If a student wanted to write an essay about how to make his home more "green," which pre-writing strategy would be most helpful for generating ideas? a) indexing b) outlining c) draft writing d) concept mapping

Answers

Answer 1

Answer:

d) concept mapping

Explanation:

What is concept mapping?

This refers to diagram that shows the relationship between different concepts and is a useful pre-writing strategy to get useful ideas


Related Questions

Three times the square of a number is greater than a second number. the square of the second number increased by 6 is greater than the first number. which system of inequalities represents these criteria? one-thirdx2 > y and y2 + 6 < x one-thirdx2 > y and y2 + 6 > x 3x2 > y and y2 + 6 > x 3x2 > y and y2 + 6 < x

Answers

The system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.

How to solve Algebra Word Problems?

Let the first number be x and the second number be y.

We are told that three times the square of a number is greater than a second number. Thus; 3x² > y

Now, The square of the second number increased by 6 is greater than the first number. Thus;

y² + 6 > x

Thus, the system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.

where;

x is first number and y is second number.

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Amara needs to create a special tasting menu at her restaurant. she needs to select 444 dishes from 777 available dishes and put them in a tasty sequence. how many unique ways are there to arrange 444 of the 777 dishes?

Answers

Based on the above scenario, the unique ways there are to arrange 444 of the 777 dishes is 840 .

What is the arrangement about?

In the case above, the number of different arrangements of the dishes is said to be the product between the numbers of options and thus it is

4 x 3 x 2 x 1 = 24

Therefore, the total number of unique ways of arranging 4 of the 7 dishes will be:

D = 24 x 35 = 840

Therefore, Based on the above scenario, the unique ways there are to arrange 444 of the 777 dishes is 840 .

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The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in. what percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%

Answers

Answer: The answer would be 5%

Explanation:

The closest answer choice is 2.5%, which is the closest value to 1.7% given in the answer choices.

What is z-score?

The Z-score is a statistical measure that describes the relationship of a value to the mean of a group of values.

To solve this problem, we can use the standard normal distribution and the z-score formula:

z = (x - μ) / σ

Where x is the value we want to find the probability for, μ is the mean of the distribution, and σ is the standard deviation of the distribution.

In this case, we want to find the percentage of snakes that are longer than 16.6 in., which corresponds to a z-score of:

z = (16.6 - 15) / 0.8 = 2.125

Using a standard normal distribution table or calculator, we can find that the percentage of values in the distribution that are greater than a z-score of 2.125 is approximately 1.7%. Therefore, approximately 1.7% of snakes are longer than 16.6 in.

Thus, the probable answer is 2.5%.

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