Slope of I-V graph is Resistance.
Its S.I. unit is Ohm.
The symbol of ohm is Ω.
why does a desert cooler cool better than a hot dry day
On a hot dry day, the amount of water vapour present in atmosphere is less. Thus, water present inside the desert cooler evaporates more, thereby cooling the surroundings more. Hence, a desert cooler cools better on a hot dry day.
While visiting the beach, you enjoy the warm ocean water, but the sand burns your feet. That night you walk along the beach and notice that the sand is colder than the ocean water. Why?
Group of answer choices
It takes a long time for sand to heat up, but it cools down very quickly. Water takes a short time to heat up and cool down.
Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.
Water is naturally colder than sand.
Sand is naturally colder than water.
The answer would be B..
Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.
Your parallel capacitors are 15 μf and 20 μf. The series capacitors are 10 μf and 12 μf. This circuit is connected to a 14 v battery, also determine the potential energy and the voltage across each capacitor
Answer:
a. i. 6.608 V ii. 5.507 V iii. 1.89 V iv. 1.89 V
b. i. 0.22 mJ ii. 0.182 mJ iii. 0.027 mJ iv. 0.036 mJ
Explanation:
a. The voltage across each capacitor
Since the 15 μf and 20 μf capacitors are in parallel, their total capacitance is C = 15 μf + 20 μf = 35 μf.
Also, since C is in series with the 10 μf and 12 μf which are in series, their total capacitance, C' is gotten from 1/C' = 1/10 μf + 1/12 μf + 1/35 μf
1/C' = (12 + 42 + 35)/420 /μf
1/C' = 89/420 /μf
C' = 420/89 μf
C' = 4.72 μf
The total charge in the circuit' is thus Q = C'V where V = voltage = 14 V
So, Q = C'V = 4.72 μf × 14 V = 66.08 μC
Since the 10 μf and 12 μf are in series, Q is the charge flowing through them.
Since Q = CV and V = Q/C
i. The voltage across the 10 capacitor is
V = 66.08 μC/10 μF = 6.608 V
ii. The voltage across the 12 capacitor is
V = 66.08 μC/12 μF = 5.507 V
The voltage across the 15 μF and 20 μF capacitors.
Since the capacitors are in parallel, the voltage across them is the voltage across their combined capacitance, C
So, V = Q/C = 66.08 μC/35 μF = 1.89 V
iii. The voltage across the 15 μF capacitor is 1.89 V
iv. The voltage across the 20 μF capacitor is 1.89 V
b. The potential energy of each capacitor
i. The potential energy of the 10 μF capacitor
E = 1/2CV² where C = Capacitance = 10 μF = 10 × 10⁻⁶ F and V = voltage across capacitor = 6.608 V
E = 1/2CV²
E = 1/2 × 10 × 10⁻⁶ F(6.608 V)²
E = 5 × 10⁻⁶ F(43.666) V²
E = 218.33 × 10⁻⁶ J
E = 0.21833 × 10⁻³ J
E = 0.21833 mJ
E ≅ 0.22 mJ
ii. The potential energy of the 12 μF capacitor
E = 1/2CV² where C = Capacitance = 12 μF = 12 × 10⁻⁶ F and V = voltage across capacitor = 5.507 V
E = 1/2CV²
E = 1/2 × 12 × 10⁻⁶ F(5.507 V)²
E = 6 × 10⁻⁶ F(30.327) V²
E = 181.96 × 10⁻⁶ J
E = 0.18196 × 10⁻³ J
E = 0.18196 mJ
E ≅ 0.182 mJ
iii. The potential energy of the 15 μF capacitor
E = 1/2CV² where C = Capacitance = 15 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V
E = 1/2CV²
E = 1/2 × 15 × 10⁻⁶ F(1.89 V)²
E = 7.5 × 10⁻⁶ F(3.5721) V²
E = 26.79 × 10⁻⁶ J
E = 0.02679 × 10⁻³ J
E = 0.02679 mJ
E ≅ 0.027 mJ
iv. The potential energy of the 15 μF capacitor
E = 1/2CV² where C = Capacitance = 20 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V
E = 1/2CV²
E = 1/2 × 20 × 10⁻⁶ F(1.89 V)²
E = 10 × 10⁻⁶ F(3.5721) V²
E = 35.721 × 10⁻⁶ J
E = 0.035721 × 10⁻³ J
E = 0.035721 mJ
E ≅ 0.036 mJ
A train travelling at 20m/s accelerate at 0.5m/s2 for 30 seconds. How far will it travel in this time?
Answer:
825m
Explanation:
u=20m/s
a=0.5m/(s)^2
s = ut + 1/2a(t)^2
s = 20(30) + 1/2(0.5)(30)^2
s = 600 + 225
s = 825m
Answer:
as we know that
S=ut+1/2(at*t)
S=20*30+1/2(0.5*30*30)
S=600+225
S=825
what do you think will happen to the people in the airplane if their location is unknown?
Question:
What do you think will happen to the people in the airplane if their location is unknown?
My opinion:
I mean what are the circumstances? Is it just a rogue pilot that takes a random plane with all the passengers Hostage or is It bad whether an they lose connection to the airport? I Mean either way, If I was on a plane being held hostage, or the plane crashing, I Would be a in a panic type state of mind. I Would be worried about what will happen when the plane crashes, I would worry about my friends or family that is aboard the plane with me, I Would be scared for my life because I Don't know if i would make it out alive.
Also:
How would they know their location is unknown wouldn't the Pilot be the only one to know exactly where there with their navigating system, But then again there was this time I headed to Florida an They had mini tv's on the seats of each chair, where you could: Watch movies, listen to music, an Also see exactly where you are in the world. It was really amazing actually.
The electric potential energy of an electric dipole is ______ when the dipole is aligned with an electric field. The electric potential energy of an electric dipole is ______ when the dipole is aligned with an electric field. most positive most negative zero infinite undefined
Answer:
Most negative
Explanation:
The electric potential energy of a dipole U = -pEcosθ where p = dipole moment, E = electric field and θ = angle between p and E.
When the electric dipole is aligned with the electric field, the angle between p and E is 0°. That is θ = 0°.
So, U = -pEcosθ
U = -pEcos0°
U = -pE
which is the most negative value it can have.
So, the electric potential energy of an electric dipole is most negative when the dipole is aligned with an electric field.
So, most negative is the answer.
A stream leaving a mountain range deposits a large part of its load in a __
Answer:
(n) alluvial fan sandbar
Explanation:
1.The distance moved by objects in a given interval of time can help us to decide which one is faster or slower. Do you agree with this statement?
Answer:
The rate of change of distance is defined as speed.
Explanation:
The speed is defined as the rate of change of distance.
Speed = distance/ time
When we know the distance and the time, we get the value of speed. So, e know that who is moving fast or slow.
hen a graph is pltted beteen the distance and time, the slope of the graph gives the value of speed. So, by checking the slopes, hoseslope ismore, the speed is more and thusit is moving faster.
So, i agree with the statement.
A water wave passes by a floating leaf that is made to oscillate up and down two complete cycles each second, which means that the wave's frequency is
Answer:
2 Hz.
Explanation:
Frequency is simply defined as the number of appearances of a periodic event occurring per time. It is usually measured in cycles/second.
Now, in this question, we are told that there are 2 cycles for each second.
Thus, we can say that the frequency is 2 cycles/1 s = 2 Hz.
Refer to the periodic table above a student is asked
Answer:
there is no context??????
An electrostatic paint sprayer has a 0.17 m-diameter metal sphere at a potential of 25.0 kV that repels charged paint droplets onto the object to be painted, which is grounded (electric potential of 0).
Answer:
[tex]q=0.236uC[/tex]
Explanation:
From the question we are told that:
Diameter [tex]d=0.17m[/tex]
Radius [tex]r=0.17/2=>0.085[/tex]
Potential [tex]E=25.0kV[/tex]
Generally the equation for Potential on spere is mathematically given by
[tex]E=\frac{1}{4 \pi e_0}*\frac{q}{r}[/tex]
Therefore
[tex]q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}[/tex]
Where
[tex]\frac{1}{4 \pi e_0}=9*10^9[/tex]
Therefore
[tex]q=\frac{25*10^3*0.085}{(9*10^9}}[/tex]
[tex]q=0.236uC[/tex]
(e) Find the height and orbital velocity of the geostationary satellite above the earth assuming earth as a sphere of radius 6370 km. [Radius of earth, R = 6370km, Acceleration due to gravity
= 10ms)
Answer:
I don't really know this one trust me am not lieing
A student sects a leaf of length 7.2 cm to draw. Her drawing is 28.8 cm in length. What is the magnification of the drawing?
a) x4
b) x207.36
c) x0.25
d) x36
Answer:
A) x4
Explanation:
Magnification is equal to image size divided by the actual size, or M = I/A.
The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:
28.8 cm/7.2 cm = 4
Which statement best describes how pigments affect what colors humans
see?
Answer:
the component of light reflected by that object
Explanation:
find the x component of a vector of 105 km/h at an angle of 25 degrees.
Answer:
Explanation:
First I converted the km/h to m/s, which is the more common unit for velocity. In m/s, 105 km/h is 29.2. Thus, to find the x component of the vector:
29.2cos25 = 26 m/s
If you want it in km/h:
105cos25 = 95 km/h
A hamster in it's ball starts at rest and accelerates to 3ms1 in 6 seconds.
What was the distance the hamster travelled
Answer:9m
Explanation:
Ball starts from rest . Time taken = 6 seconds. Distance travelled by ball. ∴Distance travelled = 9 m
Hope it helps you
Good luck
A small car increases its speed from 10 m/s to 15 m/s. Its mass is 1,200 kg. What is the impulse?
A. 6,000 kg-m/s
B. 18,000 kg-m/s
C. 12,000 kg.m/s
D. 1,200 kg-m/s
Answer:
A
Explanation:
We know that impulse(J) is the force times the change in time OR mass times the change in velocity. Because we're given mass and a final and initial velocity, we'll use the second option written as:
mΔv=J
Since Δ means change in, and Δv= vf-vi, we subtract 10 m/s from 15 m/s to get 5 m/s for Δv.
Now plugging in Δv and m(1,200 kg)
1,200 kg * 5 m/s =J
6000 kg* m/s = J
Show that the path followed by a projected horizontally frop top of the tower with uniform speed is a parabola .
Answer:
Explained below.
Explanation:
Let the initial velocity from the top of the tower of height(h) be u'
Now, since it is projected horizontally, the horizontal distance covered will be due to having a uniform horizontal velocity (u) while it will possess a vertical distance in the downward direction due to constant acceleration due to gravity (g).
If the time it takes the ball to reach the ground is "t", then we can say the horizontal distance travelled by the ball is denoted as; x(t) = x, while the vertical distance is denoted by; y(t) = y
Now, since it's a projectile the intial velocity (u) will have vertical and horizontal components which are;
u_y and u_x respectively.
Applying kinematic equations, we have;
x = u_x•t + ½at²
Acceleration is zero in the horizontal x direction. Thus;
x = u_x•t
For the vertical y-direction;
y = u_y•t + ½at²
Here since direction is in that of gravity, then a = g.
Also, since the initial velocity has no downward component, then u_y = 0 m/s
Thus;
y = ½gt²
From x = u_x•t, we have;
t = x/u_x
Thus;
y = ½g(x/u_x)²
y = ½gx²/(u_x)²
Let g/(u_x)² be treated as a constant with the letter k.
Thus;
y = kx²
This is the form of a parabolic equation.
Thus, it has been proved that the projectile follows the path of a parabola.
Imagine you see Mars rising in the east at 6:30 pm. Six hours later what direction would you face (look) to see Mars when it is highest in the sky
Answer:
The Mars appears in the direction of South.
Explanation:
Mars is rising in the east at 6: 30 PM. The period of rotation of earth is 24 hours.
So, 6 hours is the one fourth of the period of rotation of earth. Earth rotates counter clockwise on its axis, so after 6 hours, we see the Mars in the direction of South.
Two parallel conducting plates are separated by 12.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude of the electric field strength between them, if the potential 5.6 cm from the zero volt plate is 450 V
Answer:
-8.036 kV/m
Explanation:
The electric field E = -ΔV/Δx where ΔV = change in electric potential = V - V' where V = electric potential at x = 5.6 cm = 450 V and V' = electric potential at x = 0 cm, = 0 V . So, ΔV = V - V' = 450 V - 0 V = 450 V.
Δx = distance between the 0 V plate and the 450 V point = 5.6 cm = 0.056 m
So, E = -ΔV/Δx
Substituting the values of the variables into the equation, we have
E = -ΔV/Δx
E = -450 V/0.056 m
E = -8035.7 V/m
E = -8.0357 kV/m
E ≅ -8.036 kV/m
Since the electric field between two parallel conducting plates is constant, the electric field between the plates is E = -8.036 kV/m
Help Meeeeeeeee. Have a nice day:)
Answer:
01.
Explanation:
Half the acceleration. Its heavier and moves slower. If it moved the same acceleration, the forces would also have to be doubled since the mass was.
1. Priya is responsible for collecting canned food along three different streets for her school's
annual Thanksgiving Food
Drive. She walks 300 m [N] along Oak Road, 500 m [E] along
Second Street, and then 150 m (S45°W) along Cross Ave. She completes the journey in 10
minutes
a. Draw a scale diagram of her trip.
b. Calculate her total distance, displacement, speed, and velocity.
Answer:
distance = 950 m
displacement = 439.2 m
speed= 1.58 m/s
velocity = 0.732 m/s
Explanation:
A = 300 m North
B = 500 m East
C = 150 m South west
Time, t = 10 minutes = 600 s
(A) The diagram is given below.
(B) Total distance = 300+ 500 + 150 = 950 m
[tex]A = 300 \widehat{j} \\\\B = 500\widehat{i}\\\\C = - 150 (cos 45 i+ sin 45 j) = - 106 \widehat{i} - 106 \widehat{j}\\\\D = A + B + C \\\\D = 394 \widehat{i} + 194 \widehat{j}\\\\D=\sqrt{394^2 +194^2} = 439.2 m[/tex]
Speed = distance / time = 950/600 = 1.58 m/s
velocity = 439.2 / 600 = 0.732 m/s
Question 5 of 10
A 15 N force is applied to an object, which then accelerates at 5.0 m/s2. What
is the mass of the object?
A. 10 kg
B. 20 kg
C. 75 kg
D. 3.0 kg
Hi there!
[tex]\large\boxed{D. \text{ } 3.0 kg}}[/tex]
Use the following equation to solve:
F = ma, where:
F = Force (N)
m = mass (kg)
a = acceleration (m/s²)
Thus:
15 = 5m
15/5 = m
mass = 3 kg
Priya is responsible for collecting canned food along three different streets for her school's annual Thanksgiving Food Drive. She walks 300 m [N] along Oak Road, 500 m [E] along Second Street, and then 150 m [S45°W] along Cross Ave. She completes the journey in 10 minutes.Calculate her total distance, displacement, speed, and velocity.
As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.
To calculate Priya's total distance:
Total distance = 300 m + 500 m + 150 m = 950 m
So, Priya's total distance traveled is 950 meters.
To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.
Displacement = √((Δx)² + (Δy)²)
For Δx:
Δx = 500 m - 150 m × cos(45°)
Δx = 500 m - 150 m × 0.707
Δx = 500 m - 106.05 m
Δx = 393.95 m
For Δy:
Δy = 150 m × sin(45°)
Δy = 150 m × 0.707
Δy = 106.05 m
Displacement = √((393.95 m)² + (106.05 m)²)
Displacement ≈ 410.52 m
So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.
To calculate Priya's speed, we use the formula:
Speed = Total distance ÷ Time
Speed = 950 m ÷ 10 min
Speed = 95 m/min
So, Priya's speed is 95 meters per minute.
To calculate Priya's velocity:
Velocity = Displacement ÷ Time
Velocity = 410.52 m ÷ 10 min
Velocity = 41.05 m/min
Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.
For more details regarding velocity, visit:
https://brainly.com/question/34025828
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A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will be independent of
Answer:
We know that for a pendulum of length L, the period (time for a complete swing) is defined as:
T = 2*pi*√(L/g)
where:
pi = 3.14
L = length of the pendulum
g = gravitational acceleration = 9.8 m/s^2
Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.
Then the period is independent of:
The mass of the child
The initial angle
Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.
Which of these would have the greatest pressure?
Group of answer choices
A large balloon with few gas molecules at a high temperature
A small balloon with many gas molecules at a low temperature
A small balloon with many gas molecules at a high temperature
A large balloon with few gas molecules at a low temperature
If the universe is infinite, then how come there are things disappearing from the horizon? I was at a point in this video (TRUE Limits Of Humanity from Kurzgesagt) about true limits of humanity, and the narrator mentioned that (04:12) "...there is a cosmological horizon around us. Everything beyond it, is traveling faster, relative to us, than the speed of light. So everything that passes the horizon is irretrievably out of reach forever and we will never be able to interact with it again." Are they talking about how galaxies passing the horizon are physically absent, or just visually aren't there and we are unable to interact with them?
Answer:
The big rip theory
Explanation:
I believe what you are referring to is the big rip theory, in which the universe expands faster than the speed of light Kurzgesagt refers to it as a "horizon" but in reality it's a little more complicated than that. Eventually the expansion of the universe will accelerate far beyond the speed of light creating space between molecules until eventually all matter is fleeting and the entire universe is an endlessly vast cosmic void with not but the occasion molecule left from a time when things weren't so lonely.
an object that has lost its electrons become?
Please help me. Please help me.
Answer:
Make a nice powerpoint and think about the question
Explanation:
Its easier than you think :)
The Sun is an enormous ball of gas. Left to itself, a ball of so many atoms should collapse under its own tremendous gravity. Why is our Sun not collapsing
Answer:
Nuclear fusion in the Sun's core causes the release of tremendous amounts of energy that leads to very high temperatures and pressure which is much hotter and higher than the temperature and pressure at the exterior surface of the Sun causing the particles in the inner core region to push outwards towards the Sun's surface
Explanation: