[tex](\cos A-\sin A)(\cos A+ \sin A) \cdot (1+\sin A\cos A)(1-\sin A\cos A)[/tex]
to get [tex] \cos 2A (1-\sin^2A\cos^2A)[/tex]
multiply and divide by 4 to get the RHS.
because, [tex] \sin(2A)= 2\sin A \cos A[/tex]
squaring both sides, [tex] \sin^2 (2A)=4\sin^2A\cos^2A[/tex]
Answer:
they take the same form
Step-by-step explanation:
factor (1 - 1/4 sin ^2 (2A) ) (cos ^ 2 (A) -sin ^2(A))
= ( -sin 2A/ 2) + 1 ) (sin (2A)/ 2) -1
= - (-1 + ) (sin 2A/2) (1 +) (sin 2A/2) ( cos (A) + sin (A) (cos (A)- sin (A))
= (sin (2A) +sin 2) (sin (2A) -2)/4 = cos ^2(A) = (sin ^2(A)+cos (A) sin (A)) cos ^2(A) +s)
In three years, 30% of a radioactive element decays. Find its half-life. (Round your answer to one decimal place.) yr
Answer:5 years
Step-by-step explanation:
Answer:
5 years
Step-by-step explanation:
in three years 30%
so in one year 10%
For half life time- 50%
so half life time years- 5 years..
A fair coin is flipped 32 times. Let X be the number of heads. What normal distribution best approximates X?
Answer:
you can land on heads a possibility of 16 times
Step-by-step explanation:
Can you help me learn how to solve problems like these? I need to know the answer, but I also need to know how to do it because this isn't all of them.
[tex]\frac{1}{p-2} / \frac{4p^2}{p^2+p-6}[/tex]
[tex]\frac{6n}{3n+2} - \frac{2}{2n-2}[/tex]
[tex]\frac{2x}{3x^2+18x} + \frac{3}{2}[/tex]
[tex]\dfrac{\dfrac{1}{p-2}}{\dfrac{4p^2}{p^2+p-6}}=\\\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+3p-2p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p(p+3)-2(p+3)}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{(p-2)(p+3)}{4p^2}=\\\\\dfrac{p+3}{4p^2}[/tex]
--------------------------------------------------------------------
[tex]\dfrac{6n}{3n+2}-\dfrac{2}{2n-2}=\\\\\dfrac{6n(2n-2)}{(3n+2)(2n-2)}-\dfrac{2(3n+2)}{(3n+2)(2n-2)}=\\\\\dfrac{12n^2-12n-(6n+4)}{6n^2-6n+4n-4}=\\\\\dfrac{12n^2-12n-6n-4}{6n^2-2n-4}=\\\\\dfrac{12n^2-18n-4}{6n^2-2n-4}=\\\\\dfrac{2(6n^2-9n-2)}{2(3n^2-n-2)}=\\\\\dfrac{6n^2-9n-2}{3n^2-n-2}[/tex]
----------------------------------------------------------------------
[tex]\dfrac{2x}{3x^2+18x}+\dfrac{3}{2}=\\\\\dfrac{2}{3x+18}+\dfrac{3}{2}=\\\\\dfrac{2\cdot2}{2(3x+18)}+\dfrac{3(3x+18)}{2(3x+18)}=\\\\\dfrac{4+9x+54}{6x+36}=\\\\\dfrac{9x+58}{6x+36}[/tex]
Answer:
p^3−10p^2+1
—————— We find roots of zeros F(p) = p^3 - 10p^2 + 1 and see there
p^2 are no rational roots
Step-by-step explanation:
p^2
Simplify ——
p^2
1.1 Canceling out p^2 as it appears on both sides of the fraction line
Equation at the end of step 1
:1
((————-(4•1))+p)-6
(p^2)
STEP 2: working left to right
1
Simplify ——
p^2
Equation at the end of step 2:
1 /p^2 ((—— - 4) + p) - 6
STEP 3:
Rewriting the whole as an Equivalent Fraction
3.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using p^2 as the denominator :
4 4 • p^2
4 = — = ——————
1 p^2
Equivalent fraction
: The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
1 - (4 • p^2) 1 - 4p^2
———————————— = ———————
p^2 p^2
Equation at the end of step 3:
(1 - 4p^2)
(————————— + p) - 6
p^2
STEP 4:
Rewriting the whole as an Equivalent Fraction
4.1 Adding a whole to a fraction
Rewrite the whole as a fraction using p2 as the denominator :
p p • p^2
p = — = ——————
1 p^2
Trying to factor as a Difference of Squares:
4.2 Factoring: 1 - 4p^2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : 4 is the square of 2
Check : p^2 is the square of p^1
Factorization is : (1 + 2p) • (1 - 2p)
Adding fractions that have a common denominator :
4.3 Adding up the two equivalent fractions
(2p+1) • (1-2p) + p • p^2 p^3 - 4p^2 + 1
———————————————————————— = ————————————
p^2 p^2
Equation at the end of step
4:
(p^3 - 4p^2 + 1)
—————————————— - 6
p^2
STEP 5:
Rewriting the whole as an Equivalent Fraction
5.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using p^2 as the denominator :
6 6 • p^2
6 = — = ——————
1 p^2
Polynomial Roots Calculator :
5.2 Find roots (zeroes) of : F(p) = p^3 - 4p^2 + 1
Polynomial Roots Calculator is a set of methods aimed at finding values of p for which F(p)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers p which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 -4.00
1 1 1.00 -2.00
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
5.3 Adding up the two equivalent fractions
(p3-4p2+1) - (6 • p2) p3 - 10p2 + 1
————————————————————— = —————————————
p2 p2
Polynomial Roots Calculator :
5.4 Find roots (zeroes) of : F(p) = p3 - 10p2 + 1
See theory in step 5.2
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 -10.00
1 1 1.00 -8.00
Polynomial Roots Calculator found no rational roots
Final result :
p3 - 10p2 + 1
—————————————
p2
What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?
Your function is: [tex]f(x)=\frac{1}{2}\cos \Big( \frac{1}{4x}\Big) -1[/tex]
Domain: $(-\infty, +\infty)-\{ 0 \}$ or $R-\{ 0 \}$
Range: $[-\frac{3}{2}, -\frac{1}{2}]$
Midline: $y=-1$
Graph the line with the slope 1/3 that contains the point (-4, -3)
Answer:
So, 1 point is on (-4, -3)
Other point is on (-4, -7)
Step-by-step explanation:
Slope = y/x - y1/x1
=> -3 / -4 - ? = 1/3
=> -3 / -4 - 1/3 = ?
=> -3 -1 / -4 - 3
=> -4 / -7
So, -3 / -4 - (-4 / -7)
=> -3 +4 / -4 + 7
=> 1/3
So 1 point is on (-4 , -3)
Other point is on (-4, -7)
Answer:no
Step-by-step explanation:
No
What are the coordinates of the vertices of the polygon in the graph that are in Quadrant II? A) (4,–2) B) (4,3), (0,5), (0,1) C) (–5,2), (–3,2), (–3,4) D) (–1,0), (–5,2), (–3,2), (–3,4), (0,5), (0,1)
Answer:
C) (–5,2), (–3,2), (–3,4)
Step-by-step explanation:
A) (4,–2)
B) (4,3), (0,5), (0,1)
C) (–5,2), (–3,2), (–3,4)
D) (–1,0), (–5,2), (–3,2), (–3,4), (0,5), (0,1)
For quadrant two the points are always (-x,y) and x is always negative.
Image shows quadrant places.
Which constants could each equation be multiplied by to eliminate the x-variable using addition in this system of equations? 2x+3y=25 -3x+=22 first equation can be multiplied by –3 and the second equation by 2. The first equation can be multiplied by –4 and the second equation by 2. The first equation can be multiplied by 3 and the second equation by 2. The first equation can be multiplied by 4 and the second equation by –3.
Answer:
The first equation can be multiplied by 3 and the second equation by 2.
Step-by-step explanation:
Given
[tex]2x+3y=25[/tex]
[tex]-3x + y=22[/tex]
Required
How to eliminate x
To eliminate x using addition, we have to do the following;
1. Take the coefficient of x in equation 1; Coefficient = 2
2. Take the coefficient of x in equation 2; Coefficient = -3
3. Multiply equation 1 by 3
[tex]3(2x + 3y = 25)[/tex]
[tex]6x +9y = 75[/tex]
4. Multiply equation 2 by 2
[tex]2(-3x + y = 22)[/tex]
[tex]-6x + 2y = 44[/tex]
5. Add both resulting equations
[tex]6x +9y = 75[/tex] + [tex]-6x + 2y = 44[/tex]
[tex]6x - 6x + 9y + 2y = 75 + 44[/tex]
[tex]11y = 75 + 44[/tex]
Notice that x has been eliminated;
Help! You can look at the picture please
Answer:
[tex] \frac{3x}{3 - 2x} [/tex]
Step-by-step explanation:
Here,
f(x) = y
[tex]y = \frac{3x}{2x + 3} [/tex]
or , swapping x with y
[tex]x = \frac{3y}{2y + 3} [/tex]
now to solve for y we get
[tex]y = \frac{3x}{3 - 2x} [/tex]
now we put f inverse x instead of y
[tex] {f}^{ - 1} (x) = \frac{3x}{3 - 2x} [/tex]
I am done.
4. EF is the median of trapezoid ABCD.
B
X +12
с
E
4x-18
F
3x-4
A
Part I: Solve for x. Show your work. (4 points)
Answer:
x = 11
BC = 23
AD = 29
EF = 26
Step-by-step explanation:
Given:
Trapezoid ABCD, having,
median = EF = 4x - 18
base BC = x + 12
base AD = 3x - 4
Required:
Part I: value of x
Part II: Length of BC, AD, and EF.
Solution:
Part I: Value of X
The median length of a trapezoid is said to be the ½ of the sum of the 2 bases of the trapezoid.
Therefore, EF = ½(BC + AD)
4x - 18 = ½((x + 12) + (3x - 4)
4x - 18 = ½(x + 12 + 3x - 4)
4x - 18 = ½(x + 3x +12 - 4)
4x - 18 = ½(4x + 8)
Multiply 2 by both sides
2(4x - 18) = 4x + 8
8x - 36 = 4x + 8
Add 36 to both sides
8x - 36 + 36 = 4x + 8 + 36
8x = 4x + 44
Subtract 4x from both sides
8x - 4x = 4x + 44 - 4x
4x = 44
Divide both sides by 4
x = 11
Part II:
BC = x + 12 = 11 + 12 = 23
AD = 3x - 4 = 3(11) - 4 = 33 - 4 = 29
EF = 4x - 18 = 4(11) - 18 = 44 - 18 = 26
PLZZ HELPP!! Water is poured from a 1.5 L water bottle into an empty glass until both the glass and the bottle are 3/4 full. What is the volume of the glass?
Answer:
0.5 L
Step-by-step explanation:
volume of bottle: 1.5 L
amount of water = 1.5 L
volume of glass: x
3/4 full is the same as 0.75 full
vol of water in bottle + vol of water in glass = total vol of water
0.75(bottle) + 0.75(glass) = 1.5
0.75(1.5) + 0.75x = 1.5
0.75x = 0.375
x = 0.5
Jovie is maintaining a camp fire. She has kept the fire steadily burning for 10 hours with 15 logs. She wants to know how many hours (h)left parenthesis, h, right parenthesis she could have kept the fire going with 9 logs. She assumes all logs are the same.
Answer:
6 hours
Step-by-step explanation:
We can use ratios to solve
10 hours x hours
-------------- = -------------
15 logs 9 logs
Using cross products
90 = 15x
Divide by 15
90/15 = 15x/15
6 = x
6 hours
Answer:
Below
Step-by-step explanation:
Jovie has maintained the fire burning with 15 logs for 10 hours.
● 15 => 10
Let's find how many hours do 9 logs keep the fire burning.
Let x be that time
● 9 => x
■■■■■■■■■■■■■■■■■■■■■■■■■■
● 15 => 10
● 9 => x
● 15 * x = 9×10
● 15x = 90
● x = 90/15
● x = 6
So the time that the fire will keep burning is 6 hours.
Find the measure of the remote exterior angle. m∠x=(197−5n)°m∠y=(6n+22)°m∠z=(n+7)°
A. 14
B. 91
C. 21
D. 127
Answer:
D. 127°
Step-by-step explanation:
The exterior angle (x) is the sum of the remote interior angles (y, z).
Setupx = y +z
(197 -5n) = (6n +22) +(n +7) . . . . . substituting the given expressions
SolutionEliminating parentheses and collecting terms, we have ...
197 -5n = 7n +29
168 = 12n . . . . . . . . . add 5n-29
14 = n . . . . . . . . . . divide by 12
Then the measure of remote exterior angle x is ...
m∠x = (197 -5(14))° = (197 -70)°
m∠x = 127°
A, B, C and D lie on the circumierence of the circle.
Lengths AB and AD are equal.
Lengths BC and BD are equal.
Work out CBD.
Answer:
Step-by-step explanation:goofy
Triangle ABC is dilated to form new triangle DEF. If angle A is congruent to angle D, what other information will prove that the two triangles are similar by the AA similarity postulate?
Angle B is congruent to angle E.
Side AB is congruent to side DE.
Angle C is congruent to angle D.
Side BC is congruent to side EF.
Answer:
Step-by-step explanation:
option A , angle B is congruent to angle E { SINCE IT IS AA POSTULATE
Answer:
B=E (b)
Step-by-step explanation:
solve the equation
[tex] {5}^{n + 1} - {5}^{n} + {5}^{n - 1} = 105[/tex]
Answer:
n=2
Step-by-step explanation:
Hello, please consider the following.
[tex]{5}^{n + 1} - {5}^{n} + {5}^{n - 1} = 105\\\\5^{n-1}(5^2-5+1)=5^{n-1}(25-5+1)=21*5^{n-1}=105\\\\5^{n-1}=\dfrac{105}{21}=5=5^1\\\\\text{It means that}\\\\n-1=1 <=> n=2[/tex]
Let me know if you need more details.
Thank you
4 cm, 5 cm, 20 cm
can the side lengths
form a triangle ?
Answer: No
Step-by-step explanation:
Because 4^2=16
5^2=25
25+16=41
41 squared =6.4031.....
6.4031 does not = 20
Answer: No, a triangle is not possible
The two smaller sides add to 4+5 = 9 which is not larger than 20. For a triangle to be possible, we need to be able to add 2 sides to make them longer than the third side. This is an application of the triangle inequality theorem.
What is the coefficient of x5y5 in the expansion of (x + y)10?
Answer:
C=252
Step-by-step explanation:
Given:
x^5y^5
(x+y)^10
Find the coefficient of x^5y^5
To get the coefficient of x^5y^5,
we will put r = 5, in the below given general term.
The general term is : nCr =x^ry^n-r
We get:
Coefficient is = 10C5
= 10!/5!*5!
= 252
The coefficient of x^5y^5 is 252
C. 252
The perimeter of the rectangle below is 114 units. Find the length of side PQ.
Write your answer without variables.
Answer:
36.
Step-by-step explanation:
The perimeter = 2 * length + 2 * width, so we have:
2(2x - 1) + 2(3x + 3) = 114
4x + 6x - 2 + 6 = 114
10x = 114+ 2 - 6 = 110
x = 11.
So the length = 3(11) + 3
= 36.
The area of a rectangular field is 6052 m².
If the width of the field is 68 m, what is its length?
Answer:
length = 89 mStep-by-step explanation:
Area of a rectangle = l × w
where
l is the length
w is the width
From the question
Area = 6052 m²
width = 68 m
To find the length substitute the values into the above formula
6052 = 68l
Divide both sides by 68
We have the final answer as
length = 89 mHope this helps you
Given that F( x ) = x 2 + 2, evaluate F(1) + F(5).
Hi there! :)
Answer:
[tex]\huge\boxed{f(1) + f(5) = 30}[/tex]
Given:
[tex]f(x) = x^{2} + 2[/tex]
Evaluate [tex]f(1) + f(5)[/tex]
Solve for each:
[tex]f(1) = (1)^{2} + 2 = 3[/tex]
[tex]f(5) = (5)^{2} + 2 = 27[/tex]
[tex]27 + 3 = 30[/tex]
Answer:
30
Step-by-step explanation:
Solve the system of equations 2x - y = 11 and x + 3y = -5
Answer:
x = 4, y = -3
Step-by-step explanation:
{2x - y = 11
{x + 3y = -5
You can use the substitution method by solving for x in the second equation:
x + 3y = -5
Subtract 3y from both sides:
x = -3y - 5
Now, substitute this value for x into the first equation:
2x - y = 11
2(-3y - 5) - y = 11
Distribute:
-6y - 10 - y = 11
Add 10 to both sides:
-6y - y = 21
Combine like terms:
-7y = 21
Divide both sides by -7:
y = -3
Next, substitute this value for x into the second equation:
x + 3y = -5
x + 3(-3) = -5
Multiply:
x - 9 = -5
Add 9 to both sides:
x = 4
Answer:
(7, 3)
Step-by-step explanation:
2x - y =11 2x-y =11
-2(x+3y)= (-5)-2 -2x-6y= 10
Then you will cross out the x, and add.
-7y =21 divide 7
y=-21/7 or y=3
Then you plug in the y where the y is and solve
2x-(3) = 11
2x = 14
x=7
{(-2,8),(4,6),(10,4)} Which point, when added to the set, would form a relation that is not a function?
Answer:
Point : ( -2, 15 )
Step-by-step explanation:
A point that would make this relation not a function would be one that shares a common x - value with the other points. One common domain values for two range values would, when graphed, not follow the vertical test, hence making the relation not a function.
Let's say that the point is ( -2, 15 ). It has a common x - value with respect to the first point, ( -2, 8 ), and therefore would make this set not a function.
Answer:
Point : ( -2, 15 )
Step-by-step explanation:
How many of the positive integer factors of 15552 are perfect squares?
