If e : f is 3 : 7 and f : g is 2 : 3 what is e : g ? please answer asap!

I'm going to assume you start with

[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|}[/tex]

Let's simplify some pieces of this:

[tex]6^2 = 6\times6 = 36[/tex]

[tex]\sqrt{25} = \sqrt{5^2} = 5[/tex]

[tex](3 - \sqrt{25})^2 = (3 - 5)^2 = (-2)^2 = (-2)\times(-2) = 4[/tex]

[tex]|4 - 8| = |-4| = 4[/tex]

So as a first step we can reduce this to

[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|} = \dfrac{36-4\times4}4[/tex]

Now,

[tex]36 = 9\times4[/tex]

so every term contains a factor of 4 that we can cancel:

[tex]\dfrac{36-4\times4}4 = \dfrac{9\times4-4\times4}4 = \dfrac{9-4}1 = 9-4 = \boxed{5}[/tex]

as expected.

Answer:

p=Parentheses

e=Exponents

m=Multiplication

d=Division

a=Addition

s=Subtraction

its an order of solving a equation

Answer:

x = ± 6

Step-by-step explanation:

Hello!

The value of x is 6 or -6.

Hi...

[tex]\texttt{5x}[/tex]² [tex]\texttt{= 180}[/tex]

[tex]\texttt{5x}[/tex]² [tex]\texttt{= 180}[/tex]

Divide both sides by 5

[tex]\hookrightarrow{\mathtt{\frac{5x^2}{5}} = {\mathtt{\frac{180}{5}}[/tex]

Simplify:

[tex]\hookrightarrow{\mathtt{x^2 = 36}[/tex]

[tex]\hookrightarrow{\mathtt{For \: x^2 \: = f(a) \: the \: solutions \: are \: x = \sqrt{f(a)}}[/tex] , [tex]\mathtt{- \sqrt{f(a)}}[/tex]

[tex]\hookrightarrow{\mathtt{x = \sqrt{36}}[/tex] , [tex]\mathtt{x = -\sqrt{36}}[/tex]

Factor the number: 36 = 6²

[tex]\mathtt{= \sqrt{6^2}}[/tex]

Apply radical rule: [tex]\mathtt{\sqrt[n]{a^n} \: = a}[/tex]

[tex]\mathtt{\sqrt{6^2} = 6} \\\mathtt{= 6}[/tex]

- [tex]\sqrt{36} = -6[/tex]

[tex]\boxed{\fbox{\bf{x = 6 , x = -6}}}[/tex]

Hope It Helps You...

Answer:

50

Step-by-step explanation:

90+40= 130

There are 180 degrees in a triangle.

180- 130 = 50

Answer:

See below

Step-by-step explanation:

[tex]f(x)=3x^2+6x-24\\\\f(x)=3(x^2+2x-8)\\\\f(x)+3(9)=3(x^2+2x-8+9)\\\\f(x)+27=3(x^2+2x+1)\\\\f(x)=3(x+1)^2-27[/tex]

Here, we can see that the vertex of the parabola is [tex](-1,-27)[/tex] when we compare to the equation [tex]y=(x-h)^2+k[/tex] with vertex [tex](h,k)[/tex].

A second point you could plot is the y-intercept, when [tex]x=0[/tex]:

[tex]f(0)=3(0+1)^2-27\\\\f(0)=3-27\\\\f(0)=-24[/tex]

So, your y-intercept is [tex](0,-24)[/tex].

Answer:

y = 3x - 12

Step-by-step explanation:

Forming the slope-intercept equation :

y = mx + b

Substitute m = 3 and b = -12 in the equation :

Answer:

y = 3x - 12

Step-by-step explanation:

The slope intercept form of a line is y = mx + b, where m is the slope and b is the y intercept. Here, m = 3 and b = -12. Therefore, the slope intercept form for this line is y = 3x - 12.

Answer: C

Step-by-step explanation:

We know that [tex]\angle AHB=90^{\circ}[/tex], and thus by the exterior angle theorem,

[tex]90^{\circ}+\alpha=4\alpha\\\\90=3\alpha\\\\\alpha=30^{\circ}[/tex]

Thus, [tex]\angle CAB=2\theta=\boxed{60^{\circ}}[/tex]

Answer:

Step-by-step explanation:

The profit = 150 000 - 120 000 = 30 000

………………………………………………………

The profit percentage is :

[tex]=\frac{30000}{120000} \times 100=0.25 \times 100 = 25 \%[/tex]

The equation that matches the graph of the greatest integer function is y = [x] - 2

The parent function of an step function is represented as:

y = [x]

From the given graph, we can see that the lines are shifted 2 units down.

This means that:

(x,y) = (x,y - 2)

So, we have:

y = [x] - 2

Hence, the equation that matches the graph of the greatest integer function is y = [x] - 2

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Answer:

c; 6

Step-by-step explanation:

to find the rate of change from x = 2 to x = 4 you use the (y2 - y1) / (x2 - x1) formula

so

(21 - 9) / (4 - 2)

12 / 2

6

the average rate of change is 6

Using the information in the diagram, the measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is 89.0°

From the question, we are to determine the measure of [tex]\overset{\LARGE\frown}{CD}[/tex]

Consider the right triangle

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is twice the measure of the unknown angle

Let the unknown angle in the right triangle be x

∴ The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 2x

Then,

x + 90° + 45.5° = 180° (Sum of angles in a triangle)

x = 180° - 90° - 45.5°

x = 44.5°

Thus,

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 2×44.5°

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 89°

Hence, the measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is 89.0°

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The graph that shows a unit rate of 3/4, which is the time Cindy reads while riding in the car is the graph attached below.

Unit rate can be described as a constant or exactly how much of one quantity is per 1 unit of another quantity.

Unite rate (k) = x/y.

In the graph attached below, when x (hours driving) = 3, y (hours reading) = 4.

Therefore, unit rate = 3/4. We can then conclude that the graph that shows that Cindy reads 3/4 of the time she rides in a car is the graph attached below.

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The numbers between 10 and 50  when they are divided by 5 then the remainder is 2 is shown in the form of description method and in set-builder form is {12, 17, 22, 27, 32, 37, 42, 47}.

A set is a collection of clearly - defined unique items. The term "well-defined" applies to a property that makes it simple to establish whether an entity actually belongs to a set. The term 'unique' denotes that all the objects in a set must be different.

We have:

The set of numbers between 10 and 50 when they are divided by 5 then the remainder is 2

The numbers are:

12, 17, 22, 27, 32, 37, 42, 47

By description method:

1      2     3    4      5     6      7      8  

12   17   22   27    32    37   42    47  

By set builder form:

s = {12, 17, 22, 27, 32, 37, 42, 47}

Thus, the numbers between 10 and 50  when they are divided by 5 then the remainder is 2 is shown in the form of description method and in set-builder form is {12, 17, 22, 27, 32, 37, 42, 47}.

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Step-by-step explanation:

650065 = (a² + 1)(c² + 1)

and

650065 = (ac - 1)² + (a + c)² = the sum of 2 squared numbers (ac - 1)² and (a + c)².

we see that 5 and 13 and therefore 5×13=65 are all factor of 650065. and then 650065/65 = 10001.

and we know that 65 = (64 + 1) = (8² + 1)

and 10001 = (10000 + 1) = (100² + 1)

so, a = 8, c = 100

that means the 2 squared numbers summing up to 650065 are

(ac - 1)² = (8×100 - 1)² = 799² = 638,401

(a + c)² = (8 + 100)² = 108² = 11,664

650,065 = 638,401 + 11,664 = 799² + 108²

Answer: 2,444

Step-by-step explanation: We can find the answer to this problem by simplifying the scientific notation, and then adding. You would end up with 2,000 + 400 + 40 + 4 if done correctly. Hope this helps!

The pair of angles that share a ray as a common side in the given diagram is: ∠FAB and ∠FAD.

Adjacent angles are angles that lie adjacent or next to each other sharing a common vertex and have the same ray as a common side.

In the diagram attached below, ∠FAB and ∠FAD share a common vertex, A, and a ray FA as a common side.

Therefore, the pair of angles is: ∠FAB and ∠FAD.

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Let A(t) denote the amount of salt (in ounces, oz) in the tank at time t (in minutes, min).

Salt flows in at a rate of

[tex]\dfrac{dA}{dt}_{\rm in} = \left(17 (1 + 15 \sin(t)) \dfrac{\rm oz}{\rm gal}\right) \left(8\dfrac{\rm gal}{\rm min}\right) = 136 (1 + 15 \sin(t)) \dfrac{\rm oz}{\min}[/tex]

and flows out at a rate of

[tex]\dfrac{dA}{dt}_{\rm out} = \left(\dfrac{A(t) \, \mathrm{oz}}{180 \,\mathrm{gal} + \left(8\frac{\rm gal}{\rm min} - 8\frac{\rm gal}{\rm min}\right) (t \, \mathrm{min})}\right) \left(8 \dfrac{\rm gal}{\rm min}\right) = \dfrac{A(t)}{180} \dfrac{\rm oz}{\rm min}[/tex]

so that the net rate of change in the amount of salt in the tank is given by the linear differential equation

[tex]\dfrac{dA}{dt} = \dfrac{dA}{dt}_{\rm in} - \dfrac{dA}{dt}_{\rm out} \iff \dfrac{dA}{dt} + \dfrac{A(t)}{180} = 136 (1 + 15 \sin(t))[/tex]

Multiply both sides by the integrating factor, [tex]e^{t/180}[/tex], and rewrite the left side as the derivative of a product.

[tex]e^{t/180} \dfrac{dA}{dt} + e^{t/180} \dfrac{A(t)}{180} = 136 e^{t/180} (1 + 15 \sin(t))[/tex]

[tex]\dfrac d{dt}\left[e^{t/180} A(t)\right] = 136 e^{t/180} (1 + 15 \sin(t))[/tex]

Integrate both sides with respect to t (integrate the right side by parts):

[tex]\displaystyle \int \frac d{dt}\left[e^{t/180} A(t)\right] \, dt = 136 \int e^{t/180} (1 + 15 \sin(t)) \, dt[/tex]

[tex]\displaystyle e^{t/180} A(t) = \left(24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t)\right) e^{t/180} + C[/tex]

Solve for A(t) :

[tex]\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) + C e^{-t/180}[/tex]

The tank starts with A(0) = 15 oz of salt; use this to solve for the constant C.

[tex]\displaystyle 15 = 24,480 - \frac{66,096,000}{32,401} + C \implies C = -\dfrac{726,594,465}{32,401}[/tex]

So,

[tex]\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) - \frac{726,594,465}{32,401} e^{-t/180}[/tex]

Recall the angle-sum identity for cosine:

[tex]R \cos(x-\theta) = R \cos(\theta) \cos(x) + R \sin(\theta) \sin(x)[/tex]

so that we can condense the trigonometric terms in A(t). Solve for R and θ :

[tex]R \cos(\theta) = -\dfrac{66,096,000}{32,401}[/tex]

[tex]R \sin(\theta) = \dfrac{367,200}{32,401}[/tex]

Recall the Pythagorean identity and definition of tangent,

[tex]\cos^2(x) + \sin^2(x) = 1[/tex]

[tex]\tan(x) = \dfrac{\sin(x)}{\cos(x)}[/tex]

Then

[tex]R^2 \cos^2(\theta) + R^2 \sin^2(\theta) = R^2 = \dfrac{134,835,840,000}{32,401} \implies R = \dfrac{367,200}{\sqrt{32,401}}[/tex]

and

[tex]\dfrac{R \sin(\theta)}{R \cos(\theta)} = \tan(\theta) = -\dfrac{367,200}{66,096,000} = -\dfrac1{180} \\\\ \implies \theta = -\tan^{-1}\left(\dfrac1{180}\right) = -\cot^{-1}(180)[/tex]

so we can rewrite A(t) as

[tex]\displaystyle A(t) = 24,480 + \frac{367,200}{\sqrt{32,401}} \cos\left(t + \cot^{-1}(180)\right) - \frac{726,594,465}{32,401} e^{-t/180}[/tex]

As t goes to infinity, the exponential term will converge to zero. Meanwhile the cosine term will oscillate between -1 and 1, so that A(t) will oscillate about the constant level of 24,480 oz between the extreme values of

[tex]24,480 - \dfrac{267,200}{\sqrt{32,401}} \approx 22,995.6 \,\mathrm{oz}[/tex]

and

[tex]24,480 + \dfrac{267,200}{\sqrt{32,401}} \approx 25,964.4 \,\mathrm{oz}[/tex]

which is to say, with amplitude

[tex]2 \times \dfrac{267,200}{\sqrt{32,401}} \approx \mathbf{2,968.84 \,oz}[/tex]

Hi student, let me help you out! :)

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We are asked to simplify the expression 2(7x+3)+9x.

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

So, let's compute...

\\\////\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\\///\\\////\\\///\\\///\\\///\\\///\\\///\\\//\\//\\\/

After performing multiplication we obtain

[tex]\star~\mathrm{14x+6+9x}[/tex]

Now add 9x:

[tex]\star~\mathrm{23x+6}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.

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~Just a smiley person helping fellow students :)

Answer:

[tex]3*(2x+3)*(x+1)[/tex]

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

[tex]\left(2x+3\right)\left(3x+3\right)\\3x + 3 = 3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\[/tex]

histor Grammer

Step-by-step explanation:

lol bhsg HD tcvh by by by g

Answer: Hope this helps you!

6th floor

Step-by-step explanation:

If it starts on the 9th floor and goes down 7 floors that is:

9 (9 floors) + -7 (down 7 floors)

which is also equal to 9-7

9-7 = 2

Next, we need to go up by 4 floors starting with 2, 2+4

2+4 = 6

Brainliest?

Answer:

(p -3q )(p -3q  )

Step-by-step explanation:

p'2 - 6pq + 9q'2

(p -3q )(p -3q  )

find two values that add to give 6 and multiply to 9

p x p =p'2

-3q x p = -3pq   -3 x pq = -3pq    ...... -3pq - 3pq = -6pq

-3q x - 3q = 9q'2

Answer:

  66°

Step-by-step explanation:

The angle sum theorem tells you the sum of angles in a triangle is 180°.

__

  79° +x +35° = 180°

  x = 180° -114° . . . . . . . . subtract 114° from both sides

  x = 66° . . . . . simplify

Answer:



Step-by-step explanation:

Answer:

1156

Area = base times height

Area = (36-1-1) times (45-10-1)

=1156

Answer:

f(10) means to input x = 10 into the function.

From inspection of the given function:

[tex]\sf f(10)=\dfrac{10}{2}=5[/tex]

the "10" is the numerator of the fraction.

Therefore, swap the "10" for "x" to give the function in terms of x:

[tex]\sf f(x)=\dfrac{x}{2}[/tex]

For a function

x is the input or domain

y is the output or range

Here

So

x=10

y=10/2

Hence the function is

Answer:

CE = 4.6 ft

Step-by-step explanation:

(a)

given 2 secants drawn from an external point to the circle , then

the product of the external part of one secant and the entire secant is equal to the product of the other secant's external part and that entire secant, that is

BE × BC = AB × DB

(b)

substituting given values into the equation

BE × 10 = 3 × 18

10 BE = 54 ( divide both sides by 10 )

BE = 5.4 ft

then

CE = CB - BE = 10 - 5.4 = 4.6 ft

The sum of supplementary angles is 180 degrees. The measure of angle 7 is 48 degrees

The sum of supplementary angles is 180 degrees.

Let the supplement of the angle be "x", so that;

x + 132 = 180

Subtract 132 from both sides

x + 132 - 132 = 180 - 132
x =. 180 - 132
x = 48 degrees

Hence the measure of angle 7 is 48 degrees

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Answer:

1522.584

Step-by-step explanation:

1500(1+.09/12)^2=1522.584