Given a number N, write a code to print all psoitive numbers less than N in which all adjacent digits differ by 1

Answer:

The answer is "0 to 4294967295"

Explanation:

Given bit:

32 bits

Calculating smallest and largest bits:

In any processor, it works only on the 0 and 1 bit and it also stores 0 and 1 values. so, the smallest address in bit value is= 0 and the largest bit value can be defined as follows:

largest address value in bits:

[tex]\Longrightarrow 2^{32}-1\\\\\Longrightarrow 4294967296 -1\\\\\Longrightarrow 4294967295\\\\[/tex]

smallest address= 0

largest address = 4294967295

Answer:

The program written in Java is as follows

import java.util.Scanner;

public class mutilate {

public static void main(String [] args) {

Scanner input = new Scanner(System.in);

int n;

System.out.print("Array Length: ");

n = input.nextInt();

while(n<1 || n > 103)  {

    System.out.print("Array Length: ");

n = input.nextInt();

}

int a []= new int [n];

int b []= new int [n];

System.out.print("Enter Elements of the Array: ");

for(int i =0;i<n;i++)  {

 a[i] = input.nextInt();

}

System.out.print("Output: ");

for(int i =0;i<n;i++)  {

 if(i == 0)   {

     b[i] = 0+a[i]+a[i+1];

 }

 else if(i == n-1)   {

     b[i] = a[i - 1]+a[i]+0;

 }

 else   {

 b[i] = a[i - 1]+a[i]+a[i+1];    

 }

 System.out.print(b[i]+" ");

}

}

}

Explanation:

This line allows the program accepts user input

Scanner input = new Scanner(System.in);

This line declares integer n

int n;

The next two line prompts user for length of the array and also accepts input

System.out.print("Array Length: ");

n = input.nextInt();

The following while iteration ensures that the user input is between 1 and 103

while(n<1 || n > 103)  {

    System.out.print("Array Length: ");

n = input.nextInt();

}

The next two lines declares array a and b

int a []= new int [n];

int b []= new int [n];

The next for iteration allows user enter values for array a

System.out.print("Enter Elements of the Array: ");

for(int i =0;i<n;i++)  {

 a[i] = input.nextInt();

}

The next for iteration calculates and prints the values for array b based on the instruction in the question

System.out.print("Output: ");

for(int i =0;i<n;i++)  {

 if(i == 0)   {

     b[i] = 0+a[i]+a[i+1];

 }

 else if(i == n-1)   {

     b[i] = a[i - 1]+a[i]+0;

 }

 else   {

 b[i] = a[i - 1]+a[i]+a[i+1];    

 }

 System.out.print(b[i]+" ");

}

Answer:

A total of 79.3mb will be needed

Answer: APIPA

Explanation:

Automatic Private IP Addressing (APIPA) is a Windows based operating systems feature that allows a computer to assign itself automatically to an IP address even though there is DHCP server to perform the function.

From the information that has been provided in the question, we can see that the type of address that is used is APIPA.

Answer:

The output is "a pineapple is larger than a blueberry ".

Explanation:

In the given  C language code Enum, typedef, and two methods "printfruit and compareFruit" is declared, that can be defined as follows:

Answer:

Answered below

Explanation:

Deep packet inspection is a kind of data processing that thoroughly inspects data sent over a computer network and acts on it by rerouting, logging or blocking it. Uses of DPI include;

To ensure that data is in the correct format, internet censorship, to check for malicious code, and also eavesdropping.

DPI uses port mirroring and optical splitter to acquire packets for inspection. It combines the functionality of an intrusion detection system and intrusion prevention system with a traditional stateful firewall.

DPI is therefore helpful in perimeter security by keeping unauthorized users out and at the same time protecting authorized users from attack. Privacy concerns have been raised over the inspection of content layers of internet protocols such as in the case of censorship and government regulations and control.

Answer:

The completed program is

def color_translator(color):

      if color == "red":

             hex_color = "#ff0000"

      elif color == "green":

             hex_color = "#00ff00"

      elif color == "blue":

             hex_color = "#0000ff"

      else:

             hex_color = "unknown"

      return hex_color

Explanation:

Since the parameter in the above function is color,

This variable will serve as the name of a color and it'll be used in the conditional statements to check if the name of color is any of red, green and blue;

And that is why we have

if color == "red":

elif color == "green":

elif color == "blue":

The variable used to hold the color codes, hex_color, will be returned at the end of the function and that's why we have

return hex_color

When the program is tested with print(color_translator("blue")) and others, it prints the desired output

Answer:

Polymorphism

Explanation:

If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

The information regarding the polymorphism is as follows:

Therefore we can conclude that If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

Learn more about the behavior here: brainly.com/question/9152289

Answer:

AZAX is key sentence for without reloading page.

Explanation:

AJAX is also known as XHR. If some one wants to send the file without reloading then look ahead at the search function and prompt the users by auto saving the documents. This request is sent to the server. The server return the data to your network. Whenever you have seen the file form, some action on the page. You will see some request from AJAX server request on your functional area. AJAX is called a reloading file without page. AZAX is stands for Asynchronous java scripts And XML. AJAX is used to send an email. AZAX is not used in front end, it is used from back end process.

Answer:

i think is "none of them"

Answer:

Resource management is the system level transmission cellular networks and wireless communication.

Explanation:

Wireless communication is the process to continue to the address for faster response time,to the resource management.

Transmission is the provided by that more utilization and wireless resources available,and to discovered data.

Wireless communication system to demand the larger bandwidth and transmission using development to the system.

Wireless communication resources management the larger bandwidth and reliable transmission consumed all the system layer.

Resource management techniques tool are used in a preliminary concepts or mathematical tools,and average limited power battery.

Resource management are they necessary mathematical and fundamental tools are used in wireless communication.

Wireless communication in the provide that wireless industry in a wireless communication.

Answer:

Redundancy

Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1

Conflict and understandability

Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.

Completeness

Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?

Either remove mainly or clarify other print out.

What version of html or web browser is assumed in Req. 1 and Req. 3?

Explanation:

Answer:

The programming language is not stated; however, I'll answer using Python programming language (See attachment for proper format)

tuition = 10000

rate = 0.04

for i in range(1,15):

tuition = tuition + tuition * rate

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

Explanation:

The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively

tuition = 10000

rate = 0.04

The next line iterates from year 1 to year 14

for i in range(1,15):

This line calculates the tuition for each year

tuition = tuition + tuition * rate

The next 3 lines prints the tuition for year 1 to year 10

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

hellohellohellohello

Answer:

Explanation:

Using Python as our programming language

code:

def partitionArray(A,k):

flag=0

if not A and k == 1:

return "Yes"

if k > len(A) or len(A)%len(A):

return "No"

flag+=1

cnt = {i:A.count(i) for i in A}

if len(A)//k < max(cnt.values()):

return "No"

flag+=1

if(flag==0):

return "Yes"

k=int(input("k= "))

n=int(input("n= "))

print("A= ")

A=list(map(int,input().split()))[:n]

print(partitionArray(A,k))

Code Screenshot:-

Answer:

def inputNumber():

   l = []

   num = int(input("Enter the number of integers you want to enter\n"))

   for i in range(0,num):

       print("Enter the ", i+1, " integers ")

       a = float(input())

       l.append(a)

   return l

def averageCalculator(l):

   total = 0

   for i in l:

       total += i

   avg = total/len(l)

   return avg

def printoutput(avg):

   print("The average of numbers is ", avg)

l = inputNumber()

avg = averageCalculator(l)

printoutput(avg)

Explanation:

A subprogram may be considered as a method where we pass some values in the arguments and return some value.

The answer is written in python language, where we have used

inputNumber() subprogram to get the input from the user.

function averageCalculator() to calculate the average.

printoutput() subprogram to print the output or the average of the numbers.

Please refer to the attached image for better understanding of the indentation of code.

Now, let us learn about them one by one:

inputNumber(): We get the number of values to be entered as an integer value and then get the numbers as float.

Store the values in a list and return the list to the caller main program.

averageCalculator(l): Contains a list as argument as we got from inputNumber(). It sums all the numbers and divides with total number to find the average. Returns the average value to the caller main program.

printoutput(avg): Contains an argument which is the average calculated in the averageCalculator(). It prints the argument passed to it.

Answer:

a)  

int apples [5] = {2, 4, 6, 8, 10};

b)

int *aPtr   //this is the pointer to int

Another way to attach a pointer to a an int variable that already exists:

int * aPtr;

int var;

aPtr = &var;

c)

for (int i = 0; i < size; i++){

       cout << values[i] << endl;    }

d)  

   aPtr = values;

   aPtr = &values[0];    

both  the statements are equivalent

e)

If its referring to the part d) then the address is:

cout<<aPtr;

f)

     for (int i = 0; i < size; ++i) {

            cout<<*(vPtr + i)<<endl;    }

g)

   cout << (aPtr + 3) << endl;  // address referenced by aPtr + 3

   cout << *(aPtr + 3) << endl; // value stored at that location

This value stored at location is 8

h)

    aPtr = &apples[4];

    aPtr -= 4;

    cout<<aPtr<<endl;

    cout<<*aPtr<<endl;  

Explanation:        

a)

int apples [5] = {2, 4, 6, 8, 10};

In this statement the array names is apples, the size of the array is specified in square brackets. so the size is 5. The type of array apples is int this means it can store integer elements. The values or elements of the array apples are even integers from 2 to 10. So the elements of array are:

apples[0] = 2

apples[1] = 4

apples[2] = 6

apples[3] = 8

apples[4] = 10

b)

In this statement int *aPtr  

The int* here is used to make the pointer aPtr points to integer object. Data type the pointer is pointing to is int. The asterisk symbol used with in makes this variable aPtr a pointer.

If there already exists an int type variable i.e. var and we want the pointer to point to that variable then declare an int type pointer aPtr and aPtr = &var; assigns the address of variable var to aPtr.

int * aPtr;

int var;

aPtr = &var;

c)

The complete program is:

int size= 5;

int values[size] = {2,4,6,8,10};

for (int i = 0; i < size; i++){

       cout << values[i] << endl; }

The size of array is 5. The name of array is values. The elements of array are 2,4,6,8,10.

To print each element of the values array using array subscript notation, the variable i is initialized to 0, because array index starts at 0. The cout statement inside body of loop prints the element at 0-th index i.e. the first element of values array at first iteration. Then i is incremented by 1 each time the loop iterates, and this loop continues to execute until the value of i get greater of equal to the size i.e. 5 of values array.

The output is:

2

4

6

8

10

d)

aPtr = values;

This statement assigns the first element in values array to pointer aPtr. Here values is the address of the first element of the array.

aPtr = &values[0];    

In this statement &values[0] is the starting address of the array values to which is assigned to aPtr. Note that the values[0] is the first element of the array values.

e)

Since &values[0] is the starting address of the array values to which is assigned to aPtr. So this address is the physical address of the starting of the array. If referring to the part d) then use this statement to print physical address is aPtr pointing to

cout<<aPtr;

This is basically the starting address of the array values to which is assigned to aPtr.

The output:

0x7fff697e1810                

f)

i variable represents offset and corresponds directly to the array index.

name of the pointer i.e. vPtr references the array

So the statement (vPtr + i) means pointer vPtr that references to array values plus the offset i array index that is to be referenced. This statement gives the address of i-th element of values array. In order to get the value of the i-th element of values array, dereference operator * is used.  It returns an ith value equivalent to the address the vPtr + i is pointing to. So the output is:

2

3

6

8

10

g)

values[0] is stored at 1002500

aPtr + 3 refers to values[3],

An integer is 4 bytes long,

So the address that is referenced by aPtr + 3 is

1002500 + 3 * 4 = 1002512

values[3] is basically the element of values array at 3rd index which is the 4th element of the array so the value stored at that referred location  is 8.

h)

Given that aPtr points to apples[4], so the address stored in aPtr is

1002500 + 4 * 4 = 1002516

aPtr -= 4  is equivalent to aPtr = aPtr - 4

The above statement decrements aPtr by 4 elements of apples array, so the new value is:

1002516 - 4 * 4 = 1002500

This is the address of first element of apples array i.e 2.

Now

cout<<aPtr<<endl; statement prints the address  referenced by aPtr -= 4 which is 1002500  

cout<<*aPtr<<endl;  statement prints the value is stored at that location which is 2.

Answer: Yes, clicking adds/popups like the one in the image could cause your computer/electronic to catch viruses/malware.

Explanation: The cause to this is when you click an ad/popup you're exposing yourself to a potential dangerous/visious site. You're unaware to where the popup could bring you, and for all we know it could bring us to a fake site for a download which is really a visious malware to be downloaded to your device.

Explanation:

the answer is false ........

The fact that the speed of a vehicle is lower than the prescribed limits shall relieve the driver from the duty to decrease speed when approaching and crossing an intersection is not true.

An intersection serves as the point where many lanes cross on the road which is a point where driver is required to follow the traffic rules.

However, the above statement is not true because , a driver can decide not  decrease speed when approaching and crossing an intersection, even though it is a punishable offense in traffic rules.

Read more on traffic rules here: https://brainly.com/question/1071840

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Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

[tex]\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)[/tex]  where [tex]\lambda[/tex] is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from [tex]1<E < \lambda (N)[/tex]and [tex]gcd(E, \lambda (N) ) = 1;[/tex] that is [tex]E \ \ and \ \ \lambda (N)[/tex].  D was its complex number equivalent to E (modulo [tex]\lambda (N)[/tex] ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo [tex]\lambda (N)[/tex] ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and [tex]\lambda (N)[/tex] will also be confined as they can be used in measuring D. The Euler totient operates [tex]\varphi (N) = (P-1)(Q - 1)[/tex] however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because [tex]\varphi (N)[/tex], which can always be split into  [tex]\lambda (N)[/tex], and thus any D satisfying DE ≡ 1, it can also satisfy (mod  [tex]\lambda (N)[/tex]). It works because [tex]\varphi (N)[/tex], will always be divided by [tex]\varphi (N)[/tex],. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   [tex]\lambda (N)[/tex] ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   [tex]\lambda (N)[/tex]. if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  [tex]\lambda (N)[/tex].

As there are common threads (P− 1) and (Q – 1) which are present throughout the [tex]N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))[/tex], it's also possible, if there are any, for all the common factors [tex](P -1) \ \ \ and \ \ (Q - 1)[/tex]to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module [tex]\varphi (N)[/tex]) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

Answer:

Option b (Port 22) seems to the appropriate choice.

Explanation:

Below seem to be some measure you should take to correct this mistake.

The SSH server also operates on port 22, by default.  

Other choices don't apply to the specified scenario. So that the argument presented above will be appropriate.

The port number would you open on your webserver is Port 22

For better understanding let's explain SSH means.

From the above we can therefore say that the answer The port number would you open on your webserver is Port 22, is correct

Learn more about SSH and port from:

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Answer:Polymorphic Virus

Explanation:

Malware that can change its signature each time is polymorphic

Answer:

500,000

Explanation:

A computer uses a programmable clock in square-wave mode. If a 500 MHz crystal is used, what should be the value of the holding register to achieve a clock resolution of (a) a millisecond (a clock tick once every millisecond)

1 millisecond = 1 million second = 1,000,000

For a 500 MHz crystal, Counter decrement = 2

Therefore value of the holding register to a clock resolution of 1,000,000 seconds :

1,000,000/2 = 500,000

Answer:

filter

Explanation:

the filter feature allows him to fetch data that only meets a certain criteria(those who didn't play in the last game)

The FILTER feature in a database allows James to list on the players that did not play in the game.

The FILTER feature in Excel is used to clear out a number of statistics primarily based totally on the standards which you specify. The feature belongs to the class of Dynamic Arrays functions.

The end result is an array of values that mechanically spills into a number cells, beginning from the Cells wherein you input a formula.

Thus, The FILTER feature in a database allows James to list on the players that did not play in the game.

Learn more about FILTER feature here:

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Answer:

the answer is 300 feet in the daytime

Answer:

Title

Explanation:

the others describe other items in a database

Answer:

Title

Explanation: idek but I got it correct on a quiz

Answer:

mouse printer CPU touch screen

Explanation:

on a tablet computer hope this helps you :)

Answer:

system unit

Explanation:

A system unit is the part of a computer that contains the brain or central processing unit. The primary device such as central processing unit as contained in the system unit perform operations hence produces result for complex calculations.

The system unit also house other main components of a computer system like hard drive , CPU, motherboard and RAM. The major work that a computer is required to do or performed is carried out by the system unit. Other peripheral devices are the keyboard, monitor and mouse.

Answer:

def case_convertfile( file_name):

    with open(" new_file","x") as file:

         file.close( )

    with open("file_name", "r") as txt_file:

     while True:

            word = txt_file.readline( )

            word_split= word.split(" ")

            for word in word_split:

                  upper_case = word.uppercase( )

                  file= open("new_file","w+")

                  file= open("new_file","a+")

                  file.write(upper_case)

     txt_file.close( )

     file.close( )

Explanation:

This python function would open an existing file with read privilege and a new file with write and append privileges read and capitalize the content of the old file and store it in the new file.

Answer:

62.49

Explanation: