Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?

Answer:

6

Explanation:

Just did it.

The gravitational potential energy would the same lander have on top of a 350-m hill on Earth is 6.

If an object is lifted, work is done against gravitational force. The object gains energy.

The equation for calculating gravitational potential energy is

GPE =mgh

where, GPE is the gravitational potential energy, m is the mass, h is the change in height and g is the acceleration due to gravity.

The heavier the particle and the higher it is over the ground, the more gravitational potential energy it holds. Gravitational potential energy increments as weight and level increments.

Given is the height of hill h = 350m.

Thus, the same lander will have the the potential energy 6 times more.

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Answer:

Explanation:

The time taken can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{20}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

F = m*a

therefore m = F / a

m = 100 / 5 = 20 kg?

hope this helped you

Explanation:

The required mass of man, undergoing the acceleration is of 75 kg.

Given data:

The magnitude of acceleration of man is, a = 4 m/s².

The magnitude of action force on the man is, F = 300 N.

Here we can apply the Newton's second law of motion, which says that the applied force causes the acceleration of any object. Where the applied force is equal to the mass of object and the magnitude of acceleration of object.

Therefore,

F = ma

Solving as,

300 = m × 4

m = 300/4

m = 75 kg

Thus, we can conclude that the mass of man, undergoing the acceleration is of 75 kg.

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Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

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Answer:

its b >.<

Explanation:

just trust me laddies

Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words

Semantics can be defined as the message conveyed by words in a sentence and context where the sentence is placed. It is a set of rules that is concerned with the understanding of words in sentences used in a context.

Hence we can conclude that Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words.

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Answer:

A. chemical

Explanation:

the type of energy our body contain is chemical energy and that chemical energy is the one used while pushing the swing.. so I guess it's chemical energy.. based on my knowledge hope this helps.

Answer:

1. Time of flight = 7.22 s

2. Range = 255.10 m

3. Maximum height = 63.77 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Time of flight (T) =?

Range (R) =?

Maximum height (H) =?

1. Determination of the time of flight

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Time of flight (T) =?

T = 2uSine θ /g

T = 2 × 50 Sine 45 / 9.8

T = 100 × 0.7071 /9.8

T = 7.22 s

2. Determination of the range.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

R = u²Sine 2θ /g

R = 50² × Sine (2×45) /9.8

R = 2500 × Sine 90 /9.8

R = 2500 × 1 / 9.8

R = 255.10 m

3. Determination of the maximum height.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (H) =

H = u²Sine²θ /2g

H = 50² × (Sine 45)² / 2 × 9.8

H = 2500 × (0.7071)² / 19.6

H = 63.77 m

Answer:

Explanation:

Given;

initial velocity of projection, u = 50 m/s

angle of projection, θ = 45°

Time spent in the air is the time of flight, given as;

[tex]T = \frac{2usin \theta}{g}\\\\T = \frac{2(50)sin (45)}{9.8}\\\\T = 7.22 \ s[/tex]

The range of the projectile is given by;

[tex]R = \frac{u^2sin(2\theta)}{g}\\\\R = \frac{u^2sin(2*45)}{g}\\\\ R = \frac{u^2sin(90)}{g}\\\\ R = \frac{u^2(1)}{g}\\\\R=R_{max} = \frac{u^2}{g} =\frac{50^2}{9.8} = 255.1 \ m[/tex]

The maximum height of the projectile is given by;

[tex]H = \frac{u^2sin^2\theta}{2g}\\\\H = \frac{(50)^2sin^2(45)}{2*9.8}\\\\H = 63.77 \ m[/tex]

Answer:

It is a product, so it is released by the plant.

Explanation:

[tex]6CO2 + 6H2O[/tex] → [tex]C6H12O6 + 6O2[/tex]

The plant uses water and carbon dioxide to create glucose and oxygen. Glucose is plant food, and Oxygen is given off as a byproduct.

Answer:

It is a product, so it is released by the plant.

Explanation:

Answer:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

Explanation:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

Answer:

10 m

Explanation:

PE = mgh

m = 50kg

g= 9.8 m/s^2

h=?

so,

4900= 50×9.8× h

50h = 4900/9.8

50h = 500

h = 10 m

Answer:

net force

Explanation:

Net force felt by an object.

Answer:

The acceleration due to gravity near the surface of Ceres is approximately 0.284 m/s²

Explanation:

The given parameters are;

The mass of Ceres = 9.4 × 10²⁰ kg

The radius of Ceres, r = 4.7 × 10⁶ m

By Newton's law of gravitation, we have;

[tex]Gravitational \ force\ on \ the \ spacecraft \ near \ Ceres, \ F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]

Therefore;

[tex]Acceleration \ due \ to \ gravity \ g =G\dfrac{m_{1}}{r^{2}}[/tex]

Where;

m₁ = The mass of Ceres = 9.4 × 10²⁰ kg

m₂ = The mass of the spacecraft

G = 6.6743 × 10⁻¹¹ N·m²/kg²

Substituting the values, we get;

[tex]g \ near \ the \ surface \ of \ Ceres = \dfrac{ 6.6743 \times 10^{-11} \times 9.4 \times 10 ^{20}}{(4.7 \times 10^5)^{2}} \approx 0.284 \ m/s^2[/tex]

The acceleration due to gravity near the surface of Ceres ≈ 0.284 m/s²

Answer:

The radius of the blender is approximately 0.5041[tex]\bar 6[/tex] meters

Explanation:

The given parameters are;

The mass of the strawberry, m = 0.05 kg

The speed with which the strawberry is spun, v = 11.0 m/s

The centripetal force holding the strawberry = 12.0 N

The formula for the centripetal force, [tex]F_c[/tex], is given as follows;

[tex]F_c = \dfrac{m \cdot v^2}{r}[/tex]

Where;

r = The radius of the centripetal rotation, which is the radius of the blender

[tex]\therefore r = \dfrac{m \cdot v^2}{F_c}[/tex]

Substituting the values gives;

[tex]\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6[/tex]

The radius of the blender, r ≈ 0.5041[tex]\bar 6[/tex] meters.

Answer: 110 N

Explanation: trust me

Answer:

by taking other atoms that have one shell and putting it i the spot that they need t in

Explanation:

Answer:

Yes

Explanation:

Answer:

The anwser is b

Explanation:

Answer:

the answer is B

I know  because i just did it

Answer:

B.7.5m/s2

Explanation:

average acceleration=change invelocity/time taken

a=(60-30)/4

=7.5m/s2

The average acceleration of the car 7.5 m/s²

The parameters given in the question are;

initial velocity= 30 m/s

final velocity= 60 m/s

time= 4 seconds

The formula that can be used to calculate the average acceleration is

= final velocity-initial velocity/time

= 60-30/2

= 30/2

= 7.5

Hence the average acceleration is 7.5 m/s²

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Answer:

Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Explanation:

Answer:

Air pressure is created by the weight of the atmosphere pushing on Earth’s surface.

Denser air is heavier than less dense air.

Air is less dense at higher altitudes.

Explanation:

Based on the properties of air, the correct options from the given statements are:

Air is a mixture of gases in the atmosphere which consists of nitrigen, oxygen, carbon dioxide and noble gas as well as other trace partickes like water vapor.

Some properties of air include:

Therefore, the correct options from the given statements are:

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Answer:

Its C I fell confident

Explanation:

I took 2 hrs I tried on this for u dont get mad have a wonderful day :D

So the incorrect option is C the current flowing through the circuit is 27 amps because the current is related to voltage and resistance by the formula I = R + V

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit.

To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists.

E = I x R

So the incorrect option is C the current flowing through the circuit is 27 amps because the current is related to voltage and resistance by the formula I = R + V

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Answer:

Explanation:

for vertical displacement h = 1.6 , let time taken be t , initial vertical velocity = 0

h = ut + 1/2 g t²

= 1/2 g t²

1.6 = .5 x 9.8 x t²

t² = .3265

t = .57 s

b )

velocity in horizontal direction = 3.2 m /s

horizontal displacement

= 3.2 x .57 = 1.82 m

c )

for vertical movement

v = u + gt

= 0 + 9.8 x .57

= 5.58 m /s

The initial vertical velocity of a ball thrown horizontally with an initial velocity of 20 m/s from the top of a 60 m high tower is 0 m/s (option a).  

The ball is thrown horizontally, so its velocity will have only components in the x-direction (horizontal). The components of the initial velocity in the y-direction (vertical) will be zero.    

For a ball's velocity to have components in the vertical and horizontal direction, the ball must be thrown at a certain angle to the ground, describing a parabolic movement.

In a parabolic movement, the vertical and horizontal components of the velocity would be:

[tex] v_{x} = v_{i}cos(\theta) [/tex]

[tex] v_{y} = v_{i}sin(\theta) [/tex]

Where:

[tex] v_{i} [/tex]: is the initial velocity

θ: is the angle

Therefore, the initial vertical velocity of the ball is zero (option a).

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Answer:

pursuing a goal

Explanation:

Since there are no answer choices provided I would say that this is an example of pursuing a goal. This is basically all of the tasks and struggles that an individual must go through in order to finally achieve a certain goal. It also involves gradually breaking barriers and pushing forward by increasing the complexity of the tasks until you are able to break through all of them to reach the end-goal that you have been striving for. Which is exactly what John has been doing in this scenario by gradually increasing his running time.

Answer:

6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = [tex]\frac{force}{area}[/tex]

         Force  = Pressure x area

        Force  = 300 x 0.02  = 6N

Let T be the final temperature of water and nails (iron).

Given that the initial temperature of 100 g nails, [tex]T_{1F}=40^{\circ}C[/tex].

Specific heat of the iron, [tex]C_F=0.12 cal/g^{\circ}C[/tex].

So, the heat lost by nails [tex]= mC_F(T_{1F}-T}[/tex]

[tex]=100\times 0.12 \times (40-T)\cdots(i)[/tex]

The initial temperature of 100 g water, [tex]T_{1w}=20^{\circ}C.[/tex]

Specific heat of water, [tex]C_w=1 cal/g^{\circ}C[/tex]

So, the heat gained by water [tex]= mC_w(T-T_{1w}}[/tex]

[tex]=100\times 1 \times (T-20)\cdots(ii)[/tex]

As the exergy is conserved, so

the heat lost by the nails = the heat gained by the water

From equation (i) and (ii), we have

[tex]100\times 0.12 \times (40-T)=100(T-20)[/tex]

[tex]\Rightarrow 0.12(40-T)=T-20[/tex]

[tex]\Rightarrow 0.12\times 40 -120T=T-20[/tex]

[tex]\Rightarrow 0.12T+T=4.8+20[/tex]

[tex]\Rightarrow 1.12T=24.8[/tex]

[tex]\Rightarrow T=24.8/1.12= 22.1^{\circ}C[/tex]

Hence, the final temperature of both, iron nails as well as water, become [tex]22.1^{\circ}C[/tex].