Solution :
Given :
Hydrogen iodide decomposes to hydrogen and iodine gas
[tex]$2 HI \ \ \ \Leftrightarrow \ \ \ \ H_2 \ \ \\ + \ \ I_2 $[/tex]
I 0.148 0 0
C -2a +a +a
E 0.148-2a a a
We know
[tex]$k_p=\frac{P(H_2)P(I_2)}{P(HI)^2}$[/tex]
[tex]$0.016=\frac{a^2}{(0.148-2a)^2}$[/tex]
[tex]$0.016^{1/2}=\frac{a}{0.148-2a}$[/tex]
[tex]$0.12649=\frac{a}{0.148-2a}$[/tex]
0.0187 = 1.2529 a
a = 0.0149
Therefore
P(HI) = 0.148 - 2a
= 0.148 - 2(0.0149)
= 0.1182 atm
P([tex]$H_2$[/tex]) = a
= 0.0149 atm
P([tex]$I_2$[/tex]) = a
= 0.0149 atm
14. Simply, explain the role of both the nucleus and the ribosome in protein synthesis.
Answer:
Eukaryotic cells have a true nucleus, which means the cell's DNA is surrounded by a membrane. Therefore, the nucleus houses the cell's DNA and directs the synthesis of proteins and ribosomes, the cellular organelles responsible for protein synthesis.
Ribosomes are the sites in a cell in which protein synthesis takes place. ... Within the ribosome, the rRNA molecules direct the catalytic steps of protein synthesis — the stitching together of amino acids to make a protein molecule.
The lattice-like structure of a metal consists of negative metal ions in a "sea" of electrons.
O True
O False
Answer:
True
Explanation:
A gas has a solubility of 2.45 g/L at a pressure of 0.750 atm. What pressure wold be required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature
Answer:
1.91 atm
Explanation:
Step 1: Calculate Henry's constant (k)
A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry's law.
C = k × P
K = C/P
K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm
Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.
We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:
C = k × P
P = C/k
P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm
write a story of your life when you were hurted by someone whom you trusted blindly...
Answer:
Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u
Which of the following is an example of an environmental impact of agriculture?
high use of mineral resources
high use of water
high use of gold, copper, and silver
high use of rock supplies
Answer:
high use of mineral resources
Explanation:
brainliest pls
7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?
Answer:
0.0428 kg or 42.8 g
Explanation:
Applying,
Q = cmΔt.............. Equation 1
Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.
make m the subject of the equation above
m = Q/cΔt.................. Equation 2
From the question,
Given: Q = 428 J, Δt = 25 °C
Constant: c = 400 J/kg.°C
Substitute these values into equation 2
m = 428/(25×400)
m = 0.0428 kg
m = 42.8 g
Question 4 (10 points)
If a sollition has a pOH of 5.2 the [OH-] of the solution is
оа
6x 10-6 M
Ob
6.3 x 10-6 M
Oc
1.58 x 10-5M
Od
2x10-5M
Answer:
Explanation:
Select the correct answer.
Using this activity chart, which reaction will happen when a piece of copper is placed in a lead nitrate solution?
A.
2Cu + 3Pb(NO3)2 3Cu(NO3)2 + 2Pb
B.
No reaction occurs.
C.
2Cu + 3Pb(NO3)2 2Cu(NO3)2 + 3Pb
D.
3Cu + 3Pb(NO3)2 3Cu(NO3)2 + 3Pb
E.
The answer cannot be determined from the information given.
Answer:
B, No reaction will occur
Explanation:
Copper as compared to lead is less reactive. This is the reason when lead is added to copper nitrate solution, it replaces the copper and itself combines with nitrate to form lead nitrate aqueous solution
Lead + Copper(II) nitrate → Copper + Lead (II) nitrate
The same is not the case when the reaction is revered i.e Cu is added to Pb NO3 solution.
Hence, option B is correct
A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation) form and show that charge and lepton number is conserved. 2. What is the total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons
The equation in the symbolic form can be written as,
[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]
The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.
What is the meaning of lepton?Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.
The equation in the symbolic form can be written as,
[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]
Charge on the left side = -1
Charge on the right side = -1+0+0 = -1
As the charge on the electron antineutrino, [tex]{\bar{\nu }}[/tex] e and the tau neutrino, [tex]\nu\tau[/tex] are zero each.
Thus, charge on left side = charge on right side
Or, the equation is in accordance with charge conservation.
Lapton number of left side = 1
Laptop number of right side = 1-1+1 = 1
This is because, lapton number of the particles involved are,
Tau lapton, [tex]\tau[/tex]-1 = 1,
Electron, e-1 = 1,
Electron antineutrino, [tex]{\bar{\nu }}[/tex]e = -1,
Tau neutrino, [tex]\nu\tau[/tex]= 1,
Thus, lapton number of left side = lapton number of right side
So, the equation obeys lapton number conservation.
2.
The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:
Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.
Just simply multiply 3 quarks by the number of nucleons:
So, 3 (quarks) x 4 (nucleons) = 12 quarks
Therefore, there are 12 quarks in 4 nucleons.
Learn more about lepton decays here:
https://brainly.com/question/12044097
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There are 6 different organisms in the picture above. Organize them into 2 or more groups AND defend your groups by
providing details about why you put them into the chosen groups.
Example on how to answer:
Group 1- XYZ
Group 2-LM
Group 3- PORS
I put XYZ in group 1 because...
I put LM together because...
I grouped PORS together because...
Explanation: they could be grouped by how they reproduce or they can be grouped by if there hetero or autotrophic
(NH4)2Cr2O7 Cr2O3 + N2 + H2O
If 4.7369 moles of H2O are produced, how many moles of (NH4)2Cr2O7 were reacted?
Answer:
the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).
What is the name of Na