Please answer correctly.

Answer:

0.1

Step-by-step explanation:

You are adding on 0.1 for each line and since G is the first line after 0, it is 0.1.

Answer:

[tex]\dfrac{\sqrt[12]{55296} }{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}[/tex]

[tex]\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:[/tex]

[tex]\implies \dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}}[/tex]

Multiply the numerator and denominator by [tex]2^{\frac{2}{3}}[/tex] :

[tex]\implies \dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}} \times \dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}[/tex]

[tex]\textsf{Apply exponent rule to the denominator} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies \dfrac{6^{\frac{1}{4}}}{2^{\frac{1}{3}}} \times \dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2^{\frac{1}{3}+\frac{2}{3}}}=\dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2}[/tex]

Rewrite 1/4 as 3/12 and 2/3 as 8/12 :

[tex]\implies \dfrac{6^{\frac{1}{4}} \cdot 2^{\frac{2}{3}}}{2}=\dfrac{6^{\frac{3}{12}} \cdot 2^{\frac{8}{12}}}{2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^c \cdot b^c=(a \cdot b)^c:[/tex]

[tex]\implies \dfrac{6^{\frac{3}{12}} \cdot 2^{\frac{8}{12}}}{2}=\dfrac{(6^3 \cdot 2^{8})^\frac{1}{12}}{2}[/tex]

Simplify the operation in the parentheses:

[tex]\implies \dfrac{(6^3 \cdot 2^{8})^\frac{1}{12}}{2}=\dfrac{(216\cdot 256)^\frac{1}{12}}{2}=\dfrac{(55296)^\frac{1}{12}}{2}[/tex]

[tex]\textsf{Finally, apply exponent rule} \quad a^{\frac{1}{n}}=\sqrt[n]{a}:[/tex]

[tex]\implies \dfrac{(55296)^\frac{1}{12}}{2}=\dfrac{\sqrt[12]{55296} }{2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6^{\dfrac{1}{4}}}{2^{\dfrac{1}{3}}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{2^{\dfrac{1}{4}}3^{\dfrac{1}{4}}}{2^{\dfrac{1}{3}}}[/tex]

[tex]\\ \rm\Rrightarrow 2^{\dfrac{1}{4}-\dfrac{1}{3}}3^{\dfrac{1}{4}}[/tex]

[tex]\\ \rm\Rrightarrow 2^{\dfrac{-1}{12}}3^{\dfrac{1}{4}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{3^{\dfrac{1}{4}}}{2^{\dfrac{1}{12}}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{3^{\dfrac{3}{12}}}{2^{\dfrac{1}{12}}}[/tex]

[tex]\\ \rm\Rrightarrow \left(\dfrac{3^3}{2}\right)^{\dfrac{1}{12}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{3^3}{2}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{3^3\times 2^82^3}{22^82^3}}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt[12]{\dfrac{27(256)(8)}{2^12}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[12]{6912(8)}}{2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\sqrt[12]{55296}}{2}[/tex]

Answer:

4/13 is the answer

total = 4+3+5+1= 13

let a be the event of getting red marbles= total is 4

probability=4/13

Answer:

Step-by-step explanation:

The matrix of coefficients has one row corresponding to each equation. The constants in that row are the coefficients of the variables in the equation. Coefficients are listed in the same order on each row. A missing term is represented by a coefficient of 0.

The first attachment shows the coefficient matrix and its determinant.

__

The solution to the system of equations can be found by left-multiplying the constant vector by the inverse of the coefficient matrix.

  [tex]\textbf{A$\cdot$X}=\textbf{B}\\\\\textbf{X}=\textbf{A}^{-1}\cdot\textbf{B}[/tex]

This multiplication is shown in the second attachment. It tells us ...

  [tex]\textbf{X}=\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}3\\4\\1\end{array}\right][/tex]

Answer:

take the dots and either put them together or rake them away

Step-by-step explanation:

Example: .....+..=....... five dots plus two dots equals seven dots.

......-...=... six dots minus three dots equals three since you are taking away three

i hope u found this helpful.

Answer:

3

Step-by-step explanation:

18-15=3

Answer:

first option, 3

Step-by-step explanation:

The interquartile range is the difference between Q3 and Q1.

Q1 is the lower bound of the box = 15

Q3 is the upper bound of the box = 18

 Q3 - Q1

= 18 - 15

= 3

Explanation:

The solution set for a system of equation is the set of points where the graphs of the equations intersect.

__

A system will have one solution if there is a single point of intersection of the graphs of the equations.

A system will have no solutions if the graphs have no points of intersection.

A system will have an infinite number of solutions if the graphs intersect at an infinite number of points.

_____

When the equations are linear equations, their graphs are straight lines. If the lines have different slopes, they must intersect at exactly one point: there will be one solution.

If the lines have the same slope, there are two possibilities:

The attached graph illustrates these cases.

Answer: [tex]h=\frac{23}{10} =2.300[/tex]

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

[tex]h+\frac{4}{-2} -((\frac{3}{10} ))=0[/tex]

[tex]Simplify~ \frac{3}{10}[/tex]

[tex](h+\frac{4}{-2} )-\frac{3}{10} =0[/tex]

Subtracting a fraction from a whole

Rewrite the whole as a fraction using  10  as the denominator :

[tex]h-2=\frac{h-2}{1} =\frac{h-2x10}{10}[/tex]

Equivalent fraction: The fraction thus generated looks different but has the same value as the whole

Common denominator: The equivalent fraction and the other fraction involved in the calculation share the same denominator

  Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to the lowest terms if possible:

[tex]\frac{(h-2)x10-(3)}{10} =\frac{10h-23}{10}[/tex]

[tex]\frac{10h-23}{10} =0[/tex]

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, CalderonJ multiplys both sides of the equation by the denominator.

Here's how:

[tex]\frac{10h-23}{10} *10=0*10[/tex]

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  10h-23  = 0

Add  23  to both sides of the equation :

                     10h = 23

Divide both sides of the equation by 10:

                    h = 23/10 = 2.300

Final Answer: 2.3(decimal form) aka 23/10 (fraction)

Answer:

60

Step-by-step explanation:

The answers to the options are:

This inequality is known tp imply that the normal body temperature is taken (subtracted) from the minimum and maximum body temperature.

Note that in case A, the The inequality that represent the temperatures  is less than sign.

In case b, it is an open interval because it means that in -40°F to -140°F , it is not equal to as that is the reason that  the gas cannot stay liquid.

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Answer:

Parent function

[tex]f(x)=\log_2(x)[/tex]

Since we cannot take logs of zero or negative numbers, the domain is [tex](0, \infty)[/tex] and there is a vertical asymptote at [tex]x=0[/tex].

There are no horizontal asymptotes and the range is [tex](- \infty,\infty)[/tex].

The end behaviors of the parent function are:

[tex]\textsf{As } x \rightarrow 0^+, f(x) \rightarrow - \infty[/tex]

[tex]\textsf{As } x \rightarrow \infty, f(x) \rightarrow \infty[/tex]

To determine the attributes of the given function, compare the given function with the parent function.

Given function

[tex]f(x)=- \log_2(x)+5[/tex]

The given function is reflected in the x-axis.  Therefore, the end behaviors are a reflection of those of the parent function:

[tex]\textsf{As } x \rightarrow 0^+, f(x) \rightarrow \infty[/tex]

[tex]\textsf{As } x \rightarrow \infty, f(x) \rightarrow - \infty[/tex]

As the given function is translated vertically (5 units up) only, the domain, range and asymptote will not change, since the function has not been translated horizontally.

