how to find the volume of a room

Answer:

mean 38.22

median 34

mode 13 & 34

range 56

Step-by-step explanation:

mean- add all values together and divide by number of values

median- order from least to greatest find the middle value

mode- the value that appears most often, can be more than one value

range- smallest value subtracted from the largest

Step-by-step Explanation:

the volume of a pyramid is:

volume = (1/3) • base_area • height

(area = length • width)

(area) • (height) = (volume)³

Example:

area = 12cm² (12 cm squared)

height = 4cm

12 • 4 = 48cm³ (48 cm cubed)

Answer:

area: 6 • 8 = 48(1/2) = 24cm²

height: 12

volume: 24 • 12 = 288cm³(1/3) = 96cm³

Answer:

Step-by-step explanation:

16 - 4 = 12

16 + 4 = 20

then 20 ; 2 = 10

Half of 12 is 6, therefore the two numbers 10 - 6 = 4 and 10 + 6 = 16 will have a mean of 10 and a range of 12.

Step-by-step explanation:

width= x (let)

length= x+5

Area=50 cm

Now ,

area = l ×b

50 = (X×X+5)

50 = (2X + 5)

50÷ 2= X+5

25 -5 = X

X=20

LENGTH = X+5

20+5

=25

[tex]\left(- \dfrac 38 \right) \div \left(-\dfrac 13 \right)\\\\\\=-\dfrac 38 \times (-3)\\\\\\=\dfrac 98[/tex]

For both problems, we can use the section formula.

1) [tex]P=\left(\frac{(1)(1)+(5)(-9)}{6}, \frac{(1)(8)+(5)(3)}{6} \right)=\boxed{\left(-\frac{22}{3}, \frac{23}{6} \right)}[/tex]

2) [tex]Z=\left(\frac{(2)(7)+(1)(1)}{3}, \frac{((2)(5)+(1)(2)}{3} \right)=\boxed{(5, 4)}[/tex]

Answer:

Step-by-step explanation:

In this numbers:

14.63

85.62

The two numbers where the digit 6 has a value of 0.6 are 14.63 and 85.62.

To determine in which two numbers the digit 6 has a value of 0.6, we need to examine the place value of 6 in each number.

Let's go through each number:

1. 16.7: The digit 6 is in the tens place, so its value is 6 * 10 = 60 (not 0.6).

2. 61.28: The digit 6 is in the ones place, so its value is 6 (not 0.6).

3. 14.63: The digit 6 is in the tenths place, so its value is 6 * 0.1 = 0.6.

4. 28.16: The digit 6 is in the hundredths place, so its value is 6 * 0.01 = 0.06.

5. 96.77: The digit 6 is in the tens place, so its value is 6 * 10 = 60 (not 0.6).

6. 85.62: The digit 6 is in the tenths place, so its value is 6 * 0.1 = 0.6.

The two numbers where the digit 6 has a value of 0.6 are 14.63 and 85.62.

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Quadrilaterals are angles that has 4 sides and angles.  The measure of the angle m<SPQ is 110 degrees

Quadrilaterals are angles that has 4 sides and angles. The given quadrilateral is a rhombus with equal opposite sides.

Given the following angles

m<SPR = 2x + 15

m<QPR = 3x - 5

From the figure

m<SPR = m<QPR

Substitute

2x+ 15 = 3x - 5

2x - 3x = -5 - 15

x = 20

Determine the measure of <SPQ
m<SPQ = 3x - 5 +2x +15

m<SPQ = 5x + 10
m<SPQ =5(20) + 10
m<SPQ = 110 degrees

Hence the measure of the angle m<SPQ is 110 degrees

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Three points must be removed from this graph so that it will be a function

The points are given as:

(-3, 2), (-3, 3), (1, 4), (1, -4), (2, -4), (2, -2).

For a set of point to represent a function;

Each x coordinate must point to only one y coordinate

From the given points, we have the following highlights:

In the above highlights, one point each must be removed.

This means we have a total of 3 points

Hence, three points must be removed from this graph so that it will be a function

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Answer:

C. 3 points

Step-by-step explanation:

If the team can only send four divers to a competition. Then the number of the ways will be 330.

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

There are eleven divers on a swim team. If the team can only send four divers to a competition.

Then the number of the ways will be

Number of ways = ¹¹C₄

Number of ways = 11! / [(11 - 4)! x 4!]

Number of ways = 330

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Answer:

the answer is 40

Step-by-step explanation:

A = 10 x 8 over 2 which is 40

Answer:

D. 2

Step-by-step explanation:

If you multiply any side from XYZ by 2 it will equal the same length of one of the sides of UVW.

