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Related Questions

Which of the relations given by the following sets of ordered pairs is not a function?

HELPPPPP :((((( IF YOU SEND LINK I WILL REPORT YOU

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Answer:

Hi, there your answer will be C.

Step-by-step explanation:

The reason why is because X(Input) can not be repeated the same

for example the coordiante( 1,3) and (1,4). See there are two ones which make them not function

Also, if you're having trouble with Functions and nonfunctions

REMEMBER THS

Function: X and y has to be separarte  and can't have the same X

NON-FUNCTION- WHEN X REPEATS ITSELF

Hope this helps :)

Suppose that whether it rains tomorrow depends on past weather conditions only through the last 2 days. Specifically, suppose that if it has rained yesterday and today, then it will rain tomorrow with probability .8; if it rained yesterday but not today, then it will rain tomorrow with probability .3; if it rained today but not yesterday, then it will rain tomorrow with probability .4; and if it has not rained either yesterday or today, then it will rain tomorrow with probability .2. Over the long term, what proportion of days does it rain

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Answer:

The answer is "0.425".

Step-by-step explanation:

The  T be a requirement today that such rains.

The Y be a situation yesterday that now it rained.

The O is a condition for tomorrow to rain.

[tex]P(O| (Y\ AND \ T)) = 0.8\\\\P(O|(Y \ AND \ NOT\ (T)) =0.3\\\\P( O|(NOT \ (Y)\ AND\ T)= 0.4\\\\P( O| NOT\ (Y) \ OR \ NOT \ (T)) =0.2[/tex]

There Arena and morrow overview To Aspects Which will rain:

[tex]Y\ AND \ T, Y \ AND \ NOT \ (T),\ NOT\ (Y) \ AND\ T, \ NOT(Y)\ OR \ NOT(T)[/tex]

Each has the option of [tex]\frac{1}{4}[/tex] INDEPENDENTLY happening.

Its possibility of tomorrow's rain is:

[tex]P(O) = P(O | Y\ AND\ T) P(Y\ AND\ T) + P(O|(Y \ AND \ NOT\ (T))[/tex]

       [tex]P((Y\ AND \ NOT\ (T)) + P(O|(\ NOT\ (Y) \ AND \ T))P(\ NOT\ (Y) \ AND\ T) \\\\+ P( O| \ NOT\ (Y)\ OR\ NOT\ (T)) P(\ NOT\ (Y)\ OR\ NOT\ (T))\\\\[/tex]

      [tex]=0.8\times \frac{1}{4} +0.3\times \frac{1}{4}+0.4\times \frac{1}{4}+0.2\times \frac{1}{4}\\\\ =\frac{1}{4}(0.8+0.3+0.4+0.2)\\\\= \frac{1.7}{4}\\\\= 0.425[/tex]

Find the area of the shaded region.
00
please help!! i will mark brainliest, no links please!!

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Answer:

180 i think

hope it helped

Answer:

area = 118.04 units²

Step-by-step explanation:

area of circle = πr² = (3.14159)(8²) = 201.06 units²

area of triangle:

corner angle - 60°/2 = 30°

sin 30° = m/8, m = 4

height of triangle = 4 + 8 = 12

cos 30° = n/8, n = 6.93, n = 1/2 base

base of triangle = 13.86

area of triangle = 1/2bh = 1/2(13.86)(12) = 83.02 units²

area of shaded portion = 201.06 - 83.02 = 118.04 units²

This should be the last question for the day...hopefully

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I’d think it’s equated to the one, why I think that? Idek.

A cylinder and a cone have the same volume. The cylinder has a radius of 2 inches and a height of 3
inches. The cone has a radius of 3 inches. What is the height of the cone?
Show your work.
Plz help

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Answer: 4 in

Step-by-step explanation:

The volume of the cylinder is

[tex]V=(\pi)(2^{2})(3)=12\pi[/tex]

If we let the height of the cone h, the volume of the cone is

[tex]V=\frac{1}{3}(\pi)(3^{2})(h)=3\pi h[/tex]

Setting these volumes equal,

[tex]12\pi=3\pi h\\\\12=3h\\\\h=\boxed{4 \text{ in}}[/tex]

-6=2(u+3)-5u pls help me with this

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Answer:

u=3

Step-by-step explanation:

-6=2u+3-5u

-6=-3u+3

3u=6+3

3u=9

u=3

Write the equation of the line that has a slope of -3/2 and passes through (4, -3)

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Answer:

y = -3/2x + 3

Step-by-step explanation:

y = -3/2x + b

-3 = -3/2(4) + b

-3 = -6 + b

3 = b