Name something that you cannot find when looking at a box and whisker plot

Answer:

105

Multiples of 35:
35, 70, 105, 140, 175

Multiples of 21:
21, 42, 63, 84, 105, 126, 147

Answer:

105

Step-by-step explanation:

Given the following question:

We are given two numbers and we are trying to find the least common multiple (LCM) of the two. In order to find the LCM we have to find the GCM or the greatest common multiple.

[tex]35\div7=5[/tex]
[tex]21\div7=3[/tex]
[tex]GCM=7[/tex]

Now that we have the GCM we multiply 35, and 21 then divide it by the GCM.

[tex]35\times21=735[/tex]
[tex]735\div7=105[/tex]
[tex]LCM=105[/tex]

The least common multiple is "105."

Hope this helps.

The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)

The points are given as:

G = (-4,3)

H = (-1,-4)

Ratio, m : n = 3 : 2

The coordinate of the point is calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]

Evaluate the product

(x,y) = (-2.2, -1.2)

Hence, the coordinate of the point is (-2.2, -1.2)

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Answer:

[tex] 4x^2y\sqrt[4]{3y} [/tex]

Step-by-step explanation:

[tex] \sqrt[4]{768x^8y^5} = [/tex]

[tex] = \sqrt[4]{256 \times 3(x^2)^4y^4y} [/tex]

[tex] = \sqrt[4]{4^4 \times 3(x^2)^4y^4y} [/tex]

[tex] = 4x^2y\sqrt[4]{3y} [/tex]

Answer:

a)  1 cupcake = $5.50

b)  1 Popsicle = $3.50

Step-by-step explanation:

Let s = cost of one soda

Let c = cost of one cupcake

Let p = cost of one Popsicle

From the given information we can create 3 equations:

Subtract Equation 1 from Equation 2 to eliminate the variable s:

    s + 3c + 3p = 40

-        s + c + p = 22

          2c + 2p = 18

Substitute Equation 3 into this new equation and solve for p:

⇒ 2c + 2p = 18

⇒ 2(p + 2) + 2p = 18

⇒ 2p + 4 + 2p = 18

⇒ 4p = 14

⇒ p = 3.5

Substitute the found value of p into Equation 3 and solve for c:

⇒ c = p + 2

⇒ c = 3.5 + 2

⇒ c = 5.5

To find the cost of a soda (s), substitute the found values of p and c into Equation 1:

⇒ s + c + p = 22

⇒ s + 5.5 + 3.5 = 22

⇒ s = 13

Therefore,

Answer:

  B.  0.95

Step-by-step explanation:

The probability that the value of the random variable is in the given range is the area under the normal probability distribution curve over that range. The value of this area is conveniently provided by any number of calculators, apps, or spreadsheets. It can also be determined using the "empirical rule" that tells you the probability over certain normalized ranges.

__

A standard normal probability density function (PDF) has a mean of 0 and a standard deviation of 1. The range in this problem can be normalized to some number of standard deviations above or below the mean. The mean is given as 46, and the standard deviation is given as 22.

In this problem, the lower limit of the range is ...

  z = (2 -46)/22 = -2

standard deviations from the mean.

Similarly, the upper limit is ...

  z = (90 -46)/22 = +2

standard deviations from the mean.

The empirical rule tells us that 95% of the area of the PDF lies between -2 and +2 standard deviations from the mean.

  P(2 < X < 90) ≈ 0.95

_____

Additional comment

The empirical rule for other ranges is ...

  ± 1 standard deviation: 68%

  ±2 standard deviations: 95%

  ±3 standard deviations: 99.7%

Answer:

x= 0.21428571428 or x=0.2

Step-by-step explanation:

-7x+7x^2=9  1. simplify 7x^2

-7x+ 7x(7x)=9   2. combine like terms

-7x+49x=9    3. combine like terms

42x=9           4. /42 on both sides

x= 0.21428571428 or x=0.2

Parameterize S by the vector function

[tex]\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle[/tex]

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

[tex]\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle[/tex]

The integral of the field over S is then

[tex]\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}[/tex]

Answer:

-1/5

Step-by-step explanation:

To find the slope, the formula is y2-y1/x2-x1

1-2/3-(-2) = -1/5

Answer:

Step-by-step explanation:

hope this helps!!!!

Answer:

2(7x-4) = 7x(2)-4(2) = 14x-8

but

(7x-4)^2 = (7x-4) (7x-4)

Answer:

290

Step-by-step explanation:

Formula :

Number of action figures on wall = Total number of figures × % of figures on wall

=============================================================

Given :

⇒ Total number of action figures = 500

⇒ % of action figures on wall = 58%

=============================================================

Solving :

⇒ Action figures on wall = 500 × 58%

⇒ Action figures on wall = 500 × 58/100 (all % are ratios of 100%)

⇒ Action figures on wall = 5 × 58

⇒ Action figures on wall = 290

Total action figures

Done!

Answer:

213.75

Step-by-step explanation:

95×9=855

855÷4=213.75

Answer:

See below

Step-by-step explanation:

Each 32 feet of depth is 1 more atmosphere of pressure on the diver  

The approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

The missing part of the question is represented by the following function:

[tex]T(h) = \frac{386 + 110h}{h}[/tex]

10:00 a.m is 3 hours after 7:00 am and 1:00 p.m is 6 hours after 7:00 am.

This means that:

h = 3 at 10:00 am

h = 6 at 1:00 pm

Next, we calculate T(3) and T(6)

[tex]T(3) = \frac{386 + 110*3}{3} =238.7[/tex]

[tex]T(6) = \frac{386 + 110*6}{6} =174.3[/tex]

The average rate of change is then calculated as:

[tex]T'(h) = \frac{T(3) - T(6)}{3 - 6}[/tex]

This gives

[tex]T'(h) = \frac{238.7 - 174.3}{-3}\\[/tex]

Evaluate

T'(h) = -21

This means that the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

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Answer:

y= -1/2x+5

Step-by-step explanation:

Answer:

height = 7

Step-by-step explanation:

[tex]2\cdot\frac{42}{8.7 + 3.3} = 7[/tex]

The rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

The function is given as:

d = √216 +h²

At a distance of 100 feet, it means that:

d = 100

So, we have:

√216 +h² = 100

Take the square of both sides

216 +h² = 10000

Subtract 216 from both sides

h²= 9784

Take the square root of both sides

h = 98.9

Hence, the rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

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Answer:

What is the value of x in the equation?

Step-by-step explanation:

Answer:

x > 8

Step-by-step explanation:

14 - 2(x + 1) < - 4 ← distribute parenthesis and simplify left side

14 - 2x - 2 < - 4

12 - 2x < - 4 ( subtract 12 from both sides )

- 2x < - 16

divide both sides by - 2 , reversing the symbol as a result of dividing by a negative quantity.

x > 8

Answer:

7

Step-by-step explanation:

[tex]\dfrac 13(15+6)\\\\\\=\dfrac{21}3\\\\\\=7[/tex]

Answer:

4×(x+1)(3x-8)(x+4)= (4x²+4)(3x-8)(x+4)= (12x³-32x²+12x²-32)(x+4)= (12x³-20x²-32)(x+4)= 12x⁴+48x³-20x³-80x²-32x²-128x= 12x⁴+28x³-112x²-128x

Answer: See the screenshots below

I'm answering in this format because the questions aren't numbered, so its hard to reference them consistently (so we're both on the same page).

All decimal values are approximate. I decided to round to 4 decimal places, but feel free to use another level of precision.

Answer: y=2x+7

(this is a rearranged version of y-2x=7 from question)

Step-by-step explanation:

4x=5-2y

y-2x=7

i would rearrange the 2nd value into y intercept form y=mx+b

so move the -2x to the other side of the = sign by doing the opposite, +2x on both sides to isolate the y

y=2x+7

you didn't give any options for "correct answer" so i can't give

you A B C or D answers

Answer:

16 square units

Step-by-step explanation:

16 square units

Answer: The awnser is linear.

I hope this helped.

Step-by-step explanation:

Answer:

Slope is undefined.

Step-by-step explanation:

Answer:

[tex]\textsf{A)} \quad 5u^3-2u^2+5u+8[/tex]

Step-by-step explanation:

Given expression:

[tex](-2u^3+5u-1)+(7u^3-2u^2+9)[/tex]

Remove parentheses:

[tex]\implies -2u^3+5u-1+7u^3-2u^2+9[/tex]

Collect like terms:

[tex]\implies -2u^3+7u^3-2u^2+5u-1+9[/tex]

Combine like terms:

[tex]\implies 5u^3-2u^2+5u+8[/tex]

Option A

The equation for the relationship between the thickness and number of weeks is y = 3.8 - 0.2x

Ice lost at 7 weeks = 7(0.2) = 1.4 meters

Total thickness of ice before loss = Ice remaining after 7 weeks + Ice lost at 7 weeks

= 2.4 + 1.4

= 3.8 meters

The equation:

y = Total thickness of ice before loss - (Ice lost per week × Number of weeks)

= 3.8 - (0.2 × x)

y = 3.8 - 0.2x

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Answer:

[tex]\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]
[tex]\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}[/tex]
[tex]\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}[/tex]
[tex]-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]

Answer:

3x-3

Step-by-step explanation:

use synthetic division