Please show work, will mark brainliest if correct
Answer: 9 integers factors
Step-by-step explanation:
Let's first find the factor of 15552
15552 / 2 = 7776
7776 / 2 = 3888
3888 / 2 = 1944
1944 / 2 = 972
972 / 2 = 486
486 / 2 = 243
273 / 3 = 81
81 / 3 = 27
27 / 3 = 9
9 / 3 = 3
3 / 3 = 1
Some of the factors of 15552 are:
2×2×2×2×2×2×3×3×3×3×3
4×4×4×9×9×3
4^2 × 9^2 × 4 × 3
The factor that are perfect square are:
4, 9, 16, 36, 64, 81, 144, 576, 1296
Therefore, 9 of the positive integer factors of 15552 are perfect squares.
CAN SOMEWON HELP ME PLZ I NEED HELP
Answer:
1.791875241e13
Step-by-step explanation:
5.67811 x 10⁵ = 567811
3.15576 x 10⁷ = 31557600
31557600 x 567811 = 1.791875241e13
Answer:
1.791875241e13
Help please all questions.
Answer:
A is A=25
B=10
B is 40
C is A=10
B=6.428
hope i helped you
sorry if it is incorrect
Four representations of the same data are shown below. Verbal Description Shay pays a $4 monthly fee in addition to the data and minutes charges on her cell phone bill, x. Equation y = x + 4 Table A 2-column table with 3 rows. Column 1 is labeled x with entries 30 dollars, 40 dollars, 50 dollars. Column 2 is labeled y with entries 34 dollars, 44 dollars, 54 dollars. Graph Cell Phone Bill A graph with data/minutes charges on the x-axis and total bill on the y-axis. A line goes through points (0, 4) and (3, 7). Which two representations are considered to be only partial representations? the equation and the verbal description the verbal description and the graph the table and the equation the graph and the table
The table is a partial representation as we only see three data points. This is a limited view. Because of this, the answer is between C and D. However, we can rule out choice C as the equation will give us the complete view of what's going on. We can plug in any x value we want to find the corresponding y value (keep in mind that x and y can't be negative though). So that means the graph is a partial representation. This is true if the line segment doesn't extend forever upward. If we had a line segment through the endpoints (0,4) and (3,7), and it stopped at (3,7), then this is a limited view. It does not show what the bill would be if x were say x = 5.
14. You bought shoes for $60. They were on sale for 40% off their original price.
a. Write a proportion to solve for the original price of the shoes.
ce to
b. Solve the proportion in part (a).
Step-by-step explanation:
The shoes are bought for $60 and were 40% off which means $60 is 60% of the original price
if 60% = $60 the 100% = $100 (the price of the shoe before discount).
The graph shows the first 5 terms of the arithmetic sequence, an.
Which is the 6th term of the sequence?
A.)3
B.)6
C.)9
D.)12
E.)18
Answer:
D) 12
Step-by-step explanation:
the graphs slope is 3 using the rise over run method we have found this
now since we know the fifth x value gives a y value of 9 we can add 3 and have 12
can somewon help me plx
Answer:
[tex]\boxed{392in^2}[/tex]
Step-by-step explanation:
Hey there!
Well to find SA we need to find the area of the rectangles.
So lets do the top rectangle,
6*6 = 36
Now lets do the the left rectangle,
10*6 = 60
Now lets do the far right one,
6*4 = 24
Now lets do the second highest rectangle,
4*6 = 24
Now lets do the rectangle facing the right side,
6*6 = 36
Now we can do the bottom rectangle,
6*10 = 60
Now lets do the 2 facing front and back,
6*10 = 60
4*4 = 16
60+16 = 76
76*2 = 152
Now we can add everything,
152 + 60 + 36 + 24 + 24 + 60 + 36
= 392 in^2
Hope this helps :)
Some lemon, lime, and cherry lollipops are placed in a bowl. Some have a
chocolate center, and some do not. Suppose one of the lollipops is chosen
randomly from all the lollipops in the bowl. According to the table below, if it
is known to be lemon, what is the probability that it HAS a chocolate center?
Answer:
45%
Step-by-step explanation:
There are 20 lollilops with lemon in total. 9 of them have a chocolate center. 9/20=0.45. To convert it into percentage you would multiply the number by 100. 0.45*100=45
The answer is 45%
"if it is known to be lemon" means we ignore any other flavor. I recommend covering up the other values, or you could highlight just the lemon column.
We have 9+11 = 20 lemon total. Of this 20 total, only 9 lemons have a chocolate center. So 9/20 = 0.45 = 45% of the lemon candies have a chocolate center.