Air enters a two-stage compressor operating at steady state at 520ºR, 14 lbffin 2 The overall pressure ratio across the stages is 12 and each stage operates isentropically. Intercooling occurs at constant pressure at the value that minimizes compressor work input as determined in Example 9.10, with air exiting the intercooler at 520°R. Assuming ideal gas behavior, with k = 1.4. Determine the work per unit mass of air flowing for the two-stage compressor, in Btu per lb of air flowing.
Answer:
106.335 Btu/Ib
Explanation:
Given data :
T1 = 520°R = 288.89K
P1 = 14 Ibf/in^2 = 96526.6 pa
r = 12
k = 1.4
R = 287 J/kg-k
Calculate work done per unit mass of air flowing ( two-stage compressor )
we will apply the equation below
W = 2k / K-1 * ( RT₁ ) * [tex][ r^{\frac{k-1}{2k} } - 1 ][/tex]
input values into equation above
W = 247.336 KJ/kg = 106.335 Btu/Ib
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and gauge pressure of 300 kPa. The gas is heated, and the gauge pressure at the final state is 367 kPa. Determine the final temperature, in °C. The local atmospheric pressure is 1 atm.
Answer:
the final temperature is 77.1 °C
Explanation:
Given the data in the question;
Initial temperature; T₁ = 27°C = ( 27 + 273)K = 300 K
Initial absolute pressure P₁ = 300 kPa = ( 300 + 101.325 )kPa = 401.325 kPa
Final absolute pressure P₂ = 367 kPa = ( 367 + 101.325 )kPa = 468.325 kPa
Now, to calculate the final temperature, we use the ideal gas equation;
P₁V/T₁ = P₂V/T₂
but it is mentioned that the rigid tank is closed,
so the volume is the same both before and after.
Change in volume = 0
hence;
P₁/T₁ = P₂/T₂
we substitute
401.325 kPa / 300 K = 468.325 kPa / T₂
T₂ × 401.325 kPa = 300 K × 468.325 kPa
T₂ = [ 300 K × 468.325 kPa ] / 401.325 kPa
T₂ = 140497.5 K / 401.325
T₂ = 350.08 K
T₂ = ( 350.08 - 273 ) °C
T₂ = 77.1 °C
Therefore, the final temperature is 77.1 °C
(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compare to the experimental values of 70.58 and 3.90, respectively.
(2) Estimate the specific volume in cm3/g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the compressibility factor charts and compare to the experimental values2 of 70.58 and 3.90, respectively.
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
Determine the specific volume in cm^3
V = 70.66 cm^3
b) comparing the specific volumes to the experimental values
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
What is FOLLOWING PROCEDURES
Answer:
When employees follow procedures, they perform tasks correctly and provide consistent customer service. This enhances the quality of your organization's products and services. And, in turn, improves your company's reputation. Employees can know they are fulfilling their roles and take pride in their work.
froce and motion worksheet
Answer:
The following description of the problem is provided.
Explanation:
If somehow the system seems to be in movement it'll still relax, and it becomes moving whether it sits. An externality is a cost, that either affects or threatens that can modify the bodily condition.The phenomenon of anything changing their position, altering or completely replacing. Whenever moment anything keeps moving, several components are found.Find the dryness fraction, specific volume and internal energy of steam at 7bar nd enthalpy 2600kj/kh. (0.921,0.2515m³/kg , 2420kj/kg)
Answer:
hdwhifniuewohfoyyhyeiudhwbwuxvgusvfgcvxg
Explanation:
List five technology tools with respect to I.C.T
stating
their respective use.
Answer:
laptop printer scanner data
explain the term electric current as used in engineering principles
Answer:
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.Current is directly proportional to voltage, inversely proportional to resistance. One of the most common electrical measurements you'll use is the watt, a unit of electrical power: W (Watts) = E (Volts) x I (Amperes). The quantity of electric charge is measured in coulombs.They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
Explanation:
hey mate this is the best answer if you're studying engineering!
Find Ic(t),
If Vs(t)=8sin(4t+180°) V
3
د3
lic
62.5met
O 2.5cos(4t+53.1) A
O scos(4x+53.1°) A
O 2.5cos(4t+143°) A
Oscos(4t+143) A
Answer:
the answer is equal to 2.5cos(4t +53.1)
Please help!!!!! Thank u
Answer:
which class is this. I don't know sry
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
a) the phase
compressed liquid
superheated vapor
saturated liquid
saturated vapor
saturated mixture
b) temperature (in °C)
c) specific volume, in m3/kg
d) specific energy, in kJ/kg
e) specific enthalpy, in kJ/kg
f) What is the enthalpy of 500 g of water (in kJ)?
Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T = [tex]$T_{saturated}$[/tex]
Temperature = 120.21°C
c). Specific volume
[tex]$v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$[/tex]
[tex]$v_x=v_f+x(v_g-v_f)$[/tex]
[tex]$=0.001061+0.7(0.88578-0.001061)$[/tex]
[tex]$=0.62036 \ m^3/kg$[/tex]
d). Specific energy ([tex]u_x[/tex])
[tex]$u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$[/tex]
[tex]$u_x=504.5 + 0.7(2024.6)$[/tex]
[tex]$=1921.72 \ kJ/kg$[/tex]
e). Specific enthalpy [tex]$(h_x)$[/tex]
At [tex]$h_f = 504.71, \ \ h_{fg} = 2201.6$[/tex]
[tex]h_x=504.71+(0.7\times 2201.6)[/tex]
[tex]$= 2045.83 \ kJ/kg$[/tex]
f). Enthalpy at m = 0.5 kg
[tex]$H=mh_x$[/tex]
[tex]$= 0.5 \times 2045.83$[/tex]
= 1022.91 kJ
A 5 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10ns propagation delay. The output of the inverter goes to the Y input of the OR gate.
a. Draw the circuit
b. Plot the output of the clock for two cycles. Show times and voltages.
c. Plot the output of the inverter in the same plot. Show times and voltages.
d. Plot the output of the OR gate in the same plot. Show times and voltages.
Answer:
Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.
Ferrous metals contain ____ (ferrite) so most have ________ properties. Ferrous metals are vulnerable to _____ when exposed to_______, except for ____________ and wrought iron.
Answer:
Iron
Magnetic properties
Rust
Moisture
Stainless steel
Explanation:
Ferrous materials are those that contain iron. Now iron is a magnetic material and this makes ferrous materials to possess magnetic properties.
Since they contain iron, when they are exposed to moisture they react with oxygen in oxidation to form iron oxide which is reddish and gets worse over time which forms a rusty surface.
- Apart from Wrought iron that resists corrosion,another ferrous metal that does that is Stainless steel because it contains chromium, which is an element that protects it from rust.
What is a SAFETY CHECK
Answer:
Safety check is defined as rounding to make sure that the patients and the milieu (patients living quarters) is secured and free of harmful items that can be used to hurt someone.
affect the amount and rate the alcohol reaches the
bloodstream.
Answer:
Answer to the following question is as follows;
Explanation:
The amount of alcohol consumption can be influenced by a variety of things, including food.
The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.
In a creep test, increasing the temperature will (choose the best answer) A. increase the instantaneous initial deformation B. increase the steady-state creep rate
Answer:
All of the above
Explanation:
firstly, a creep can be explained as the gradual deformation of a material over a time period. This occurs at a fixed load with the temperature the same or more than the recrystallization temperature.
Once the material gets loaded, the instantaneous creep would start off and it is close to electric strain. in the primary creep area, the rate of the strain falls as the material hardens. in the secondary area, a balance between the hardening and recrystallization occurs. The material would get to be fractured hen recrstallization happens. As temperature is raised the recrystallization gets to be more.
Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final
Answer:
Take a 3 to 8 decoder with active low outputs
Assuming you are familiar with the functioning of decoders,
The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.
Next we examine the truth table of the full subtractor i formatted in the picture.
Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!
Explanation:
hopi it to help you!!
Some_____
include peanut butter, bacon, and chocolate.
Snap traps baits
Glue boards
Catchalls
IGRs
Bait stations
Answer:
it’s IGS
Explanation:
because i read
Answer:
snap trap baits
Explanation: its kind of obvi, but i took the test and got it right.
A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.
Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the account at the end of 10 years?
Answer:
2,160,000
Explanation:
8/100 × 200000/1 = 8/1 × 2000/1
2000 × 8 = 16,000 = interest
200,000 + 16,000 = 216,000
216,000 × 10 = 2,160,000 = amount in bank account
Consider a 6-bit cyclic redundancy check (CRC) generator, G = 100101, and suppose that D = 1000100100. 1. What is the value of R? (10 pts)
Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question
3Px=y−y2p2
first order higher dgree
Answer:
the order higher is 3p79g5t88=yv5379
Karen just checked her bank balance and the balance was 1111.11. She is kind of freaking out and saved the receipt, thinking that it must mean something. Karen is probably just suffering from
Answer:
chronic stoner syndrome
Explanation:
"the universe just sends us messages sometimes mannnn, you just have to be ready to listen to them" lol
Air enters an adiabatic gas turbine at 1590 oF, 40 psia and leaves at 15 psia. The turbine efficiency is 80%, and the mass flow rate is 2500 lbm/hr. Determines:
a) The work produced, hp.
b) The exit temperature, oF.
Answer:
a) 158.4 HP.
b) 1235.6 °F.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:
[tex]m_{in}h_{in}=W_{out}+m_{out}h_{out}[/tex]
Whereas the mass flow is just the same, which means we have:
[tex]W_{out}=m_{out}(h_{out}-h_{in})[/tex]
And the enthalpy and entropy of the inlet stream is obtained from steam tables:
[tex]h_{in}=1860.7BTU/lbm\\\\s_{in}= 2.2096BTU/lbm-R[/tex]
Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:
[tex]s_{out}= 2.2096BTU/lbm-R[/tex]
Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.
Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:
[tex]h_{out}=1659.15BUT/lbm[/tex]
Then, the isentropic work (negative due to convention) is:
[tex]W_{out}=2500lbm/h(1659.15BUT/lbm-1860.7BUT/lbm)\\\\W_{out}=-503,875BTU[/tex]
And the real produced work is:
[tex]W_{real}=0.8*-503875BTU\\\\W_{real}=-403100BTU[/tex]
Finally, in horsepower:
[tex]W_{real}=-403100BTU/hr*\frac{1HP}{2544.4336BTU/hr} \\\\W_{real}=158.4HP[/tex]
Regards!
An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people
$255 per hour
Explanation:Total number of employed people = 16
(i) 5 people earn $15 per hour
That means that the total amount earned by those 5 is;
5 x $15 = $75 per hour
(ii) 4 people earn $17 per hour
That means that the total amount earned by those 4 is;
4 x $17 = $68 per hour
(iii) The remaining people earn $16 per hour.
There are 7 people remaining. i.e
16 - 5 - 4 = 7
That means that the total amount earned by those remaining (7) is;
7 x $16 = $112 per hour
The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e
Total = $75 + $68 + $112
Total = $255
Therefore, the total hourly wage earned by all 16 people is $255
Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.
a. True
b. False
Answer:
True
Explanation:
Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true
Find the value of L
I= 1.52-30A
Vcoil
+
225LO V
50 HZ
sout I VE
O 0.441 H
0 0.33 Н
O 0.451 H
O 0.562 H
Answer:
the value is 356732 Volt
A s100 N m torque is applied to a 1-m-long, solid round steel shaft. Design it to limit its angular deflection 2°, if shear modulus of elasticity 80 GPa and to determine the fatigue strength of the material.
Answer:
assuming factor of safety of 2
Se = 118.858 MPa
Explanation:
Torque = ± 100 N m
length of solid round steel shaft = 1-m
Angular deflection = 2°
shear modulus of elasticity = 80 GPa
Calculate Fatigue strength of material
apply Von-miss effective stress rule to determine the Von mises stress
max torque = 100 + 0
assuming a factor of safety of 2
Se(fatigue strength of material ) = Von mises stress * Fs
= 59.429 * 2 = 118.858 MPa
I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?
Answer:
tie es que sumar restar y multiplicar
Explanation:
espero que sea así
Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. Knowing that the average normal stress must not exceed 210 MPa in the bolts and 145 MPa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design.
Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm