Methane gas (CH4) at 25oC, 1 atm, and a volumetric flow rate of 27m3/h enters a furnace operating at steady-state. The methane burns completely with 140% of theoretical air that enters at 127oC, 1 atm. Products of combustion exit at 427oC, 1 atm. Determine:
(a) the volumetric flow rate of the air, in m3/h.
(b) the rate of heat transfer from the furnace, in kJ/h.

Answer:

37.33 grams

Explanation:

The missing information embedded in the idea section is attached in the image below:

The aim of this question is to determine the atomic wt. of Iron (Fe) from the hypothetic formula:

Fe₁O₁

Here, we know that the mole ratio can be written as:

[tex]\dfrac{O}{Fe}=\dfrac{1}{1}[/tex]

Suppose we assume that the atomic wt. of Fe = β(unknown)???

Then the grams of O and Fe that is contained in Fe₁O₁ can be expressed as:

For O:

1 × 16 grams of Oxygen = 16 grams of O

For Fe:

1 × β grams of Fe = β grams of Fe      

Now, let's take a look at the idea experiment, the mole solution can be computed as:

[tex]\dfrac{O}{Fe} = \dfrac{3}{2} \\ \\ \text{It implies that} \implies \dfrac{(3\times 16) \text{grams of O}}{(2 \times 56 ) \ \text{grams of Fe}}[/tex]

Equating both expressions above, we have:

[tex]\implies \dfrac{16}{ \beta} = \dfrac{3\times 16}{2\times 56}[/tex]

[tex]{ \beta} = \dfrac{(2\times 56)\times 16}{ 3\times 16}[/tex]

[tex]\mathbf{{ \beta} = 37.33 \ grams}[/tex]

Answer:

When you come up on a steady yellow traffic light you should always yield to cross traffic if you can yield safely. The flashing yellow light is there to inform drivers to be careful and to slow down.

Explanation:

hope it helped!

Answer:

Time required = 287.2 secs  

Explanation:

Volume  of room = 25 * 10 * 4 = 1000 m^3

power consumed by pump = 15 kW

T1 ( initial temperature ) = 12°C

P1 ( Initial pressure ) = 1 bar

COPhp = 3

Calculate time taken to raise room Temp to 27°C

average heat supplied ( ∅ ) = COPhp * power consumed by pump

                                             = 3 * 15 = 45 kW

Time required can be calculated using the relation below

∅t = P*V*Cv ( T2 - T1 )   [ p = 1.2 kg/m^3 , Cv = 0.718 KJ/kg ( air properties ) ]

45 * 10^3 ( t )  = 1.2*1000* 718 ( 27 - 12 )

∴ solving for t

t = 287.2 secs  ≈ 4.79 mins

False, Good housekeeping eliminates accident and fire hazards. It also maintains safe, healthy work conditions; saves time, money, materials, space, and effort; improves productivity and quality; boosts morale; and reflects an image of a well-run, successful organization.

Hope it helps you❤️

Answer:

bood ekogcd gcaerh is an American fbnuxc

Answer:

Explanation:

From the information given:

The instantaneous expression of the electric field in the wave is:

[tex]E(r,t)= (i_x \sqrt{3} -i_z) 2 \ sin (2 \pi*10^8t + 2 \pi x/3+2 \pi z /\sqrt{3} + 30 ^0) , \ V/m[/tex]

To determine the unit vector in line with the wave electric field, we take the first term in E(r,t) for [tex]I_E^\to[/tex] as:

[tex]I_E^\to = i_x \sqrt{3}-i_z \\ \\ I_E^\to = \dfrac{i_x \sqrt{3}-i_z}{\sqrt{3 +1}} \\ \\ \mathbf{ I_E = \dfrac{i_x\sqrt{3} -i_z}{2}}[/tex]

The amplitude is denoted by the numerical value after the first term, which is:

[tex]\mathbf{E_o = 2}[/tex]

The wavelength can be determined by using the expression:

[tex]\beta =\dfrac{2 \pi}{\lambda }[/tex]

from the given instantaneous expression:

[tex]\beta = \dfrac{2 \pi}{3}x+\dfrac{2 \pi}{\sqrt{3}}z[/tex]

[tex]\beta = \sqrt{\dfrac{2 \pi}{(3)^2}+\dfrac{(2 \pi}{(\sqrt{3})^2}}[/tex]

[tex]\beta = \sqrt{\dfrac{2 \pi}{9}+\dfrac{2 \pi}{{3}}}[/tex]

Factorizing 2π

[tex]\beta =2 \pi \sqrt{\dfrac{1}{9}+\dfrac{1}{{3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{9+3}{9*3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{12}{27}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{4*3}{9*3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{4}{9}}}[/tex]

[tex]\beta =2 \pi\times {\dfrac{2}{3}}}[/tex]

recall from the expression using in calculating wavelength:

[tex]\beta =\dfrac{2 \pi}{\lambda }[/tex]

∴

equating both together, we have:

[tex]\dfrac{2 \pi}{\lambda }= 2 \pi\times {\dfrac{2}{3}}}[/tex]

[tex]\lambda = \dfrac{3}{2}[/tex]

λ = 1.5 m

In line with the wave direction; unit vector [tex]i_k[/tex] can be computed as follows:

[tex]i_k = - [ \beta_1x +\beta_2z]/\beta[/tex]

where;

[tex]\beta_1 = \dfrac{2 \pi }{3} \ ; \ \beta_2 = \dfrac{2 \pi }{\sqrt{3}} \ ; \ \beta = \dfrac{2 \pi \times 2}{3} ;[/tex]

∴

[tex]i_k = - \Big[\dfrac{2 \pi}{3}x + \dfrac{2 \pi}{\sqrt{3}} z\Big]\times \dfrac{1}{\dfrac{2 \pi *2}{3}}[/tex]

[tex]i_k = - \Big[\dfrac{x}{2} + \sqrt\dfrac{{3}}{4}} z\Big][/tex]

[tex]i_k = - \Big[\dfrac{1}{2}x + \sqrt{\dfrac{3}{4} }z\Big][/tex]

[tex]\mathbf{i_k = - \Big[0.5x +0.86 z\Big]}[/tex]

Answer:

Following are the program to the given question:

def calculate_storage(filesize):#definging a method calculate_storage that takes filesize as a parameter  

 block_size = 4096#definging block_size that holds value

 full_blocks = filesize//block_size#definging full_blocks that divides the value and hold integer part

 partial_block_remainder = filesize%block_size#definging partial_block_remainder that holds remainder value

 if partial_block_remainder > 0:#definging if that compare the value

   return block_size*full_blocks+block_size#return value

 return block_size*full_blocks#return value

print(calculate_storage(1))    # calling method by passing value

print(calculate_storage(4096)) # calling method by passing value

print(calculate_storage(4097)) # calling method by passing value

Output:

4096

4096

8192

Explanation:

In this code, a method "calculate_storage" is declared that holds a value "filesize" in its parameters, inside the method "block_size" is declared that holds an integer value, and defines "full_blocks and partial_block_remainder" variable that holds the quotient and remainder value and use it to check its value and return its calculated value. Outside the method, three print method is declared that calls the method and prints its return value.

Answer:

a. True

b. False

Explanation:

a. Since true stress, σ' = σ(1 + ε) where σ = engineering stress and ε = engineering strain.

Also under tension ε > 0, so, (1 + ε) > 1

Since (1 + ε) = σ'/σ > 1, ⇒ σ' > σ

So, the true stress is greater than the engineering stress.

So, the statement is true

b. Creep is a time-dependent deformation under certain applied load.

Creep occurs at high temperatures under different types of stress.

But, Creep test is carried out at constant high temperature and constant stress.

This statement is false.

Answer:

Video game designers typically have a bachelor's degree in game design, computer engineering, or computer science which takes four to five years to complete. Courses in a game design degree program may include project management, integrated video design and technology, game prototyping and level design.

Solution :

Given data :

p = 315612 Pa

[tex]$V_1=7.07 \ m/sec$[/tex]

At exit of B,

p = [tex]$P_{atm}$[/tex]

[tex]$V_B = 26.1 \ m/sec$[/tex]

At exit of A,

[tex]p=P_{atm}[/tex]

[tex]$V_{A} = 26.1 \ m/s$[/tex]

We need to determine X component of force ([tex]$R_x$[/tex]) to hold in its place.

From figure,

[tex]$\sum F_x = m_0'V_{0x} - m_iV_{ix} $[/tex]

[tex]$=F_x+P_1A_1\sin 30=-mVA-mV_1 \sin 30$[/tex]

[tex]$=F_x=-pA_1\sin 30-m_AV_AA-m_B \sin30$[/tex]

Substitute all the values,

[tex]$=F_x=[-315612 \times \frac{\pi}{4}(0.3)^2 \sin 30]-[26.1 \times 1000 \times 26.1 \frac{\pi}{4}(0.1)^2]-[7.07 \times 1000\times 0.5 \sin 30]$[/tex][tex]$=F_x = -11154.64-5350.21-1767.28$[/tex]

[tex]$F_x = -18.2733 \ kN$[/tex]

Therefore, the force required to hold the nozzle in its place along horizontal direction.

[tex]$F_x = -18.2733 \ kN$[/tex]

Android provides a huge set of 2D-drawing APIs that allow you to create graphics.

Android has got visually appealing graphics and mind blowing animations.

The Android framework provides a rich set of powerful APIS for applying animation to UI elements and graphics as well as drawing custom 2D and 3D graphics.

1. Property Animation

2. View Animation

3. Drawable Animation

Solution :

For R-134a, we are given :

[tex]$T_i = 25^\circ C$[/tex]

[tex]$P_i=750 \ kPa$[/tex]

[tex]$P_e=165 \ kPa$[/tex]

Now we have one inlet and one exit flow, no work and no heat transfer. The energy equation is :

[tex]$h_e+\frac{1}{2}.v_e^2= h_i+\frac{1}{2}.v_i^2 $[/tex]

We also know that the gas is throttled and there is no change in the kinetic energy.

So, [tex]$v_e=v_i$[/tex]

Now from the energy equation above, we can see that the inlet and the exit enthalpies are also the same. Therefore,

[tex]$h_i=h_e$[/tex]

From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the exit saturation temperature.

[tex]$T_e=-15^\circ C$[/tex]

From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the specific enthalpies :

[tex]$h_f = 180.19 \ kJ/kg$[/tex]

[tex]$h_{fg} = 209 \ kJ/kg$[/tex]

Calculating the exit flow quality factor,

[tex]$x_e=\frac{h_e-h_f}{h_{fg}}$[/tex]

    [tex]$=\frac{234.59-180.19}{209}$[/tex]

   = 0.26

From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the specific volumes :

[tex]$v_f = 0.00746 \ m^3/kg$[/tex]

[tex]$v_{fg} = 0.11932 \ m^3/kg$[/tex]

Calculating the exit specific volume :

[tex]$v_e=v_f+x_e(v_{fg})$[/tex]

   = 0.000746 + 0.26 (0.11932)

   = 0.0318 [tex]m^3/kg[/tex]

The mass flow is equal to :

[tex]$\dot{m} = A_i . \frac{v}{v_i}$[/tex]

  [tex]$=A_e . \frac{v}{v_e}$[/tex]

So, [tex]$\frac{A_e}{A_i}=\frac{v_e}{v_i}$[/tex]

Therefore, the ratio of the exit pipe and the inlet pipe diameter is equal to

[tex]$\frac{D_e}{D_i}=\sqrt{\frac{A_e}{A_i}}$[/tex]

[tex]$\frac{D_e}{D_i}=\sqrt{\frac{v_e}{v_i}}$[/tex]

[tex]$\frac{D_e}{D_i}=\sqrt{\frac{0.0318}{0.000829}}$[/tex]

[tex]$\frac{D_e}{D_i}=6.19$[/tex]

Answer:

Đường dây siêu cao áp 500kV: Những chuyện giờ mới kể ... ​Ngày 27/5/1994, hệ thống đường dây điện siêu cao áp 500kV Bắc - Nam chính thức đưa ... Tại thời điểm đó, các nước như Pháp, Úc, Mỹ khi xây dựng đường dây dài nhất ... và chế ra các máy kéo dây theo đặc thù công việc của từng đơn vị.

Explanation:

This question is incomplete, the complete question is;

Consider a venturi with a throat-to-inlet area ratio of 0.75, mounted on the side of an airplane fuselage. The airplane is in flight at standard sea level. If the static pressure at the throat is 2050 lb/ft2 , calculate the velocity of the airplane.

Note that standard sea level density and pressure are 1.23 kg/m3 (0.002377 slug/ft3) and 1.01 x 105 N/m2 (2116lb/ft3), respectively.

Answer:

the velocity of the airplane is 267.2 ft/s

Explanation:

Given the data in the question;

throat-to-inlet area ratio A₂/A₁ = 0.75

density of air ρ = 0.002377 slug/ft³

the pressure at inlet p₁ = 2116 lb/ft³

the pressure at the throat p₂ = 2050 lb/ft³

Now, for a venturi duct, the velocity of the airplane V is given as;

V = √[ (2( p₁ - p₂ )) / (ρ( [A₁/A₂]² - 1 )) ]

so we substitute in our values

V = √[ (2( 2116 - 2050 )) / (0.002377 ( [1/0.75]² - 1 )) ]

V = √[ ( 2 × 66 ) / (0.002377 ( 1.7778 - 1 )) ]

V = √[ ( 2 × 66 ) / (0.002377 × 0.7778 ) ]

V = √[ 132 / 0.0018488 ]

V = √[ 71397.663349 ]

V = 267.2 ft/s

Therefore, the velocity of the airplane is 267.2 ft/s

Answer: True

Explanation:

The statement that "a masonry chimney should be braced with horizontal metal straps every few feet against the structure and into reinforced points such as wall studs to stabilize the chimney from the shaking force of an earthquake" is true.

