please I need the answer

Answer:

Step-by-step explanation:

when a number x is added to it's square, the total is 12. find two possible values of x

x+x^2=12

x^2+x=12

x^2+x−12=12−12

x^2+x−12=0

(x−3)(x+4)=0

x−3=0 or x+4=0

x=3 or x=−4

x=3 or x=−4

Answer:

Mr. Garcia had 5 kilograms of blueberries at first

Step-by-step explanation:

to make this easiest, we can imagine that we're undoing mr. garcia's actions.

So, we can start by 'unpacking' mr garcia's bags

we know that each of the nine bags had 1/4 kilograms, so we can multiply 1/4 by 9 to find the collective mass packed into bags

(remember, multiplication is repeated addition. we could also add 1/4 + 1/4 + 1/4... nine times, but this would take a while)

so,

1/4  x 9 = 9/4

(9 = 9/1 [if that is how you're used to multiplying a fraction])

Then, he also sold 2 3/4 kilograms

so, we can add 2 3/4 + 9/4 to find the total mass of the blueberries at first

2 3/4 + 9/4 =  2 + 12/4

(12/4 = 3)

2 + 3 = 5

So, Mr. Garcia had 5 kilograms of blueberries at first

Answer:

the orange one

Step-by-step explanation:

(10 + 10) : (5-3) =

20 : 2 =

10

Answer:

6 m²

Step-by-step explanation:

Original area :

12 × 14 = 168 m²

New area :

(12-3) × (14+4) =  

9 × 18 = 162 m²

168 - 162 = 6

Area would change by 6 m²

Answer:

No, right answer is = 1017.36

Answer:

1017.36

Step-by-step explanation:

All your work is correct, but the final answer is not. In the problem it says to use 3.14 as pi, but when you multiplied you did:

[tex]\pi * 6^{2}*9 = 1017.88[/tex]

instead of

[tex]3.14*6^{2}*9 = 1017.36[/tex]

like you had written above. So the final is actually supposed to be 1017.36

Answer:

Dilation

Step-by-step explanation:

it’s a dilation because the dilation changes how big the image is or what it looks like after the original image.

Answer:

z = 1/4

Step-by-step explanation:

See attached image

Answer:

z = 5

Step-by-step explanation:

simplify

5/(z-25) first

turning it into

((0 - 3/z) + 7/4z) - 5/(z - 25) = 0

then simplify 7/4z

((0 - 3/z) + 7/4z) - 5/(z-25) = 0

when the fractions denominator is 0 then the numerator must be 0

turning the equation into

-25  *  (z - 5)  = 0

solve

-25   =  0

something that is not zero cannot equal zero.

z - 5 = 0

5 - 5 = 0

z = 5

hope this helps:)

(i) In decimals: 0.65

(ii) In percentage: 65%

The graph shows that after the spinner is spun after 40 times. The Fraction of wins is 0.65 out of 1. Look at the very end of the graph to look at the conclusion for probability. Similar cases when, after the spinner is spun after 20 times, the probability is 0.65.

Answer:

0.65 or 65%

Step-by-step explanation:

Answer:

Step-by-step explanation:

(1) The sum of the interior angles of a polygon is [tex]180(n-2)[/tex] degrees, where n is the number of sides. In this case, n=5, so the sum is 180(5-2)=540 degrees, meaning the first statement is false.

(2) Since the angles add to 540 degrees, dividing this amongst the five equal angles, we get that each angle measures 108 degrees, so this statement is true.

(3) By definition, all angles of a regular polygon are congruent.

(4) A hexagon has 6 sides, but this polygon has only 5 sides, so this statement is false.

(5) This is true. (See statement (1)).

Answer:

Options B, C, E

Step-by-step explanation:

Answer: 450

Step-by-step explanation:

The volume is (1/2)(5)(12)(15)=450.

