Answer:
The approximate value of the scale is 1:67
or the actual value without approximation is 1: 66 2/3 ( 66 while number , two over three)
Step-by-step explanation:
Here, we want to figure out the scale in inches of the drawing to the actual object.
The actual object is 500 ft by 700 ft
while the drawing is 90 inches by 126 inches
Mathematically, we know that 12 inches = 1 foot
So the actual object will be;
500(12) by 700(12)
= 6000 inches by 8400 inches
Now let’s make a division to get the scale;
6000/90 by 8400/126
we get 66.67 as answers on both ends
This is approximately equal to 67
So the scale we have here is 1:67
The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a standard deviation of $5.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 50 customers, answer the following questions.
(a) What is the likelihood the sample mean is at least $25.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)
Probability
(b) What is the likelihood the sample mean is greater than $22.50 but less than $25.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)
Probability
(c) Within what limits will 90 percent of the sample means occur? (Round your answers to 2 decimal places.)
Answer:
a. [tex]\mathtt{P(X \geq 25) =0.0170}[/tex] ( to four decimal places)
b. [tex]P(22.5<X<25) = 0.9043[/tex] ( to four decimal places )
c. The limits will be between the interval of ( 22.33,24.67 )
Step-by-step explanation:
Given that :
mean = 23.50
standard deviation = 5.00
sample size = 50
The objective is to calculate the following:
(a) What is the likelihood the sample mean is at least $25.00?
Let X be the random variable, the probability that the sample mean is at least 25.00 is:
[tex]P(X \geq 25) = 1 - P(\dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{25- 23.50}{ \dfrac{5}{\sqrt{ 50}} })[/tex]
[tex]P(X \geq 25) = 1 - P(Z< \dfrac{1.5}{ \dfrac{5}{7.07107}} })[/tex]
[tex]P(X \geq 25) = 1 - P(Z< \dfrac{1.5 \times 7.071}{ {5}})[/tex]
[tex]P(X \geq 25) = 1 - P(Z< 2.1213)[/tex]
[tex]P(X \geq 25) = 1 - P(Z< 2.12)[/tex] to two decimal places
From the normal tables :
[tex]P(X \geq 25) = 1 - 0.9830[/tex]
[tex]\mathtt{P(X \geq 25) =0.0170}[/tex] ( to four decimal places)
(b) What is the likelihood the sample mean is greater than $22.50 but less than $25.00?
[tex]P(22.5<X<25) = P(\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}} <\dfrac{25-23.5}{\dfrac{5}{\sqrt{50}}} ) - P(\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}} <\dfrac{22.5-23.5}{\dfrac{5}{\sqrt{50}}} )[/tex]
[tex]P(22.5<X<25) = P(Z<\dfrac{1.5}{\dfrac{5}{7.071}} ) - P(Z<\dfrac{-1}{\dfrac{5}{7.071}} )[/tex]
[tex]P(22.5<X<25) = P(Z<2.12) - (Z<-1.41 )[/tex]
[tex]P(22.5<X<25) = (0.9830 ) - (0.0787)[/tex]
[tex]P(22.5<X<25) = 0.9043[/tex] to four decimal places
(c) Within what limits will 90 percent of the sample means occur?
At 90 % confidence interval, level of significance = 1 - 0.90 = 0.10
The critical value for the [tex]z_{\alpha/2} = 0.05[/tex] = 1.65
Standard Error = [tex]\dfrac{\sigma}{\sqrt{n}}[/tex]
Standard Error = [tex]\dfrac{5}{\sqrt{50}}[/tex]
Standard Error = 0.7071
Therefore, at 90 percent of the sample means, the limits will be between the intervals of : [tex](\mu \pm z_{\alpha/2} \times S.E)[/tex]
Lower limit = ( 23.5 - (1.65×0.707) )
Lower limit = ( 23.5 - 1.16655 )
Lower limit = 22.33345
Lower limit = 22.33 (to two decimal places).
Upper Limit = ( 23.5 + (1.65*0.707) )
Upper Limit = ( 23.5 + 1.16655 )
Upper Limit = 24.66655
Upper Limit = 24.67
The limits will be between the interval of ( 22.33,24.67 )
I am so confused Please Help it is DUE NOW!!
Select the polynomial that is a perfect square trinomial.
9x^2 + 9x + 1
36b^2 − 24b + 8
16x^2 + 24x + 9
4a^2 − 10a + 25
Answer:
16x^2 + 24x + 9
Step-by-step explanation:
perfect square trinomial is of the form
a^2 + 2 * a * b + b^2
9x^2 + 9x + 1 = (3x)^2 + 3*3x*1 + 1^2 not a perfect square trinomial
36b^2 − 24b + 8 = ( 6b)^2 -2 * 6b *2 + ( 2 sqrt(2)) ^2 not a perfect square trinomial
16x^2 + 24x + 9 = ( 4x) ^2 + 2 * ( 4x) * 3 + 3^2 = perfect square trinomial
4a^2 − 10a + 25 = ( 2a) ^2 - 1 * 2a *5 + 5^2 not a perfect square trinomial
Answer:
The third answer listed:
[tex]16x^2+24x+9[/tex]
Step-by-step explanation:
The trinomial:
[tex]16x^2+24x+9[/tex]
can be factored out as follows:
[tex]16x^2+24x+9\\(4x)^2+24x+3^2\\(4x)^2+12x+12x+3^2\\4x(4x+3)+3(4x+3)\\(4x+3)\,(4x+3)\\(4x+3)^2[/tex]
which as can be seen,is the perfect square of a binomial, so this trinomial is what is called a perfect square trinomial.
Which translation maps the graph of the function f(x) = x2 onto the function g(x) = x2 − 6x + 6? left 3 units, down 3 units right 3 units, down 3 units left 6 units, down 1 unit right 6 units, down 1 unit
Answer:
its not 1, its the second one (B)
Step-by-step explanation:
Answer:
I know I'm 1 year late but B is the correct answer choice. I just did it on edge 2021.
I'm just big brain.The table shows the annual profits (in thousands of dollars) of a county fair from 2013 to 2016. What must the 2017 profit be (in hundreds of dollars) to break even over the five-year period?
Answer:
8 hundred dollars
Step-by-step explanation:
The break even value means zero profit or loss over the five years period. So if 2017 profit is x, then we get:
2.5 + 1.4 - 3.3 - 1.4 + x = 0x - 0.8 = 0x = 0.8 thousands of dollars x= 800 dollars(x^2-4x)^2+7x^2-28x+12=0
Answer:
[tex]x^4-9x^2-28x=-12[/tex]
Step-by-step explanation:
[tex](x^2-4x)^2+7x^2-28x+12=0[/tex]
[tex](x^4-16x^2)+7x^2-28x=-12[/tex]
[tex]x^4-9x^2-28x=-12[/tex]
What is the average rate of change from x = 0 to x = 18?
Average rate of change ... of what?
Given some continuous function [tex]f(x)[/tex] and some interval [tex][a,b][/tex], its average rate of change over the interval is
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Without knowing what your function is exactly, I can only give a symbolic answer,
[tex]\dfrac{f(18)-f(0)}{18}[/tex]
Answer: -5/18
Step-by-step explanation: edg
What are the solutions to the quadratic equation 4x2 = 64? A. x = −16 and x = 16 B.x = −8 and x = 8 C.x = −4 and x = 4 D.x = −2 and x = 2
Answer:
x = ±4
Step-by-step explanation:
4x^2 = 64
Divide each by 4
4x^2 /4= 64/4
x^2 = 16
Take the square root of each side
sqrt(x^2) = ±sqrt(16)
x = ±4
Answer:
[tex]\boxed{\boxed{x=\pm 4}}[/tex]
Step-by-step explanation:
[tex]4x^2 = 64[/tex]
Divide both sides by 4.
[tex](4x^2)/4 = 64/4[/tex]
Simplify.
[tex]x^2 =16[/tex]
Take the square root on both sides.
[tex]\sqrt{x^2 } =\pm \sqrt{16}[/tex]
Simplify.
[tex]x=\pm 4[/tex]
Determine the minimum rotation (in degrees) which will carry the following figures onto itself (where all sides and verticles will match up). Assume this is a regular polygon. Round to the nearest tenth if necessary.
Answer:
60°
Step-by-step explanation:
A full rotation is 360°. The figure has six sides.
1. Divide
360 ÷ 6 = 60
Each angle of the polygon is 60°. Therefore, the polygon must be rotated at least 60° for the figure to match all sides and vertices.
I need help with this question badly
Step-by-step explanation:
[tex] {9}^{ - 53} . {9}^{37} [/tex]
To solve this question we use the rules of indices
Since the bases are the same and are multiplying we add the exponents using the formula
[tex] {a}^{b} \times {a}^{c} = {a}^{b + c} [/tex]So for the above question we have
[tex] {9}^{ - 53} \times {9}^{37} = {9}^{ - 53 + 37} [/tex]We have the final answer as
[tex] {9}^{ - 16} [/tex]Which is the same as
[tex] \frac{1}{ {9}^{16} } [/tex]Hope this helps you
An isosceles triangle has two sides of equal length. The third side is five less than twice the length of one of the other sides. If the perimeter of the triangle is 23 cm what is the length of the third side?
Answer:
9
Step-by-step explanation:
We can set up a systems of equations to find the value of the third side.
Let's assume that [tex]x[/tex] is the length of both sides 1 and 2. Let's also assume that [tex]y[/tex] is the length of the third side.
We know that [tex]x + x + y = 23[/tex], and looking at the first clue we can make the equation [tex]y = 2x-5[/tex].
We can substitute y into the equation [tex]x + x + y = 23[/tex].
[tex]x + x + (2x-5) = 23\\\\2x + 2x-5 = 23\\4x-5 = 23\\4x = 28\\x = 7[/tex]
So the length of the side that is the same as the second is 7.
Now we can plug this into the equation [tex]y = 2x-5[/tex] to find [tex]y[/tex].
[tex]y = 2(7) - 5\\\\y = 14-5\\\\y = 9[/tex]
Hope this helped!
Answer:
9 cm
Step-by-step explanation:
Let's say that the length of the 2 equal sides is x.
That means:
Side 1 = x
Side 2 = x
We know that the third side is 5 less than twice the length of the 2 equal sides, or 2x-5
Side 3 = 2x-5
The perimeter is all sides together.
Side 1 + Side 2 + Side 3
We know the length of each side, so let's put that in instead.
x + x + 2x-5
Let's simplify this expression:
x + x + 2x - 5
2x + 2x - 5
4x - 5
We know the perimeter, 4x-5, is 23 cm.
4x - 5 = 23
4x = 28
x = 7
The third side is 2x-5. If x is 7...
2*7 - 5 = 14-5 = 9
Answer: 9 cm
Solve the equation for x. the square root of the quantity x plus 4 end quantity minus 7 equals 1 x = 4 x = 12 x = 60 x = 68
Answer:
x = 60
Step-by-step explanation:
Given
[tex]\sqrt{x+4}[/tex] - 7 = 1 ( add 7 to both sides )
[tex]\sqrt{x+4}[/tex] = 8 ( square both sides )
([tex]\sqrt{x+4}[/tex] )² = 8² , that is
x + 4 = 64 ( subtract 4 from both sides )
x = 60
URGENT PLZ HELP THANK YOU!
Answer:
[tex](-5)^{11}[/tex]
Step-by-step explanation:
We can use the exponent rules. If we have [tex]\frac{a^b}{a^c}[/tex], then it will simplify to [tex]a^{b-c}[/tex].
b is 5, c is -6, and a is -5 so:
[tex]-5^{5-(-6)}\\-5^{11}[/tex]
Hope this helped!
PLS ANSWER I WILL GIVE YOU BRAINLIST AND A THANK YOU!!
Answer:
x=45
Step-by-step explanation:
2x+45+x=180
Combine 2x and x to get 3x.
3x+45=180
Subtract 45 from both sides.
3x=180−45
Subtract 45 from 180 to get 135.
3x=135
Divide both sides by 3.
x=135/3
Divide 135 by 3
x=45
question : 4(3x + 2) -6 x 6
Answer:
x= 24
Step-by-step explanation:
open the bracket
4×3x =12x + 4 × 2 =8
12×+ 8-6×6
12×+ 12
x= 24
Answer:
12x - 28
Step-by-step explanation:
Because of PEMDAS you start with the parentheses and distribute the 4.
So,
(12x + 8) -6 x 6
Then, solve for the 6's
(12x + 8) -36
Remove the parentheses
12x + 8 - 36
Lastly, you get
12x - 28.
This is as far as you can go because there is no equals sign so you cannot actually solve for x.
Which box-and-whisker plot best represents the information from the data?
10 12 15 19 22 22 23 26 30 32
6r-1+6r=11 explain how to get so
Answer:
r = 1
Step-by-step explanation:
6r - 1 + 6r = 11
Adding 6r and 6r (because they're like terms) gives us:
12r - 1 = 11
Adding 1 to both sides of the equation gives us:
12r - 1 + 1 = 11 + 1
12r = 12
Dividing both sides of the equation by 12 gives us:
12r/12 = 12/12
r = 1
solve for -5x-13(2+x)=5x-10
Answer:
[tex]x=-\frac{16}{23}[/tex]
I hope this helps!
Question. 1 The product of a monomial and a binomial is a (a) monomial (b) binomial (c) trinomial (d) None of these
Answer:
The answer to this question is (D)
Solve. 2x−y+3z=6 2x+y=3 2y−4z=−4 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
Answer:
(3/2, 0, 1)
Step-by-step explanation:
From 2x+y=3 we have => y=3-2x
From 2y-4z=-4 we have -4z=-2y-4 => z=1/2y+1 => z=1/2 (3-2x) +1 => z=5/2-x
Plug in y & z to find x
2x−y+3z=6 => 2x+(3-2x)+3(5/2-x)=6 => 2x+3-2x+15/2-3x=6 => 21/2-3x =6 => x=3/2
plug in x to find y
2x+y=3 => 2(1.5) + y =3 => y=0
plug in y to find z
2y -4z =-4 => 2(0)-4z=-4 => -4z=-4 => z=1
What’s is the greatest common factor of 100x^2 - 250xy + 75x
Answer:
The greatest common factor of the expression is 25x
Step-by-step explanation:
Here, we are interested in giving the greatest common factor of the expression.
We can do this by factorization till we have no common factors left.
the expression is;
100x^2 -250xy + 75x
we start with the common factor x;
x(100x -250y + 75)
The next thing to do here is to find the greatest common factor of 100,250 and 75.
The greatest common factor here is 25.
Thus, we have;
25x(4x -10y + 3)
There is no more factor to get from the terms in the bracket. This simply means that the terms in the bracket are no longer factorizable
So the greatest common factor we have is 25x
help!! im stuck on this and i can't remeber how to sove this.... 6/3c = 2/3
Hello!
Answer:
[tex]\huge\boxed{c = 3}[/tex]
Given:
[tex]\frac{6}{3c} = \frac{2}{3}[/tex]
Cross multiply:
[tex]6 * 3 = 3c * 2[/tex]
Simplify:
[tex]18 = 6c[/tex]
Divide both sides by 6:
[tex]c = 18/6 = 3[/tex]
Answer:
c=3
Step-by-step explanation:
6 2
----- = -----
3c 3
Using cross products
6*3 = 2*3c
18 = 6c
Divide each side by 6
18/6 = 6c/6
3 =c
Find the value of x in the given
right triangle.
Enter your answer as a decimal rounded to the
nearest tenth.
Answer:
x = 12.5Step-by-step explanation:
Since the figure above is a right angled triangle we can use trigonometric ratios to find x
To find x we use cosine
cos∅ = adjacent / hypotenuse
From the question
The hypotenuse is x
The adjacent is 10
Substitute these values into the above formula and solve for x
That's
[tex] \cos(37) = \frac{10}{x} [/tex][tex]x \cos(37) = 10[/tex]Divide both sides by cos 37
[tex]x = \frac{10}{ \cos(37) } [/tex]x = 12.52135
We have the final answer as
x = 12.5 to the nearest tenthHope this helps you
Answer:
probably 16.5
Step-by-step explanation:
A square has a perimeter of 24cm. Work out its area.
Answer:
A = 36 cm^2
Step-by-step explanation:
The perimeter of a square is given by
P =4s
24 = 4s
Divide by 4
24/4 = 4s/4
6 =s
The area of a square is
A =s^2
A = 6^2
A = 36 cm^2
2( -4n+ 2)
6n = 4(-2 - 2n)
Answer:
(n^(2)+6n-4)(2n-4)
What are the solutions of x2 + 20 = 12x.
Answer:
x₁ = 2
x₂ = 10
Step-by-step explanation:
x² + 20 = 12x
x² - 12x + 20 = 0
(x-2)(x-10) = 0
then:
x₁ = 2
x₂ = 10
Check:
x₁
2² + 20 = 12*2
3 + 20 = 24
x₂
10² + 20 = 12*10
100 + 20 = 120
What is the greatest common factor? Need help fast!
Answer:
Step-by-step explanation:
9x^3,15x^5= 3x^3
The GCF is constructed by multiplying all the factors that are common to all the given expressions, exponentiated to the smallest power.
In our example, the following factors are common to all the given expressions: 3, x^3
Therefore, the GCF is equal to 3x^3.
10
Complete the conversion. $2 per pound = $_ per ounce (round to the nearest hundredth)
Answer:
$2 per pound = $0.125. per pound
Step-by-step explanation:
The unit of weight conversion from pound to ounce is given as follows;
1 pound weight = 16 ounces weight
1 ounce weight = 1/16 pound weight
Therefore, whereby the cost of 1 pound weight of an item is two dollars, we have;
The cost of one ounce weight of the item will be the cost of 1 pound weight, divided by 16 and given as follows;
$2 per pound = $2/16 per pound = $0.125. per pound
Therefore;
$2 per pound = $0.125. per pound.
3(q−7)=27 need help plzz 1st peep gets brainlest
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▹ Answer
q = 16
▹ Step-by-Step Explanation
3(q - 7) = 27
3q - 21 = 27
Add 21 to both sides:
21 + 21 = na
27 + 21 = 48
3q = 48
Divide both sides by 3:
3/3 = q
48/3 = 16
q = 16
Hope this helps!
CloutAnswers ❁
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Answer:
q=16
Step-by-step explanation:
3q-21=27
27+21=48
48/3=16
Add the matrices to find the answer.
Answer:
[tex]\large \boxed{\mathrm{Option \ C}}[/tex]
Step-by-step explanation:
[tex]{\mathrm{view \ attachment}}[/tex]
On the first day in each month, Enid deposited $4 into her bank account and Jim deposited $3 into his. They opened these accounts on May 15, 1990. On December 31, 1990, they each had $72 dollars in their account. How much did each person deposit on May 15?
Answer:
The amount of money in Enid bank account can be written as a linear equation.
Ye = Xe + $4*m
where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.
For Jim, the equation is similar:
Yj = Xj + $3*m
where Yj and Xj are similar as above.
Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).
Then we have that:
Ye = $72 = Xe + $4*7 = Xe + $28
Xe = $72 - $28 = $44
So in May 15, Enid deposited $44.
For Jim we have:
Yj = $72 = Xj + $3*7 = Xj + $21
Xj = $72 - $21 = $51
So in May 15, Jim deposited $51.