Help me please guys

Answer:

option D is correct

Step-by-step explanation:

Given data

From the given expression/options of answers, option D is correct

This is because the given expression in the attached file corresponds to the terms in option D

Answer:

ok so the probility of gettting one white fish is

13/23

and if we take out one white fish the problity is

12/22

so we just multiply

12/22*13/23=0.30830039525

so the problity is 0.30 if you choose two fish you will get white for both

Answer:

[tex](2,8][/tex]

Step-by-step explanation:

Given

The attached piece wise function

Required

The domain

To do this, we simply consider the inequalities that bound the values of x.

The inequalities are:

[tex]2 < x < 4[/tex]     [tex]4 < x < 8[/tex]   and   [tex]x \ge 8[/tex]

Combine the first two inequalities:

[tex]2 < x < 8[/tex]    and   [tex]x \ge 8[/tex]

For the inequality to be true, we must have:

[tex]2 < x \le 8[/tex]

In interval notation, the inequality is:

[tex](2,8][/tex]

Answer:

16

Step-by-step explanation:

Answer:

Volume of sphere = 4/3 * π * r³

Since 36π = 4/3 * π * r³, r³ = 27 and r = 3.

Step-by-step explanation:

Answer:

65 percent certain to get the job

Step-by-step explanation:

The given parameters are;

The chance that she gets the job if she receives a strong recommendation, P(J|S) = 80 percent = 0.8

The chance that she gets the job if she receives a moderately good recommendation, P(J|M) = 40 percent = 0.4

The chance that she gets the job if she receives a weak recommendation = 10 percent, P(J|W) = 0.1

The probability that the recommendation will be strong, P(S) = 0.7

The probability that the recommendation will be moderate, P(M) = 0.2

The probability that the recommendation will be weak, P(W) = 0.1

Therefore, the probability that she gets the job given any condition, is given as follows;

P(J) = P(J|S)×P(S) + P(J|M)×P(M) + P(J|W)×P(W)

∴ P(J) = 0.8 × 0.7 + 0.4×0.2 + 0.1×0.1 = 0.65

Therefore, she is 65 percent certain to get the job

Answer:

[tex]10[/tex].

Step-by-step explanation:

See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".

Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:

[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.

Sum of these digits:

[tex]\text{A} + 9\, x= 2021[/tex].

Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].

Therefore:

[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].

[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].

[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].

Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].

Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Proof:

The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".

For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.

Either of the following must be true:

If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.

Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.

let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].

The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:

[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].

However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].

Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".

Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].

Answer:

50

Step-by-step explanation:

simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.

Answer:

each member needs to put in 91.70 dollars in.

Step-by-step explanation:

you add the costs of all the tools needed. in this case the two controllers and wheels which adds up to 275.1.

then you divide by the amount of people which is three. so 275.1/3 and you get 91.7

Step-by-step explanation:

hoped this will help you

if that's help you plz vote me or mask as brinalist

Answer:

Step-by-step explanation:

[tex]\frac{5}{10}*\frac{-4}{12}-\frac{1}{3}-\frac{4}{12}*\frac{2}{10}\\\\=\frac{1}{2}*\frac{-1}{3}-\frac{1}{3}-\frac{1}{3}*\frac{1}{5}\\\\= \frac{-1}{3}[\frac{1}{2}+1+\frac{1}{5}]\\\\=\frac{-1}{3}[\frac{1*5}{2*5}]+\frac{1*10}{1*10}+\frac{1*2}{5*2}]\\\\=\frac{-1}{3}[\frac{5}{10}+\frac{10}{10}+\frac{2}{10}]\\\\=\frac{-1}{3}[\frac{5+10+2}{10}]\\\\=\frac{-1}{3}*\frac{17}{10}\\\\=\frac{-17}{30}[/tex]

Answer:

Using trigonometric ratio

sin(0)=opposite/hypotenise

sin(A)=BC/BA

sin(A)= 6/7

A=arcsin(6/7)

A=58.997°

A=59.00°

----------------------

Hope it helps...

Have a great day!!!

Answer:

16

Step-by-step explanation:

[tex](-64)^2/3[/tex]

64 = [tex]2^{6}[/tex]

[tex]2^{6} ^{\frac{1}{3} } ^{2}[/tex]

[tex]2^{ 2^{2} }[/tex]

[tex]2^{4}[/tex]

16

Answer:Monday, Wednesday and Friday.

Step-by-step explanation:

It’s the other weekdays.

the answer is 1024 because 7²+25²=b²

factor out the square which gives you

(7+25)²=b²

32²=b²

squaring 32 gives 1024

Answer:

24 units

Step-by-step explanation:

i just took the quiz

Answer:

8

Step-by-step explanation:

[tex] \frac{23}{2} = 11.5[/tex]

[tex]92 \div 11.5 = 8[/tex]

Answer:

74820

Step-by-step explanation:

9.5% of 3000 is 285

there are 12 months in a year

so 12 times 21 equals 252

so 285 times 252 add 3000 equals 74820

Answer:

[tex]m\angle 2=122^{\circ},\\m\angle 1 = 58^{\circ}[/tex]

Step-by-step explanation:

By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.

In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since [tex]\angle 2[/tex] forms an arc labelled 244 degrees, the measure of angle 2 must be [tex]\frac{244}{2}=\boxed{122^{\circ}}[/tex].

Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:

[tex]\angle 1+\angle 2=180,\\\angle 1 + 122=180,\\\angle 1=180-122=\boxed{58^{\circ}}[/tex]

Answer:

19

Step-by-step explanation:

(-6)-(-25)=(-6) +25 = 19

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

[tex]\implies 360m^2 = 360 \times 10^4 \ cm^2 [/tex]

And , the number of tiles required will be ,

[tex]\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}[/tex]

Hence the required answer is 1500 .

Answer:

96 green pens

Step-by-step explanation:

Super simple. You do: 14x+15x+24x=212 which is 53x = 212 and x=4

Green = 4*24=96

Answer:

the answer is going to be 1/3

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the vertices of the triangles is missing.

However, the following formula can be used to calculate distance;

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

Take for instance:

[tex]A = (1,8)[/tex]

[tex]A' = (7,8)[/tex]

The distance between both is:

[tex]d = \sqrt{(1- 7)^2 + (8- 8)^2}[/tex]

[tex]d = \sqrt{(-6)^2 + 0^2}[/tex]

[tex]d = \sqrt{36 + 0}[/tex]

[tex]d = \sqrt{36}[/tex]

Take square root

[tex]d = 6[/tex]

Apply the above steps to the complete question

Answer:

A D 3 3

B E 3 3

C F 3 3

A G 5 5

B H 5 5

C I 5 5

A J 6.4 6.4

B K 6.4 6.4

C L 6.4 6.4

Step-by-step explanation:

PLATO ANSWER

Answer:  

a        

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Because the ops are always trying to oppose things, so you show them why they're wrong.

Answer:

y=1x-5

Step-by-step explanation:

it goes over to the right 1 time and down 5

(1+1,6-5)=(2,1)

Step-by-step explanation:

If the volume of a cubical room is 2700 cm³ .

l³=2700

l=3 (100)⅓

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = \pm 5[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow \sqrt{x^2}=\sqrt{25}\\\\\rightarrow \boxed{x = \pm 5}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]x = 5 \: \: \: or \: \: \: x = - 5[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 25 = 0 \\ {x}^{2} - {5}^{2} \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5[/tex]

Answer:

if you look at carefully the left triangle has two same side. so left-angle of C is 180-130=50 degree 5x+5x+50=180 x=13 degree

Step-by-step explanation:

for right triangle again one angle is 50 degree and other is 6*13-(3)=75 degree so 75+50+(10y+5)=180 degree y=5 degree

Answer:

[tex]x=13\text{ and } y=5[/tex]

Step-by-step explanation:

First, notice that ∠BCD and ∠DCE form a linear pair. Linear pairs sum to 180°. Therefore:

[tex]m\angle BCD + m\angle DCE = 180[/tex]

And since we know that ∠BCD measures 130°:

[tex]m\angle DCE = 180-130=50^\circ[/tex]

And since ∠DCE and ∠BCA are vertical angles:

[tex]\displaystyle \angle DCE \cong \angle BCA[/tex]

Therefore, by definition:

[tex]m\angle DCE = m\angle BCA = 50^\circ[/tex]

Looking at the left triangle, we can see that BC and AC both have one tick mark. This means that they are congruent. Therefore, ΔABC is an isosceles triangle. The two base angles of an isosceles triangle are congruent. Hence:

[tex]m\angle A = m\angle B[/tex]

The interior angles of a triangle must total 180°. So:

[tex]m\angle A + m\angle B +m\angle BCA = 180[/tex]

Substitute in known values:

[tex]m\angle A + m\angle A+ (50)=180[/tex]

Simplify:

[tex]2m\angle A=130[/tex]

Divide both sides by two:

[tex]m\angle A = 65[/tex]

Substitute:

[tex](5x)=65[/tex]

Therefore:

[tex]x=13[/tex]

Similarly, for the triangle on the right, we can write that:

[tex]m\angle D + m\angle E + m\angle DCE = 180[/tex]

Substitute:

[tex](10y+5)+(6x-3)+(50)=180[/tex]

Combine like terms:

[tex]10y+6x+52=180[/tex]

Since we determined that x = 13:

[tex]10y+6(13)+52=180[/tex]

Simplify:

[tex]10y+130=180[/tex]

Therefore:

[tex]10y=50[/tex]

And by dividing both sides by 10:

[tex]y=5[/tex]