The absolute value equation that satisfy the solution set of -4 and -8 is |2 - x| = -6

The solution sets on the number line are given as:

x = {-8, -4}

Calculate the average of the solutions

Mean = (-8 - 4)/2

Mean = -6

Calculate the difference of the solutions divided by 2

Difference  = (-4 + 8)/2

Difference = 2

The absolute value equation is the represented as:

|Difference - x | = Mean

Substitute known values

|2 - x| = -6

Hence, the absolute value equation is |2 - x| = -6

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Answer:

|b+6|=2

Step-by-step explanation:

Step-by-step explanation:

7

4

1

----

12

reality

6.833

3.594

1.369

----------

11.796

a) [tex](a+b)(x)=a(x)+b(x)=7x+10+12x-18=\boxed{19x-8}\\[/tex]

b) [tex](a-b)(x)=a(x)-b(x)=(7x+10)-(12x-18)=7x+10-12x+18=\boxed{-5x+28}[/tex]

c) [tex](a-b)(x)=a(x)-b(x)=(7x+10)-(12x-18)=7x+10-12x+18=\boxed{-5x+28}[/tex]

d) [tex]a(b(x))=a(12x-18)=7(12x-18)+10=84x-126+10=\boxed{84x-116}[/tex]

Answer:

a-3

Step-by-step explanation:

[tex]2a-(a+3)\\= 2a - a - 3\\= a - 3[/tex]

Answer:

a-3

Step-by-step explanation:

2a - (a+3)

removing bracket

2a -a-3

a-3

final answer

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

[tex] \frac{1}{x - 5} [/tex]

Set the expression in the denominator equal to 0, because you can't divide by 0.

[tex]x - 5 = 0[/tex]

[tex]x = 5[/tex]

So the vertical asymptote is x=5.

Disclaimer if you see something like this

[tex] \frac{(x - 5)(x + 3)}{(x - 5)} [/tex]

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

[tex] \frac{1}{x} [/tex]

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

[tex]a \times {x}^{0} [/tex]

For example,

[tex]1 = 1 \times {x}^{0} [/tex]

[tex]2 = 2 \times {x}^{0} [/tex]

And so on,

and

[tex]x = {x}^{1} [/tex]

So our equation is basically

[tex] \frac{1 \times {x}^{0} }{ {x}^{1} } [/tex]

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

[tex] \frac{3 {x}^{2} }{ {x}^{2} + 1} [/tex]

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

[tex]x = \frac{3}{1} [/tex]

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

[tex]~~~~~~|x-4| = 17\\\\\implies x -4 = 17~~~~ \text{or}~~~~~ x -4 = -17\\\\\implies x = 17+4~~~~\text{or}~~~~~ x = -17+4\\\\\implies x = 21~~~~~~~~~\text{or}~~~~~x = -13[/tex]

Answer:

h(0.1) = 4.97

Step-by-step explanation:

See attached working :)

Remember that h(0.1) is the same as saying find what the equation is equal to when x = 0.1

Answer:

y = - x

Step-by-step explanation:

From the given table:-

( x_1,x_2): (5,-5)

( y_1,y_2): (6,-6)

1) Let's find the slope (m):-

[tex]m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{ - 6( - 5)}{6 - 5} = \frac{ - 6 + 5}{1} = \frac{ - 1}{1} = - 1[/tex]

2) Substitute x_1= 5, y_1=-5 and m=-1 into y-y_1=m(x-x_1)

[tex]y - ( - 5) = - 1(x - 5)[/tex]

[tex]y + 5 = - x + 5[/tex]

[tex]y = - x + 5 - 5[/tex]

[tex]y = - x[/tex]

The student that simplified the expression incorrectly is student 2

The steps are given as:

[tex]\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}[/tex]

Student 1:

Student 2:

As a general trigonometry rule;

[tex]\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)[/tex]

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

[tex]\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 + \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}[/tex]

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

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Step-by-step explanation:

we need the least or smallest common multiple for both numbers, 5 and 6.

this is very simple for the small numbers here, but in general we look at the prime factors of both numbers :

6 has the prime factors 2 and 3.

5 has only 5.

so, the LCM is 2×3×5 = 30.

they will meet again after 30 days.

FYI -

the LCM is for larger numbers a and b not automatically a×b. if both numbers share prime factors, the LCM can be smaller than a×b, as the LCM is using every overlapping prime factor only once.

#1

Volume

#2

Radius=10/2=5cm

Volume

#3

Volume

#4

#5

radius=8/2=4

Volume

Answer:

1)  314 cm³

2)  523.33 cm³

3)  87.92 in³

4)  11 cm

5)  502.4 cm³

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 5^2 \cdot 4\\& = 3.14 \cdot 25 \cdot 4\\& = 3.14 \cdot 100\\& = 314 \: \sf cm^3\end{aligned}[/tex]

[tex]\textsf{Volume of a sphere}=\sf \dfrac43 \pi r^3\quad\textsf{(where r is the radius)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =\dfrac{4}{3} \cdot 3.14 \cdot 5^3 \\& =\dfrac{4}{3} \cdot 3.14 \cdot 125 \\& =\dfrac{500}{3} \cdot 3.14 \\& = 523.33\: \sf cm^3\:(2\:dp)\end{aligned}[/tex]

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 2^2 \cdot 7\\& = 3.14 \cdot 4 \cdot 7\\& = 3.14 \cdot 28\\& = 87.92\: \sf in^3\end{aligned}[/tex]

[tex]\textsf{Volume of a square pyramid}=\sf \dfrac{1}{3} a^2h \quad\textsf{(where a is the base edge and h is the height)}[/tex][tex]\textsf{Area of base of square pyramid}=\sf a^2 \quad\textsf{(where a is the base edge)}[/tex]

Given:

[tex]\implies 81=a^2[/tex]

[tex]\implies a=\sqrt{81}[/tex]

[tex]\implies a=9\: \sf cm[/tex]

Substitute the given values into the formula and solve for h:

[tex]\begin{aligned}\implies \textsf{297} & =\dfrac{1}{3} \cdot 9^2 \cdot h\\\\297 & =\dfrac{81}{3} h\\\\891 & =81 h\\\\h & = 11 \: \sf cm\end{aligned}[/tex]

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substitute the given values into the formula:

[tex]\begin{aligned}\implies \textsf{Volume} & =3.14 \cdot 4^2 \cdot 10\\& = 3.14 \cdot 16 \cdot 10\\& = 3.14 \cdot 160\\& = 502.4\: \sf cm^3\end{aligned}[/tex]

Answer: andres is 5 years old pls banned him he called e a mean word like the N word

Step-by-step explanation:

Answer:

1600

Step-by-step explanation:

[tex]\text{Number of terms}, ~n = 40\\\\\text{Sum of n odd integers} = n^2 = 40^2 = 1600[/tex]

By using the pythagoras theorum you can find an unknown leg of right angled triangle.

Hypotenuse side is in the front of the 90 degree angle and other two sides can be taken as base and perpendicular, so formula goes as :-

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2

H^2 = B^2 + P^2

Step-by-step explanation:

The directrix of the parabola is [tex]y = \frac {-49}{16}[/tex]

The parabola equation is given as:

[tex]\frac 14(y + 3) = (x -2)^2[/tex]

A parabola is represented as:

[tex]4p(y - k) =(x -h)^2[/tex]

By comparing both equations, we have:

4p = 1/4 ==> p = 1/16

-k= 3 ==> k = -3

The directrix is represented as:

y = k - p

So, we have:

[tex]y = -3 - \frac 1{16}[/tex]

Take the LCM

[tex]y = \frac {-16 * 3- 1}{16}[/tex]

Evaluate

[tex]y = \frac {-49}{16}[/tex]

Hence, the directrix of the parabola is [tex]y = \frac {-49}{16}[/tex]

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Answer:

20%

Step-by-step explanation:

the units of measure must be the same, so

2m = 2 × 100 cm = 200 cm

then

[tex]\frac{40}{200}[/tex] × 100%

= 0.2 × 100%

= 20%

Answer:

20%

Step-by-step explanation: