Answer:
33 blocks
Step-by-step explanation:
Given the length , breath and height for small block 6cm, 4cm, and 2cm an d for large 2m = 200cm, 4cm and 2cm.
volume is given by
V = Length x breath x height
Volume of small block = 6 x 4 x 2 = 48 cm^3
Volume of big block = 200 x 4 x 2 = 1600 cm^
No of blocks = Volume of big block/ volume of small block
= 1600/48
= 33.33
Therefore no of blocks formed = 33
The grade 10 class is going to bake muffins. The recipe that they are going to use requires the following ingredients: RECIPE ✓2 Egga ✔125ml Cooking oll ✓375ml brown sugar (300g) ✓800ml Milk ✓300g Whole wheat flour ✓ 375ml cake flour (210g) ✓5ml Salt ✓ 5ml Vanilla Essence ✓ 10ml Bicarbonate of soda ✓ 250ml Raisins (150g) 2.1 The volume of 150g of Whole wheat is 250ml. Calculate the volume of the Whole wheat flour in the recipe 2.2 When they are all mixed together, all the above ingredients make up 2 litres of mixture (because some parts dissolve into other parts). 2.2.1 Convert 2 litres into ml 2.2.2 How many muffins can the above recipe make if 60ml is required for each muffin? 2.2.3 Using your answer to question 2.2.2, how many eggs will the girls need to buy to make 500 muffins? 2.3 The students need to make 500 muffins, using muffin trays that hold 6 muffins par tray. They plan to put 4 trays at a time into the ovens. Each oven takes 30 minutes to bake. How long will they take to make 500 muffins if they will be using 4 ovens?
The conversion of 2 liters into millimeters from the information regarding the muffins is 2000ml.
How to convert?From the information, we are told to convert 2 litres into ml. This will be:
= 1000 × 2
= 2000ml
The number of eggs that will be bought to make 500 muffins will be:
= 500 × 2
= 1000 eggs.
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Forming quadratic expression.Two consecutive odd numbers are such that their product is 35.find the numbers
Answer:
Numbers are 5 , 7
Step-by-step explanation:
Forming quadratic equation and solving:Let the two consecutive odd numbers be (2x + 1) and (2x + 3)
Their product = 35
(2x + 1)(2x + 3) = 35
Use FOIL method.
2x*2x + 2x*3 + 1*2x + 1*3 = 35
4x² + 6x + 2x + 3 = 35
Combine like terms
4x² + 8x + 3 = 35
4x² + 8x + 3 - 35 = 0
4x² + 8x - 32 = 0
Quadratic equation: 4x² + 8x - 32 = 0Solving:
4x² + 8x - 32 = 0
Divide the entire equation by 2
[tex]\sf \dfrac{4}{2}x^2 +\dfrac{8}{2}x - \dfrac{32}{2}=0[/tex]
2x² + 4x - 16 = 0
Sum = 4
Product = -32
Factors = 8 , (-4)
When we multiply 8*(-4) = -32 and when we add 8 + (-4) = 4.
Rewrite the middle term
2x² + 8x - 4x - 16 = 0
2x(x + 4) - 4(x + 4) = 0
(x + 4) (2x - 4) = 0
2x - 4 = 0 {Ignore x +4 = 0 as it gives negative number}
2x = 4
x = 4/2
x= 2
2x + 1 = 2*2 + 1 = 5
2x + 3 = 2*2 +3 = 7
The numbers are 5 , 7
-9x²(x²+2x²y - 3y²)
Simplify
−9x^4−18x^4y+27x^2y^2
HAVE A NICE DAY!Answer:
=−18x^4y−9x^4+27x^2y^2
Step-by-step explanation:
(−9x^2)(x^2+2x^2y−3y^2)
=(−9x^2)(x^2+2x^2y+−3y^2)
=(−9x^2)(x^2)+(−9x^2)(2x^2y)+(−9x^2)(−3y^2)
=−9x^4−18x^4y+27x^2y^2
=−18x^4y−9x^4+27x^2y^2
---
Hope I helped! Have a great day :)
The length of a rectangle is 3m less than double the width, and the area of the rectangle is 65m^2 .
What is the length & width of the rectangle?
By solving a quadratic equation, we will see that the length is 10m and the width is 6.5m
How to find the length and width of the rectangle?For a rectangle of width W and length L, the area is:
A = W*L
In this case, we know that the area is 65m² and that the length is 3 meters less than 2 times the width, so:
L = 2*W - 3m
Then we can write:
65m² = (2*W - 3m)*W = 2*W² - 3m*W
This is a quadratic equation:
2*W² - 3m*W - 65m² = 0.
The solutions are given by the Bhaskara's formula:
[tex]W = \frac{3 \pm \sqrt{(-3)^2 - 4*2*(-65)} }{2*2} \\\\W = \frac{3 \pm 23 }{4}[/tex]
We only care for the positive solution, which is:
W = (3m + 23m)/4 = 26m/4 = 6.5m
Then the length is:
L = 2*6.5m - 3m = 10m
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5. Sabrina put $3,000 into a Money Market (high-yield savings)
account with an interest rate of 2.6% compounded quarterly.
a. Write an equation to model the amount in the account over
time.
b. Assuming no deposits or withdrawals are made, how much
money would be in the account after 15 years? Show your
calculation.
c. How would this problem be different if it was compounded
"continuously" instead? Calculate the amount after 15 years.
d. Name 2 or more other situations (other than a savings
account) where you might encounter compound interest later in
your life.
let me answer the last one first
compound interest is just an exponential sequence really, where the next value is some exponential amount of the previous.
hmmm that can happen in say, a bouncing ball, the 1st bounce is high, let it keep on boucing by itself and the next bounce is usually a compounded value of the previous one, since it's smaller it'd be a Decay type of equation.
hmmm it also happens in say population growth, of any organism, humans, bees, amoebas.
now let's do the others
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3000\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=3000\left(1+\frac{0.026}{4}\right)^{4\cdot t}\implies \boxed{A=3000(1.0065)^t} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{after 15 years}}{t=15}\hspace{5em} A=3000(1.0065)^{15}\implies A\approx 3306.19 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3000\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ t=years\dotfill &15 \end{cases} \\\\\\ A=3000e^{0.026\cdot 15}\implies A=3000e^{0.39}\implies A\approx 4430.94[/tex]
Gray can ride his bike 6miles in 20 minutes at this rate how many miles can he ride in 100 minutes
Kindly solve all the questions below .
I'll give the brainliest
(4)
1. 11.444 repeater
2. 0.58333 repeater
3. 6.7333 repeater
4. 27.5454 repeater (on both 5 and 4)
5. 1.482517482517 (482517 repeater)
6. 2.285714285714 (285714 repeater)
7. 7.5666 repeater
8. 60.60606060 (60 repeater)
(5)
1. 0.666 (repeater)
2. 0.3666 (repeater)
3. 1.1818181818 (18 repeater)
4. 0.418181818 (18 repeater)
²-6x +10 is to be written in the form (x-p)² +g. Find the values of p and q.
Answer:
[tex]p = 3\\\\q= 1[/tex]
Step-by-step explanation:
[tex]x^2 -6x +10\\\\=x^2 -2 \cdot 3x +3^2 -3^2 +10\\\\=(x-3)^2 -9+10\\\\=(x-3)^2 +1\\\\\text{By comparing with}~ (x-p)^2 +q, \\\\p = 3\\\\q = 1[/tex]
What property states that changing the order of two or more terms does what to the value of the sum
Answer: Commutative property
Find the greatest common factor of 6m² and 7m².
Answer:
your answer is 4 my friend
Step-by-step explanation:
Solve for p: -3p + 2 > 5
To solve these types of problems:
⇒ just solve like a regular algebraic equation
⇒ with an inequality sign in the middle
Let's solve:
[tex]-3p + 2 > 5\\-3p > 3[/tex]
whenever there is any division/multiplication⇒ must change the inequality sign to face the other direction
[tex]-3p > 3\\p < -1[/tex]
Answer: p < -1
Hope that helps!
Answer:
p < -1
Step-by-step explanation:
-3p + 2 > 5
subtract 2 from both sides
-3p + 2 - 2 > 5 - 2
-3p > 3
divided both sides by -3 to get p alone
-3p / -3 > 3 / -3 reverse the inequality
p > -1
solve
16x+8>=12x+20
A. x<=3
B. x<=7
C. x>=3
D. x>=7
Answer: C
Step-by-step explanation:
[tex]16x+8 \geq 12x+20\\ \\ 4x+8 \geq 20\\ \\ 4x \geq 12\\ \\ \boxed{x \geq 3}[/tex]
if x+7y=16 and 3x-7y=4 what is the value of x
Answer:
[tex]x=5\\[/tex]
Step-by-step explanation:
First, put your equations into a system.
