Answer: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]
Step-by-step explanation:
[tex]f(x)=10x^{3}\\y=10x^{3}[/tex]
switch the x and y:
[tex]x=10y^{3}[/tex]
Now solve for y:
[tex]x=10y^{3} \\\frac{x}{10} =y^{3} \\\sqrt[3]{\frac{x}{10} } =y\\[/tex]
Therefore, the inverse of that function is: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]
What is the answer
5 10 25 100 × ÷ ÷
Answer: 1/50, or 0.02
Step-by-step explanation:
I'm assuming this is 5*10/25/100. if you just follow the equation, you get 50/25/100, which is 2/100, or 1/50.
If V= {i}, subset of V are?
Answer:
Defintion. A subset W of a vector space V is a subspace if
(1) W is non-empty
(2) For every v, ¯ w¯ ∈ W and a, b ∈ F, av¯ + bw¯ ∈ W.
Expressions like av¯ + bw¯, or more generally
X
k
i=1
aiv¯ + i
are called linear combinations. So a non-empty subset of V is a subspace if it is
closed under linear combinations. Much of today’s class will focus on properties of
subsets and subspaces detected by various conditions on linear combinations.
Theorem. If W is a subspace of V , then W is a vector space over F with operations
coming from those of V .
In particular, since all of those axioms are satisfied for V , then they are for W.
We only have to check closure!
Examples:
Defintion. Let F
n = {(a1, . . . , an)|ai ∈ F} with coordinate-wise addition and scalar
multiplication.
This gives us a few examples. Let W ⊂ F
n be those points which are zero except
in the first coordinate:
W = {(a, 0, . . . , 0)} ⊂ F
n
.
Then W is a subspace, since
a · (α, 0, . . . , 0) + b · (β, 0, . . . , 0) = (aα + bβ, 0, . . . , 0) ∈ W.
If F = R, then W0 = {(a1, . . . , an)|ai ≥ 0} is not a subspace. It’s closed under
addition, but not scalar multiplication.
We have a number of ways to build new subspaces from old.
Proposition. If Wi for i ∈ I is a collection of subspaces of V , then
W =
\
i∈I
Wi = {w¯ ∈ V |w¯ ∈ Wi∀i ∈ I}
is a subspace.
Proof. Let ¯v, w¯ ∈ W. Then for all i ∈ I, ¯v, w¯ ∈ Wi
, by definition. Since each Wi
is
a subspace, we then learn that for all a, b ∈ F,
av¯ + bw¯ ∈ Wi
,
and hence av¯ + bw¯ ∈ W. ¤
Thought question: Why is this never empty?
The union is a little trickier.
Proposition. W1 ∪ W2 is a subspace iff W1 ⊂ W2 or W2 ⊂ W1.
i hope this helped have a nice day/night :)
A five-question multiple-choice quiz has five choices for each answer. Use the random number table provided, with O's representing Incorrect answers
and 1's representing correct answers, to answer the following question:
What is the probability of correctly guessing at random exactly one correct answer? Round to the nearest whole number.
Answer:
Step-by-step explanation:
jnow colata
Which expression is equivalent to -28xy + 35y?
o 7y(-4xy + 5y)
O 7x{-4x+ 5y)
o 7xl-4y+54)
O 7y(-4x+5)
Answer:
[tex]-28xy+35y[/tex]
[tex]GCF ~is~ 7y[/tex]
[tex]=7y(-4+5)[/tex]
The equivalent expression: [tex]7y(-4x+5)[/tex]
-------------------------
hope it helps...
have a great day!!
Compute the total cost per year of the following pair of expenses. Then complete the sentence: On an annual basis, the first set of expenses is _______% of the second set of expenses.
Vern buys seven lottery tickets each week at a cost of $3 each and spends $900 per year on his textbooks.
Answer:
So 912$ is 58% of 1584 $
Step-by-step explanation:
: Use the image to complete the equation below.
Vertically opposite angles are equal.
So,
(11y - 36)° = 63°
=> 11y - 36 = 63
Answer:
11y-36=63
Step-by-step explanation:
use the concept of vertically opposite angle
Nellie prepares 2 kilograms of dough every hour she works at the bakery. How many hours
did Nellie work if she prepared 6 kilograms of dough?
