How many protons,neutrons, and electrons does uranium 238 have

Answers

Answer 1

Explanation:

92 protons 92 electrons and 146 neutrons

Answer 2

Answer:

92 protons, 92 electrons, 146 neutrons

Explanation:

U-238 has 92 protons, 92 electrons, 146 neutrons.

The 238 is mass number talking about protons + neutrons. Uranium will always have 92 protons so the rest of the things are neutrons (146). Electrons will always equal protons if the element is neutral (no charge) and since no charge was given the numbers will match


Related Questions

Part E
Tsunami evacuation plans often consider the elevation of the community and its distance from the shoreline when
deciding which towns to evacuate. How could this data help in building new homes and communities along coastal areas
that are prone to tsunamis?

Answers

Answer:

make the house elevated

Atoms are spherical in shape. Therefore, the Pt atoms in the cube cannot fill all the available space. If only 74.0 percent of the space inside the cube is taken up by Pt atoms, calculate the radius in picometers of a Pt atom. The mass of a single Pt atom is 3.240 × 10−22 g. [The volume of a sphere of radius r is (4/3) πr3. The volume of a cube is l3, where l is the length of a side. Avogadro's number is 6.022 × 1023.]

Answers

Answer:

Answer:

A)6.6×10^22atoms of Pt in the cube

B)1.4×10^-8m

Explanation:

(a) Calculate the number of Pt atoms in the cube.

an edge length of platinum (Pt) = 1.0 cm.

Then Volume= 1.0 cm×1.0 cm×1.0 cm=1cm^3

Then we have volume of the cube as 1cm^3

Given:

The density Pt = 21.45 g/cm3

the mass of a single Pt atom =3.240 x 10^-22 g

Then with 1atom of the platinum element, we can calculate the number of Pt atoms in the cube as

Density of pt/mass of a single Pt atom

=(21.45 /=3.240 x 10^-22)

=6.6×10^22atoms of Pt in the cube

B)Volume of cube V=4/3πr^3

V= 4/3 ×π×r^3

V= 4.19067r^3

r^3= V/4.19067

But volume is not total volume but just 74% of it, then With 74% of the space inside the cube is taken up by Pt atoms, then we need to find 74% of volume of the cube which is 1cm^3

74/100 ×1= 0.74cm^3

Then our new volume V is 0.74cm^3

r^3=0.74/4.19067×6.620 x 10^22

r^3=2.6674×10^-24

r= 3√2.6674×10^-24

r=1.4×10^-8m

A gas cylinder contains 5.0 kg of propane. How many propane molecules are in the cylinder? The Avogadro constant, L = 6.022 x 1023 mol^-1
A 6.8 × 10^22
B 7.2 x 10^22
C 6.8 × 10^25
D 7.2 x 10^25
[1 mark]​

Answers

Answer:

Here's your answer.

M(C3H8) = 44 g/mol

n(C3H8) = 5000 (g)/44 (g/mol) = 113,6 mol

[tex] N = n \times N_{a} = 113,6 \times 6,02 \times {10}^{23} \\ \\ = 684,1 \times 10 ^{23} \sf{molecules} [/tex]

Hope it helps you from my side

Calculate AH for the reaction:
2N2 (g) + 6H20 (g) → 302 (g) + 4NH3(g)

Answers

Answer:

Explanation:

4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)

Δ[tex]H_r={\sum}{ \Delta }H_f(\text{product})-{\sum}{ \Delta }H_f(\text{reactant})[/tex]

ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f​ (NH 3 (g))+3ΔH f (O 2 (g)))

ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186

ΔH rex =−1532kJ/mol

Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.

What volume of 12M HCI is needed to prepare 250
of 0.20M HCI?

Answers

Answer: 4.2

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(12)V_{A}=(250)(0.20)\\V_{A}=\frac{(250)(0.20)}{12}=\boxed{4.2}[/tex]

Which two nuclides are isotopes of the same element

Answers

Answer:

1940K and 1939K Isotopes are two forms of the same element that have different numbers of neutrons in the nucleus. This means same symbol, and same atomic number (subscript), but different mass number (superscript).

Calculate 5.1234 + 0.033÷ 1.650 and report to the correct number of significant figures.

Answers

5.1434 contains 5 significant figures and 4 decimals.

What is a significant figure?

All zeros that occur between any two non-zero digits are significant. For example, 108.0097 contains seven significant digits.

Calculation:

5.1234 + 0.033÷ 1.650 = 5.1434

5.1434 contains 5 significant figures and 4 decimals. 5.1434 rounded to 4 sig figs is 5.143, to 3 sig figs is 5.14, and to 2 sig figs is 5.1.

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Consider the following reversible reaction:
2 CO(g) + O₂(g) 2CO₂(g). Describe a way to increase the CO concentration at equilibrium. Explain your reasoning.

Answers

The given equilibrium reaction indicates the reaction between carbon monoxide and the oxygen and forms carbon dioxide. In this reaction, by increasing the concentration of the carbon monoxide, the equilibrium shifts towards the right. Since, the reactant concentration increases, the equilibrium stress decreases the concentration of the reactants and therefore, the equilibrium shift towards the right side of the equation.

reaction indicates that carbon monoxide reacts with oxygen and forms carbon dioxide gas.

By increasing the concentration of carbon monoxide image, the equilibrium in the reaction shifts towards the right.

The effect of change of pressure, concentration and temperature on the state of equilibrium can be predicted with the help of a principle known as Le Chatelier's principle. Here by increasing the concentration of CO₂, the amount of CO formation can increase.

What is Le Chatelier's principle?

If a system in equilibrium is subjected to a change in concentration, pressure or temperature, the equilibrium shifts in the direction that tends to reduce or to counteract the effect of change. When the concentration of any substance in equilibrium is increased, the equilibrium shifts in the direction which decreases the concentration of that substance.

On other hand, increasing the concentration of any of the products results in shifting the equilibrium in the backward reaction forming more products. So here increasing the amount of CO₂, shifts equilibrium in the backward direction and forms more amount of CO.

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A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL. What is the volume in milliliters of the lead ball, Vieras? Viead =

Answers

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

What is a graduated cylinder?

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

[tex]93.0 mL= V_(lead ball) +50.6 ml[/tex]

[tex]V_(lead ball) = 93.0 mL - 50.6 ml[/tex]

[tex]V_(lead ball) = 42.4 ml[/tex]

Hence, 42.4 ml is the volume in milliliters of the lead ball.

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Question 1 (1 point)
Using the graph from the article, which air pollutant caused a change in bird abundance?

Question 1 options:

tropospheric ozone (O3)


fine particulates (PM 2.5)

Answers

Answer:

Di ko na po matandaan yung answer ko Jan kasi

nakalimutan ko po sorry talaga

Explanation:

How many moles of a gas can be contained in a 1600-cm° flask at 25°C and 75 kPa?

Answers

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

Now

Apply ideal gas equation

PV=nRTn=PV/RTn=75000(1.6)/8.314(298)n=48.43mol

The number of moles needed is

n=48.43mol.

Calculations

Given the values of the volume and temperature, we would convert them to the required units.

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

We would use the ideal gas equation

PV=nRT

n=PV/RT

n=75000(1.6)/8.314(298)

n=48.43mol

Chemical equation of isopropyl alcohol and ethanoic acid

Answers

Answer:

chemical formula of isopropyl alcohol can also be written as: C3H7OH, CH3CHOHCH3 or (CH3)2CHOH.

chemical formula of ethanoic acid is CH₃COOH.

URGENT!!! Based on the following reaction, how much water is produced when oxygen react with 1 mole of C₂H8?

C₂H8 (g) + 40₂ (g) →2CO2 (g) + 4H₂O(g)​

Answers

Answer:

4 moles

Explanation:

For every mole of deuteriomethane consumed, 4 moles of water are produced.

So, the answer is 4 moles

FLAG A nurse is preparing to administer morphine 0.05 mg/kg intermittent IV bolus to a newborn who weighs 3 kg. Available is morphine 0.5 mg/mL injection. How many mL should the nurse administer? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.) ​

Answers

The quantity of morphine, the nurse should administer is 0.3 ml.

What is morphine?

Morphine is a drug which comes under the pain relieving drugs.

The quantity of morphine is 0.05 mg/kg

The weight of the baby is 3 kg.

Available morphine is 0.5 mg/mL.

0.05 x 3 = 0.15 mg

then, 0.15 mg / 0.5 = 0.3

Thus, the quantity of morphine, the nurse should administer is 0.3 ml.

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ASAP 100 POINTS Which molecules carries instructions for inherited traits
A.DNA
B CARbohydrate
C.Protein
D.Lipid

Answers

Answer:

A.DNA

Explanation:

Ahaa Its gona be right

Answer:

D.N.A.

Explanation:

Hi student! Let me help you out on this question.

D.N.A. is the molecule which carries instructions for inherited traits.

[tex]\therefore,Option\quad A \quad is \quad correct[/tex]

Hope that this helped! have a good day ahead.

1. Related to the number of particles in a gram of
substance and to possible motions of the
particles (2 words)

Answers

Answer:

Avogadro's number or Avogardro’s constant

Explanation:

I’m pretty sure this is correct if it’s not I’m sorry lol.

3) The following reaction produces chlorine molecules:
Energy + HCl (g) + CINO3 (8) Cl₂ (8) + HNO3 (8)
a) Describe 4 ways you could increase the concentration of chlorine molecules.
b) How would cooling shift the equilibrium of this reaction?

Answers

The 4 ways to increase the concentration of chlorine molecules is listed below and the reaction will go into reverse if cooled.

What is Le Châtelier’s principle ?

Le Châtelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish an equilibrium.

Energy + HCl (g) + ClNO₃ ⇄  Cl₂  + HNO₃

a. So in this reaction when at equilibrium , To increase the concentration of Chlorine molecules

1. An increase in Temperature will favour the formation of Chlorine molecules.

2. Decrease in concentration of Chlorine , or partial removal of Chlorine will result the equation to go in forward direction.

3.An Increase in the concentration of HCl will favour formation of Chlorine molecules.

4.An Increase in the concentration of  CINO₃ will also favour formation of Chlorine molecules.

b. The cooling would shift the reaction into backward direction as it is an endothermic reaction in forward state.

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Which of these is a benefit of including comments in your code
makes the app run faster
O helps other programmers understand your code
O improves the user interface
O makes your app more user friendly

Answers

A benefit of including comments in your code is that it helps other programmers understand your code.

What is a Code?

These are numbers and letters which are used to identify a particular thing at a point in  time.

Comments can be put in a code so as to enable others know and understand real intentions about it etc.

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Answer: O helps other programmers understand your code

Explanation: got it right on edgen

A solution of the ionic salt
NaCI would have
pH.
an acidic
a basic
a neutral

Answers

Answer:

Neutral

Explanation:

NaCl aqueous solution is formed by NaOH and HCl.

NaOH is a base and HCl is an acid, so they go through neutralization process forming a neutral salt and water.

Question 11 of 30
During a reaction, the enthalpy of formation of an intermediate is -286
kJ/mol. During the reaction, 2 moles of the intermediate are produced. What
is the enthalpy value for this step of the reaction?
O A. -286 kJ
B. 572 kJ
OC. 286 kJ
OD. -572 kJ

Answers

the answer is b you welcome

By convention, the standard enthalpy of formation of all elements in their standard states are assumed to be zero. Here the enthalpy value for the intermediate formation step is  -572 kJ. The correct option is D.

What is enthalpy of formation?

The standard enthalpy of formation of a compound is defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements, all the substances being in their standard states.

The symbol used to represent the standard enthalpy of formation is ΔfH⁰.  The knowledge of standard enthalpies of various substances is useful for calculating the standard enthalpies of a reaction.

The overall energy difference between the reactants and products remains the same no matter how many intermediates there are in the reaction pathway.

The enthalpy value  = 2 × -286 = -572 kJ

Thus the correct option is D.

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Could really use a few pointers on this question!

Answers

From the calculations, we can see that the theoretical yiled of NO2 is 100L of NO2

What is the theoretical yield?

The theoretical yield is that calculated from the stoichiometry of the reaction.

We can see that 1 mole of O2 produced 2 moles of NO2. Thus;

2.23 moles of O2 will produce 4.46 moles of NO2

Since 1 mole of NO2 occupies 22.4 L

4.46 moles of NO2 occupies 100L of NO2

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select the correct answer from each drop down menu how do you the freezing point and boiling point of a solution compare with those of us pure solvent? The freezing point of the solution is ___ and the boiling point is _____ than that of its pure solvent.

Answers

Explanation:

select the correct answer from each drp down

The enzyme provided is a stock solution which should be diluted 50-fold with 0.001M HCl immediately before use.

Enzyme :1mg/ml chymotrypsin A in 0.001M HCl



How do I work out this calculation, if I want the 5ml of the diluted enzyme?

Answers

In order to prepare a 50-fold diluted enzyme, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl.

What is dilution?

Dilution is a process whereby a solution of lower concentration is prepared from one of a higher concentration.

Dilution is done by using the dilution formula below:

C1V1 = C2V2

C1; Initial concentration of enzyme = 1 mg/mL

C2; Final concentration of enzyme = 1/50 mg/ml = 0.02 mg/ml

V1; Initial volume of enzyme = y

V2; Final volume = 5.0 ml

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, in order to prepare a 50-fold diluted enzyme, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl.

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with strong heating calcium carbonate undergoes thermal decomposition how many mole of CaCO3 are there in 50g of calcium carbonate

Answers

Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole

Answer:

a)CaCO 3→CaO+CO 2CaCO3→CaO+CO2

b) Moles of CaCO3=4.37moles

c) I) Mass of calcium oxide =28g

ii)Mass of carbon dioxide=16.7g

iii)Volume=203cm3

HCl + Fe + ____ + H²
Simple Way.
Hydrochloric acid + iron --> ______ + hydrogen gas.

• Answer this question, only if you know.
• Misuse of points will cost a report. ​

Answers

Answer:

This is a correct answer. 2HCL + Fe = FeCl2 + H2

2. Calculate the mass, in grams, for 3.47 moles of each of the following:
a. lead(II) acetate
b. sodium chloride

Answers

Explanation:

1 moles Lead(II) Acetate to grams = 325.28804 grams

3.47 moles Lead(II) Acetate to grams = 325.28804 ×3.47 grams=1128.749 grams

1 moles sodium chloride to grams=58.5 grams

3.47 moles sodium chloride to grams=58.5×3.47 grams

=202.995 grams

How many grams do 6.534e+24 molecules of phosphoric acid weigh?

Answers

Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
                                                            6.022 x 10²³ molecules          1 mole

= 1,063 grams HPO

Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.

Answers

No of molecules=26.02×10²³molecules

No of moles

26.02×10²³/6.023×10²³4.3mol

Molar mass

C2H82(12)+8(1)24+832g/mol

Mass

Moles×Molar mass32(4.3)137.6g

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol[/tex]

Molar mass of Ethane=32g/mol

We need the mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass[/tex]

[tex]\\ \tt{:}\longrightarrow 32(4.32)[/tex]

[tex]\\ \tt{:}\longrightarrow 138.24g[/tex]

the density of 190mg of a liquid is 0.0076g/cm calculate the volume in ml

Answers

Mass=190mg=0.19gDensity=0.0076g/cm³

[tex]\\ \rm\Rrightarrow Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \rm\Rrightarrow Volume=\dfrac{Mass}{Density}[/tex]

[tex]\\ \rm\Rrightarrow Volume=\dfrac{0.19}{0.0076}[/tex]

[tex]\\ \rm\Rrightarrow Volume=25cm³[/tex]

[tex]\\ \rm\Rrightarrow Volume=25mL[/tex]

What does a negative AH for a molecule mean?
A. Energy was released when the molecule was formed from its
elements.
B. Energy was added when the molecule was formed from its
elements.
C. Energy was added when the molecule changed phases.
D. Energy was released when the molecule went through a phase
change.

Answers

A negative enthalpy (ΔH)for a molecule means energy was released when the molecule went through a phase change.

What is change in enthalpy (ΔH)?

The enthalpy change of a reaction is the amount of heat absorbed or released as the reaction takes place.

Also, the amount of energy required to change the phase of a material is known as the enthalpy,

A negative enthalpy entails the amount of energy released during an exothermic reaction.

Thus, a negative enthalpy (ΔH)for a molecule means energy was released when the molecule went through a phase change.

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