I need some help please

find D which is the discriminant and with D < 0.

therefore the equation has an imaginary root and not a real root.

A total of 720 tickets were sold for the school play. They were either adult tickets or student tickets is mathematically given as

Generally, the equation for a sold tickets is mathematically given as

S=x+72

Therefore

x+x+72=772

2x+72=772

2x=772-72

x=350

In conclusion, tickets sold was

x=350

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Answer:

Adults = 448

Students = 888

Step-by-step explanation:

Write equations with info given

A = Adult tickets

S = Student tickets

5A+1S=3,128

A+S=1336

Subtract equations from each other

4A=1792

Solve for A

A=448

Plug A into second equitation

448+S=1336

Solve for S

S=888

Answer:

[tex]x= -\dfrac {9}2 +\dfrac{\sqrt{57}}{2},~~x = -\dfrac {9}2 - \dfrac{\sqrt{57}}{2}[/tex]

Step-by-step explanation:

[tex]~~~~~~~x^2 +9x +12 = 6\\\\\implies x^2 +9x = 6-12\\\\\implies x^2 +9x = -6\\\\\implies x^2 +2 \cdot \dfrac 92 \cdot x +\left(\dfrac 92\right)^2 -\left( \dfrac 92 \right)^2 = -6\\\\\implies \left(x+ \dfrac 92 \right)^2 -\dfrac{81}{4}= -6\\\\\implies \left(x +\dfrac 92 \right)^2 = -6 + \dfrac{81}4\\\\\implies \left(x + \dfrac92 \right)^2 = \dfrac{57}{4}\\\\\implies x+ \dfrac 92 = \pm\sqrt{\dfrac{57}4}\\\\\implies x = -\dfrac {9}2 \pm\dfrac{\sqrt{57}}{2}[/tex]

Answer:

Step-by-step explanation:

(a). In set notation:

B. { x | x < 2 }

(b).

( - ∞ , 2 )

(c). See attachment.

Domain of f(x) is {x | x ≠ 6} and Domain of g(x) is {x | x ≠ +7 and x ≠ +7}.

The domain of a function is the set of all input values that make the function possible.

Now, for f(x) = (x + 6)/(x² - 12x + 36)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 12x + 36 = 0

Solving this using quadratic formula gives; x = 6. Thus, domain of f(x) is;

Domain = {x | x ≠ 6}

Now, for g(x) = (x + 7)/(x² - 49)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 49 = 0

Solving this using quadratic formula gives; x = +7 or -7. Thus, domain of g(x) is; Domain = {x | x ≠ +7 and x ≠ +7}

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a. A critical point at x = 25 would mean f'(25) = 0 or doesn't exist. We have derivative

[tex]f(x) = x - k \sqrt x \implies f'(x) = 1 - \dfrac k{2\sqrt x}[/tex]

so that

[tex]f'(25) = 1 - \dfrac k{2\sqrt{25}} = 1 - \dfrac k{10} = 0 \implies \boxed{k=10}[/tex]

b. Taking the second derivative, we get

[tex]f''(x) = \dfrac k{4 x^{3/2}} = \dfrac5{2 x^{3/2}}[/tex]

At x = 25, the second derivative has a positive sign,

[tex]f''(25) = \dfrac 5{2 \times 25^{3/2}} = \dfrac 5{2\times5^3} = \dfrac1{50} > 0[/tex]

which means f(x) is concave upward around x = 25, so this critical point is a local minimum.

Answer:

See below

Step-by-step explanation:

h^2 - 5h = 84

h^2 - 5h - 84 = 0

Answer:

u should subract those not add

An equation is formed of two equal expressions. The correct option is A.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Ms. Banerjee bought a car for $22,500. The amount she paid for her new car was twice the amount she paid for her previous car, which she bought 8 years ago. Therefore, the equation shows p, the price in dollars that she paid for her previous car,

Price of new car = 2 (Price of the previous car)

22,500 = 2p

Hence, the correct option is A.

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Answer: a

Step-by-step explanation:

The number would you add to both sides of x² + 7x = 4 to complete the square option C 7²/2.

Suppose the considered quadratic equation is of the form

ax^2 + bx + c = 0

Then, completing the squares method tries to make a squared term in terms of x in the left side, so that x comes in linear form, instead of quadratic.

The given quadratic equation is

x² + 7x = 4

add  7²/2 to both sides of x² + 7x = 4 to complete the square

7²/2 = 49/4

x² + 7x + 49/4 = 4+ 49/4

(x + 7/2)² = 4+ 49/4

Thus, option C 7²/2 is correct.

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Answer: 1.) 3 2/3  2.) 2 9/10  3.) 9 11/15   4.) 7 11/12

B. Question 2,

My answer is reasonable, because if we round 1 7/10 to 2 and 1 1/5 to 1

2+1=3 and my answer is 2 9/10. This estimate makes sense because 2 9/10 can be rouned to 3, meaning it is reasonable.

Step-by-step explanation:

1 1/6 + 2 3/6= 3 4/6

Simplifyed=3 2/3

1 7/10 + 1 2/10 = 2 9/10

7 5/15 + 2 6/15= 9 11/15

4 8/12 + 3 3/12= 7 11/12

Answer:

there is no line

The linear equation that models the cost for having x additional family members added is:

c(x) = $75 + $10.99*x

Here we know that the plan has a fixed price of $75 plus $10.99 for each family member added beyond the primary account holder.

Then if there are x family members added, the cost will be:

$75 + $10.99*x

Then the linear equation that models the cost for having x additional family members added is:

c(x) = $75 + $10.99*x

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Answer:

m = 50h, where m is the distance traveled in miles

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

therefore then

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}[/tex]

Answer:

2x+3y=21.

the answer is [tex]\frac{3}{2}[/tex]

simplify the answer I think. x = 2 + y = 3 = 21

x = 2
x + 1 = 3

y = 3

y - 1

2 + 1 = 3

3 - 1 = 2

The answer will only be [tex]\frac{3}{2}[/tex] no y = [tex]\frac{3}{2}[/tex] just  [tex]\frac{3}{2}[/tex]

Don't forget to look at the picture

92.16 pi cm^3.

Step-by-step explanation:

Shape of a party hat : conical

Volume of a cone = (1/3)(pi)(r^2)(h)

(pi(1/3)(23.04)(12))cm^3

Therefore, approximately

92.16 pi cm^3.

The triangle is an isosceles right triangle. Then the value of x will be 1.27 cm.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The right-angle triangle is given below.

The given triangle is an isosceles right triangle.

P = B = x

Then we have

1.8² = x² + x²

2x² = 3.24

 x² = 1.62

   x = 1.27 cm

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Answer:

Normally,in calculating the amount of space an object occupies...the volume method is require due to 3 dimensional rule,vice versa an area

Answer:

x = 7

Step-by-step explanation:

8*7 - 6 = 50

The sine of ∠I is represented by the ratio 63:65

First, let's draw the triangle (see the picture below.)

We need to use it here.

-sin = opposite/hypotenuse

-cos = adjacent/hypotenuse

-tan = opposite/adjacent.

Assuming that ∠I is Ф,

we can see that its opposite side is equal to 63 and the hypotenuse is 65. Therefore,

[tex]sin(I)=\frac{63}{65} \\\\sinI=75^0[/tex]

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Answer:

0.18

Step-by-step explanation:

It’s right bc I got it correct with that answer

Answer:

60°

Step-by-step explanation:

Arc BC and Angle BWC are the same number of degrees.

When the vertex of an angle is at the center of a circle, its called a Central Angle. A central angle and the arc it "cuts off" have the same number of degrees.

Angle AWB and Angle BWC lay together on a straight line, so they add up to 180°.

180° - 120° is 60°

Angle BWC is 60° so Arc BC is 60°

Answer:

320 cents per pound

Step-by-step explanation:

so we do 9.60 divided by 3, which is 3.20. So, 3.20 for each pound. Now we need in cents. 3 dollars is 300 cents, plus another 20, so 320 cents. I hope this helped.

Answer:

that's easy all you have to do is find out what is the value of x then divided by 2 once you divide by 2 subtract 3x 18 and 0

Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

The general form of the equation of height for ballistic motion is ...

  [tex]h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}[/tex]

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

The solution is ...

  [tex]t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}[/tex]

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

Additional comment

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

Answer:

see the attachment photo!

Answer: The correct answer is 135 in².

Step-by-step explanation: An area of a polygon is this:

Area = (number of sides × length of one side × apothem)/2

(5 x 6 x 9) / 2 = 135