2 kg dough = 1 hour
1 kg dough = 1 hour/2 = 1/2 hour
6 kg dough = 6 × (1/2 hour) = 6/2 hours = 3 hours
Answer: 3 hours
Step-by-step explanation: x represents the number of hours she works
2x=6
x=6/2
x=3
Evaluate:
11x - 8(x - y)
Answer:
11x-8x+8y
3x+8y SEEESH IN DEEZ NU TS
Step-by-step explanation:
The cost of renting a car is $46/week plus $0.25/mile traveled during that week. An equation to represent the cost would be y = 46 + 0.25x, where x is the number of miles traveled.
what is your cost if you travel 59 miles
cost: 60.75
if your cost Is $66.00, how many miles were you charged for traveling?
miles: ?
you have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?
max miles: ?
Answer:
If your cost Is $66.00, how many miles were you charged for traveling?
y = cost = $66[tex]66=46+0.25x\\66-46=0.25x\\20=0.25x\\x=\frac{20}{0.25} =80[/tex]80 miles
You have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?
y = cost = $100[tex]100=46+0.25x\\100-46=0.25x\\54=0.25x\\x=\frac{54}{0.25} =216[/tex]216 miles
HELPPP PLEASEEE! I tried everything from adding to dividing, subtracting, multiplying but still no correct answer. Can someone help me out here please? I am not sure where to start either now. Thank you for your time.
We deposit $12000 into an account carning 3 % interest compounded continuously, How many years will it take
for the account to grow to $16800? Round to 2 decimal places,
Answer:
The answer is 13.33 year
Step-by-step explanation:
P = $12000
Rate = 3%
Amount = $16800
so,
I = A-P
= $16800 - $12000
= $4800
So,
T = (I × 100)/P×R
= (4800×100)/P×R
= 480000/($12000×3)
= 480000/36000
= 480/36
= 13.33 year
Using the Fenske equation, calculate the number of theoretical plates for a fractional distillation set up used to separate Ethyl acetate (the more volatile component) from hexane (less volatile component) in a mixture with the following experimental data:
n=log(X/Xb) -log(Y a/Yb)/ log α Fenske Equation
Experimental data: l
The following are the data optained from injection of a 1-microliter sample of the equimolar stock solution used in the distillation experiment into a GČ. The percent of the area under the appropriate peak is idicated.
a = 1.6
GC results of the stock mixture used in the experiment
Component Rt (retention time) Percent Area
Ethyl acetate 1.09 53 82
Hexane 1.58 47 18
GC results of a 1-microliter sample after 3 mL had been collected:
Component Rt (retention time) Percent Area
Ethyl acetate 1.09 82
Hexane 1.58 18
a. 3.9
b. 7.2
c. 7.0
d. 3.0
If the tangent line to y = f(x) at (6, 3) passes through the point (0, 2), find f(6) and f '(6). f(6) = Incorrect: Your answer is incorrect. f '(6) = Correct: Your answer is correct.
Answer:
f(6) = 3
f'(6) = 1/6
Step-by-step explanation:
Remember that for a function f(x), we define f'(x) as the slope of the tangent line to the point (x, f(x))
We know that:
y = f(x) passes through the point (6, 3)
Then we already know that:
f(6) = 3.
Now we also know that the tangent at this point, also passes through (0, 2)
Remember that a line can be written as:
y = a*x + b
Where in this case, a = f'(6)
so we just want to find the slope of this line.
Remember that for a line that passes through (x₁, y₁) and (x₂, y₂) the slope is given by:
a = (y₂ - y₁)/(x₂ - x₁)
And we know that the tangent line passes through the points (0, 2) and (6, 3)
Then the slope is:
a = (3 - 2)/(6 - 0) = 1/6
Then we have:
a = f'(6) =1/6
are sheep?ои b. At Molebogeng station, a train arrives every 50 minutes the first in domenat z. 122cio Ise minutes. The first train stops at 7:00 a.m. How many trains have stopped at the station just nun before 11:00 p.m.?