[tex]\left \{ {{x+7y=16} \atop {3x-7y=4}} \right.[/tex]
Next, use the method of elimination to solve the system. Elimination is when either x or y has an opposite coefficient (so in this case y has a coefficient of 7 or -7 depending on the equation). You can then add the equations, and y is eliminated as a variable. Now you can solve for x.
[tex]4x=20[/tex]
Lastly, divide by 4 on both sides to get x by itself.
[tex]x=5\\[/tex]
y=-3³ +4
step by step of the rules and formula of this equation
Which function is shown in the graph below?
O y = logo 4x
O y = log₁x
O y = log3x
O y = log10x
The correct function shown in the graph is,
⇒ log₁₀ (ax) = 1
What is mean by Function?A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
It has been given that the point (3,1) is on the graph. For the point (3,1) to be on the graph, the following must hold true:
⇒ log₁₀ (ax) = 1
or , ax = 10¹ = 10
Thus, x = 10/a
So, in order for the point (3,1) to lie on the graph, of all the given options the closest we can get is when we have Option D, that is, when a = 3. That will make x = 3.33 and thus, .
⇒ log (3 × 3.33) = 0.99 ≈ 1
Thus, out of the given options only Option D seems to be the most probable answer.
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the lenghts of five boxes are shown in the table which line plot shows the data from the table
Answer:
The bottom right line plot.
Step-by-step explanation:
In the table, 9 1/4 shows up twice. This can be represented in the line plot by putting 2 x's over the 9 1/4 point.
Help!!!!! Meeee!! Asappppp
Reason:
Refer to the diagram below. The tiny square angle markers tell us we have a 90 degree angle, meaning those lines are perpendicular.
You can think of the parallel lines being the metal part of train tracks, while the perpendicular line connecting the metal rails is the wooden part of the train tracks.
A leak in a pool causes the height of the water to decrease by 0.25 foot over 2 hours. After the leak is fixed, the height of the water is 4.75 feet. The equation 4.75 = x + (negative 0.25) can be used to find x, the original height of the water in a pool.
What was the original height of the water in the pool in feet?
4.5
5.0
6.5
7.0
The original height of the water in a pool is 5 ft , Option B is the correct answer.
What is an Equation ?An equation can be defined as a mathematical statement when two algebraic expressions are equated using an equal sign.
It is given in the question that
A leak in a pool causes the height of the water to decrease by 0.25 foot over 2 hours.
the height of the water is 4.75 feet.
The equation
4.75 = x + (negative 0.25)
can be used to find x, the original height of the water in a pool.
4.75 = x - 0.25
x = 5
Therefore the original height of the water in a pool is 5 ft , Option B is the correct answer.
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Answer:
B
Step-by-step explanation:
Parallel lines q and q are cut by transversal r forming 4 angles at each intersection. At the intersection of lines r and q, clockwise from top left, the angles are: 1, 2, 4, 3. At the intersection of lines r and s, clockwise from top left, the angles are: 5, 6, 8, 7.
Use the diagram to complete the statements.
Angles 1 and 5 are
because they are
angles.
Angles 4 and 6 are
because they are
angles.
Using the vertically opposite angles theorem and corresponding angles theorem, we have proven that alternate exterior angles are congruent
Angle theoremsFrom the question, we are to prove that alternate exterior angles are congruent.
In the given diagram, examples of alternate exterior angles are
∠1 and ∠8
∠2 and ∠7
Now, we will prove that ∠1 = ∠8
In the diagram, we can observe that
∠1 = ∠4 (Vertically opposite angles theorem)
and
∠4 = ∠8 (Corresponding angles theorem)
Then,
By the substitution property of equality
∠1 = ∠8
Hence, alternate exterior angles are congruent
Here is the complete and correct question:
Consider parallel lines cut by a transversal. Parallel lines q and s are cut by transversal r. On line q where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line s where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7.
Explain which theorems, definitions, or combinations of both can be used to prove that alternate exterior angles are congruent.
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Answer:
Step-by-step explanation:
Parallel lines q and q are cut by transversal r forming 4 angles at each intersection. At the intersection of lines r and q, clockwise from top left, the angles are: 1, 2, 4, 3. At the intersection of lines r and s, clockwise from top left, the angles are: 5, 6, 8, 7.
Use the diagram to complete the statements.
Angles 1 and 5 are
✔ congruent
because they are
✔ corresponding
angles.
