How many children are working around the world today, according to the ilo? a. 215,000 b. 2.15 million c. 21.5 million d. 215 million

The true statement is the cost of steak at grocery store 1 is $0.75 less per pound than at grocery store 2.

In store 1, the cost of 1 pound of steak is $6.75.

Cost of 1 pound of steak in store 2 is 15 /2 = $7.50

Difference in the cost : $7.50 - $6.75 = $0.75

Here is the complete question:

The equation y = 6.75x models the cost, in dollars, to purchase x pounds of steak at grocery store 1. This table shows the cost to buy different weights of steak at grocery store 2.

Cost of Steak at Grocery Store 2

Weight (pounds) Cost

2..........................$15.00

3..........................$22.50

5......................... $37.50

9......................... $67.50

Which statement is true?

answer choices

The cost of steak at grocery store 1 is $0.75 less per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.75 more per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.50 less per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.50 more per pound than at grocery store 2. R

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Answer: pi/4 and -1

Step-by-step explanation:

Using translation concepts, considering S(2,-1), the x-coordinate of S' is given by 6.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the rule is given by:

(x, y) -> (x+4, y-2).

Considering S(2,-1), 4 is added to the x-coordinate in the translation, hence:

2 + 4 = 6.

The x-coordinate of S' is given by 6.

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Any time we have a single positive tile pair up with a single negative tile, those two tiles cancel out.

Three positive tiles and three negative tiles will pair up and cancel out. We're left with two positive tiles only. This represents the number 2.

In other words, 5 + (-3) = 5 - 3 = 2

The value of x of the cubic equation e³ˣ + eˣ - 6 = 0 will be 0.49

The cubic equation is given as ax³ + bx² + cx + d = 0. Then degree of the equation will be 3. Then we have

The cubic equation will be

e³ˣ + eˣ - 6 = 0

Let eˣ = u, then the equation will be

u³ + u - 6 = 0

Then the root of the equation is calculated by the calculator, then we have

u = 1.634, -0.817, -0.817

eˣ = 1.634, -0.817, -0.817

Take log on both sides, then we have

x = ln 1.634, ln(-0.817), ln(-0.817)

x = 0.49, not defined, not defined

Then the value of x will be 0.49.

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Answer:

do u still need help with this

Answer:

x=30

Step-by-step explanation:

You have to use intercept theorem, also known as Thales's theorem to slvoe this.

Answer: SAS similarity theorem

Proportional relationship:

[tex]\sf \dfrac{AB}{AC} = \dfrac{AM}{AN}[/tex]

insert values

[tex]\rightarrow \sf \dfrac{21+9}{14+6} = \dfrac{21}{14}[/tex]

simplify

[tex]\rightarrow \sf 1 = 1[/tex]

L.H.S = R.H.S

The triangles are congruent and follows the rule SAS similarity theorem.

The triangles has/starts from the same angle, corner (A).

Answer:

[tex]\text{1st term} = 3\\\\\text{Common ratio} = 2[/tex]

Step by step explanation:

[tex]\text{Given that,}\\\\\text{5th term} = ar^{5-1} = ar^4 = 48~~~~~~~~...(i)\\ \\\text{8th term} = ar^{8-1} = ar^7 = 384~~~~~~~...(ii)\\\\\text{1st term,}~ a = ?\\\\\text{Common ratio,}~ r = ?\\\\(ii) \div (i):\\\\~~~~~~\dfrac{ar^7}{ar^4}=\dfrac{384}{48}\\\\\implies r^{7-4} = 8\\\\\implies r^3 = 8\\\\\implies r^3 = 2^3\\\\\implies r =2\\\\\text{Substitute r = 2 in eq (i):}\\\\~~~~~~a\cdot 2^4 = 48\\\\\implies 16a =48\\\\\implies a = \dfrac{48}{16}\\\\\implies a = 3\\[/tex]

Answer:

Answer is $2,637.38

Step-by-step explanation:

AND means multiply, so if probability is dependent on two things happening, then we will multiply the individual probabilities together.

1. P(A and 1) = 1/4 x 1/6 = 1/24

2. P(C and 2) = 1/4 x 2/6 = 2/24 = 1/12

3. P(B and 3) = 2/4 x 1/6 = 2/24 = 1/12

4. P(A and 4) = 1/4 x 2/6 = 2/24 = 1/12

5. P(C and 3) = 1/4 x 1/6 = 1/24

6. P(B and 2) = 2/4 x 2/6 = 4/24 = 1/6

7. P(a consonant and an odd #) = 3/4 x 2/6 = 6/24 = 1/4

8. P(a consonant and a prime #) = 3/4 x 3/6 = 9/24 = 3/8

9. P(a vowel and a 5) = 1/4 x 0/6 = 0

10. P(a vowel and a number less than 3) = 1/4 x 3/6 = 3/24 = 1/8

11. P(B and 1) = 2/4 x 1/6 = 2/24 = 1/12

Experimental probability is based on something that has already happened, or data that has already been collected.

12. P(1) = 3/30 = 1/10

13. P(2) = 8/30 = 4/15

14. P(3) = 7/30

15. P(4) = 5/30 = 1/6

16. P(5) = 3/30 = 1/10

17. P(6) = 4/30 = 2/15

Hope this helps!

The method which is best for solving the system of equations when you remove one variable by adding them is B Elimination

To answer the question, we need to know what system of equations are

System of equations are pairs of equations that contain two unknowns

We have different ways of solving systems of equations which include

Since we have the system of equations

3x + 2y = 4

-3x + y = 2

The method which we can use to remove one variable by adding them is the elimination method.

Adding them, we have

3x + 2y = 4

+

-3x + y = 2

3y = 6

y = 6/3

y = 2

So, the method which we can use to remove one variable by adding them is B Elimination

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Answer:

Step-by-step explanation:

Formula

The sin(A) =  opposite / hypotenuse

Givens

Opposite = CB = 11

Hypotenuse = AB = 61

Solution

Sin(A) = 11/61

Sin(A) = 0.1803

Answer

Sin(A) = 11/61

Sin(A) = 0.1803

After 6 hours the drug remains is 19.66 mg if the drug decays at a rate of 20 percent per hour.

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

We have:

If a doctor prescribes 75 milligrams of a specific drug to her patient how many milligrams of the drug will remain in the patients' bloodstream.

We know the exponential decay can be given as:

D = a(1 - r)ⁿ

a is the starting value and n is the number of hours.

D = 75(1 - 0.20)⁶

D = 19.66 milligrams

Thus, the after 6 hours the drug remains is 19.66 mg if the drug decays at a rate of 20 percent per hour.

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Outlet A sold the greatest number of copies of album x in July and August

The tables of values are given as:

July

Album X Album Y Album Z

Outlet A 14 8 6

Outlet B 7 13 4

Outlet C 2 11 1

August

Album X Album Y Album Z

Outlet A 12 14 10

Outlet B 5 12 8

Outlet C 16 12 7

In July, the total sales of album x are:

Outlet A  = 14

Outlet B = 7

Outlet C = 2

In August, the total sales of album x are:

Outlet A  = 12

Outlet B = 5

Outlet C = 16

Add both sales

A = 14 + 12 = 26

B = 7 + 5 = 12

C = 2 + 16 = 18

26 (in outlet A) is greater than 12 and 18

Hence, outlet A sold the greatest number of copies of album x in July and August

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Answer:

Outlet D

Step-by-step explanation:

they sold 28 of album x

outlet a only sold 26

The equations of the graphed line and function can be written as:

f(x) = 1/2x + 2

y - 3 = 1/2(x - 2)

y - 1 = 0.5(x + 2)

Equation of a graphed line can be expressed in:

Slope-intercept form as y = mx + b, where m = slope, b = y-intercept; or

Point-slope form as y - b = m(x - a), where (a, b) is a point and m = slope.

Find the slope (m) of the line:

Slope (m) = change in y / change in x = 1/2 = 0.5

y-intercept (b) = 2

To express the graphed line in slope-intercept form, substitute m = 1/2 and b = 2 into f(x) = mx + b:

f(x) = 1/2x + 2.

Using the point-slope form, write the equation by substituting m = 1/2 and (a, b) = (2, 3) into y - b = m(x - a):

y - 3 = 1/2(x - 2)

Or substitute m = 0.5 and (a, b) = (-2, 1) into y - b = m(x - a):

y - 1 = 0.5(x - (-2))

y - 1 = 0.5(x + 2)

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Answer:

$50 interest

Step-by-step explanation:

Simple interest formula

I = Prt

where:

Given:

Substitute the given values into the formula and solve for I:

⇒ I = 500 · 0.02 · 5

⇒ I = 50

Therefore, Frank will earn $50 interest in 5 years.

assuming is simple interest

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$960\\ P=\textit{original amount deposited}\dotfill & \$3840\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 960 = (3840)(0.05)(t)\implies \cfrac{960}{(3840)(0.05)}=t\implies 5=t[/tex]

Answer: 453.592 grams

Step-by-step explanation:

I searched it up online. But if you're going to use this to calculate. Use 454 grams.

Answer:

453.592 rounded would be 454* grams witch is equal to 1 pound

Step-by-step explanation:

1 pound is equivalent to __453.592 or just say 454*__ grams.

Had to fix that hehehe

Hope This Helped

Answer:

Use given values of h and j, and find the value of k:

The equation is now:

Find the value of g when h is 2 and j is 3:

Correct choice is D

Answer:

D. 144

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

Question:

[tex] \bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solution:

Here, we need to use PEMDAS rule, where:

There's a rule as well, the sum given is need to solved from the left, whichever sign is there.

Solved:

[tex]\bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solve for parentheses first:

[tex] = 5 \times 7 + 5 - 4[/tex]

Then multiplication of course:

[tex] = 35 + 5 - 4[/tex]

Then addition:

[tex] = 4 0 - 4[/tex]

[tex] =36[/tex]

Hence, the answer is 36.

Since the paper representing her desk is 1 1/4 inches by 2 1/4 inches, the actual dimensions of her desk are D: 2 ¹/₂ ft by 4 ¹/₂ ft

To answer the question, we need to know what scale is

A scale is the ratio of two dimension and it is given on a scale drawing.

Given that Chelsea makes a scale drawing of the room and cuts out pieces of paper to represent her furniture, and the paper representing her desk is 1 1/4 inches by 2 1/4 inches.

Since on the scale, we have 1/2 in = 1 foot ⇒ 1 in = 2 ft

So, the actual dimensions of her desk are

1 ¹/₄ in by 2 ¹/₄ in = 5/4 in by 9/4 in

= 5/4 × 1 in by 9/4 × 1 in

= 5/4 × 2 ft by 9/4 × 2 ft

= 5/2 ft by 9/2 ft

= 2 ¹/₂ ft by 4 ¹/₂ ft

So, the actual dimensions of her desk are D: 2 ¹/₂ ft by 4 ¹/₂ ft

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Answer:

Can't see the problem. Send a picture of it.

The number of rows in the arena is 26

The hockey arena illustrates an arithmetic sequence, and it has the following parameters:

The number of rows (i.e. the number of terms) is calculated using:

[tex]S_n = \frac{n}{2}(2a + (n -1) * d)[/tex]

So,we have:

[tex]10920 = \frac{n}{2}(2 * 220 + (n -1) * 16)[/tex]

Evaluate the terms and factors

[tex]21840 = n(440 + 16n -16)[/tex]

Evaluate the like terms

21840 = n(424+ 16n)

Expand

21840 = 424n + 16n^2

Rewrite as:

16n^2 + 424n - 21840 = 0

Using a graphical tool, we have:

n = 26

Hence, the number of rows in the arena is 26

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Answer:

see the attachment photo!

By evaluating the piecewise function, we get:

g(-2) = 0.

g(4) = 4.

A piecewise function is a function that behaves differently in different parts of its domain.

Here, we first want to get g(-2). x = -2 belongs to the second domain, then we use that part:

g(-2) = 0.

For x = 4, it belongs to the third domain, then we have:

g(4) = 4.

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Answer: (0, 1), (-1, -3)

Given two equation's:

Solve them simultaneously:

[tex]\sf 2x^2 + 6x + 1 = -4x^2 + 1[/tex]

[tex]\sf 2x^2 + 4x^2 = 1 - 1[/tex]

[tex]\sf 6x^2 + 6x = 0[/tex]

[tex]\sf 6x(x + 1) = 0[/tex]

[tex]\sf 6x = 0, \ x + 1 = 0[/tex]

[tex]\sf x = 0, \ x = -1[/tex]

(a) When x = 0,     y = −4(0)² + 1 = 1

(b) When x = -1,    y = -4(-1)² + 1 = -3

Solution: (x, y) → (0, 1), (-1, -3)

Answer:

System of equations

[tex]\large \begin{cases}y=2x^2+6x+1\\y = -4x^2+1\end{cases}[/tex]

To solve the given system of equations, use the substitution method:

[tex]\large\begin{aligned}2x^2+6x+1 & = -4x^2+1\\2x^2+6x+1+4x^2-1 & = 0\\6x^2+6x & = 0 \\6x(x+1) & = 0\\\implies x+1 & = 0 \implies x=-1\\\implies 6x & = 0 \implies x=0\end{aligned}[/tex]

Therefore the x-values of the solutions are:

        [tex]\large \begin{aligned}x & =-1\\x & =0\end{aligned}[/tex]

Substitute the found values of x into the second equation to find the y-values:

[tex]\large \begin{aligned}x & =-1 & \implies &-4(-1)^2+1 =-3 & \implies & (-1,-3)\\x & =0 & \implies & -4(0)^2+1 =1 & \implies & (0,1)\end{aligned}[/tex]

Therefore, the solutions of the system of equations are:

(-1, -3) and (0, 1)