Multiple Choice
Which option identifies why the engineer should choose the reverse engineering process in the following scenario?
A client has contacted an engineer to determine why a product is not selling. It is up to the engineer to gather information and reconfigure the product by using the most strategic process.


The client wants a functional analysis of the product.

There will be changes to the existing product.

The client will be comparing the product to its competition.

The client wants a brand new product designed

Answer:                      

Explanation:

Answer:

Resistance = 3 Ω

Explanation:

As we know that, By Ohm's Law

V = IR

where

V is the voltage in volt

I is the current in amps

R is the resistance in ohm

Now,

Given that,

V = 15 volts

I = 5 amps

So,

R = V/I

  = 15/5

 = 3 Ω

⇒R = 3 Ω

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

[tex]A_1 \ and \ A_2[/tex]

Thus, using the summation rule, the view factor [tex]F_{11[/tex] and [tex]F_{12[/tex] is as follows:

[tex]F_{11}+F_{12}=1[/tex]

Let assume the surface (1) is flat, the [tex]F_{11} = 0[/tex]

Now:

[tex]0+F_{12}=1[/tex]

[tex]F_{12}=1[/tex]

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder [tex]A_2[/tex] to the flat base surface [tex]A_1[/tex]; we have:

[tex]A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}[/tex]

Suppose, we replace DL for [tex]A_1[/tex] and

[tex]A_2[/tex] =  [tex]\dfrac{\pi D}{2}[/tex]

Then:

[tex]F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\ =\dfrac{2}{\pi} \\ \\ =0.64[/tex]

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

[tex]Q_{21} = Q_{evaporation}[/tex]

But, before that;  let's find the radian heat exchange occurring among the dome and the flat base surface:

[tex]Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)[/tex]

where;

[tex]\sigma = Stefan \ Boltzmann's \ constant[/tex]

[tex]T_1 = base \ temperature[/tex]

[tex]T_2 = temperature \ of \ the \ dome[/tex]

∴

[tex]Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m[/tex]

Recall the energy balance formula;

[tex]Q_{21} = Q_{evaporation}[/tex]

where;

[tex]Q_{evaporation} = mh_{fg}[/tex]

here;

[tex]h_{fg}[/tex] = enthalpy of vaporization

m = the water mass flow rate

∴

[tex]83899.15 = m \times 2257 \times 10^3 \\ \\ m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}[/tex]

The drying rate per unit length is 0.037 kg/S.m

Given data;

From the attached diagram, the surface 1 is flat, it is a view factor, f[tex]_1_1[/tex] = 0.

Applying summation rule and solving the view factor from the base surface A[tex]_1[/tex] to the cylindrical dome A[tex]_2[/tex].

[tex]f_1_1+f_1_2=1[/tex]

Put F[tex]_1_2=0[/tex]

[tex]0+f_1_2=1[/tex]

This makes [tex]f_1_2=1[/tex]

Applying reciprocal rule and solving the view factor from the cylindrical dome A[tex]_2[/tex] to the base surface A[tex]_1[/tex].

[tex]A_2F_2_1=A_1F_1_2\\F_2_1=(\frac{A_1}{A_2})F_1_2[/tex]

Where A is the area of the surface.

Substitute DL for A[tex]_1[/tex] and [tex]\frac{\pi D}{2}[/tex] for A[tex]_2[/tex]

[tex]F_2_1 = \frac{DL}{(\frac{\pi D}{2}})L *1 = \frac{2 }{\pi } =2/3.14 = 0.64[/tex]

Using the energy balance equation to the dryer,

[tex]Q_2_1=Q_e_v_a_p[/tex]

Let's calculate the radiation heat exchange between the dome and the base surface per unit length by using the equation below

[tex]Q_2_1=F_2_1A_2[/tex]δ[tex](T_2^4-T_1^4)[/tex]

[tex]Q_2_1= F_2_1 * \frac{\pi D}{2}[/tex]δ[tex](T_2^4-T_1^4)[/tex]

substitute the respective values into the equation

[tex]Q_2_1=0.64*(\frac{\pi }{2}*1.5)*5.67*10^-^8*(1000^4-370^4)\\Q_2_1=8.3899.15W/m[/tex]

Let's calculate the mass flow rate of water using the amount of heat required for drying up.

[tex]Q_2_1=Q_e_v_a_p\\Q_e_v_a_p=mh_f_g\\[/tex]

where [tex]h_f_g= 2257*10^3J/kg[/tex]

and this is the enthalpy of vaporization and mass flow rate of water.

[tex]83899.15=m*2257*10^3\\m=0.037kg/S.m[/tex]

The drying rate per unit length is 0.037kg/S.m

Learn more about mass flow rate here

https://brainly.com/question/24356835

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Answer:

This is not a clear indication of the hot zone as the information of the radioactivity of the background is not provided clearly.

Explanation:

According to IAEA as well as NRCP, the hot area is defined on the basis of the radioactivity reading it shows instead of contrast or comparative reading from the background. The value of radiation activity which will be required to declare an area as hot zone is if it is greater than 0.1 mSv/h or [tex]1.5091\times 10^{29} kg^{-1} s^{-1}[/tex].

Answer:

medium sized ears

Explanation:

Answer:

I am not sure it's confusing