need help with this question, please

Given:

The expression is:

[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)[/tex]

To find:

The missing values in the simplification of the given expression.

Solution:

We have,

[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)[/tex]

Combining like terms, we get

[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\left(\dfrac{6}{17}t+\dfrac{7}{17}t\right)+\left(-6+9\right)[/tex]

[tex]\left(\dfrac{6}{17}t-6\right)+\left(\dfrac{7}{17}t+9\right)=\dfrac{13}{17}t+3[/tex]

Therefore, the missing values for 1,2,3,4 blanks are [tex]\dfrac{6}{17}t,9,\dfrac{13}{17},3[/tex] respectively.

Is a plain the result of constructive forces, destructive forces, or both?

help pls ill give brainliest!

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screenshotted question under the cut

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screenshot down below

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help me with this question

plz help me this is over due but i just cant do it.
It's Translations and Reflections.
(40 points)

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