Answer:
TRUE
Explanation:
A suggestion for improving the user experience
for the app navigation, has the following
severity
Usability
Low
Critical
Medium
High
User experience is one of the most important things considered in the modern IT world. Almost 90% of the population is dependent on mobile phones, electronic devices. So, one things that come is app development. Therefore, in order to enhance more growth in app development, there need to better user experience. We need to think about users and i don't Know More info.
Suppose that a minus sign in the input indicates pop the stack and write the return value to standard output, and any other string indicates push the string onto the stack. Further suppose that following input is processed:
this parrot - wouldn't voom - if i put -- four thousand --- volts - through it -
What are the contents (top to bottom) left on the stack?
a. through wouldn't this.
b. this wouldn't through.
c. it through wouldn't.
d. it through volta.
e. volts through it.
Answer:
e. volts through it
Explanation:
volts through it
The contents (top to bottom) left on the stack is volts through it. Thus, option E is correct.
What is standard output?When a computer program begins execution, standard streams are interconnected input and output channels of communication between the program and its surroundings. The three I/O connections are known as standard input (stdin), standard output (stdout), and standard error (stderr).
A negative sign in the input indicates that the stack should be popped, and the return value should be sent to standard output, whereas any other string means that the string should be pushed into the stack. Assume that the following input is processed: this parrot would not voom if I pushed — four thousand —- volts - through it.
The contents of the stack (from top to bottom) are volts via it. As a result, option E is correct.
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Can you debug the following code using the given test code?public class SavingAccount{ // interest rate for all accounts private static double annualInterestRate = 0; private final double savingsBalance; // balance for currrent account // constructor, creates a new account with the specified balance public void SavingAccount( double savingsBalance ) { savingsBalance = savingsBalance; } // end constructor // get monthly interest public void calculateMonthlyInterest() { savingsBalance += savingsBalance * ( annualInterestRate / 12.0 ); } // end method calculateMonthlyInterest // modify interest rate public static void modifyInterestRate( double newRate ) { annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04; } // end method modifyInterestRate // get string representation of SavingAccount public String toString() { return String.format( "$%.2f", savingsBalance ); } // end method toSavingAccountString} // end class SavingAccount Using this test codepublic class SavingAccountTest{ public static void main(String[] args) { SavingAccount s1 = new SavingAccount(400); SavingAccount s2 = new SavingAccount(1000); SavingAccount.modifyInterestRate(0.05); System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s\n", s1, s2); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s\n", s1, s2); SavingAccount.modifyInterestRate(.025); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s\n", s1, s2); }}
Answer:
Explanation:
The reason the code was not working was due to a couple of errors. First, the SavingAccount class needed to be public so that it can be accessed within the same file. Secondly, the savingsBalance variable was set to final and therefore could not be modified, the final keyword needed to be removed. Lastly, the constructor for the SavingAccount class was incorrect. Constructors do not use the keyword void and instance class variables need to be referenced using the this keyword.
class SavingAccount{
// interest rate for all accounts
private static double annualInterestRate = 0;
private double savingsBalance;
public SavingAccount(double savingsBalance) {
this.savingsBalance = savingsBalance;
}
public void calculateMonthlyInterest() {
savingsBalance += savingsBalance * ( annualInterestRate / 12.0 );
}// end method calculateMonthlyInterest
// modify interest rate
public static void modifyInterestRate( double newRate ) {
annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04;
} // end method modifyInterestRate
// get string representation of SavingAccount
public String toString() { return String.format( "$%.2f", savingsBalance );
} // end method toSavingAccountString
}// end class SavingAccount
// Using this test codepublic
//
class SavingAccountTest{
public static void main(String[] args) {
SavingAccount s1 = new SavingAccount(400);
SavingAccount s2 = new SavingAccount(1000);
SavingAccount.modifyInterestRate(0.05);
System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s", s1, s2);
s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s", s1, s2);
SavingAccount.modifyInterestRate(.025);
s1.calculateMonthlyInterest();
s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s", s1, s2); }}
c Write a program that simulates a magic square using 3 one dimensional parallel arrays of integer type. Each one the arrays corresponds to a row of the magic square. The program asks the user to enter the values of the magic square row by row and informs the user if the grid is a magic square or not. flowchart
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
PLEASE HELP ME ASAP!!!!
Write a program that reads in a text file, infile.txt, and prints out all the lines in the file to the screen until it encounters a line with fewer than 4 characters. Once it finds a short line (one with fewer than 4 characters), the program stops. Your program must use readline() to read one line at a time. For your testing you should create a file named infile.txt. Only upload your Python program, I will create my own infile.txt using break
Answer:
Explanation:
f=open("infile.txt","r")
flag=True
while(flag):
s=f.readline().strip()
if(len(s)>=4):
print(s)
else:
flag=False
why the internet is not considered a mass medium in Africa
Answer:
the reason why internet not considered as a mass medium is probably because most of the African are not educated and civilized, thereby making them not common to the usage of the internet.
We can cluster in one dimension as well as in many dimensions. In this problem, we are going to cluster numbers on the real line. The particular numbers (data points) are 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100, i.e., the squares of 1 through 10. We shall use a k-means algorithm, with two clusters. You can verify easily that no matter which two points we choose as the initial centroids, some prefix of the sequence of squares will go into the cluster of the smaller and the remaining suffix goes into the other cluster. As a result, there are only nine different clusterings that can be achieved, ranging from {1}{4,9,...,100} through {1,4,...,81} {100}. We then go through a reclustering phase, where the centroids of the two clusters are recalculated and all points are reassigned to the nearer of the two new centroids. For each of the nine possible clusterings, calculate how many points are reclassified during the reclustering phase. Identify in the list below the pair of initial centroids that results in exactly one point being reclassified.
a) 36 and 64
b) 36 and 100
c) 4 and 16
d) 4 and 81
The list of the pair of initial centroids that results in exactly one point being reclassified is 36 and 64. The correct option is a.
What is the real line?A real axis, or a line with a set scale so that each real number corresponds to a distinct point on the line, is the most popular definition of "real line." The complex plane is a two-dimensional extension of the real line.
A cluster is a collection or grouping of items in a certain place. Mathematicians define a cluster as data accumulating around a single value, specifically a number. On a table or graph, a cluster can be seen visually where the data points are grouped together.
The numbers are 4, 9, 16, 25, 36, 49, 64, 81, and 100. In the real line, it will be 36 and 64.
Therefore, the correct option is a. 36 and 64.
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Write a recursive method named hanoi that prints a solution to the classic Towers of Hanoi puzzle. Your method should accept three integer parameters representing the number of disks, the starting page number, and ending peg number. Your method should print the solution to the game to move from the given start peg to the given end peg. For example, the call of hanoi(3, 1, 3); should print the following output to move the three pegs from peg
Answer:
Explanation:
The following recursive method is written in Java. It creates a simulation of the towers of Hanoi and outputs every step-by-step instruction on how to solve it. The output for the code can be seen in the attached picture below.
class Brainly {
public static String hanoi(int numOfDisks, int startPeg, int endPeg) {
int helpPeg;
String sol1, sol2, MyStep, mysol; // Contains moves
if (numOfDisks == 1) {
return "Move from " + startPeg + " to " + endPeg + "\n";
} else {
helpPeg = 6 - startPeg - endPeg; // Because startPeg + helpPeg + endPeg = 6
sol1 = hanoi(numOfDisks - 1, startPeg, helpPeg);
MyStep = "Move from " + startPeg + " to " + endPeg + "\n";
sol2 = hanoi(numOfDisks - 1, helpPeg, endPeg);
mysol = sol1 + MyStep + sol2; // + = String concatenation !
return mysol;
}
}
public static void main(String[] args) {
String output = hanoi(3, 1, 3);
System.out.println(output);
}
}
spreadsheet formula for total 91?
Answer:
Go to any blank cell. Enter the number 91.
Select the cell that contains 91. Press Ctrl+C to copy.
Select your range the contains numbers.
Press Ctrl+Alt+V to open the Paste Special dialog.
In the top of the Paste Special dialog, choose Values. In the Operation section, choose Add. Click OK.
Explanation:
n
What options are available in the Lookup Wizard? Check all that apply.
label the field
sort the records
filter the records
o adjust the column width
O adjust the header height
reduce the number of columns
Je
set where to get lookup field values
Answer:
Label the field
sort records
adjust the column width
set where to get lookup fields
Explanation:
Write the MIPS assembly code to find the area of a given shape. Your program must take a floating-point value and shape (Circle - 1, Triangle - 2, Square - 3) as input and return the circumference/perimeter and area of the shape. Assume the floating-point value units are meters and the triangle is an equilateral triangle. [Note: you can search for the expression to calculate the area and circumference/perimeter of these shapes]
Answer:
Explanation:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number
syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4
la $a0,msg2 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer
syscall # call operating system to perform read operation
move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi
l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4
la $a0,msg3 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg6
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,eq_tr_area
mul.s $f2,$f0,$f0
mul.s $f2,$f2,$f3
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
ELSE:
bne $t0,3,END
li $v0,4
la $a0,msg10
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,four
mul.s $f3,$f3,$f0
li $v0, 2
mov.s $f12,$f3
syscall
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg11
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
mul.s $f2,$f0,$f0
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
END:
li $v0,10
syscall
Code is as follows:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4 la $a0,msg2 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer syscall # call operating system to perform read operation move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2 mov.s $f12,$f0 #move the single precision f2 in f12 syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4 la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4 la $a0,msg3 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall
bne $t0,3,END #if not 3 then end
li $v0,4 # system call code for printing string = 4
la $a0,msg10 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f0 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,four # multilply by 4
mul.s $f3,$f3,$f0 #calculate 4*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f3 in f12
syscall # call operating system to perform print operation
END:
li $v0,10 # system call code for printing exit (end of program)
syscall # call operating system to perform print operation
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In a spreadsheet what does the following symbol mean?
$
Answer:
$ = dollar sign
Explanation:
In a spreadsheet, the $ symbol is the symbol of the dollar. The dollar is the currency of the United States.
What is currency?Currency is a form of payment for goods and services. In a nutshell, it is money in the form of paper and coins that is usually issued by a government and is generally accepted as a form of payment at face value.
Currency exchange rates differ between businesses because each one distorts the interbank rate to maximize profits. We encounter numerous competitors who post interbank rates internet as bait to attract new customers, but once the customers are onboard, they drastically change the rate, typically not in the customers' favor.
Therefore, the $ symbol represents the dollar in a spreadsheet. The US dollar is the country's currency.
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The given SQL creates a Movie table and inserts some movies. The SELECT statement selects all movies released before January 1, 2000 Modify the SELECT statement to select the title and release date of PG-13 movies that are released after February 1, 2008. Run your solution and verify the result table shows just the titles and release dates for The Dark Knight and Crazy Rich Asians. 3 6 1 CREATE TABLE Movie ( 2 ID INT AUTO_INCREMENT, Title VARCHAR(100), 4 Rating CHAR(5) CHECK (Rating IN ('G', 'PG', 'PG-13', 'R')), 5 ReleaseDate DATE, PRIMARY KEY (ID) 7); 8 9 INSERT INTO Movie (Title, Rating, ReleaseDate) VALUES 19 ('Casablanca', 'PG', '1943-01-23'), 11 ("Bridget Jones's Diary', 'PG-13', '2001-04-13'), 12 ('The Dark Knight', 'PG-13', '2008-07-18'), 13 ("Hidden Figures', 'PG', '2017-01-06'), 14 ('Toy Story', 'G', '1995-11-22'), 15 ("Rocky', 'PG', '1976-11-21'), 16 ('Crazy Rich Asians', 'PG-13', '2018-08-15'); 17 18 -- Modify the SELECT statement: 19 SELECT * 20 FROM Movie 21 WHERE ReleaseDate < '2000-01-01'; 22
Answer:
The modified SQL code is as follows:
SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate > '2008-02-01'
Explanation:
The syntax of an SQL select statement is:
SELECT c1, c2, c...n FROM table WHERE condition-1, AND/OR condition-n
In this query, we are to select only the title and the release date.
So, we have:
SELECT Title, ReleaseDate
The table name is Movie.
So, we have:
SELECT Title, ReleaseDate FROM movie
And the condition for selection is that:
Ratings must be PG-13
And the date must be later than February 1, 2008
This implies that:
Rating = "PG-13"
ReleaseDate > '2008-02-01'
So, the complete query is:
SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate > '2008-02-01'
1) Create a class called Villain. Specifically, a Villain has the following fields: .name (String)
a number of evil plans (int) In addition, a Villain has the following methods: • a constructor that accepts an argument for each of the fields . a copy constructor
an equals method, which checks/returns whether all the fields are the same
a toString method
2) Create a class called Crazy Villain, which inherits from Villain. Specifically, a Crazy Villain has the following additional fields:
a crazy laughter (String)
a crazy idea (String In addition, write code for the following Crazy Villain methods:
a constructor that accepts an argument for each of the fields
a toString method that overrides the Villain toString method, in order to include the additional fields You do not need to instantiate/demo Villain or Crazy Villain objects.
Answer:
Explanation:
The following code is written in Java and creates both of the classes as requested with their variables and methods as needed. The crazyVillain class extends the Villain class and implements and overrides the needed variables and methods. Due to technical reasons, I have added the code as a txt file below.
Which security measure provides protection from IP spoofing?
A ______ provides protection from IP spoofing.
PLEASE HELP I need to finish 2 assignments to pass this school year pleasee im giving my only 30 points please
Answer:
An SSL also provides protection from IP spoofing.
In numerical methods, one source of error occurs when we use an approximation for a mathematical expression that would otherwise be too costly to compute in terms of run-time or memory resources. One routine example is the approximation of infinite series by a finite series that mostly captures the important behavior of the infinite series.
In this problem you will implement an approximation to the exp(x) as represented by the following infinite series,
exp(x) = Infinity n= 0 xn/xn!
Your approximation will be a truncated finite series with N + 1 terms,
exp(x, N) = Infinityn n = 0 xn/xn!
For the first part of this problem, you are given a random real number x and will investigate how well a finite series expansion for exp(x) approximates the infinite series.
Compute exp(x) using a finite series approximation with N E [0, 9] N (i.e. is an integer).
Save the 10 floating point values from your approximation in a numpy array named exp_approx. exp_approx should be of shape (10,) and should be ordered with increasing N (i.e. the first entry of exp_approx should correspond to exp(x, N) when N = 0 and the last entry when N = 9).
Answer:
The function in Python is as follows:
import math
import numpy as np
def exp(x):
mylist = []
for n in range(10):
num = (x**n)/(math.factorial(n))
mylist.append([num])
exp_approx = np.asarray(mylist)
sum = 0
for num in exp_approx:
sum+=num
return sum
Explanation:
The imports the python math module
import math
The imports the python numpy module
import numpy as np
The function begins here
def exp(x):
This creates an empty list
mylist = []
This iterates from 0 to 9
for n in range(10):
This calculates each term of the series
num = (x**n)/(math.factorial(n))
This appends the term to list, mylist
mylist.append([num])
This appends all elements of mylist to numpy array, exp_approx
exp_approx = np.asarray(mylist)
This initializes the sum of the series to 0
sum = 0
This iterates through exp_approx
for num in exp_approx:
This adds all terms of the series
sum+=num
This returns the calculated sum
return sum
Rideshare companies like Uber or Lyft track the x,y coordinates of drivers and customers on a map. If a customer requests a ride, the company's app estimates the minutes until the nearest driver can arrive. Write a method that, given the x and y coordinates of a customer and the three nearest drivers, returns the estimated pickup time. Assume drivers can only drive in the x or y directions (not diagonal), and each mile takes 3.5 minutes to drive. All values are doubles; the coordinates of the user and of the drivers are stored as arrays of length 2. 289222.1780078.qx3zqy7
Answer:
The program in Java is as follows:
import java.util.*;
public class Main{
public static void main (String[]args){
Scanner input = new Scanner(System.in);
double user[] = new double[2]; double dr1[] = new double[2];
double dr2[] = new double[2]; double dr3[] = new double[2];
System.out.print("Enter user coordinates: ");
for(int i =0;i<2;i++){ user[i] = input.nextDouble(); }
System.out.print("Enter driver 1 coordinates: ");
for(int i =0;i<2;i++){ dr1[i] = input.nextDouble(); }
System.out.print("Enter driver 2 coordinates: ");
for(int i =0;i<2;i++){ dr2[i] = input.nextDouble(); }
System.out.print("Enter driver 3 coordinates: ");
for(int i =0;i<2;i++){ dr3[i] = input.nextDouble(); }
double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);
double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);
double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);
System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");
System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");
System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");
}
}
Explanation:
The following array declarations are for the customer and the three drivers
double user[] = new double[2]; double dr1[] = new double[2];
double dr2[] = new double[2]; double dr3[] = new double[2];
This prompts the user for the customer's coordinates
System.out.print("Enter user coordinates: ");
This gets the customer's coordinate
for(int i =0;i<2;i++){ user[i] = input.nextDouble(); }
This prompts the user for the driver 1 coordinates
System.out.print("Enter driver 1 coordinates: ");
This gets the driver 1's coordinate
for(int i =0;i<2;i++){ dr1[i] = input.nextDouble(); }
This prompts the user for the driver 2 coordinates
System.out.print("Enter driver 2 coordinates: ");
This gets the driver 2's coordinate
for(int i =0;i<2;i++){ dr2[i] = input.nextDouble(); }
This prompts the user for the driver 3 coordinates
System.out.print("Enter driver 3 coordinates: ");
This gets the driver 3's coordinate
for(int i =0;i<2;i++){ dr3[i] = input.nextDouble(); }
This calculates the distance between driver 1 and the customer
double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);
This calculates the distance between driver 2 and the customer
double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);
This calculates the distance between driver 3 and the customer
double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);
The following print statements print the estimated pickup time of each driver
System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");
System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");
System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");
Write a function to calculate the distance between two points Distance( x1, y1,x2.2) For example Distance(0.0,3.0, 4.0.0.0) should return 5.0 Use the function in main to loop through reading in pairs of points until the all zeros are entered printing distance with two decimal precision for each pair of points.
For example with input
32 32 54 12
52 56 8 30
44 94 4439 6
5 19 51 91 7.5
89 34 0000
Your output would be:__________.
a. 29.73
b. 51.11
c. 55.00
d. 73.35
e. 92.66
Answer:
The function in Python3 is as follows
def Distance(x1, y1, x2, y2):
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
return dist
Explanation:
This defines the function
def Distance(x1, y1, x2, y2):
This calculates distance
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
This returns the calculated distance to the main method
return dist
The results of the inputs is:
[tex]32, 32, 54, 12 \to 29.73[/tex]
[tex]52,56,8,30 \to 51.11[/tex]
[tex]44,94,44,39\to 55.00[/tex]
[tex]19,51,91,7.5 \to 84.12[/tex]
[tex]89,34,00,00 \to 95.27[/tex]
In c please
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used-times.
b was used - times.
c was used - times .... ...and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array|
| Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]:
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}
Plz answer it’s timed
Answer: the third one
Explanation:
just trust me, the other ones dont mke sense to what I know about the subject, which is a lot
Using a text editor, create a file that contains a list of at least 15 six-digit account numbers. Read in each account number and display whether it is valid. An account number is valid only if the last digit is equal to the remainder when the sum of the first five digits is divided by 10. For example, the number 223355 is valid because the sum of the first five digits is 15, the remainder when 15 is divided by 10 is 5, and the last digit is 5. Write only valid account numbers to an output file, each on its own line. Save the application as ValidateCheckDigits.java.
Answer:
Explanation:
The following code is written in Java. It reads every input and checks to see if it is valid. If it is it writes it to the output file.
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
try {
File myObj = new File("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/input.txt");
Scanner myReader = new Scanner(myObj);
FileWriter myWriter = new FileWriter("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/output.txt");
while (myReader.hasNextLine()) {
String data = myReader.nextLine();
int sum = 0;
for (int x = 0; x < 5; x++ ) {
sum += data.charAt(x);
}
int remainder = (sum % 10);
System.out.println(remainder);
System.out.println(data.charAt(5));
if (remainder == Integer.parseInt(String.valueOf(data.charAt(5)))) {
System.out.println("entered");
try {
myWriter.write(data + "\n");
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
sum = 0;
}
myWriter.close();
myReader.close();
} catch (FileNotFoundException e) {
System.out.println("An error occurred.");
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
When developing an algorithm to solve a problem, which of these steps can help you design the solution for the problem?
Answer:
3 is the answer please mark me brainlist
Explanation:
ok
A "Pythagorean Triple" is a set of integers which will make the sides of a right triangle when used in the calculation of Pythagoras’ Theorem. For example, "3, 4, 5" is a Pythagorean Triple. Write a short "C" function that takes three decimal integers and determines if they are a "Pythagorean Triple". The function should return a boolean which is true if the three numbers fit the pattern, and false otherwise. DO NOT write a "main()" method in this code! [15 pts.]
Answer:
The function in C is as follows:
bool checkPythagoras(int a, int b, int c ){
bool chk = false;
if(a*a == b*b + c*c || b*b == a*a + c*c || c*c == b*b + a*a){
chk = true;
}
return chk;
}
Explanation:
This defines the function. It receives three integer parameters a, b and c
bool checkPythagoras(int a, int b, int c ){
This initializes the return value to false
bool chk = false;
This checks if the three integers are Pythagorean Triple
if(a*a == b*b + c*c || b*b == a*a + c*c || c*c == b*b + a*a){
If yes, the return value is updated to true
chk = true;
}
This returns true or false
return chk;
}
PLEASE HELP ME ASAP!!!!
First party insurance: Loss due to laptop theft, loss due to interruption in business activities due to website failure
Third party insurance: cost of lawsuits filed against the policyholder, fees of a special programmer investigating a cyber fraud, expenses of providing notifications of the cyber attack to clients and employees
Use at Least one hundred words to explain what you did the last time your handheld personal computer went slow.
Answer:
Disk defragmentation
clear up storage
restart the computer
Explanation:
PC's going slow is a very common occurence nowadays and what i had to do to usually fix slow computers is to first use disk defragmentation which will automatically sort our files and put them in the right order.Second is to delete any unnessary files,folders,programs that i no longer use or its just sitting there eating dust and finally my last resort is to restart the pc which usually helps fix most of the issues including slow PCs which might be caused by some errors during startup.
Hope this helped
Java 2D Drawing Application. The application will contain the following elements:
a) an Undo button to undo the last shape drawn.
b) a Clear button to clear all shapes from the drawing.
c) a combo box for selecting the shape to draw, a line, oval, or rectangle.
d) a checkbox which specifies if the shape should be filled or unfilled.
e) a checkbox to specify whether to paint using a gradient.
f) two JButtons that each show a JColorChooser dialog to allow the user to choose the first and second color in the gradient.
g) a text field for entering the Stroke width.
h) a text field for entering the Stroke dash length.
I) a checkbox for specifying whether to draw a dashed or solid line.
j) a JPanel on which the shapes are drawn.
k) a status bar JLabel at the bottom of the frame that displays the current location of the mouse on the draw panel.
If the user selects to draw with a gradient, set the Paint on the shape to be a gradient of the two colors chosen by the user. If the user does not chosen to draw with a gradient, the Paint with a solid color of the 1st Color.
Note: When dragging the mouse to create a new shape, the shape should be drawn as the mouse is dragged.
Answer:
sadness and depression is my answer
Explanation:
The speed density fuel injection system uses the blank sensor as the primary sensor as the primary sensor to determine base pulse width
A. Map
B TP
C Maf
D baro
Answer:
A) Map
Explanation:
All gasoline (petrol) fuel systems need ways or method that will be calculating amount of the air that is entering the engine.This is true as regards mechanical fuel injection, carburetors and electronic fuel injection.Speed density system fall under one of this method. "Speed" in this context means the speed of the engine while "density" means density of the air. The Speed is been measured using the distributor, crankshaft position sensor could be used here. The Density emerge from from measuring of the air pressure which is inside the induction system, using a typical "manifold absolute pressure" (MAP) sensor as well as air temperature sensor. Using pieces of information above, we can calculate
mass flow rate of air entering the engine as well as the correct amount of fuel can be supplied. With this system,
the mass of air can be calculated. One of the drawback if this system is that
Any modification will result to incorrect calculations. Speed-Density can be regarded as method use in estimation of airflow into an engine so that appropriate amount of fuel can be supplied as well as. adequate spark timing. The logic behind Speed-Density is to give prediction of the amount of air ingested by an engine accurately during the induction stroke. Then this information could now be used in calculating how much fuel is required to be provided, This information as well can be used in determining appropriate amount of ignition advance. It should be noted The speed density fuel injection system uses the Map sensor as the primary sensor to determine base pulse width
First one who answers gets brainiest
Answer:
thank for the point anyway
Ill give alot of points if you answer: How do I get a 100 dollar ps4