In a scenario whereby the chimney isn't braced with the horizontal metal straps every few feet, this can lead to its collapse in case of an earthquake. Therefore, the correct option is "true".

Answer:

the maximum bending stress in the strap is 3.02 ksi

Explanation:

Given the data in the question;

steel strap thickness = 0.125 in

width = 2 in

circular arc radius = 600 in

we know that, standard value of modulus of elasticity of L2 steel is; E = 29 × 10³ ksi;

Now, using simple theory of bending

1/p = M/EI

solve for M

Mp = EI

M = EI / p ----- let this be equation 1

The maximum bending stress in the strap is;

σ = Mc / I -------let this be equation 2

substitute equation 1 into 2

σ = ( EI / p)c / I

σ = ( c/p )E

so we substitute in our values

σ = ( (0.125/2) / 600 )29 × 10³

σ = 0.00010416666 × 29 × 10³

σ = 3.02 ksi

Therefore, the maximum bending stress in the strap is 3.02 ksi

Answer:

For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. qf = final temperature of object

Explanation:

hope this helps you sorry if it doesn’t help you

Answer:

8.4627 m

Explanation:

Transmissivity( T ) = 300 m^2/day

Storativity( S )  = 0.0005

well radius ( r ) = 0.3m

Determine the drawdown in well at 100 days

Drawdown at 100 days = ∑ Drawdown at various period

We will use the equation : S = Q / U*π*T [ -0.5772 - In U ]  ----- ( 1 )

where : Q = discharge , T = transmissivity

             S = drawdown ,

U = r^2*s / 4*T*t  --- ( 2 )

r = well radius , S = Storativity, t = time period

i) During 0-20

U1 = r^2*s / u*π*t  = 1.875 * 10^-9

Input values into equation 1

S1 = 2.5885

ii) During 20-50

U2 = r^2*s / 4*π*t = 0.3^2 * 30 / u * 300 * 30 = 1.25 * 10^-9

input values into equation 1

S2 = 1.5854 m

iii) During 50 -90

U3 = r^2*s / 4*π*t = 9.375 * 10^-10

input values into equation 1

S3 = 4.2888 m

iv) During 90-100

U4 = 0

s4 = 0

Drawdown at 100 days = ∑ Drawdowns at various period

                                       = s1 + s2 + s3 + s4 = 2.5885 + 1.5854 + 4.2888 + 0

                                       = 8.4627 m

Answer:

here you go.

screenshot 2 should give you some basic idea

Answer:

25 mins into hours = 0.416667 hours

25 inches as mm = 635

Explanation:

Answer: hello your question is poorly written below is the complete question

Ethanol blended with gasoline can be used to power a flex-fueled car. One particular blend that is gaining in popularity is E85 , which is 85% ethanol and 15% gasoline. E85 is 80% cleaner burning than gasoline alone, and it reduces our dependency on foreign oil. But a flex-fueled car costs $1,000 more than a conventional gasoline-fueled car. Additionally, E85 fuel gets 10% less miles per gallon than a conventional automobile. Consider a 100% gasoline -fueled car that averages 30 miles per gallon. The E85-fueled car will average about 27 miles per gallon. If either car will be driven 81000 miles before being traded in, how much will the E85 fuel have to cost (per gallon) to make the flex-fueled car as economically attractive as a conventional gasoline-fueled car? Gasoline costs $3.89 per gallon. Work this problem without considering the time value of money

answer :

$3.17

Explanation:

Determine how much E85 fuel have to cost

Fuel needed by 100% gasoline fueled car

= 81,000 miles / 30 = 2700 gallons

Fueled needed by E85 car

= 81,000 miles / 27 = 3000 gallons

next step : use the relation below

[ (Additional cost of flex fuel car) + (flex fuel consumption * cost of flex fuel per gallon( x ) )  ]   = [ Gasoline consumption * cost of gasoline per gallon ]

= 1000 + 3000x = 2700 * 3.89

= 1000 + 3000x = 10503

∴ x = 9503 / 3000 = $3.17 per gallon

This question is incomplete, the complete question is;

To convert from the U.S. Customary (FPS) system of units to the SI system of units. A first-year engineering student records three separate measurements as 653 lb, 69.0 mi/h, and 293 × 10⁶ ft². Suppose this engineering student has to turn in the results, but the professor only accepts results given in SI units.  

Required:

What is the area measurement, 293 × 10⁶ ft², in SI units?

293 × 10⁶ ft² = ?km²

Answer:

the area measurement is  27.221 km²

Explanation:

Given the data in the question;

What is the area measurement, 293 × 10⁶ ft², in SI units

we are to the result of the measured area from ft² to km²

we know that;

1 meter = 3.2808 ft

1 km = 1000 m

1 ft = (1 / 3.2808)m

1 m = ( 1/1000 ) km

since our measured are is 293 × 10⁶ ft²

hence

A = 293 × 10⁶ × [ (1 / 3.2808)m ]²

A = 27221252.74 m²

A = 27221252.74 × [ ( 1/1000 ) km ]²

A = 27.221 km²

Therefore, the area measurement is  27.221 km²

Answer:

1 NAND gate

Explanation:

The minimum number of 2 input NAND gates that can be used to implement the combinational circuit = 1

The only true combinations conditions that can produce a false result ( i.e. condition/result different from the expected result as stated in the question )

Sensor 2 activated + Emergency switch pressed = False ( Line will keep moving )

Answer:

The basic difference between Total cost and total revenue is that the total cost includes the total expenditure incurred on the production of a commodity whereas total revenue refers to the money received from selling that commodity.

Explanation:

Answer:

The costs to run the dryer for one year are $ 9.03.

Explanation:

Given that the clothes dryer in my home has a power rating of 2250 Watts, and to dry one typical load of clothes the dryer will run for approximately 45 minutes, and in Ontario, the cost of electricity is $ 0.11 / kWh, to calculate the costs to run the dryer for one year the following calculation must be performed:

1 watt = 0.001 kilowatt

2250/45 = 50 watts per minute

45 x 365 = 16,425 / 60 = 273.75 hours of consumption

50 x 60 = 300 watt = 0.3 kw / h

0.3 x 273.75 = 82.125

82.125 x 0.11 = 9.03

Therefore, the costs to run the dryer for one year are $ 9.03.

Answer:

The answer is below

Explanation:

a) The work done is equal to the loss in kinetic energy (KE)

Change in kinetic energy (ΔKE) = Final kinetic energy - initial kinetic energy

Final KE = [tex]\frac{1}{2}mv_f^2[/tex]

But the final velocity is 0 (at rest). Hence:

Final KE = [tex]\frac{1}{2}mv_f^2=\frac{1}{2}m(0)^2=0[/tex]

ΔKE = 0 - K = -K

W = ΔKE = -K

Also, the work done (W) = charge (q) * distance (d) * electric field intensity (E)

W = qEd

but q = -e, hence:

W = -e * E * d

Using:

W = ΔKE

-e * E * d = -K

E= K / (e * d)

b) The electric field is in the direction of the electrons motion

Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution

Answer:

False.

Explanation:

Project management can be defined as the process of designing, planning, developing, leading and execution of a project plan or activities using a set of skills, tools, knowledge, techniques and experience to achieve the set goals and objectives of creating a unique product or service.

Generally, projects are considered to be temporary because they usually have a start-time and an end-time to complete, execute or implement the project plan.

The fundamentals of Project Management includes;

1. Project initiation.

2. Project planning.

3. Project execution.

4. Monitoring and controlling of the project.

5. Adapting and closure of project.

Basically, the specifications of a project or manufacturing process outlines the minimum requirements and quality that are acceptable. Thus, it must be adhered to strictly in order to achieve a successful and desired outcome.

As a rule, it is essential to check at every stage of a project if the sponsor or customer requirements and expectations have been met regarding the quality of the project deliverables.

Answer: hello attached below is the question properly written

a) 2670 Kw

b) product will be made up of vapor and liquid

c) Product will be a super cooled liquid

Explanation:

mass Flow rate ( m ) = 175 kg/min

pressure = 1 atm

molecular weight of ethylene glycol ( mw ) = 62.07 g/mol

enthalpy of vaporization ( ΔHv ) = 56.9 KJ/mol

Using values from the table 8.1 related to the question

a) Determine the rate at which heat must be transferred from condenser

Using values from the table 8.1 related to the question

ΔH = 2670 Kw

b) If heat is transferred  at a lower temperature the product will be made up of vapor and liquid

c) If heat was transferred at a higher temperature the product will be a super cooled liquid