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Question 7 of 10 Here is a model of the Sun-Earth system at a certain point in Earth's orbit around the Sun. Axis 对联 Rotation axis Arctic Trop of Cancer C Sunlighet Equator Trople of Capricom D netic Circle B 1 Perpendicular to orbit According to the model, which two places on Earth are experiencing summer? AC B. A D C D 0 DB​

Answer:

Uhm i think its a

Explanation:

srry if i get it wrong ._. my bad

Answer:

the correct answer is A

Answer:

About 66 miles per hour

Explanation:

Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.

400/6 ≈ 66 miles per hour

Answer

66 mph

Explanation:

400 ÷ 6 = 66.666666666666666.......

Answer:

378

Explanation:

60 seconds in one minute

add the 24 seconds

multiply it by 4.5

60 + 24 = 84

4.5 x 84 = 378

Answer:D 125

Explanation:

Answer:

you can predict where the juggling ball is going to land and the move you hand to catch it

Explanation:

Answer:

Rainforests contain around 50% of all life on Earth and only take up 6% of the Earths surface area. It contains more species of plant and animals than any other ecosystem. It's climate and geography lend it to growing more plant life which sustains many small animals. The arctic is inhospitable to most species because of the extreme cold. It's food webs do not sustain themselves well as there are fewer species at the bottom the the chain. The genetic variations are greater at the equator than the arctic giving the organisms a greater chance to survive.

Rainforests are far more diverse than arctic ecosystems because of the amount of sunlight and the rain it receives throughout the year.

Biomes can be defined as regions specified by particular biological and geographical communities that evolved because of the shared regional climate of that region.

Generally, there are mainly five major types of biomes those are forest desert grassland aquatic, and tundra.

Even though they only cover 6% of the planet's surface, rainforests are home to about 50% of all living. More plant and animal species may be found there than in any other habitat.

The high temperature of the arctic makes it uninhabitable for the majority of creatures. Because there are fewer species at the base of the food chain, its food webs are unable to support themselves.

Because there are more genetic variants around the equator than in the north, species there has a better chance of surviving.

Thus, rainforests are far more diverse than arctic ecosystems.

Learn more about biomes from here,

brainly.com/question/11491362

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Answer:

For any v-t graph the acceleration is the slope of the graph. For average acceleration in a time period ‘t’ consider the change in velocity in time t and divide it by the time t. For instantaneous acceleration you need to go into the realm of differential calculus.

Explanation:

I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!

Answer:

The main application for fusion is in making electricity. Most fusion reactors make less radiation than the natural background radiation we live with in our daily lives. ... Clean - No combustion occurs in nuclear power (fission or fusion), so there is no air pollution.

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

d) Eg = 5,140.2 j

Ek = 0 j

Etotal = 5,140.2 j

Explanation:

The given parameters of the person riding the skateboard are;

The mass of the person, m = 65 kg

The height of the person (above ground level), h = 4.8 m

The speed at which the person is traveling, v = 8.0 m/s

a) The gravitational potential energy, Eg = m·g·h

Where;

m = The mass of the object at the given height = 65 kg

g = The acceleration due to gravity, g ≈ 9.81 m/s²

h = The height by which the object is elevated = 4.8 m

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 joules

The gravitational potential energy, Eg = 3,060.72 J

b) The kinetic energy, Ek, is given as follows;

Ek = 1/2·m·v²

Where;

v = The velocity of the object = 8.0 m/s

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 joules

The kinetic energy, Ek = 2,080 J

c) The total mechanical energy, Etotal = Eg + Ek

∴  Etotal = 3,060.72 j + 2,080 j = 5,140.72 J

The kinetic energy, Ek = 5,140.72 J

d) If the ramp had a total height of 8.0 m, we have;

At the 8.0 m height

Etotal = Eg(max), Ek = 0 j

With the given values, we get;

Eg(max) = 65 kg × 9.81 m/s² × 8 m = 5,101.2 joules = Etotal

Eg(max) = 5,101.2 j

Etotal = 5,101.2 j

Ek = 0 j

However, using only the values in the question with the assumption that all things being equal, we have;

Etotal = Constant = 5,140.72 j

Eg a the max height, 8.0 m = Eg(max) = Etotal = 5,140.2 j

Ek = 0 j

Answer:

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

Explanation:

Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.

Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.

Parte I

La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).

[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)

Donde:

[tex]M[/tex] - Masa del acróbata.

[tex]g[/tex] - Constante gravitacional.

[tex]v_{o}[/tex] - Rapidez inicial del acróbata.

[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.

[tex]h[/tex] - Altura inicial del mono.

Parte II

La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:

[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)

Donde:

[tex]m[/tex] - Masa del mono.

[tex]z[/tex] - Altura máxima del sistema acróbata-mono.

De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]

[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]

[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]

Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]

[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

Answer:

C. Data is analyzed on a computer

Explanation:

Computers can analyze electrical signals, not radio signals. This means that the radio waves need to be converted to electrical signals to help the computer analyze the data.

Answer:

C

Explanation:

Answer:

The electrically charged gas particles are affected by magnetic forces.

For the past eleven years, the Sun's north geographic pole has also been home to its north magnetic pole

Explanation:

Answer:

B. Acceleration in the direction of motion speeds you up

Explanation:

Acceleration is defined as when something gains speed. For example, when a car speeds up. Deceleration is when the car slows down, and looses speed. When defining these terms, think of a car going faster, then slowing down at a red light.

Answer:

2500/240 will give the resistance to be 10.42

Answer:6.2

Explanation:

Answer:

h = 200 m

Explanation:

The energy content of the chocolate is completely converted to the potential energy of the climber. Therefore:

[tex]Energy\ of\ Chocolate = Potential\ Energy\\Energy\ of\ Chocolate = mgh[/tex]

where,

m = mass of climber = 50 kg

Energy of Chocolate = 100 KJ = 100000 J

g = acceleration due to gravity = 10 m/s²

h = height = ?

Therefore,

[tex]100000\ J = (50\ kg)(10\ m/s^2)h\\\\h = \frac{100000\ J}{500\ N}[/tex]

h = 200 m

Answer:

just like he saide you can downloude the answer

Answer:

dion sanders

Explanation:c

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

[tex]\Delta L=\alpha L_{0}\Delta T[/tex]

Where:

So, we have:

[tex]L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})[/tex]

[tex]L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})[/tex]

[tex]L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)[/tex]

[tex]L_{f}=0.117\: m[/tex]

Therefore, the length at the final temperature is 11.7 cm.

I hope it helps you!

Answer:

A.

Explanation:

more heat = heat energy becomes more kinetic energy = more particle collision

Answer:

the answer is A.There is increased kinetic energy making them collide more and speeds up the rate of reaction.

Explanation: