Phenol red is a pH indicator that changes color depending on the acidity of the solution. it is the Acid-Base reaction. When you breathe into a solution containing phenol red, the carbon dioxide in your breath reacts with the water in the solution to form carbonic acid, which is an acid. This increases the acidity of the solution, which causes the phenol red to turn yellow.
Phenol red is a pH indicator that turns yellow when you breathe into a solution. This reaction explains why the solution turned acidic, which can be explained by the following reaction process:
CO2 + H2O → H2CO3 → H+ + HCO3-
The carbon dioxide you exhale into the solution is soluble in water and reacts with it to form carbonic acid (H2CO3).Carbonic acid is a weak acid that dissociates into bicarbonate ions (HCO3-) and hydrogen ions (H+).The hydrogen ions then combine with the indicator phenol red and make the solution acidic, turning it yellow. Hence, the color change of the phenol red to yellow is an indicator that the solution is acidic. Phenol red is a pH indicator that is used to determine whether a solution is acidic or basic. It is widely used in microbiology as an indicator of carbohydrate fermentation. The indicator changes from red to yellow as the pH of the solution decreases. A yellow color indicates that the solution is acidic, while a red color indicates that the solution is alkaline. Phenol red is widely used to detect pH changes in laboratory and clinical settings. It is commonly used in biology labs to determine the pH of bacterial cultures and media. In clinical settings, it is used to measure pH changes in blood and urine samples.
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the principles which underlie balancing chemical equations include
The principles that underlie balancing chemical equations include the law of conservation of mass and the concept of stoichiometry.
The law of conservation of mass states that matter can neither be created nor destroyed in a chemical reaction, meaning that the total mass of the reactants must be equal to the total mass of the products. This principle requires that the number of atoms of each element on the reactant side of the equation must be equal to the number of atoms of that element on the product side. The concept of stoichiometry involves using the balanced equation to determine the quantitative relationships between the reactants and products, including the amounts of each substance involved in the reaction.
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--The complete question is, The principles that underlie balancing chemical equations include the______________ and the concept of stoichiometry. ---
Balance the equation. H3PO4 → H4P₂O7 +
H₂O
Answer:
2,1,1
Explanation:
the procedure for making zeolite is carried out in an acidic medium. true or false
The statement "the procedure for making zeolite is carried out in an acidic medium" is False.
Zeolite is a crystalline aluminosilicate mineral that occurs naturally.
It is widely used in various applications, including water purification, agriculture, and petrochemical refining.
Zeolites can be synthesized in the laboratory using different methods, such as hydrothermal and sol-gel methods.
The zeolite synthesis process is carried out in an alkaline or basic medium, not in an acidic medium.
Alkaline solutions, such as sodium hydroxide or potassium hydroxide, are commonly used to initiate the synthesis reaction, which involves the reaction of a source of silica, such as silicate, with a source of alumina, such as aluminate, in the presence of water and other chemical agents.
There are various types of zeolites with different chemical compositions, crystal structures, and properties.
The specific synthesis conditions, such as temperature, pressure, and reaction time, can also affect the final properties of the zeolite.
Therefore, the synthesis of zeolites requires precise control of the reaction conditions to obtain the desired properties.
Zeolites have a unique structure that can adsorb and exchange ions and molecules.
This property makes them useful in various applications, such as catalysis, separation, and ion exchange.
Zeolites can also be modified or functionalized to enhance their properties for specific applications.
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whats is called a physical and mental impairment resulting from the use of alcohol.
A physical and mental impairment resulting from the use of alcohol is called Alcohol Use Disorder (AUD).
AUD is a chronic disease characterized by a preoccupation with alcohol, increased tolerance to it, and physical dependence on it. Symptoms include intense cravings, withdrawal, and a loss of control over drinking. Long-term effects of AUD include liver damage, poor mental and physical health, and an increased risk of developing certain types of cancer. Treatment for AUD often involves therapy and medication to help with withdrawal symptoms, cravings, and the physical and mental impairments resulting from the use of alcohol.
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Why is a physical property not a characteristic of matter that you can’t observe or measure without changing the identity of matter
Answer:
Characteristics of matter change due to chemical changes, not physical ones. Physical properties can be determined without changing the substance's chemical identity
Explanation:
A change that is useful for the environment and living things is called
The change that is useful for the environment and living things is called "positive environmental change."
Positive environmental change refers to any alteration or modification in the environment that improves or benefits living organisms' well-being. Examples of positive environmental changes include reducing pollution, conserving water, using renewable energy sources, and recycling waste products. Positive environmental change is essential to ensure a sustainable future and to maintain the planet's biodiversity.
It can be achieved by implementing new policies, practices, and technologies that promote sustainable development and reduce the negative impact on the environment. Positive environmental change can also help to address climate change and other environmental challenges faced by humanity. By taking positive steps to protect the environment, we can ensure that future generations can also enjoy a healthy, prosperous, and sustainable planet.
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If the reaction quotient (Q) is smaller than the equilibrium constant (K) for a reaction then which way will the reaction proceed? a. The reaction is at equilibrium and the reaction will proceed at equal rates in the reverse and forward direction. b. The reaction will proceed to the right (products side) c. The reaction equation is required to answer this question d. The reaction will proceed to the left( reactants side)
The answer to the question is option b. The reaction will proceed to the right (product side) when the reaction quotient (Q) is smaller than the equilibrium constant (K).
A chemical reaction will not proceed spontaneously in the forward direction if Q is larger than K. The reaction will proceed spontaneously in the forward direction if Q is less than K. The reaction will be at equilibrium if Q is equal to K.
According to Le Chatelier's principle, when Q is less than K, the system will shift to the right in order to reach equilibrium. This signifies that the reaction will continue to generate products until equilibrium is achieved.
What is the meaning of the reaction quotient (Q)?The reaction quotient (Q) is a measure of the relative amounts of products and reactants in a chemical reaction that is not in equilibrium. The reaction quotient is determined in the same manner as the equilibrium constant (K) using molar concentrations or partial pressures of reactants and products. The only difference is that the reaction quotient is calculated at any point in the reaction, not just at equilibrium.
Therefore, if the reaction quotient (Q) is smaller than the equilibrium constant (K) for a reaction, the reaction will proceed to the product side with a tendency to achieve equilibrium.
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after successfully isolating solid copper in part b of this experiment, bernice is wondering if there are other acids that could be used in place of the acids available in part b of this experiment. which of the following acids could be used instead of the provided acids (h2so4 and h3po4) to isolate solid copper in part b of this experiment? select all that apply
o. HBr
o. HNO3
o. H2S
o. H2CO3
HNO3 and HBr can also be used instead of the provided acids (h2so4 and h3po4) to isolate solid copper in this experiment. Solid copper can be isolated by reacting it with acid. This is achieved in two stages: stage one, where copper reacts with sulfuric acid to produce copper sulfate and hydrogen gas, and stage two, where copper sulfate is reduced to copper using hydrogen gas.
Therefore, in part b of the experiment, H2SO4 and H3PO4 are used. HNO3 and HBr can also be used instead of H2SO4 and H3PO4 to isolate solid copper. H2S and H2CO3 cannot be used as the acids to isolate solid copper. 'Hence, the correct options are : HNO3 and HBr Therefore, both HBr and HNO3 could be used in place of the acids (H2SO4 and H3PO4) to isolate solid copper in part b of this experiment.
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Explain the following statement about the rate law equation: The rate constant isn't really
constant. Include the definition of the term rate constant in your answer and give two
specific examples to support this statement.
Answer:
In chemical kinetics, the rate constant (k) is a proportionality constant that relates the rate of a chemical reaction to the concentrations of the reactants. It is often included in the rate law equation, which expresses the relationship between the rate of the reaction and the concentrations of the reactants.
However, the rate constant is not truly constant because it can vary with different experimental conditions. The rate constant is affected by factors such as temperature, pressure, and the presence of catalysts or inhibitors. For example, an increase in temperature usually leads to an increase in the rate constant, while the addition of a catalyst can decrease the activation energy and increase the rate constant.
Two specific examples that support this statement are:
1) The effect of temperature on the rate constant: Consider the reaction A → B, which has a rate law equation of rate = k[A]. If the temperature is increased, the rate constant will increase due to the increase in kinetic energy of the reactant molecules. This means that the reaction will proceed faster at higher temperatures, even if the concentration of A remains the same.
2) The effect of catalysts on the rate constant: Consider the reaction C + D → E, which has a rate law equation of rate = k[C][D]. If a catalyst is added to the reaction, it can increase the rate constant by providing an alternate pathway with a lower activation energy. This means that the reaction will proceed faster at the same concentrations of C and D with the catalyst present than without it.
Explanation:
to conduct the synthesis of iodosalicylamide, edward used 0.97 g of salicylamide (mw: 137.14 g/mol) and 1.63 g of sodium iodide (mw:149.89 g/mol). assuming the reaction yield is 100%, how many grams of iodosalicylamide (mw:263.03 g/mol) would be formed? round your answer to two decimal places.
The amount of iodosalicylamide synthesized in the reaction performed by Edward by using 0.97 g of salicylamide will be about 2.87 grams.
What is the mass of iodosalicylamide?Iodosalicylamide is synthesized by reacting salicylamide and sodium iodide in the presence of an oxidant. Iodosalicylamide is used as a reagent to detect the presence of oxidizing agents.
To find the mass of iodosalicylamide produced, we must first determine the limiting reagent for the reaction. The limiting reagent is the one that is consumed entirely, preventing the reaction from continuing even though the other reactants are present. The limiting reagent is the one that produces the least amount of product.
Moles of salicylamide:
moles = mass / molar mass = 0.97 g / 137.14 g/mol = 0.00708 moles
Moles of sodium iodide:
moles = mass / molar mass = 1.63 g / 149.89 g/mol = 0.0109 moles
Since iodosalicylamide is formed in a 1:1 ratio with the limiting reagent, sodium iodide, the limiting reagent is sodium iodide. Therefore, the theoretical yield of iodosalicylamide is the same as the moles of sodium iodide used.
Moles of iodosalicylamide = 0.0109 mol
Mass of iodosalicylamide = moles × molar mass = 0.0109 mol × 263.03 g/mol = 2.87 g
Therefore, the mass of iodosalicylamide that would be formed, assuming 100% yield, is 2.87 g, rounded to two decimal places.
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determine the limiting reactant: naoh (aq) hcl (aq) --> h2o (l) nacl (aq) (balanced) 10 moles of naoh reacts with 12 moles of hcl.
NaOH (aq) + HCl (aq) → H2O (l) + NaCl (aq). The stoichiometric coefficient of NaCl is 1, so it will produce the same amount of moles as NaOH.
To determine the limiting reactant in this equation, the first step is to calculate the number of moles of each reactant available.
10 moles of NaOH and 12 moles of HCl are available, so we can use these values.
Then, we need to compare the calculated moles to the stoichiometric coefficients in the balanced equation.
The reactant that produces the least amount of product is the limiting reactant.
Let us begin with the number of moles of NaOH:
10 mol NaOH × (1 mol HCl / 1 mol NaOH) = 10 mol HCl
This means that if 10 mol of NaOH reacts, then 10 mol of HCl is also consumed.
Next, we calculate the number of moles of HCl available:
12 mol HCl × (1 mol NaOH / 1 mol HCl) = 12 mol NaOH
So if 12 mol of HCl is reacted, then 12 mol of NaOH is consumed.
Since we have more HCl than NaOH, the limiting reactant is NaOH.
Therefore, NaOH is the limiting reactant in this reaction.
We can also determine the maximum amount of NaCl that can be produced from this reaction by using the moles of NaOH. The stoichiometric coefficient of NaCl is 1, so it will produce the same amount of moles as NaOH.
Therefore, 10 mol of NaOH can produce a maximum of 10 mol of NaCl.
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in fireworks, the heat of the reaction of an oxidizing agent, such as kclo4, with an organic compound excites certain salts, which emit specific colors. strontium salts have an intense emission at 641 nm. what is the energy (in kj) of this emission for 4.09 g of the chloride salt of strontium? assume that all the heat produced is converted to emitted light. enter to 2 decimal places. (mts 2/17/2018)
The energy emitted by 4.09 g of strontium chloride salt is 8.01 8.00 x 10⁻²⁴ kJ (rounded to 2 decimal places).
What is the emission energy?
To determine the energy of the emission at 641 nm, we can use the formula:
E = hc/λ
where;
E is the energy, h is Planck's constant (6.626 x 10⁻³⁴ J·s), c is the speed of light (3 x 10⁸ m/s), and λ is the wavelength in meters.First, we need to convert the wavelength from nanometers to meters:
641 nm = 641 x 10⁻⁹ m
Next, we can plug in the values and solve for E:
E = (6.626 x 10⁻³⁴J·s)(3 x 10⁸ m/s)/(641 x 10⁻⁹ m)
E = 3.10 x 10⁻¹⁹ J
To convert from joules to kilojoules, we divide by 1000:
E = 3.10 x 10⁻²² kJ
Now we can use the molar mass of the chloride salt of strontium to calculate the total energy released:
SrCl₂ has a molar mass of 158.53 g/mol, so 4.09 g is equivalent to:
n = 4.09 g / 158.53 g/mol
n = 0.0258 mol
The energy released by 0.0258 mol of strontium chloride at 100% efficiency is:
E_total = nE
E_total = (0.0258 mol)(3.10 x 10⁻²² kJ/mol)
E_total = 8.00 x 10⁻²⁴ kJ
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8 H₂S+_8_Cl₂ --> _16_HCI + _1_Sg8
57 g H₂S makes how many grams of HCL
Answer:109.5g HCL
Explanation: 1st get the GFM of H2S, which is 34g/mol, and divide 57g by it. You get the moles for H2S: 1.7. Put what you have over what you want (have/want) equal to what other chemical you want like this:
8H2S/1.7H2S = 16HCl/X
Solve for it like an algebra equation
8x = 27.2 27.2/8 = 3.4molHCl
Round to sig figs
3molHCl
Multiple by HCL GFM (36.5g/mol)
3mol x 36.5g/mol
109.5gHCl
assuming the density of a 5% acetic acid by mass solution is 1.0 g/ml, determine the volume of the acetic acid solution necessary to neutralize 25.0 ml of 0.10 m
To determine the volume of a 5% acetic acid by mass solution necessary to neutralize 25.0 ml of 0.10 m is 300 mL
To calculate the volume of the acetic acid solution necessary to neutralize, you will use the formula:
M₁V₁ = M₂V₂
Where,
M₁ = molarity of acetic acid
V₁ = volume of acetic acid
M₂ = molarity of sodium hydroxide
V₂ = volume of sodium hydroxideInitially
You need to calculate the moles of NaOH in 25 ml of 0.10 M NaOH;
Molarity (M) = 0.10 M
Moles (n) = M × Vn = 0.10 × 25/1000n = 0.0025 mol of NaOH
To neutralize NaOH, you need the same number of moles of acetic acid;
1 mol of NaOH reacts with 1 mol of acetic acid0.0025 mol NaOH reacts with 0.0025 mol acetic acid
Concentration of acetic acid = 5%
Mass of acetic acid in 100 ml of solution = 5 g
Density of solution = 1.0 g/ml
Therefore, volume of acetic acid solution that is necessary to neutralize 25.0 ml of 0.10 m
V = (0.0025 mol acetic acid) x (60.05 g acetic acid/1 mol acetic acid) x (1/5 g acetic acid in 100 ml of solution) x (1000 ml/1 L) x (1/1.0 g/ml)
V = 0.30 L of acetic acid solution
V = 300 mL of acetic acid solution (3 significant figures)
Hence, the volume of the acetic acid solution necessary to neutralize 25.0 ml of 0.10 m is 300 mL.
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Directions: Balance the following chemical equations. Descriptions of the equation, physical states, and atoms that are ions (have a
positive or negative charge) have absolutely no effect on balancing. The problems at the very end with a "**" are extremely difficult.
They are far more difficult thaN the problems that will appear on your test of final exam. Give them a try if you like a challenge or have
extra time in class
1) 2 C2H6(g) + 7 O2(g) 4 CO2(g) + 6 H2O(g)
2) 2 NaN3(s) 2 Na(s) + 3 N2(g)
3) 6 Na + Fe2O3 3 Na2O + 2 Fe
4) 3 Mg(s) + N2(g) Mg3N2(s)
5) 2 Na + 2 NH3 2 NaNH2 + H2
6) Na2O + 2 CO2 + H2O 2 NaHCO3
7) P4S3(s) + 6 O2(g) P4O6(g) + 3 SO2(g)
8) 2 Na3PO4 + 3 CaCl2 Ca3(PO4)2 + 6 NaCl
9) 2 C8H18(l) + 25 O2(g) 16 CO2(g) + 18 H2O(g)
10) C2H6O(l) + 3 O2(g) 2 CO2(g) + 3 H2O(g)
11) Pb(NO3)2 + 2 KI PbI2 + 2 KNO3
12) 2 N2O5 4 NO2 + O2
13) 2 KClO3(s) 2 KCl(s) + 3 O2(g)
14) 2 CO(g) + O2(g) 2 CO2(g)
15) 2 C57H110O6(s) + 163 O2(g) 114 CO2(g) + 110 H2O(l)
16) 6 Na + 2 O2 2 Na2O + Na2O217) 2 Al + 3 H2SO4 Al2(SO4)3 + 3 H2
18) 2 C7H10N + 21 O2 14 CO2 + 10 H2O + 2 NO2
19) 2 Al(OH)3 + 3 H2SO4 Al2(SO4)3 + 6 H2O
20) 3 BaO + 14 Al 3 BaAl4 + Al2O3
21) 2 AgN3(s) 3 N2(g) + 2 Ag(s)
22) Pt + 4 HNO3 + 6 HCl H2PtCl6 + 4 NO2 + 4 H2O
23) 2 LuCl3 + 3 Ca 2 Lu + 3 CaCl2
24) XeF6 + 3 H2O XeO3 + 6 HF
25) Ba2XeO6 + 2 H2SO4 2 BaSO4 + 2 H2O + XeO4
26) P4O6 + 6 H2O 4 H3PO3
27) 2 C6H14(l) + 19 O2(g) 12 CO2(g) + 14 H2O(g)
28) 2 MoS2 + 7 O2 2 MoO3 + 4 SO2
**22) 2 K2MnF6 + 4 SbF5 4 KSbF6 + 2 MnF3 + F2
**23) S + 6 HNO3 H2SO4 + 6 NO2 + H2O
**24) 3 Cu + 8 HNO3 3 Cu(NO3)2 + 2 NO + 4 H2O
**25) CuS + 8 HNO3 CuSO4 + 8 NO2 + 4 H2O
**26) Cu2S + 12 HNO3 Cu(NO3)2 + CuSO4 + 10 NO2 + 6 H2O
**27) 5 NaBr + NaBrO3 + 3 H2SO4 3 Br2 + 3 Na2SO4 + 3 H2O
**28) 48 KNO3 + 5 C12H22O11 24 N2 + 36 CO2 + 55 H2O + 24 K2CO3
The chemical equations shown in the question are already balanced. It can be said to be balanced if the number of atoms of each element involved in the reaction is equal to the number of atoms of the same element in the product of the reaction.
The Balancing methodThe Balancing method is used to balance chemical equations. Here are the steps involved in balancing chemical equations:
Step 1: First write down the unbalanced chemical equation.Step 2: Next, start balancing the elements that appear in the equation.Step 3: Begin by adding a coefficient to one of the elements on one side of the equation.Step 4: In order to balance the equation, the coefficient will then have to be added to other elements on the same side of the equation.Step 5: Finally, when the elements on the left and right sides of the equation are equal, then the equation is balanced.The equation is now balanced if the number of atoms of each element in the reactants is equal to the number of atoms of the same element in the products after balancing.learn more about balanced chemical equations
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Nitrogen oxides are pollutants, and common byproducts of power plants and automobiles. NO2 can react with the NO in smog, forming a bond between the N atoms. Draw the structure of the resulting compound, including formal charges. Use this table to predict the energy of the bond in NO. about 200 kJ/mol about 400 kJ/mol about 600 kJ/mol Use the same table to predict the energies of the bonds in NO2. both are about 200 kJ/mol both are about 400 kJ/mol both are about 600 kJ/mol one is about 200 kJ/mol and the other is about 600 kJ/mol *indicates an energy that is an average for that type of bond in several different molecules.
The structure of the resulting compound from the reaction of NO and NO2 is the compound is known as dinitrogen pentoxide, N2O5.The bond energy in NO is about 631 kJ/mol.The bond energies in NO2 are both about 240 kJ/mol.
N2O5 is the chemical formula for dinitrogen pentoxide, often known as nitrogen pentoxide or nitric anhydride. It belongs to the family of chemicals known as binary nitrogen oxides, which simply consists of nitrogen and oxygen. It exists as colourless crystals that sublimate at a temperature just above ambient to produce a colourless gas. Dinitrogen pentoxide, an unstable and potentially harmful oxidant, was originally employed as a reagent for nitrations when dissolved in chloroform, but nitronium tetrafluoroborate has completely replaced it (NO2BF4).
N2O5 is a rare instance of a substance that can change its structure based on the environment. The solid is a salt, nitronium nitrate, consisting of distinct nitronium cations [NO2]+ and nitrate anions [NO3]−; although in the gas phase and under some other situations it is a covalently-bound molecule.
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understand what are the effects when there is low [s], high [s], and when vo is one half of the vmax. biochem]
The effect of low [s] is that the rate of the reaction will decrease and the effect of high [s] is that the rate of the reaction will increase. When Vo is one-half of Vmax, the effect is that the reaction has reached its half-maximum velocity, or that the reaction has reached its maximum efficiency.
The rate of the reaction will decrease in the case of low [s] as the substrate concentration is too low to support the reaction. On the other hand, the rate of reaction will increase in the case of high [s] as there is a greater amount of substrate to drive the reaction.
To understand these effects in a better way, we can use the Michaelis-Menten equation to calculate the rate of reaction at various substrate concentrations (Vo and Vmax) and also the reaction's maximum velocity (Vmax):-
V = Vmax[S]/(Km + [S])
Where Vmax is the maximum velocity of the reaction, Km is the Michaelis constant, and [S] is the concentration of the substrate.
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A certain half-reaction has a standard reduction potential EPod=-0.75 V. An engineer proposes using this half-reaction at the cathode of a galvanic cell that must provide at least 0.90 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the cathode of the cell. Is there a minimum standard reduction potential that the half-reaction used at the anode of this cell can have? Is there a maximum standard reduction potential that the half-reaction used at the anode of this cell can have? By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the anode of this cell. Note: write the half reaction as it would actually occur at the anode.
Using the following formula, the total cell potential, Ecell, may be calculated: Ecathode + anode equals Ecell. where Ecathode is the cathode half-reduction reaction's potential and Eanode.
We can determine the minimal Eanode needed to create a cell potential of 0.90 V since the engineer suggests employing a half-reaction with EPod = -0.75 V at the cathode:
Ecathode + anode equals Ecell.
Eanode: 0.90 V = -0.75 V
Eanode = 0.75 0.90 volts
Eanode equals 1.65 V.
The half-reaction employed at the anode must thus have a standard reduction potential of -1.65 V or less.
The typical reduction potential of the half-reaction utilised at the anode, on the other hand, has no upper limit. Yet, a higher Ecell and a more effective galvanic cell would be produced by a larger reduction potential at the anode.
We can utilise the half-reaction to create a balanced equation for the anode half-reaction:
Cu(s) becomes Cu2+(aq) plus 2e-
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Which stressor causes high concentrations of abscisic acid to travel from the roots to the shoot? a. Drought b. Flooding c. Salinity d. Heavy metal toxicity
a.) The stressor that causes high concentrations of abscisic acid to travel from the roots to the shoot is drought.
An essential element of a plant's reaction to abiotic stress, particularly drought, is played by the hormone abscisic acid (ABA). Drought causes plants to create large amounts of ABA, which is then transferred from the roots to the shoot. Many physiological reactions result from this, including the closing of stomata, which lowers water loss through transpiration, and the activation of genes that encourage the manufacture of proteins that shield cells from dehydration-related cell damage. In addition, ABA causes inhibition of root development, which enables roots to sever deeper layers of soil in quest of water. In general, ABA production and transport play a key role in how plants manage drought stress and keep their water balance.
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what is the mass of potassium nitrate that will dissolve in 25g of water at 20° C?
a. 0.3g
b. 7.5g
c. 4g
d. 25g
e. 30g
Answer:
7.5g is the mass of potassium nitrate that will dissolve in 25g of water at 20° C?
The answer is 4g. At 20° C, the solubility of potassium nitrate in water is 3.7 g per 100 g of water, which means that about 4 g of potassium nitrate will dissolve in 25 g of water.
What is solubility?Solubility is the ability of a substance to dissolve in a liquid or other solvent. It is a measure of the maximum amount of substance that can be dissolved in a given amount of solvent. Solubility can be affected by factors such as temperature, pressure, and the type of solvent used. In general, the more soluble a substance is, the more easily it will dissolve. Solubility is an important factor in the formulation of many products, such as pharmaceuticals, cosmetics, and food products. It is also used in the manufacture of detergents, paints, and inks. Solubility can be determined experimentally, by measuring the amount of a substance that can be dissolved in a given volume of solvent. The solubility of a substance can also be calculated using equations that take into account the temperature and pressure of the system. Understanding solubility is important for determining the effectiveness of drugs, the shelf life of food products, and the environmental impact of certain chemicals.
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n-octane gas (c8h18) is burned with 95 % excess air in a constant pressure burner. the air and fuel enter this burner steadily at standard conditions and the products of combustion leave at 265 0c. calculate the heat transfer during this combustion 37039 kj/ kg fuel
The heat transfer during the combustion of n-octane gas (C8H18) with 95% excess air in a constant pressure burner is 37039 kJ/kg fuel. This is calculated using the enthalpy of the formation of the products and reactants. The air and fuel enter the burner steadily at standard conditions, and the products of combustion leave at 265°C.
The enthalpy of combustion of the fuel is determined by subtracting the enthalpy of formation of the reactants from the enthalpy of formation of the products. The enthalpy of formation of the reactants is determined by multiplying the standard enthalpy of formation for each compound in the reaction by the number of moles of each compound and adding the result.
The enthalpy of formation of the products is determined by multiplying the standard enthalpy of formation for each compound in the reaction by the number of moles of each compound and adding the result. The heat transfer during combustion is then determined by subtracting the enthalpy of formation of the reactants from the enthalpy of formation of the products, resulting in 37039 kJ/kg fuel.
The heat transfer during the combustion of n-octane gas (C8H18) can be calculated using the formula Q = m × Cp × ΔT. Here, m is the mass of the fuel burnt, Cp is the specific heat capacity, and ΔT is the change in temperature. Let's substitute the given values: Mass of fuel burnt = 1 kg (since 37039 kJ/kg fuel is given)Cp of n-octane gas = 2.22 kJ/kg/K (given)ΔT = (265 - 25) = 240 K (since the temperature of products is given as 265°C = 538 K and standard temperature is 25°C = 298 K)Therefore, the heat transfer during combustion of n-octane gas is: Q = m × Cp × ΔT = 1 × 2.22 × 240 = 532.8 kJAnswer: The heat transfer during this combustion is 532.8 kJ.
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Which one of the following compounds is a non-electrolyte when dissolved in water?
Cu(NO3)2
CaCl2
HCl
NaCH3CO2
CCl4
The compound that is a non-electrolyte when dissolved in water is CCl4.
When CCl4 dissolves in water, it does not break down into ions, and it does not conduct electricity.What is an electrolyte?An electrolyte is a compound that dissolves in water, and its solution conducts electricity due to the presence of ions. A compound must dissociate in water to produce ions to be considered an electrolyte. The ions can move freely through the solution, allowing for the conduction of electricity.There are three types of electrolytes: strong electrolytes, weak electrolytes, and nonelectrolytes. Strong electrolytes dissociate fully into ions in water and conduct electricity very efficiently. Weak electrolytes only partially dissociate, and they conduct electricity less efficiently than strong electrolytes.Nonelectrolytes are substances that do not dissolve in water or dissolve but do not dissociate into ions. Because they do not have ions, they do not conduct electricity. CCl4 is a nonelectrolyte, as it does not produce any ions when it dissolves in water.
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Classify each substance as a strong acid, strong base, weak acid, or weak base. Drag the appropriate items to their respective bins NH3 HCOOH KOH CSOH CH3NH2 HF (CH3)2NH HI CH COOH HCIO Strong acids:Weak acids: Strong bases:Weak bases:
The given substances are listed as follows strong acids as HCIO, HI; weak acids as [tex]CH_3COOH[/tex], [tex]CH_3NH_2[/tex], HCOOH, HF; strong bases as KOH, CSOH and weak bases as [tex]NH_3(CH_3)_2NH[/tex].
Substances are classified into four types strong acids, weak acids, strong bases, and weak bases.
Strong acids: Strong acids are acidic substances that have high ionization capacity. These acids are said to be strong acids because they have a pH of less than 7.0. HCl, [tex]H_2SO_4[/tex], and [tex]HNO_3[/tex] are examples of strong acids.Weak acids: Weak acids are acidic substances that have a low ionization capacity. These acids are said to be weak acids because they have a pH of greater than 7.0. [tex]CH_3COOH, CH_3NH_2,[/tex] HCOOH and HF are examples of weak acids.Strong bases: Strong bases are basic substances that have a high degree of ionization capacity. These bases are said to be strong bases because they have a pH of greater than 7.0. NaOH, KOH, and [tex]Ca(OH)_2[/tex] are examples of strong bases.Weak bases: Weak bases are basic substances that have a low degree of ionization capacity. These bases are said to be weak bases because they have a pH of less than 7.0. [tex]NH_3[/tex] and [tex](CH_3)_2NH[/tex] are examples of weak bases.Learn more about strong acids: https://brainly.com/question/30900251
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which chemical does the brain produce that makes people feel good when they exercise?
The chemical that the brain produce that makes people feel good when they exercise is dopamine and endorphins.
What are endorphins?Endorphins are any of a group of peptide hormones found in the brain that act as neurotransmitters and have properties similar to morphine.
A neurotransmitter is any substance, such as acetylcholine or dopamine, responsible for sending nerve signals across a synapse between two neurons.
When you exercise, your body releases chemicals such as dopamine and endorphins in your brain that make you feel happy.
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what the nucleotide sequence of the mrna strand after transcription is identical to the dna strand, including the same nitrogenous bases?
A sense strand is the mRNA strand that is translated from a DNA strand with a same nucleotide sequence. the codons have specific functions when the mRNA sequence is translated into a protein.
The DNA sequence serves as a template for the synthesis of a complementary mRNA molecule during transcription. The nucleotide arrangement of the DNA template strand dictates the sequencing of the mRNA. The mRNA sequence is not identical to the template DNA strand; rather, it is complementary to it. RNA polymerase, which builds the mRNA molecule on the DNA template strand, adds complementary RNA nucleotides to the lengthening mRNA chain. Since RNA nucleotides have uracil (U) as a base instead of thymine (T), the mRNA sequence will have the same nucleotide sequence as the DNA template strand. The mRNA sequence is read in groups of three nucleotides called codons, and the codons have specific functions when the mRNA sequence is translated into a protein.
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Which of the following substances is excreted by sweat glands in response to the break down of proteins and the formation of ammonia?A) waterB) ureaC) lysozymesD) sebum
The correct answer is B) Urea. Urea is a waste product of protein metabolism, and is released from the body through sweat, where the ammonia and other waste products form urea.
What are lysozymes?Lysozymes are enzymes that are naturally produced in most living organisms. They are responsible for helping to break down peptidoglycan, a substance found in the cell walls of various bacteria. This helps to prevent bacterial growth and spread, as well as helping to keep the cells intact. Lysozymes are also known to act as an antimicrobial agent, helping to destroy the cell walls of some types of bacteria.
How sebum is produced?Sebum is an oily substance produced by the sebaceous glands of the skin. The sebaceous gland is located in the hair follicles and it is responsible for secreting the sebum. Sebum production is regulated by hormones and usually occurs when the body needs more moisture (such as during puberty). Sebum can act as a barrier to protect the skin and prevent it from drying out. It helps to keep the skin hydrated, soft and supple. In addition, it helps to reduce bacterial buildup on skin. Sebum is also responsible for giving skin its natural glow.
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which type of atomic orbital can be described as having 2 lobes of electron density separated by a nodal plane?
The type of atomic orbital that can be described as having 2 lobes of electron density separated by a nodal plane is the P orbital.
In atomic theory, an atomic orbital is a mathematical function that describes the behavior of one electron in an atom. It is a region in space with a high probability of locating an electron.
There are 3 types of orbitals available in each sub-shell of an atom. The sub-shell in each shell can be used to predict the number of orbitals.
There are 1 s-orbital, 3 p-orbitals, 5 d-orbitals, and 7 f-orbitals available in the first, second, and third shells, respectively. The type of atomic orbital that can be described as having 2 lobes of electron density separated by a nodal plane is the P orbital.
Each P orbital has two lobes of electrons located on either side of the nucleus separated by a nodal plane. The lobes can be polarized, making them more or less prominent depending on the situation.
This configuration provides the P orbital with a unique geometry and makes it highly suitable for molecular bonding.
The P orbital has a total of three different orientations. Each orientation corresponds to a different direction in space in which the lobes can be located. The three orientations are Px, Py, and Pz.
Each P orbital can hold a maximum of 2 electrons.
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when the carbonyl group of a neutral ketone is protonated . group of answer choices = a.the resulting species becomes more electrophilic.
b. subsequent nucleophilic attack on the resulting species is said to occur under acid-catalyzed conditions.
c. the resulting species is activated toward nucleophilic attack.
d. all of the above.
e. the resulting species has a positive charge.
The correct answer is d All of the above
The protonation of a neutral ketone creates an electrophilic species that is activated toward nucleophilic attack, which is said to occur under acid-catalyzed conditions.
Therefore, All of the above are true: the resulting species becomes more electrophilic, subsequent nucleophilic attack on the resulting species is said to occur under acid-catalyzed conditions, and the resulting species has a positive charge.
Wat is a ketone?A ketone is an organic compound with a carbonyl group (CO) bound to two other carbon atoms.
The chemical formula for a ketone is RCOR′, where R and R′ can be any group from the periodic table.
Ketones are classified as carbonyl compounds since they contain a functional group with a carbon atom double-bonded to an oxygen atom.
When the carbonyl group of a neutral ketone is protonated, the resulting species is activated toward nucleophilic attack.
When the group of a neutral ketone is protonated, the carbonyl carbon atom acquires a partial positive charge, and the oxygen acquires a partial negative charge
As a result, the carbonyl carbon atom becomes more electrophilic than before. The carbonyl group of the resulting species is more prone to nucleophilic attack than it was in the original ketone. The nucleophile can be a negative ion or a lone pair of electrons.
Subsequent nucleophilic attack on the resulting species is said to occur under acid-catalyzed conditions.
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(a) What would you expect the pH of pure water to be?(b) What colour would the universal indicator show in an aqueous solution of sugar? Why?(c) A sample of rain water turned universal indicator paper yellow. What would you expect its pH to be? Is it a strong or a weak acid?
(a) The pH of pure water is 7, which is neutral. (b) The universal indicator would show a yellow color in an aqueous solution of sugar, because sugar is a neutral compound with a pH of 7.(c) The pH of the rain water is likely around 5 or 6, which indicates a weak acid.
pH is less than 7 since yellow color indicates acidic rainwater. Rainwater has an acidic pH because it dissolves atmospheric carbon dioxide (CO2), sulfur dioxide (SO2), and nitrogen oxides (NOx), forming weak carbonic, sulfuric, and nitric acids.
Rainwater that has a pH below 5.6 is considered to be acid rain. Therefore, the acid present in rainwater is a weak acid because the pH of the rainwater is above 1.
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a 25.00 ml monoprotic strong acid solution was titrated with 0.09014 m naoh. 8.781 ml of naoh was required to reach the endpoint of the titration. calculate the number of moles of naoh used in this titration.
The number of moles of NaOH used in this titration of a 25.00 ml monoprotic strong acid solution is 0.0007919 moles.
In order to find out the number of moles of NaOH used in a titration, we can use the formula:
moles of NaOH = concentration of NaOH × volume of NaOH used in titration
Given:Volume of monoprotic strong acid solution = 25.00 mL
Concentration of NaOH = 0.09014 M
Volume of NaOH used in titration = 8.781 mL
We can convert mL to L by dividing it by 1000. So,Volume of monoprotic strong acid solution = 25.00 mL = 25.00/1000 L = 0.02500 L
moles of NaOH = concentration of NaOH × volume of NaOH used in titration= 0.09014 M × 8.781/1000 L= 0.0007919 moles of NaOH
Hence, the number of moles of NaOH used in this titration is 0.0007919 moles.
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