Angles 4 and 6 are
✔ supplementary
because they are
✔ same-side interior
angles.
this is probability can someone please give me an answer
Answer:
The experimental probability is 4%
Step-by-step explanation:
Which of the following theorems verifies that AKML AOPQ?
The theorem that verifies that the two right angled triangles are similar is HA.
What are similar triangle?Two triangles are said to be similar if the ratio of their corresponding sides and the corresponding angles are equal.
Analysis:
From the diagrams KL = OQ ( hypotenuse)
∠L is equal to ∠Q which are acute.
so the two triangles are similar in hypotenuse and acute angle which is the HA theorem.
In conclusion, the HA theorem verifies that the two triangles are similar.
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Let a and ß be first quadrant angles with cos(a)=
√11/7
and sin(B)=
√11/4
Find cos(a+B)
Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,
sin²(x) + cos²(x) = 1
we always take the positive square root when solving for either sin(x) or cos(x).
Given that cos(α) = √11/7 and sin(β) = √11/4, we find
sin(α) = √(1 - cos²(α)) = √38/7
cos(β) = √(1 - sin²(β)) = √5/4
Now, recall the sum identity for cosine,
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
It follows that
cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28
Two balls are drawn without replacement from a box containing 2black and 3 red balls. What is the probability of drawing a black ball on the second draw? Draw a tree diagram
The probability of drawing a black ball on the second draw will be 3/5.
How to solve the probability?From the information given, the total number of balls will be:
= 2 + 3 = 5 balls.
When the first ball is black and the second is red. This will be:
= 2/5 × 3/4
= 3/10
When the first is red and the second is black, this will be:
= 3/5 × 2/4
= 3/10
Therefore, the probability of drawing a black ball on the second draw will be:
= 3/10 + 3/10
= 3/5.
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1) Which is the first INCORRECT step in the
solution of the inequality shown below?
2(x+1)-(3-x) ≤ -4:
Step 1: 2x + 2-3+x≤-4;
Step 2: 3x - 1≤-4;
Step 3: 3x
-3;
Step 4: x>-1
(a) Step 1
(b) Step 2
(c) Step 3
(d) Step 4
Step-by-step explanation:
we are missing the inequality sign in step 3.
step 1 and step 2 are correct.
step 4 is wrong.
the correct step 3 looks like
3x <= -3
if your original step 3 says the same, then the first wrong step is step 4.
if your original step 3 does not say the same, then the first wrong step is step 3.
A school wants 2 chaperones for every 25 students on a field trip. There are 100 students going on the field trip. How many chaperones does the school need?
A
4
B
8
C
108
D
50
Using proportions, it is found that the number of chaperones that the school needs is given by:
B. 8.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, 2 chaperones are needed for every 25 students. How many are needed for 100 students? The rule of three is given by:
2 chaperones - 25 students
n chaperones - 100 students
Applying cross multiplication:
25n = 2 x 100
n = 200/25
n = 8.
Hence option B is correct.
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What is the distance between the points (-4,-8) and (6,16), to the nearest tenth of a units?
A. 8.2 units
B.676.0 units
C.21.8 units
D.26.0 units
Answer:
D.26.0 unitsStep-by-step explanation:
Given : the points A(-4,-8) and B(6,16),
Let d be the distance between A and B.
Then
[tex]d=\sqrt{\left( 16-\left( -8\right) \right)^{2} +\left( 6-(-4)\right)^{2} }[/tex]
[tex]=\sqrt{\left( 24\right)^{2} +\left( 10\right)^{2} }[/tex]
[tex]=\sqrt{676 }[/tex]
[tex]=26[/tex]
Can 3×2×2×3 be written as a power with an exponent of 4? Explain your thinking.
The average Wealth of a person in Richville is $150,000 and the average wealth of a
person in Poorville 15 $20,000. Suppose Richville and Poorville combine to form Mediumville.
Find the solution set for |2x-3|=9
Answer:
x = 6, -3
Step-by-step explanation:
. . . . . . . . . . . . . . . . .
(a) If cos² (34°) - sin² (34°) = cos(A°),then
A =
degree’s
[tex]~~~~~~~\cos^2 \left(34^{\circ}\right) - \sin^2 \left( 34^{\circ} \right)=\cos A\\\\\implies \cos \left( 2 \cdot 34^{\circ} \right) = \cos A~~~~~~~~~~~~~;[\cos 2x = \cos^2 x -\sin^2 x]\\\\\implies \cos \left(68^{\circ}\right) = \cos A\\\\\implies A = 68^{\circ}[/tex]