The value of the composite function (p + q)(2) is 1

The function expression is given as:

(p + q)(2)

As a general rule

(p + q)(x) = p(x) + q(x)

Substitute 2 for x

(p + q)(2) = p(2) + q(2)

From the table, we have:

p(2) = 3 and q(2) =-2

So, we have:

(p + q)(2) = 3 - 2

Evaluate

(p + q)(2) = 1

Hence, the value of the composite function (p + q)(2) is 1

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Answer: (p+q)(2)=1

Step-by-step explanation:

Edge

Supplementary Angles:

[tex]\boxed{100°} and \boxed{80°}[/tex]

Arithmetically speaking, the closest 2 supplementary angles can get (in 3 and 2 digits respectively) is the upwritten.

Complementary Angles:

[tex]\boxed{45°} and \boxed{45°}[/tex]

Simply, in this case, for angles to be numerically as close as possible - make both the angles 45°.

Answer:3.46

Step-by-step explanation:i dont know the other one

The ratio of the days it rained to number of days is 3 : 7

The proportion of the number of days it rained is given as:

Proportion = 3/7

This means that:

Proportion = Days it rained/Total number of days.

So, we have:

Days it rained/Total number of days = 3/7

Express as ratio

Days it rained : Total number of days = 3 : 7

Hence, the ratio is 3 : 7

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Answer:

a^4

a^2×a^3= a^5(a^2+3)

a^5/a= a^4(a^5-1)

The expression that represents the width of the patio is (x+3) feet

From the question, we are to determine the width of the patio

The area of the patio = Length of the patio × Width of the patio

From the given information,

Length of the patio = (x+11) feet

Area of the patio = x^2+14x+33 = x²+14x+33

Putting the parameters into the formula,

x²+14x+33 = (x+11)  × Width of the patio

∴ Width of the patio = (x²+14x+33) / (x+11)

First, we will factor x²+14x+33

x²+14x+33

x²+11x+3x+33

x(x+11) +3(x+11)

(x+3)(x+11)

Thus,

Width of the patio = [(x+3)(x+11)] / (x+11)

∴ Width of the patio = (x+3) feet

Hence, the expression that represents the width of the patio is (x+3) feet

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Answer:

x=36

Step-by-step explanation:

2x+2x+70+78+68=360

4x+216=360

4x=360-216

4x=144

x=144/4=36

The height of the square-based pyramid is 91.72 in if the length of one side of the base is 23.4 in.

In geometry, it is defined as the shape having a square base with equal sides length and all the vertex of the square's joints at the top, which is perpendicular to the center of the square.

We have a square pyramid.

Length of the pyramid = 23.4 in

The slant height of the pyramid = 93.2 in

From the figure:

Base length CB  = DC = 23.4 in

In a right-angled triangle, BCD

Applying Pythagoras theorem:

DC² + CB² = DB²

23.4² + 23.4² = DB²

DB = 33.092 in

OB = (1/2)DB

OB = (1/2)33.092 = 16.546 in

In the right-angle triangle AOB, again applying Pythagoras theorem:

AO² + OB² = AB²

h² + 16.546² = 93.2²

AO = h (height of the square pyramid)

AB = slant height = 93.2 in

After calculating, we get:

h = 91.719 ≈ 91.72 in

Thus, the height of the square-based pyramid is 91.72 in if the length of one side of the base is 23.4 in.

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By graphing both equations, we see that the solutions of the system of equations are  (1.05, 4.05) and  (-4.97, - 1.97)

Here we have the system of equations:

y = x + 3

y = 13*(x + 5)*(x - 1).

To solve this system graphically, we need to graph both equations and see where the curves intercept.

The graph of the two equations can be seen below.

There are two solutions, one is (1.05, 4.05) and the other is (-4.97, - 1.97)

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Answer:

y=-2x+10

Step-by-step explanation:

i graphed it i graphed all of them

Answer:

y-2x-2

Step-by-step explanation:

The way I would do this is by first using the information given and making an equation in point-slope form, before bringing it to y=mx+b.

We know that the slope is -2, and we have a point, (2,-6). The formula for equations in point slope form is [tex]y-y_{1} =m(x-x_{1} )[/tex]. So, we can insert the given information into this formula to get [tex]y+6=-2(x-2)[/tex].

Next, we distribute the slope to the the parenthesis to get [tex]y+6=-2x+4[/tex]

Then, we subtract 6 from both sides to get [tex]y=-2x-2[/tex]

Since this equation is now in the form [tex]y=mx+b[/tex], the answer is [tex]y-2x-2[/tex]

Hope this helps! :)

Given that

[tex]\displaystyle \lim_{x\to0} f(x) = 4[/tex]

we can use the properties of limits to show

[tex]\displaystyle \lim_{x\to0} \frac14 f(x)^4 = \frac14 \lim_{x\to0} f(x)^4 = \frac14 \left(\lim_{x\to0} f(x)\right)^4 = \frac14 \times 4^4 = 4^3 = \boxed{64}[/tex]

Let's see

[tex]\\ \rm\Rrightarrow \lim_{x\to 0}\dfrac{1}{4}f(x)^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{4}\lim_{x\to 0}f(x)^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{4}\times 4^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{256}{4}[/tex]

[tex]\\ \rm\Rrightarrow 64[/tex]