Plastic parts manufactured using an injection molding process may exhibit one or more defects, including sinks, scratches, black spots, and son on. Let x represent the number of defects on a single part, and suppose the distribution of x is as follows: x: 0 1 2 3 4 p(x): 0.79 0.09 0.05 0.04 0.03 What is the expected value, E(X), for the number of defects on a randomly selected plastic part

Answer:

The expected value for the number of defects on a randomly selected plastic part is 0.43.

Step-by-step explanation:

We have the following probability distribution:

P(X = 0) = 0.79

P(X = 1) = 0.09

P(X = 2) = 0.05

P(X = 3) = 0.04

P(X = 4) = 0.03

What is the expected value, E(X), for the number of defects on a randomly selected plastic part?

Each value multiplied by its probability. So

[tex]E(X) = 0.79*0 + 0.09*1 + 0.05*2 + 0.04*3 + 0.03*4 = 0.43[/tex]

The expected value for the number of defects on a randomly selected plastic part is 0.43.

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