i have to finish this today HELPPPP!


a teacher asks five students to write an equation with a solution of x= 4 . the students and their equations are shown below. which of the following students correctly wrote an equation with x= 4 as the solution ? select three that apply

I believe that the answer is $426,960.

I hope this helps!

Answer:

Step-by-step explanation:

a

or D

Answer:

x=0 and x=-1

Step-by-step explanation:

Given: x^2+x=0

Factor: x(x+1)=0

Use Zero Product Property: x=0 and x+1=0

Therefore, x=0 and x=-1

Answer:

No

Step-by-step explanation:

70 is divisible by 5. 5 is not an even number.

Answer:

No

Step-by-step explanation:

The factors of 70 are 1, 2, 5,7,10, 14, 35, and 70. the even numbers are 2, 10,14, and 70. but there are odd numbers, like 1, 5, 7, and 35. And since we know there are odd factors, the answer is No. 70 has even AND odd factors.

Answer:

A (g(x) = }(x-2)5.1).

Step-by-step explanation:

The function which results after the sequence of transformations given is B. g(x) = 1/2 (x + 2)⁵ - 1.

Translation of functions is defined as the when each point in the original graph is moved by a fixed units in the same direction.

There are horizontal translation and vertical translation of functions.

Given function is,

f(x) = x⁵

When a function is compressed vertically, then new function formed will be of the form, k f(x), where k is the factor that is compressed.

After compress vertically by 1/2,

f(x) changes to 1/2 f(x) = 1/2 x⁵

After the horizontal translation of 2 units to the left,

1/2 f(x) changes to 1/2 f(x + 2) = 1/2 (x + 2)⁵.

After vertical translation of 1 unit to the down,

1/2 f(x + 2) changes to 1/2 f(x + 2) - 1 = 1/2 (x + 2)⁵ - 1

Hence the correct option is B . g(x) = 1/2 (x + 2)⁵ - 1.

Learn more about Transformations of Functions here :

https://brainly.com/question/13810353

#SPJ7

Your answer would be 57.5%.

Answer: I gotcha

Step-by-step explanation:

B, C, C, D, B

I just helped my brother with this

Answer:

-9

Step-by-step explanation:

yu subtract 21 from 30 and and just add a negative before the answer

Answer:

[tex]\boxed{ \displaystyle y = 7\sin\left(\frac{2}{9}x-\frac{1}{4}\right)}[/tex]

Step-by-step explanation:

we want to figure out the equation of a sine function that has the following characteristics.

the standard form of sine function is given by

[tex] \displaystyle y = a\sin(bx-c)+d[/tex]

where:

Finding a and phase shift:

a and c is simply given which is

finding b:

using the equation we acquire:

[tex]\dfrac{2\pi}{b}=9\pi[/tex]

solving the equation for b,we obtain:

b=2/9

finding d:

Since d Isn't mentioned, we would assume it 0

finding the equation:

substitute what we got:

[tex]\boxed{ \displaystyle y = 7\sin\left(\frac{2}{9}x-\frac{1}{4}\right)}[/tex]

and we're done!

Step-by-step explanation:

Choose the correct inequality that matches the information on the sign. the answers are

s<60

Answer:

B

Step-by-step explanation:

If you at the graph it shows that the dots in bettwen Y side (left side)

so the first dot is 15 due to it between 10 and 20 and the 2nd dot is 20

Answer:

B

-2(0)²+24(0)-54

= -54

Answer:

I think its C

Step-by-step explanation:

y intercepts (0,-54)

Answer:

32600

Step-by-step explanation:

Answer: 8

Step-by-step explanation:

Answer:

[tex]Pr = \frac{1}{26}[/tex]

Step-by-step explanation:

Given

In a deck of card, we have:

[tex]Cards = 52[/tex]

[tex]King[Heart] = 1[/tex]

[tex]Queen[Spade] = 1[/tex]

Required

The probability of obtaining a king of heart or a queen of spade.

The probability of king of heart is:

[tex]P(King[Heart]) = \frac{n(King[Heart])}{Cards}[/tex]

[tex]P(King[Heart]) = \frac{1}{52}[/tex]

The probability of queen of spade is:

[tex]P(Queen[Spade]) = \frac{n(Queen[Spade])}{Cards}[/tex]

[tex]P(Queen[Spade]) = \frac{1}{52}[/tex]

The required probability of obtaining a king of heart or a queen of spade. is:

[tex]Pr = P(King[Heart]) + P(Queen[Spade])[/tex]

[tex]Pr = \frac{1}{52}+ \frac{1}{52}[/tex]

Take LCM

[tex]Pr = \frac{1+1}{52}[/tex]

[tex]Pr = \frac{2}{52}[/tex]

Simplify

[tex]Pr = \frac{1}{26}[/tex]

Answer:

7 is the smallest number making it the closest to the x- axis.

Step-by-step explanation:

Answer:

[tex]d=1.61\times 10^{10}\ miles[/tex]

Step-by-step explanation:

Given that,

The speed of light, v = 300,000,000

eWe need to find the distance light travel in 1 day. We know that,

1 day = 86400 seconds

Distance = speed × time

So,

[tex]d=3\times 10^8\times 86400[/tex]

[tex]d=2.592\times 10^{13}\ m[/tex]

or

[tex]d=0.001610\times 10^{13}\\\\d=1.61\times 10^{-3}\times 10^{13}\\\\d=1.61\times 10^{10}\ miles[/tex]

So, the required distance is equal to [tex]1.61\times 10^{10}\ miles[/tex].

Answer:

I think B and D

Step-by-step explanation:

I’m not 100% sure tho

Answer:

15.2cm

Step-by-step explanation:

From the given diagram;

KN = SN = 14cm

KL = NT = 6cm

Required

ST

Using the Pythagoras theorem;

ST² = SN² + NT²

ST² = 14² + 6²

ST² = 196 + 36

ST² = 232

ST = √232

ST = 15.2cm

Hence the length of ST is 15.2cm

Answer:

[tex]1 \to 22 \to 0.176[/tex]

[tex]2 \to 13 \to 0.104[/tex]

[tex]3 \to 18 \to 0.144[/tex]

[tex]4 \to 29 \to 0.232[/tex]

[tex]5 \to 37 \to 0.296[/tex]

[tex]6 \to 6 \to 0.048[/tex]

Step-by-step explanation:

Given

[tex]n = 125[/tex]

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

[tex]Pr = \frac{Frequency}{n}[/tex]

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

[tex]Pr(2) = \frac{13}{125} = 0.104[/tex]

[tex]Pr(4) = \frac{29}{125} = 0.232[/tex]

[tex]Pr(6) = \frac{6}{125} = 0.048[/tex]

When the frequency is to be calculated, we use:

[tex]Pr = \frac{Frequency}{n}[/tex]

[tex]Frequency = n * Pr[/tex]

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

[tex]Frequency(3) = 125 * 0.144 = 18[/tex]

[tex]Frequency(5) = 125 * 0.296 = 37[/tex]

For roll of 1 where the frequency and the probability are not known, we use:

[tex]Total \ Frequency = 125[/tex]

So:

Frequency(1) added to others must equal 125

This gives:

[tex]Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125[/tex]

[tex]Frequency(1) + 103 = 125[/tex]

Collect like terms

[tex]Frequency(1) =- 103 + 125[/tex]

[tex]Frequency(1) =22[/tex]

The probability is then calculated as:

[tex]Pr(1) = \frac{22}{125}[/tex]

[tex]Pr(1) = 0.176[/tex]

So, the complete table is:

[tex]1 \to 22 \to 0.176[/tex]

[tex]2 \to 13 \to 0.104[/tex]

[tex]3 \to 18 \to 0.144[/tex]

[tex]4 \to 29 \to 0.232[/tex]

[tex]5 \to 37 \to 0.296[/tex]

[tex]6 \to 6 \to 0.048[/tex]

The minimum z-score that a data point could have to remain in the top 30% of the data is 0.52.

We have,

To find the minimum z-score that a data point could have to remain in the top 30% of a set of data, we need to find the z-score that corresponds to a cumulative probability of 0.70 (since the top 30% is equivalent to the cumulative probability of 0.70).

Using a standard normal distribution table or a statistical calculator, we can find that a cumulative probability of 0.70 corresponds to a z-score of approximately 0.52 (rounded to two decimal places).

Therefore,

The minimum z-score that a data point could have to remain in the top 30% of the data is 0.52.

Learn more about z-score here:

https://brainly.com/question/15016913

#SPJ2

Answer:

f(x) = (x - 3)^2 + 34

Step-by-step explanation:

Answer: 38.8

Step-by-step explanation:

use formula C = π * D

Diameter = 6

C = π * 6

C = 18.8495559215 = 18.8

18.8 + 10 + 10 = 38.8

Answer: q= 30

Step-by-step explanation:

Solve for q

by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

q>25

Interval Notation:

(25,∞)

Answer:

[tex]134.56[/tex]

Step-by-step explanation:

Break 11.6 into addenda.

[tex](11 + 0.6)[/tex]

Apply the binomial expansion method.

[tex](11 + 0.6)(11 + 0.6)[/tex]

[tex]11 {}^{2} = 121[/tex]

[tex]2(11)(0.6) = 13.2[/tex]

[tex]0.6 {}^{2} = 0.36[/tex]

Add them all up and you get.

[tex]134.56[/tex]

Answer:

46% is the percent of the bags of baby carrots that have between 90 and 100 carrots

Step-by-step explanation:

The baby carrot is normally distributed.  

z = (x - µ)/σ

x is equal to number of baby carrots  

µ = mean

σ = standard deviation

Substituting the given values, we get -

90 ≤ x ≤ 100

z = (90 - 94)/8.2 = - 0.49

 For z value of -0.49, the probability is 0.31

For x = 100

z = (100 - 94)/8.2 = 0.73

For z value of 0.73, the probability is 0.77

P(90 ≤ x ≤ 100) = 0.77 - 0.31 = 0.46

The percent of the bags of baby carrots having carrots between 90 and 100 carrots is  0.46 × 100 = 46%

Answer:

See step by step explanation

Step-by-step explanation:

From the problem statement, we understand that we need to investigate if 2nd graders RETAIN OR LOSE knowledge comparing information concerning two different months, therefore we are going to find out if the information gives us enough evidence of a difference in the two groups

a) The test should be a two tail-test

Sample sizes are small ( n₁ = n₂  = 9 ) which means we have to use  t-student test

b   and    c) Test Hypothesis:

For Null Hypothesis H₀,  we establish that the two means are equal, which in this case means that the two samples´ means are equal. And as Hypothesis alternative Hₐ that the H₀ is not true,  or that the samples mean are different.

Null Hypothesis     H₀             x₁  -  x₂   = 0   or    x₁  =  x₂

Alternative Hypothesis  Hₐ    x₁  -  x₂   ≠  0   or   x₁  ≠  x₂

d) Significance level α  = 0,05   then   α/2  = 0,025

then t(c)  with  α/2  =  0,025  and degree of freedom  

df =  n₁  +  n₂  - 2      df =  9 + 9 -2     df = 16

From t s-tudent table we find     t(c) =  2,12

e) Calculating:

x₁   and  σ₁

x₂  and  σ₂

σₓ  = [ ( n₁ - 1 )* σ₁² + ( n₂  - 1 )*σ₂² ]/ n₁ + n₂ - 2

Using a calculator:

x₁  =  77,11        σ₁  = 13,86

x₂  = 85,89      σ₂  = 12,74

σₓ  = [ ( 8*(13,86)² + 8*( 12,74 )² ] / 16

σₓ  =  (8* 192,1) + 8* ( 162,31) / 16

σₓ  = (1536,8 + 1298,48 ) / 16

σₓ  =  177,205

t(s) = ( x₁ - x₂ ) /√ σₓ²/ n₁  + σₓ²/ n₂

t(s) = ( 77,11 - 85,89 )/ (177,205)²/n₁ + (177,205)²/n₂

t(s) = - 8,78 / √3489,07 + 3489,07

t(s) = -8,78 / 83,54

t(s) =  - 0,11

Comparing  t(s) and  t(c)

|t(s)| < |t(c)|      

0,11 <  2,12

t(s) is in the acceptance region. We accept H₀