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The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.
The spring in the dart gun is compressed by 0.16 m
From the question given above, the following data were obtained:
Spring constant (K) = 50 N/m
Potential Energy (PE) = 0.640 J
Compression (e) =?The compression experience by the spring can be obtained as follow:
PE = ½ke²
0.64 = ½ × 50 × e²
0.64 = 25 × e²
Divide both side by 25
e² = 0.64 / 25
Take the square root of both side
e = √(0.64 / 25)
e = 0.16 m
Therefore, the spring is compressed by 0.16 m
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2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?
Answer:
3.125 Kilometers
Explanation:
To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.
how is pure salt obtained from the sea water ?describe in brief
Answer:
Evaporation
Explanation:
Evaporation
Answer:
Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.
Da 6.0 kg wooden crate slides across a wooden floor
at a speed of 2.4 m/s, it it takes an applica force
of 25 N to keep it going at a steady speed. What is the
coe of kinetic friction between the floor and crate?
Answer:coe?
Explanation:
Why is wrestling ring floor always softThis is physics
Answer:
So the people in the ring don't get hurt or break anything on impact once they hit the floor
When did the objects that we now see as asteroids and comets form in the solar system?.
Answer:
After solid particles condensed from the gas but before the planets finished forming
If the submarine intends to submerge to a depth of 150 m, what pressure must it be designed to withstand
Explanation:
Hydrostatic pressure, P = hdg where d is density if the liquid ( water)
P= 150m × 1000kgm-3 × 10ms-2
P= 1.5 ×10^6 Pa
I'll give brainliest
Answer: figuratively speaking both the lines for the force Q and force P is equal.
plz help will mark brainliest
Explanation:
The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.
We have to take moments around the pivoted point.
Moment = Force × Perpendicular distance to the force
For the rod to be in equilibrium,
Clockwise moment - Anticlockwise moment = 0
Clockwise moment = Anticlockwise moment
The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm
So 20 cm× 1.2 N produces a Clockwise moment
If Perpendicular distance between pivoted point and 2N load is x,
Anticlockwise moment = x × 2N
20 cm× 1.2N = 2N × x
x = 12 cm
So 2 N load is at 12 from the pivoted point.
From the left edge of the meter ruler, 2N load is at 30-12 cm distance
= 18 cm
Answer: 18 cm
Explanation:
A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.
(a) Determine the maximum possible efficiency of the engine.
Answer: 72.3 %
Formula:
e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)
Explanation: Unsure??
(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.
Answer: 46 kW
Explanation:
Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)
How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %
Use kelvin not celsius
C + 273 = K
This will fix my problem of the equation not making sense.
A projectile is shot at an angle of 45 degrees with velocity components Vx and Vy both equal to 5 m/s. What is the magnitude of the initial velocity? Round to nearest tenth.
Answer:
7.1 m/s
Explanation:
Explanation is attached
An "energy bar" contains 26 ggof carbohydrates.How much energy is this in joules?
Help me quick!!! please!!
Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.
Answer:
39.240 W
Explanation:
Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]
At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]
Answer:
P=39200W
Explanation:
P=(mgh)/t
P=(40×9.8×1000)/10
P=39200W
we cannot see the milky way galaxy without binocular or telescopes. true or false?
Answer:
I'm pretty sure it's false
Explanation:
.
pluto is part of the kuiper belt. what captured moon likely originated in the kuiper belt?
moon Triton, Neptune's largest moon Triton
The moon Triton is the captured moon which most likely originated in the Kuiper belt.
What is Kuiper belt?This is defined as a donut-shaped region beyond Neptune and has an extension from 30 to 50 AU or more from the Sun.
The moon Triton is the captured moon which originates from this belt thereby making it the most appropriate choice.
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help -----------------------------------------
Answer:
H,G,E,D,C,B,A,I,F
Explanation:
F is an ignious intrusion and I cross cuts H to A so it must be newer.
Inertia causes bodies to slow in their motion, unless they’re pushed by a force.
Inertia resists changes to the state of motion of a body.
Inertia decelerates a body.
Inertia is due to friction.
Answer:
ill go with B
Explanation:
inertia is the ability of a body to remain at rest or in a constant speed in a constant direction when no force is acting on it
The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant
an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electric filed at P *
Which key phrase below would imply that an object has no (0) initial velocity?
1) smoothly
2) in motion
3) backwards
4) from rest
5) uniformly
I assume number 4.
The key phrase which describes zero (0) initial velocity is from rest.
When the velocity of an object at initial time is zero (0), it implies that the change in the displacement of the object with time is zero
[tex]v= \frac{\Delta x}{\Delta t} \\\\v_0 = 0[/tex]
Generally, when an starts its motion from rest, the initial velocity of the object will be zero. As the object acquires more momentum, the velocity increases with time.
Thus, we can conclude that the key phrase which describes zero (0) initial velocity is from rest.
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This should be pretty easy i think.
Describe the components within the system involved in the collision between pilot and landing zone.
Answer:
its a sure for not but i think its a 192583
How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
Answer: the weight would be 4.6 (I think i don’t know))
Explanation:
How does the diameter of a black hole (size of the event horizon) depend on the mass inside the black hole
Answer:
The greater the mass, the greater is the diameter
Explanation:
The greater the mass, the greater is the diameter. almost all galaxies contain supermassive black holes.
What is a thought experiment?
Answer:
A thought experiment is an experiment carried out only in the imagination
Explanation:
Solve 100N up 90N down for net force
Answer:
10 Newtons up
Hope this helps!
please answer right please
Answer:
i think its A
Explanation:
I hope this helps :)
What quantity is represented by the mass number minus the atomic number?.
Answer:
Mass = mass of nucleus
Atomic Number = number of protons (charge) of nucleus
Mass - Atomic Number = number of neutrons
A father pushes his child in a cart. The cart starts to move.
Scientists can use many physical quantities to describe what is happening.
The car is placed on a ramp, which is 20 meters high. The mass of the car and the child is 100kg.
Calculate the potential energy the car will have before it is let go and the velocity the car will travel at down the ramp assuming no frictional forces.
Acceleration due to gravity (g) = 10 m/s2
The potential energy of the car when it let go is 20,000 J.
The speed of the car at the bottom of the ramp is 20 m/s.
The given parameters;
mass of the car, m = 100 kgheight of the car, h = 20 mThe potential energy of the car is calculated as follows;
P.E = mgh
P.E = 100 x 10 x 20
P.E = 20,000 J
The speed of the car at the bottom of the ramp is calculated as follows;
[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s[/tex]
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How does the radius of a string affect centripetal force.
Answer:
because a raduis is half of 25% of a cicrle.
Explanation:
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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