Answer:
They don’t ‘represent’ anything, they are properties of the wave.
Depending on the type of wave, we experience them as various phenomena. For example, with a sound wave we experience frequency (or wavelength, which is just another way to describe the same property) as the pitch of the sound. We experience amplitude as the loudness of the sound, although due to the characteristics of the ear, frequency also effects perceived loudness.
If the wave is a light wave, we experience the frequency (wavelength) as the colour of the light, and the amplitude as the brightness of the light.
For many waves, we don’t perceive them at all (e.g. radio waves).
For ocean waves, frequency is the time for each peak or trough to reach us, and amplitude is how tall the wave is.
a crane lifts a 450kg concrete to the top of a 50m building in 5s.assuming g=10m/s²,calculate a,the potential energy if the concrete
Answer:
The answer is 225,000Joules
What is role of force on the speed of moving object?
Explanation:
this is the ans hope it works
Answer:
Forces make things speed up (or accelerate). When a force pushes or pulls the object, the object will move in the direction of the force. The bigger the force, and the lighter the object, the greater the acceleration.
Explanation:
The action from a force can cause an object to move or speed up (accelerate), to slow down (decelerate), to stop, or to change direction. Since any change in velocity is considered acceleration, it can be said that a force on an object results in the acceleration of an object.
A simple mathematical relationship exists between the mass of an object (m), the net force on the object (f) and its acceleration (a). The acceleration of an object is directly proportional to the net force and indirectly proportional to the object’s mass (a = f/m).
Please select the word from the list that best fits the definition
Does not easily transfer electricity
conductor
insulator
circuit
current
Answer:
conductor
Does not easily transfer electricity
If F=15 N, a=3 m/s², m=? *
45 Kg
5 kg
0.2 kg
0 kg
Answer:
5 kg
Explanation:
if the voltage across a 12 ohm resistor is 4.0 volts. the current through the resistor is?
Answer:
Current = 0.33 Amperes
Explanation:
Given the following data:
Resistance = 12 ohm
Voltage = 4 v
To find the current;
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
Voltage = current * resistance
Substituting into the formula, we have;
4 = current * 12
Current = 4/12
Current = 0.33 Amperes
NEED HELP The main difference between kinetic energy and potential energy is thatSingle choice.
(2 Points)
kinetic energy involves position, and potential energy involves motion.
kinetic energy involves motion, and potential energy involves position.
although both energies involve motion, only kinetic energy involves position.
although both energies involve position, only potential energy involves motion.
Answer:
kinetic energy involves motion, and potential energy involves position.although both energies involve position, only potential energy involves motion.hope it is helpful to you ☺️☺️✌️
5. How do you represent the strength of a force in a free-body diagram?
Describe how an oscilloscope should be used to measure the frequency of the sound wave from the sonometer
Answer:
T = reading (cm) time base (s / cm)
f = 1 / T
Explanation:
An oscilloscope is a piece of equipment that allows you to visualize and measure a wave that reaches you, in the case of having a sonometer this transforms the sound wave into an electrical signal to be introduced through one of the voltage channels of the equipment, on the screen we will see the oscillating alternating signal, if it is fixed we can make the reading, if it is moving the time base and the trigger must be adjusted to stop it.
In the oscilloscope we can read the period of the signal, this is the time it takes for the signal to repeat itself with this value, we can calculate the frequency with the formula, for the reading of the period the distance is measured on the labeled screen and multiplied by the time base
T = reading (cm) time base (s / cm)
f = 1 / T
Two vehicles A and B accelerate uniformly from rest.
Vehicle A attains a maximum velocity of 30ms - in los
while B attains a maximum velocil) ol 40ms in the same
time. Both vehicles maintain these velocities for 6s belore
they are decelerated to rest in 6s and 4s respectively
Sketch on the same axes, velocity time graphs
for the motion of the vehicles
Calculate the velocity of each vehicle 18s aftur
the start. (VA
= 20ms -land vs
and vs = 20ms-')
How far will the two vehicles be from one
another during the moment in (ii) above?
(SA = 380m and SB
= 500m: SAB
120m). plz help
Answer:
(i) Please find attached the required velocity time graphs plotted with MS Excel
(ii) The velocity of vehicle A at the 18th second = 20 m/s
The velocity of vehicle B at the 18th second = 0 m/s
(iii) The distance between the two vehicles at the moment in (ii) above is 60 meters
Explanation:
The given parameters of the motion of vehicles A and B are;
The acceleration of vehicles A and B = Uniform acceleration starting from rest
The maximum velocity attained by vehicle A = 30 m/s
The time it takes vehicle A to attain maximum velocity = 10 s
The maximum velocity attained by vehicle B = 30 m/s
The time it takes vehicle B to attain maximum velocity = The time it takes vehicle A to attain maximum velocity = 10 s
The time duration vehicle A maintains its maximum velocity = 6 s
The time duration vehicle B maintains its maximum velocity = 4 s
(i) From the question, we get the following table;
[tex]\begin{array}{ccc}Time &V_A&V_B\\0&0&0\\10&30&40\\14&30&40\\16&30&20\\18&20&0\\22&0&\end{array}[/tex]
From the above table the velocity time graphs of vehicles A and B is created with MS Excel and can included here
(ii) The velocity of vehicle A at the start = 0 m/s
After accelerating for 10 seconds, the velocity of vehicle A = The maximum velocity of vehicle A = 30 m/s
The maximum velocity is maintained for 6 seconds which gives;
At 10 s + 6 s = 16 s, the velocity of vehicle A = 30 m/s
The time it takes vehicle A to decelerate to rest = 6 s
The deceleration of vehicle A, [tex]a_A[/tex] = (30 m/s - 0 m/s)/(6 s) = 5 m/s²
Therefore, we get;
v = u - [tex]a_A[/tex]·t
At the 18th second, the deceleration time, t = 18 s - 16 s = 2 s
u = 30 m/s
∴ v₁₈ = 30 - 5 × 2 = 20
The velocity of vehicle A at the 18th second, [tex]V_{18A}[/tex] = 20 m/s
For vehicle B, we have;
At the 14th second, the velocity of vehicle B = 40 m/s
Vehicle B decelerates to rest in, t = 4 s
The deceleration of vehicle B, [tex]a_B[/tex] = (40 m/s - 0 m/s)/(4 s) = 10 m/s²
For vehicle B, at the 18th second, t = 18 s - 14 s = 4 s
∴ [tex]v_{18B}[/tex] = 40 m/s - 10 m/s² × 4 s = 0 m/s
The velocity of the vehicle B at 18th second, [tex]v_{18B}[/tex] = 0 m/s
(iii) The distance covered by vehicle A up to the 18th second is given by the area under the velocity-time graph as follows;
The area triangle A₁ = (1/2) × 10 × 30 = 150
Area of rectangle, A₂ = 6 × 30 = 180
Area of trapezoid, A₃ = (1/2) × (30 + 20) × 2 = 50
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = A₁ + A₂ + A₃
∴ [tex]S_A[/tex] = 150 + 180 + 50 = 380
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = 380 m
The distance covered by the vehicle B in the 18th second is given by the area under the velocity time graph of vehicle B as follows;
Area of trapezoid, A₅ = (1/2) × (18 + 4) × 40 = 440
The distance covered by the trapezoid, [tex]S_B[/tex] = 440 m
The distance of the two vehicles apart at the 18t second, [tex]S_{AB}[/tex] = [tex]S_B[/tex] - [tex]S_A[/tex]
∴ [tex]S_{AB}[/tex] = 440 m - 380 m = 60 m
The distance of the two vehicles from one another at the 18th second, [tex]S_{AB}[/tex] = 60 m.
A man is driving his 1100 kg car at 36 km/h on a straight freeway. After accelerating for 30 seconds, the car
has a speed of 108 km/h. How much work did the engine do during the 30 seconds?
Answer:
W = 439998 J = 439.99 KJ
Explanation:
First, we will calculate the acceleration of the car by using the first equation of motion:
[tex]v_f = v_i + at\\\\a = \frac{v_f-v_i}{t}[/tex]
where,
a = acceleration = ?
vf = final speed = [tex]108(\frac{km}{h})(\frac{1000\ m}{1\ km})(\frac{1\ h}{3600\ s})[/tex] = 30 m/s
vi = initial speed = [tex]36(\frac{km}{h})(\frac{1000\ m}{1\ km})(\frac{1\ h}{3600\ s})[/tex] = 10 m/s
t = time = 30 s
Therefore,
[tex]a = \frac{30\ m/s - 10\ m/s}{30\ s}[/tex]
a = 0.67 m/s²
Now, we will calculate the force applied by the engine:
F = ma
where,
F = force = ?
m = mass = 1100 kg
Therefore,
F = (1100 kg)(0.67 m/s²)
F = 733.3 N
Now, we will calculate the distance covered by the car by using the second equation of motion:
[tex]s = v_it+\frac{1}{2}at^2\\\\s = (10\ m/s)(30\ s)+\frac{1}{2} (0.67\ m/s^2)(30\ s)^2[/tex]
s = 600 m
Now, the work done (W) by engine can be calculated as follows:
W = Fs
W = (733.3 N)(600 m)
W = 439998 J = 439.99 KJ
Two Brothers are playing soccer on the beach. One brother kicks the ball really hard and the ball lands in the water, about 50 meters from the beach. They wonder if the ball will float back to the beach.
Answer:
Due to wind and waves of water.
Explanation:
They wonder that the ball will float back to the beach because of the wind and the waves of the water. The wind blows towards the beach which moves the water in the form of waves towards the beach so if the ball lands in the water, it will floats on the surface of water and move towards the beach with the help of wind and waves of the sea. The ball floats on the water due to its lighter weight and lower density as compared to water.
Fundamentally, pressure is defined as force per unit area. What is the source of the force in a gas sample? A) The force is from gravity acting on the particles. B) The force is composed of the sum of the collisions only between gas molecules. C) The force is composed of the sum of the collisions only between the gas molecules and the container. D) The force is composed of the sum of all collisions--between the gas molecules, each other and the container. E) The force was imparted to the container in its initial filling, a transfer of momentum.
Answer:
Option C
Explanation:
Given
Pressure = Force /Area
For any gas sample, force is defined as basically the force exerted by the gas molecules when they strike the surface (with in which they are contained) and bounce back.
Hence, Option C is the correct
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
The half-life of iodine-131 is 8 days. If a sample originally contains 0.96 g of the isotope, how much will remain after 24 days?
Answer: you ever get the awnser?
Explanation:
Answer: 0.12 g
Explanation: I got it right on the quiz.
Starting circuit One battery. 2 light bulbs in parallel; switch What is the voltage across the battery? What is the voltage across light bulb 1? What is the voltage across light bulb 2?
Answer:
The voltage across light bulb 1 and light bulb 2 is the the same i.e V
Explanation:
In a parallel circuit, the Voltage is same across all the components of the circuit and the current flowing through each component is added to get the total current across the circuit.
Let us say, the voltage across the circuit is V. The voltage across light bulb 1 and light bulb 2 is the the same i.e V
During which radioactive decay process does the mass number of a nucleus change?
A. Beta Decay (Electron)
B. Beta Decay (Positron)
C. Alpha Decay
D. Gamma Decay
Answer:
Alpha decay
Explanation:
Answer:
C
Explanation:
Alpha Decay
The value of gravitational pull on the moon is 1.6 m/s/s. What is the weight of a 75 kg
astronaut on the moon?
Answer:
120N
Explanation:
Weight=mass x acceleration due to gravity (on the planet)
Mass of an astronaut is 75kg and value of acceleration due to gravity on moon is 1.6m/s2
Weight of astronaut on moon=mass of astronaut x value of acceleration due to gravity on moon
75kg x 1.6m/s2
=120N
A father is homo….zygou dominant for green eyes, the mother is heterozygous. How many of the offspring will have green eyes?
Answer:
100%
Explanation:
Father - EE
Mother - Ee
6. Which of the following statements is true for displacement ?
a. It cannot be zero
b. Its magnitude is more than the distance covered by the object.
Both are false..........
Which of the following settings describes a displacement vs. time graph that
looks like this?
Displacement
Time
Check all that apply
O A. Constant velocity
OB. Increasing velocity
I C. Zero acceleration
O D. Decreasing acceleration
I NEED HELP ASAP
Answer:
c and a
Explanation:
ape x
sheet of paper and a ball having same mass are dropped from the same height and obviously paper balls faster than a sheet of paper. what conclusion can be drawn from this acticity?
Answer:
In free fall, all items will fall at the same time. You were told that they have the same mass hence g×t which is constant.Help help help help help
Below is a single strand of DNA, what is the complementary base pair for the strand?
AAG, GCA, TCA, GAT
Below is a single of DNA, What is the complementary base pair for RNA?
AGC, CGT, ATA, GAT
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a 0.400-kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move after ward
Answer:
0.38m/s
Explanation:
Given data
M1= 0.4kg
U1= 10m/s
M2= 70kg
U2= 0m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
0.4*10+ 70*0= (0.4+10)*V
4= 10.4V
4=10.4V
V= 4/10.4
V=0.38m/s
Hence the common velocity is 0.38m/s
differences between weightlessness in space and weightlessness in earth
Answer:
it depends on a person's own weight
Answer:
The gravity is roughly the same. The inverse square law applies to gravity and that means that being 60 miles above Earth is about the same as being on Earth. The thing is, they are going really fast in an orbit and thus falling around the Earth. The weightlessness comes from a sort of cancellation of gravity pulling them down and their going perpendicular to that force. The forces are cancelling and making them relatively “weightless”. It’s not really weightlessness but just an equilibrium reached between the two accelerations of gravity and their motion against the pull of the Earth.
Explanation:
Si un conductor tiene una longitud de 4 metros y una sección de 2 mm^2 calcule su resistencia, si su coeficiente de resistividad es de 0.10(Ωmm^2/m)
Answer:
R = 0.2 Ω
Explanation:
Para aplicar el concepto de resistencia de un conductor electrico, consideramos la siguiente formula:
R = ρ . l / S
Donde l es la longitud del conductor
S la superficie
y ρ el coeficiente de resistividad
Primero necestiamos hacer ciertas conversiones:
ρ = 0.10 ×10⁻⁶ (Ω . m²/m)
S = 2 mm² → 2 ×10⁻⁶ m²
R = 0.10 ×10⁻⁶ (Ω . m²/m) . 4m / 2 ×10⁻⁶ m²
Dentro de la formula simplificamos las unidades, los metros de ρ con la longitud y ambos m². De esa forma la unidad de R queda en Ω (ohmios).
Resolvemos:
R = 0.10 ×10⁻⁶ Ω . 4 / 2 ×10⁻⁶
R = 0.2 Ω
which feature is used to classify galaxies
age
color
shape
size
Answer:Shape
I took the quiz
Answer:shape
Explanation:
I took the quiz
A juggler is throwing balls up in the air and catching them. An observer in the crowd makes the statement that the potential and kinetic energy of the ball is the same when the ball is halfway down from its highest point. In one paragraph, using your own words, explain using the relationship of mechanical energy, potential energy, and kinetic energy why the observer is correct.
Answer:
do you have the answer?
Explanation:
if so whats the answer?
A very long cylindrical shell made of copper has an inner radius 2 cm and an outer radius of 3 cm. This shell concentrically surrounds a very long charged aluminum rod of radius 1 cm with a charge density of 4 pC/m. All charges on the aluminum rod reside at its surface. The inner surface of the copper shell has exactly opposite charge to that of the aluminum rod while the outer surface of the copper shell has the same charge as the aluminum rod. Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
Question:
Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
(a) 0.5 cm, (b) 1.5 cm, (c) 2.5 cm, (d) 3.5 cm, (e) 7.0 cm
Answer:
(a) 0
(b) 4.795 N/C
(c) 2.877 N/C
(d) 2.055 N/C
(e) 1.027 N/C
Explanation:
The given parameters are;
The inner radius of the copper = 2 cm
The outer radius of the copper - 3 cm
The radius of the aluminum rod, r = 1 cm
The radius of the aluminum rod = 4 pC/m
a) The charge at the 0.5 cm from the center of the aluminum rod, E = 0
There is no charge inside the rod given that the aluminum road is a conductor of electricity, having all the charge on its surface
b) At 1.5 cm, we have;
[tex]E = \dfrac{2 \cdot \lambda}{4 \cdot \pi \cdot r \cdot \epsilon_0}[/tex]
Where;
[tex]\dfrac{ \lambda}{4 \cdot \pi \cdot \epsilon_0} = 8.99 \times 10^9 \times 4 \times 10^{-12}[/tex]
r = 1.5 cm = 0.015 m
∴ E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.015 ≈ 4.795
The magnitude of the electric field, E = 4.795 N/C
The direction of the charge depends on the charge sign on the rod
c) At 2.5 cm, we have;
r = 2.5 cm = 0.025 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.025 ≈ 2.877
The magnitude of the electric field, E ≈ 2.877 N/C
d) At r = 3.5 cm, we have;
r = 3.5 cm = 0.035 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.035 ≈ 2.055
The magnitude of the electric field, E ≈ 2.055 N/C
e) At
r = 7.0 cm = 0.070 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.07 ≈ 1.027
The magnitude of the electric field, E ≈ 1.027 N/C