[tex]\textsf{Domain}: \quad (0, \infty)[/tex]

[tex]\textsf{Range}: \quad (- \infty, \infty)[/tex]

[tex]\textsf{Asymptote}: \quad x=0[/tex]

Conclusion

The function f(x) is a [tex]\boxed{\sf logarithmic}}[/tex] function with a [tex]\boxed{\sf vertical}}[/tex] asymptote of [tex]\boxed{x = 0}[/tex].  

The range of the function is [tex]\boxed{(- \infty, \infty)}[/tex], and it is [tex]\boxed{\sf decreasing}[/tex] on its domain of [tex]\boxed{(0, \infty)}[/tex].  

The end behavior on the LEFT side is as [tex]\boxed{x \rightarrow 0^+}[/tex], [tex]\boxed{f(x) \rightarrow \infty}[/tex], and the end behavior of the RIGHT side is [tex]\boxed{x \rightarrow \infty}[/tex], [tex]\boxed{f(x) \rightarrow -\infty}[/tex].

Answer:

your answer will be 18

Step-by-step explanation:

2/3 of 72 is 48,  1/4 of 72 is 18

i need some extra words here so hopefully this works

Answer:

The choice second . a=18/3 and b = 32/4

Step-by-step explanation:

[tex]a + 3 = 18 \\ a = 18 - 3[/tex]

[tex]4b = 32 \\ \\ b = \frac{32}{4} [/tex]

Answer:

a-x=y+25

b-35 minutes

c-nort possible

Step-by-step explanation:

can't explain due to the fact it will take 30m to type up

Answer:

Yes

Step-by-step explanation:

1. Yes , the data franchise owner is collecting, will be helpful in order to counter the criticism from the critic. As he has a record for every delivery they are making on daily basis.

2. The scenario is that for every fifth customer , the owner cross the four lines he makes. Thus a pack of five and easy to remember. As the data on regular week days is less, As can do the same for the third customer. Crossing the 2 lines for 3rd customer.

3. With this provision of crossing the third customer, the owner can have a better check on the late delivery. As it will bring in his notice earlier as compared to fifth crossing.

4. With the data as provided in the table, we can come to the conclusion that on weekends , i.e. both on time delivery and late deliveries are high in numbers. It must be because of high demand on that days. So owner must make some provision like hiring some more delivery boys for weekend in order to reduce the late deliveries.

Answer:

The fundamental counting principle is a rule used to count the total number of possible outcomes in a situation

The solution of the given radical expression√20 using factorization is [tex]2 \sqrt{5}[/tex]. Therefore, the correct option for the  radical expression√20 is option A, i.e  [tex]2 \sqrt{5}[/tex].

A collection of constants, variables or numbers connected using one or more arithmetic operator is called an expression.

Example = 4y, 3x+4.

An expression containing the values in the form of square root, cube root is called a radical expression.

The breaking of a number into its own factors, so that they multiply to give the same number again, is called factorization.

Given expression, √20

The solution of the expression can be obtained by the factors of 20.

[tex]\sqrt{20} = \sqrt{2\times2\times5}[/tex]

[tex]\sqrt{20}[/tex] = [tex]2 \sqrt{5}[/tex]

Here, 2 and 5 are factors of 20.

Thus, the value of the radical expression [tex]\sqrt{20}[/tex]  is [tex]2 \sqrt{5}[/tex].

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Answer:

Image included:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Comment

It is not possible to figure out what choices are are given for the first blank. I will say that the probable choice has the word product in it.

The second blank is the actual number of choices. It is 3 page count times color or 3*4 = 12 different choices.

Answer

product

12

Answer:

x = 144

Step-by-step explanation:

Angle sum of heptagon = 900

5x + 90 + 90 = 900
5x + 180 = 900
5x + 180 - 180= 900 - 180
5x = 720
Divide both sides by 5
x = 144

The LCM stands for the least common multiple. The least of the possible number of choir members at the rehearsal is 59.

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

Given the configurations of choir members at the rehearsal, which are,

Now, it takes the LCM of 12, 15, and 20, then the LCM will be 60, But since None of these configurations worked because for each, the last row had 1 person less than the other rows. The number of members was 1 less than the LCM.

Hence, the least of the possible number of choir members at the rehearsal is 59.

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Step-by-step explanation:

|...| means absolute value of "...". that means always the "+" value of "...", even if it is negative.

in other words

|-x| = x

|x| = x

|-x - 2y| for x = -2 and y = 3

|- -2 - 2×3| = |2 - 6| = |-4| = 4

In trapezoid ABCD ,length of AB is equals to 8.4units(nearest tenth).

" Trapezoid is defined as the quadrilateral whose one pair of opposite side is parallel."

According to the question,

Given

Length of AE=5.2

Length of  AC=11.7

Length of  CD=10.5

As shown in figure

In trapezoid ABCD,

AB is parallel to CD, AC is the transversal.

AC and BD intersect at point E.

In ΔABE and ΔCDE,

∠BAE ≅∠ECD

∠ABE ≅∠EDC

By AA theorem,

ΔABE ~ ΔCDE

Therefore,

[tex]\frac{AE}{EC}=\frac{AB}{CD}[/tex]

  AE + EC = AC

⇒ 5.2 + EC = 11.7

⇒ EC = 11.7 - 5.2

⇒ EC = 6.5units

Substitute the value in the given proportion we get,

   [tex]\frac{5.2}{6.5}=\frac{AB}{10.5}[/tex]

⇒ [tex]AB = \frac{(10.5)(5.2)}{6.5}[/tex]

⇒[tex]AB = 8.4[/tex] units

Hence, in trapezoid ABCD ,length of AB is equals to 8.4units(nearest tenth).

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Based on the definition of sequence and the characteristics of the given sequence, the complete sequence is: 4, 543, 65432, 7654321, 876543210.

Sequences are sets whose elements observes at least a condition. In this question we have a sequence formed by numbers formed by decimal digits ordered in descent way. Where the consecutive element has more digits than the previous one.

Then, we conclude that the complete sequence is: 4, 543, 65432, 7654321, 876543210.

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The simplified form of the given expression is tan(r) + cot(r) - 2

From the question, we are to simplify the given trigonometric function

The given trigonometric function is

[tex]\frac{(1-cot(r))^{2} }{cot(r)}[/tex]

Expanding, we get

[tex]\frac{(1-cot(r))(1-cot(r)) }{cot(r)}[/tex]

Simplifying

[tex]\frac{1 - 2cot(r) +cot^{2}(r) }{cot(r)}[/tex]

[tex]\frac{1}{cot(r)} -\frac{2cot(r)}{cot(r)}+\frac{cot^{2}(r) }{cot(r)}[/tex]

[tex]\frac{1}{cot(r)} -2+cot(r)[/tex]

Recall: [tex]tan(x) = \frac{1}{cot(x)}[/tex]

Therefore, we get

[tex]tan(r) -2 + cot(r)[/tex]

[tex]tan(r) + cot(r)-2[/tex]

Hence, the simplified form of the given expression is tan(r) + cot(r) - 2.

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Answer:

n+3-(5n+6)=0

n+3-5n-6=0

5n-n=6-3

4n=3

4n/4=3/4

n=3/4

The risk versus return of the investments that Marc and Julian are considering are:

Money Market savings accounts are offered by commercial banks and are quite safe which is why they have low returns. The same is true of a Five year CD.

IRAs and Mutual funds are considered moderate because they offer higher rates than CDs but with higher risk as well.

Stock and high-yield bonds are quite risky but they have a chance of a high return as well.

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Answer:

2/8, 3/12 and 4/16

Step-by-step explaination:

All these fractions are equivalent to 1/4 as the numerator is a multiple of 1, the denominator is a multiple of 4, and the numerators are all a quarter of their respective denominators.