Answer:
We at Bright Side invite you to take a look at what you can expect from your body when you finally pull yourself together and start training. Illustrated by Ekaterina Gapanovich for Bright Side.
Explanation:
Possibility of causing unnecessary stress and strain on your muscles, especially your heart.
What if I didn't warm-up exercises before doing any physical activities?To help prevent injury, include static stretches in your cool-down routine. Static stretching as part of a maintenance stretching program can also help lower your risk of injury.Possibility of causing unnecessary stress and strain on your muscles, especially your heart. Inability to prepare the pathways between your nerves and muscles for a good workout. Inability to increase blood flow into muscle groups, which is critical for delivering oxygen and nutrients.Stretching is relaxing because it activates the parasympathetic nervous system and increases blood flow to the muscles.To learn more about : Static stretching
Ref : https://brainly.com/question/1297773
#SPJ2
Which structure in plants produces a substance that protects the extending roots from developing friction?
a.root cap
b. stele
c.stem
d.epidermis
Answer:
The correct answer is - option a. root cap.
Explanation:
Roots of the plants are developed from the structure called radical in seed during germination of seed.The tip of the root is tender due to the present of the apical meristem that is the precursor of the new cells of the root and protected by the root cap and penetrate in to the soil with the help of mucigel. Mucigel is the which protects the extending roots from developing friction.
Thus, the correct answer is : option a. root cap.
Answer:
The answer is ROOT CAP
Explanation:
Got it right on my test.
Explain to your lab mate the health risk associated with consuming a diet low in vitamin K along with the ingestion of antibiotics over multiple days. How would the termination of antibiotic treatment help to remove this health risk?
Answer:
Vitamin K, a fat soluble vitamin is rich in green leafy vegetables,and also produced by bacterial in the intestine.
Its major function is blood clotting or arrest of bleeding to prevent blood loss.
Antibiotics especially with Cephalosporins,reduces Vit. K absorption in the intestine. Intake of these antibiotic kill the targeted bacterial together with the the bacteria which produces Vit. K in the intestine.
Hence when antibiotic is taken with low level of Vit, K the individual is prone to excessive bleeding or haemorrhage,because the concentration of the vitamins is further depleted.
If the medication is stopped,the condition will improve because the bacteria which produces Vt K can resumes the secretions,and its absorption will resume
Explanation:
ABO blood type is examined in a Taiwanese population, and allele frequencies are determined. In the population,
f (IA) = 0.30,
f(IB) = 0.15, and
f (i) = 0.55.
What are the frequencies of the various genotypes and various phenotypes in this population? Assume Hardy-Weinberg equilibrium.
Answer and Explanation:
Due to technical problems, you will find the answer and explanation in the attached file.
Why it is important to emasculate and bag wheat, oats and groundnut flowers before a cross is made by using another desirable plant.
Answer:
There are no options in this question but it can be answered using general knowledge. The answer is:
In order to prevent self-pollination or natural cross-pollination of the wheat, oats or groundnut flowers.
Explanation:
The flowers of wheat, oat and groundnut plants have something in common, which is the fact that they are all bisexual flowers i.e. flowers that have both male and female reproductive parts. Hence, they tend to undergo self-pollination i.e. transfer of pollen to female reproductive part on the same flower.
To prevent this from occuring when a desirable trait is wanted during crop breeding procedures, a process called EMASCULATION is carried out. Emasculation is the process whereby the stamen (male flower) or pollen of a plant is removed without destroying the female part of the flower. This is done in order to discourage self-pollination in plants with a bisexual flower.
Also, after emasculation, the flowers are bagged in order to prevent natural cross-pollination i.e. to prevent pollens from other plant from being transferred to the stigma of the desired plants in random manner.
Hence, emasculation and bagging is important to make sure the desired plants are still viable for the crop breeding procedure.
Marking as brainliest
name another type of compound ( besides polysaccharides) that fits the definition of polymer
Answer:
A protein is also a polymer. The monomer in this case would be the subunits comprised of amino acids.
DNA. The subunits are nucleoTides.
Explanation:
Brainliest please
The main function of a cell membrane is to allow substances to enter and leave the cell. Which is a correct description of transport through a cell membrane
Answer:
The question is incomplete, below is the completed question:
The main function of a cell membrane is to allow substances to enter and leave the cell. Which is a correct description of transport through a cell membrane ?
a. Diffusion, or passive transport, occurs when molecules diffuse from a lower concentration to a higher concentration.
b. Facilitated transport occurs when proteins that extend through the cell membrane provide a channel through which certain substances can diffuse more rapidly than by passive diffusion.
c. The lipid bilayer opens up and allows the ions or molecules to enter the cell, then closes.
d. Active transport occurs when molecules diffuse from a higher concentration to a lower concentration.
Answer:
b. Facilitated transport occurs when proteins that extend through the cell membrane provide a channel through which certain substances can diffuse more rapidly than by passive diffusion.
Explanation:
Transport through cell membranes can be broadly classified as active transport or passive transport.
Active transport requires energy in the form of ATP for the transportation of substances across the cell membrane.
Option b correctly describes facilitated diffusion, which is a passive-mediated diffusion process, where channels in the cell membrane mainly composed of proteins called transmembrane integral proteins, allow for the movement of certain molecules (mostly polar/hydrophilic) molecules that will not otherwise be transported through simple diffusion because of the hydrophobic nature of the cell membrane.
The other options are wrong because:
a. diffusion or simple transport involves the movement of substances from regions of higher to a lower concentration not lower to higher as suggested here.
c. The lipid bi-layer does not allow ions or hydrophilic molecules because it is hydrophobic in nature, and it is not a channel, so it does not open and closes
d. In active transport, transfer of molecules is from regions of lower to higher concentration and not higher to lower concentration as suggested here.
Which is a function of the cell membrane? performs photosynthesis controls what enters and leaves the cell produces proteins provides energy to the cell
Answer: controls what enters and leaves the cell
Explanation: it is a barrier keeping the constituents of the cell in and unwanted substansces out and is also a gate allowing transport into the cell of essential nutirnts and movement from cell of waste products.
The cell membrane is also referred to as the plasma membrane or cytoplasmic membrane of the cell. It lays various functions in the cell.
The correct answer is:
Option B. controls what enters and leaves the cell
Role of the cell membrane are:
The cell membrane is a biological membrane, which separates the interior of the cell from the external environment. The cell membrane is selectively permeable such that it allows certain molecules to pass through them. The cell membrane controls the entry and exiting of molecules from the cell.
Thus, the correct answer is Option B.
To know more about cell membrane, refer to the following link:
https://brainly.com/question/17254662
On April 26, 1986, Reactor 4 at the Chernobyl Nuclear Power Station in Ukraine exploded, releasing radioactive isotopes into the air. The majority of the isotopes that were released and spreading thousands of miles were of the element iodine. As a class, discuss what endocrine glands would be most affected and how it would become apparent in the nearby population.
Answer:
In the given case, the thyroid gland will be affected the most due to the exposure of the element iodine. For the synthesis of thyroid gland hormone, T3 and T4 iodine is required. As the exposure of the radioactive iodine element is taking place, therefore, it will result in the deterioration of the thyroid gland. Radioactive iodine is generally used in the treatment of hyperthyroidism.
However, in normal individuals, the exposure of the radioactive iodine element results in a decrease in the level of thyroid hormones below the normal level due to the destruction of the thyroid cells. The symptoms seen can be neck tenderness, swollen salivary gland, and loss in body weight.
The thyroid gland will be mostly affected in this case. The element Iodine is
the major precursor which is involved in the formation of two hormones.
Thyroid hormonesTriiodothyronine (T3)Thyroxine (T4).When an individual is exposed to radioactive iodine , it alters the production
of the hormones which leads to series of effects such as:
Decreased metabolismLow body weightGoitre etc.Read more about Thyroid hormones here https://brainly.com/question/2469666
g Cell autonomous genes affect only those cells in which they are expressed. Which group of early developmental genes are not cell autonomous?
Answer:
The options are not given..
Here are the options.
A. segment polarity genes
B. gap genes
C. coordinate genes
D. homeotic genes
The correct option is A.
segment polarity genes
Explanation:
Segment polarity genes is a group of early developmental genes that are not cell autonomous because their expression helps to define anterior and posterior polarities within each embryonic parasegment. They are the genes that help to function for the polarity within each parasegment of the embryo
If a cusp is lost during preparation, which matrix band would provide the best support while restoring
Answer:
I would use a specialized or preformed matrix for the posterior sector.
Explanation:
Losing a cusp is a much more critical situation, that is, there will be less tooth remnant and less resistance to functional and parafunctional forces.
The matrices that are usually used in the posterior sector are matrices that must be burnished and already come with a format to better restore the functional unit of the occlusal surface.
It is important to clarify that cusps are only in the posterior sector and not in the anterior sector.
The cusps, even if they have the most correct selection of the matrix, will fail in their restoration if they are not performed according to the patient's occlusion, under a good dental integration system such as adhesion through resins, and respecting the normal antomy of the piece to be restored.
In a population of flowers growing in a meadow, C1 and C2 are autosomal codominant alleles that control flower color. The alleles are polymorphic in the population, with f (C1) = 0.8 and f (C2) = 0.2. Flowers that are C1C1 are yellow, orange flowers are C1C2, and C2C2 flowers are red. A storm blows a new species of hungry insects into the meadow, and they begin to eat yellow and orange flowers but not red flowers. The predation exerts strong natural selection on the flower population, resulting in relative fitness values of C1C1 = 0.30, C1C2 = 0.60, and C2C2 = 1.0.
Required:
a. What is the C1C2 genotype frequency among the progeny of predation survivors?
b. What is the C2C2 genotype frequency among the progeny of predation survivors?
c. What is the C2C2 genotype frequency among the progeny of predation survivors?
d. What is the equilibrium C2 allele frequency in the predation environment?
Transcriptional regulation of operon gene expression involves the interaction of molecules with one another and of regulatory molecules with segments of DNA. In this context, define and give an example of each of the following:
a. operator
b. repressor
c. inducer
d. corepressor
e. promoter
f. positive regulation
g. allostery
h. negative regulation
i. attenuation
Answer and explanation:
The operator is a DNA fragment localized between the promoter and structural gene sequences that are able to repress operon transcription. A repressor is a molecule that binds to the operator to inhibit transcription, while an inducer is a molecule that activates transcription by binding either to the repressors or to the activators. A corepressor is a molecule that binds to repressors in order to activate them. A promoter is a DNA sequence localized upstream structural genes which binds to a transcription factor in order to activate operon transcription. Positive regulation is the process by which operon transcription acts as a positive loop, thereby increasing its own transcription, while negative regulation is the process by which operon transcription inhibits its own expression. Allostery refers to the process by which a molecule regulates operon transcription by binding to distal (and therefore non-functional) sites of the operon. Attenuation is a process able to reduce operon transcription and also to block subsequent translation.
The vector allows for protein expression in E. coli.
Briefly explain the role of the following elements in the context of gene expression and protein production:
1- LacP:
2- LacO:
3- LacZa:
4-Briefly explain and indicate what is required for high expression in E. coli in this context..
The vector also contains other important elements. Explain their role:
5- AmpR:
6- ori:
Answer:
1. Lac P or the promoter is the binding site for RNA polymerase, situated just upstream to the gene.
2. Lac O or operator is a sequence situated just downstream to the sequence of the promoter at which binding of the repressor protein is done and ceases RNA polymerase enzyme from binding.
3. Lac Z refers to the gene that encodes for protein beta-galactosidase, which further results in the formation of glucose and galactose from lactose.
4. For high expression in E.coli IPTG is required. It attaches with the lac repressor and discharges the tetrameric repressor from the lac operator in an allosteric fashion, thus, permitting gene transcription in the lac operon.
5. AmpR is also known as the ampicillin-resistant gene, which is utilized as a selective marker for selection against ampicillin antibiotic.
6. Ori or the origin of replication refers to the sequence of the genome, which is accountable for the initiation of replication.
somebody help me please A cross is performed between a bird that is homo for red feathers and a bird that is homo for blue feathers. Purple offspring result due to incomplete dominance. Then, two of the purple offspring are crossed. What proportion of the offspring from the second cross will be purple? 1 in 4 2 in 4 3 in 4 4 in 4
Answer:
2 in 4
Explanation:
Let PP are the gametes of red feather bird and pp are the gamete of blue feather bird. In the first cross they both will give purple feather bird because of incomplete dominance.
Consider Pp as the allele of purple offspring for the second cross. When two of the purple offspring are crossed, it will give the proportion of 2 in 4
F2: Pp X Pp
Offspring: PP, Pp,Pp, pp
So, only two offspring, Pp is with purple feathers while PP has red and pp has blue feathers.
Hence, the correct option is 2 in 4.
The proportion of the offspring from the second cross that would be purple will be 2 in 4.
Let us assume that the red feather color is controlled by allele A and that of blue feather color is controlled by allele B.
Homzygous red feather birds will have the genotype AA
Homzygous blue feather birds will have the genotype BB
Crossing the 2 birds:
AA x BB
AB AB AB AB
Thus, the purple offspring are AB.
Crossing 2 of the purple offspring:
AB x AB
AA AB AB BB
1 AA - red
2 AB - purple
1 BB - blue
Thus, 2/4 or 1/2 or 50% of the offspring from the second cross will be purple.
More on incomplete dominance can be found here: https://brainly.com/question/13402032
____ are thought to be present before vertabrates
Answer:
Jawless fish was present before vertebrates.
Explanation:
Jawless fish has some characteristics of vertebrates and also considered as the ancestor of vertebrates on earth which is similar in appearance with the hagfish. It was present about 500 to 600 million years ago. They consist of cranium but vertebral column is absent. but with the passage of time, evolution occurs and many animals which was the descendant of this jawless fish having vertebral column or backbone in their body.
Explain the relationship between a thriving civilization and it’s agriculture system? In a paragraph
Answer:
They use advance technologies in agriculture.
Explanation:
There is a direct relationship between thriving civilization and it’s agriculture system because they use advance methods and technologies in agriculture instead of traditional practices. They use heavy machinery for tillage in order to save the time, use high yielding varieties, use proper dose of fertilizers, use of pesticides and weedicides in order to protect the crop. They harvest the crop by using thresher in order to avoid post harvest losses. In short, they use all technologies available to make a higher yield in order to earn more profit.
The anticodon (Select all that apply):
a. is a triplet of nucleotides in tRNA
b. determines the identity of the amino acid to be added to the peptide chain
c. is complementary to the codon
d. binds to the codon via hydrogen bonds
Answer:
choice A
Explanation:
An anticodon is a trinucleotide sequence complementary to that of a corresponding codon in a messenger RNA (mRNA) sequence. An anticodon is found at one end of a transfer RNA (tRNA) molecule.
____________ a regulatory protein that may bind DNA to inhibit transcription. ____________ a DNA sequence that binds a regulatory protein. ____________a DNA sequence that binds RNA polymerase and regulates transcription. ____________a compound that interacts with another protein or compound to form an active repressor ____________a compound that induces or activates transcription, such as lactose.a. Repressorb. Operator c. Promoterd. Corepressore. Inducer
Answer:
A repressor is a regulatory protein that may bind DNA to inhibit transcription. An operator is a DNA sequence that binds a regulatory protein. A promoter is a DNA sequence that binds RNA polymerase and regulates transcription. A corepressor is a compound that interacts with another protein or compound to form an active repressor. An inducer is a compound that induces or activates transcription, such as lactose.
Explanation:
Repressor proteins bind to DNA and RNA to suppress target gene expression. A DNA repressor blocks transcription by inhibiting the attachment of RNA polymerase to the promoter sequence, while an RNA repressor bind to the mRNA to block translation of the protein. An operator is a DNA sequence required for the attachment of transcription factors. The genes that are transcribed by the binding of a transcription factor to an operator sequence are collectively referred to as an operon. Operons are generally found in prokaryotes but they also can be found in some eukaryotes including Caenorhabditis elegans and Drosophila melanogaster. An inducer is a molecule that activates gene transcription either by binding to repressors/corepressors (thereby inactivating their functions) or by binding activators. For example, the allolactose act as an inducer of the lac operon.
The mechanisms regulating sodium and water balance help maintain blood pressure homeostasis. These mechanisms include the renin-angiotensin II mechanism, neural regulation, and ADH.
Match each item to the appropriate category. Keep in mind relationships may be direct or indirect.
Categories:
1. Angiotensin II.
2. Sympathetic Nervous System
3. Both
a. stimulates ADH release
b. stimulates renin release
c. stimuates aldosterone release
d. increases sodium uptake
e. increases water reabsorption
f. stimulates vasoconstriction
g. increases peripheral resistance
h. stimulated by baroreceptors in blood vessels
i. stimulated by low blood pressure or volume
Answer:
a. stimulates ADH release : 2. Sympathetic Nervous System
b. stimulates renin release : 2. Sympathetic Nervous System
c. stimulates aldosterone release: 3. Both
d. increases sodium uptake : 1. Angiotensin II
e. increases water reabsorption: 2. Sympathetic Nervous System
f. stimulates vasoconstriction: 1. Angiotensin II.
g. increases peripheral resistance : 1. Angiotensin II.
h. stimulated by baroreceptors in blood vessels: 2. Sympathetic Nervous System
i. stimulated by low blood pressure or volume: 3. Both
Explanation:
The antidiuretic hormone is one of the hormones released by the hypothalamus (regulator center in the brain) and collected by the posterior hypophysis from where they are then released again to the system. This hormone, also known as vasopressin hormone, is released by changes in serum osmolarity or blood pressure. The osmotic receptors are located in the hypothalamus, while the pressure receptors are located in the heart, the aorta, and carotids. The amount of hormone secreted depends on these two aspects. Its function is to keep homeostasis and make kidneys conserve or excrete water to regulate its volume. The antidiuretic hormone stimulates water reabsorption when factors such as dehydration or hemorrhages are causing an increase in blood solutes. It might also stimulate water excretion when solutes in the blood are very low or blood pressure is too high.
Aldosterone is another hormone that acts stimulating the sodium ions reabsorption. This hormone production is controlled by a circuit named the renin-angiotensin-aldosterone system. This system is activated by the decrease of blood supply to the kidney, and hence, the decrease in blood pressure and sodium concentration. These factors cause the release of the renin, a proteolytic enzyme that acts on angiotensinogen producing angiotensin I which is converted into angiotensin II. Angiotensin II is a peripheric vasoconstrictor peptide, that can increase the blood pressure when it is circulating in the plasma. It also stimulates the secretion of aldosterone.
What complications might arise from genetic screens targeting an organ that differentiates late in development?
Answer:
No sign of testicular development in boys and breast development in girls.
Explanation:
Complications like no sign of testicular development in boys and breast development in girls occurs if an organ develop very late. There are many causes of this type of complications such as long term illness, eating improper food and disorder of sexual development. Sometime these complications also occurs due to genetically. These complications should be treated well with medication and use of nutritious food. These medicines increases the performance of sex hormones in order to initiate puberty.
g dGDP is made from ________ by the ribonucleotide reductase. This enzyme is inactive when ______ is bound to its master regulatory pocket.
Answer:
1. GTP dephosphorylation
2. hydrolyzed or removed
Explanation:
GDP, (Guanosine diphosphate) is a biological term, that is made of composition including pyrophosphate group, a pentose sugar ribose, and the nucleobase guanine and it is made from GTP ( Guanosine triphosphate ) dephosphorylation by the ribonucleotide reductase. This enzyme is inactive when hydrolyzed or removed, and then eventually bound to its master regulatory pocket.
The backbone vertebrae, skull, and rib cage make up the _______ skeleton. Among other types of cells, bone marrow produces _______ blood cells, which carry oxygen in the blood. _______ can eventually become osteocytes. If bones rapidly deconstruct faster than new bone tissue grows, this can lead to less dense and more fragile bones. When severe, this condition is called _______. _______ such as the MCL and ACL connect bone to other bone at joints.
ANSWERS :
1.axial
2. red
3. Osteoblasts
4. osteoporosis
5. Ligaments
6. Osteoblasts are cells that build bone tissue, and are called osteocytes when they become surrounded by the bone that they have built. Osteoclasts are cells that break down bone tissue. The building and breaking down of bone tissue continues throughout a person’s lifetime and makes bones strong. If osteoclasts break down more bone than osteoblasts build, this can lead to osteopenia and osteoporosis, causing bones to be fragile and break more easily.
Answer:
1. axial
2. red
3. Osteoblasts
4. osteoporosis
5. Ligaments
Explanation:
The axial skeleton consists of the bones of the head and trunk of a vertebrate including skull, and rib cage.
Bone marrow produces red blood cells, which carry oxygen in the blood.
Osteoblasts can become osteocytes, which are the third type of bone cells.
Osteoporosis is a bone resorption disease in which bones rapidly deconstruct faster than new bone tissue grows, and decreases the mechanical strength of bones.
Ligaments connects one bone to other at joint such as medial collateral ligament (MCL) and anterior cruciate ligament (ACL) that joins knee.
Hence, the correct answer for the question is as follows:
1.axial
2. red
3. Osteoblasts
4. osteoporosis
5. Ligaments
Answer:
1. axial
2. red
3. Osteoblasts
4. osteoporosis
5. Ligaments
6. Osteoblasts are cells that build bone tissue, and are called osteocytes when they become surrounded by the bone that they have built. Osteoclasts are cells that break down bone tissue. The building and breaking down of bone tissue continues throughout a person’s lifetime and makes bones strong. If osteoclasts break down more bone than osteoblasts build, this can lead to osteopenia and osteoporosis, causing bones to be fragile and break more easily.
Explanation:
Penn Foster
if a short sequence of dna reads 3'TAACGTCCAGGCAAA5', what is the complementary sequence in the other strand of dna g
Answer:
5' ATTGCAGGTCCGTTT 3'
Explanation:
Complimentary strands of DNA run anti-parallel to each other, the ends facing in opposite directions.
The complimentary base pairs for DNA are:
A=T and C=G and when finding the complimentary strand these pairs are only paired with each other.
which of the following MOST directly influences a measurable outcome in an experiment?
Answer:
Hello. You did not enter the answer options, but the factor that most directly influences a measurable result in an experiment is the manipulation of the variables.
Explanation:
In an experiment, the manipulation of variables becomes highly important so that it is possible to measure, that is, evaluate the result. This is because it is the variables that express values that represent the characteristics that are being analyzed and studied within the experiment. Therefore, the manipulation between them must be done in a very rational and balanced way so as not to modify the values shown by them, changing the data and generating false or immeasurable data.
n your lab you are studying the genome of venomous rattlesnakes to find the gene which codes for their venom glands. You have two rattlesnakes, one rattlesnake has a mutation but can still produce venom. You compare his DNA to a normal rattlesnake. What type of mutation has occurred? Normal: AATCGCTACGCACGTCAG Mutated: TATCGCTACGCACGTCAG
Answer:
There are no options but the kind of mutation that occurred by carefully observing both sequences is:
POINT SUBSTITUTION MUTATION
Explanation:
Mutation is any change, whether small or big, in the nucleotide sequence of a gene (DNA). Mutation occurs from time to time in an organism either by a mistake during DNA replication or induced by a mutagen (mutation-causing substance). Mutation can be of different types depending on the effect on the mutant.
In this case of comparing the DNA sequence two rattle snakes, the sequences of the two snakes are:
Normal: AATCGCTACGCACGTCAG
Mutated: TATCGCTACGCACGTCAG
By carefully observing the two DNA sequences, one would realize that the only difference in the two sequences is the first nucleotide base. That is, in the normal sequence, th first base is Adenine (A) while in the mutated sequence, the first base is Thymine (T).
This type of mutation that involves only one nucleotide base is called POINT MUTATION. It can also be noticed that base "A" was changed "T". Hence, this is a type of SUBSTITUTION MUTATION because a single base was replaced by another in the sequence.
A graduate student studying biology at the University of Nebraska has identified a new species of spider found only in Eastern Nebraska around Omaha. The graduate student determines that the spider has six homologous pairs of chromosomes. How many chromosomes would a cell in that spider have during metaphase of mitosis?
Answer:
12 chromosomes
Explanation:
Mitosis is a type of cell division that involves the formation of two genetically identical daughter cells. The two daughter cells are genetically identical in the sense that they contain the same number of chromosomes as the parent cell. Mitosis involves four stages namely: Prophase, Metaphase, Anaphase and Telophase.
In the metaphase stage as stated in this question, homologous chromosomes align at the equator of the cell called cell plate, before each chromatids are pulled apart by microtubules at the Anaphase stage.
According to the question, the spider being worked on has 6 pairs of chromosomes, which will align at the cell's equator during metaphase stage of mitosis. Since the replicated chromosomes (chromatids) are yet to separate to opposite poles of the cell, the cell will still contain 12 chromosomes at the metaphase stage.
N.B: Each chromosome contains 2 chromatids or replicated chromosome, which will be separated at the Anaphase stage. Each chromatid will be an individual chromosome after cytokinesis.
Describe at least 2 benefits and 2 drawbacks there might be for animal cells (including humans) to make their own food through photosynthesis.
Answer:
Explanation:
Benefits
Animals will not depend on plant source again for their food but have it produced directly by themselves because photosynthesis will allow animal produce their own food
Animal will get a direct source of energy for their activities. Energy is derived from food consumed after the food has been broken down in the body system of animal. Animal photosynthesis will give animals access to direct source of energy as the product their food.
Demerit
Animal lacks chlorophyll the green. Pigment in plant that light hit on absorption that will enable them to photosynthesis.
Animal lacks ways or mechanism of regulating Carbondioxide in take as in the case of C4 plant and crassulacean metabolic pathway (CAM).
Animals such as human will not have access to varieties of food but stick to photosynthate produced by them.
Studies of the relative efficacy or nonefficacy of a drug based on specific genotypes would be considered part of the field of
Answer:
Personalized genomic medicine
Explanation:
Personalized genomic medicine is a field that uses genomics data to develop personalized technologies and therapies for clinical care. All people share a sequence homology level higher than 99%; however a very small fraction of the genome (lesser than 1%) contains genetic polymorphisms among individuals, and this variation is associated with the likelihood of suffering diseases, either by increasing or by reducing disease susceptibility. Personalized genomic medicine first identifies genetic variations and then develops new strategies and personalized drugs to treat genetic disorders.
Give four reasons why th toe operating system pivotal in teaching and learning
The correct answer to this open question is the following.
The four reasons why the operating system is pivotal in teaching and learning are the following.
1) Operating systems are the foundation of the computer. Without the operation system in place, you could not run any program.
2) The operating system presents an interface that allows users to perform many tasks at the same time, with all degrees of complexity.
3) The operating system permits the installation of all kinds of software so the user could work on practically anything.
4) Applications for sound, video, graphics, mathematics, and many other activities can be run due to the operating system.
In these times of digital education, the operation system of a computer allows users to do all the needed activities to fulfill the goals of teaching and learning. From video classes, team meetings, corporate dates, continuing training activities, and many more, the capacity of a good operating system is what makes it easy for you to accomplish your goals.
g The ____ ring is built onto ribose-5-phosphate of PRPP for its de-novo nucleotide biosynthesis, while the ring structure of the ______ bases are synthesized separately and then coupled to ribose-5-phosphate via the C-N glycosidic bond.
Answer:
The purine ring is built onto ribose-5-phosphate of PRPP for its de-novo nucleotide biosynthesis, while the ring structure of the pyrimidine bases are synthesized separately and then coupled to ribose-5-phosphate via the C-N glycosidic bond.
Explanation:
Purines are produced as bases attached to the ribose 5-phosphate (pentose sugar). The adenine and guanine nucleotides derive from inosine monophosphate (IMP), which is synthesized on an existing ribose-phosphate. Thus, purine bases are built on a ribose sugar that is directly attached to the pyrimidine ring. On the other hand, pyrimidines are produced from the carbamoyl phosphate precursor. In this case, the ribose-5-phosphate pentose sugar is attached after the pyrimidine ring is made.