Answer:
19 trains
Step-by-step explanation:
Firstly, we need to calculate the difference in the number of hours
From the question, we have 7 am to 11 pm
7 am to 7 pm is 12 hours
7 pm to 11 pm is 4 hours
So total is 16 hours
16 hours to minutes is multiplied by 60 minutes
We have this as;
16 * 60 = 960 minutes
so to get the number of trains, we simply have to divide the number of minutes by 50
Mathematically, we have this as 960/50
= 19.2
Since we cannot have a fractional train stop, it means the number of trains that has stopped is 19
in a class of 50 student,35 are boys.what is the ratio of girls to boys in the class?
Answer:
15:35
Step-by-step explanation:
50-35=Girls
50-35=15
Please help me i will give brainlest please i need help
Answer:
Since you didn't mention which question.
Step-by-step explanation:
13.
[tex]1.\overline{52}\\[/tex] = 1.525252...
Let x = 1.525252...
10x = 15.2525252....
100x = 152.525252...
100x - x = 151.00
99x = 151
[tex]x = \frac{151}{99}\\\\or\\\\x = 1 \frac{52}{99}[/tex]
14.
4x + 10 = 8x - 26 [ corresponding angles are congruent ]
4x - 8x = - 26 - 10
- 4x = - 36
[tex]x = \frac{-36}{-4} \\\\x = 9[/tex]
15.
Given breadth of a rectangle is ( 2/3) its length.
Let the length be x
Therefore, breadth = ( 2 /3) of x
[tex]= \frac{2}{3} \times x\\\\=\frac{2}{3}x[/tex]
Given perimeter = 40m
Perimeter of a rectangle = 2( length + breadth)
[tex]40 = 2 (x + \frac{2}{3}x )\\\\\frac{40}{2} = \frac{2}{2}(x + \frac{2}{3}x)\\\\20 = x + \frac{2}{3}x\\\\20 = \frac{3x + 2x}{3}\\\\20 \times 3 = 5x \\\\x = \frac{60}{5}\\\\x = 12\\\\Therefore, Length = x = 12 \ m \ and \ breadth = \frac{2}{3}x = \frac{2}{3} \times 12 = 8 \ m[/tex]
16.
Sum of the angles of a triangle = 180°
Given ratio = 2 : 3 : 4
Sum of the ratio = 9
Therefore,
[tex]first \ angle = \frac{2}{9} \times 180 = 2 \times 20 = 40 ^\circ\\\\Second \ angle = \frac{3}{9} \times 180 = 3 \times 20 = 60^\circ\\\\Third angle = \frac{4}{9} \times 180 = 4 \times 20 = 80^\circ[/tex]
17.
Sum of interior angles of a polygon with n sides = ( n - 2) x 180°
Given polygon is pentagon, that is n = 5
Therefore, sum of the interior angles = ( 5 - 2) x 180 = 3 x 180 = 540°
That is ,
x + 125 + 125 + 88 + 60 = 540°
x + 398 = 540°
x = 540 - 398
x = 142°
Answer:
Please can you say which question?
Thank you
Find the area of the shaded region in terms of .
Please help :)
9514 1404 393
Answer:
50π cm²
Step-by-step explanation:
The radius of the larger circle is 10 cm, so its area is ...
A = πr² = π(10 cm)² = 100π cm²
The area of each smaller circle is ...
A = π(5 cm)² = 25π cm²
Then the shaded area is ...
shaded = large circle - 2 × small circle
shaded = 100π cm² - 2(25π cm²) = 50π cm²
Which statement must be true if APQR = ASTU?
Answer:
(a) [tex]PQ \sim ST[/tex]
Step-by-step explanation:
Given
See attachment
Required
Which must be true
[tex]\triangle PQR \simeq \triangle STU[/tex] implies that:
The following sides are corresponding
[tex]PQ \sim ST[/tex]
[tex]PR \sim SU[/tex]
[tex]QR \sim TU[/tex]
The following angles are corresponding
[tex]\angle P \sim \angle S[/tex]
[tex]\angle Q \sim \angle T[/tex]
[tex]\angle R \sim \angle U[/tex]
From the given options, only option (a) is true because:
[tex]PQ \sim ST[/tex]
Please answer!<333 xx
12. X= 6
14. B= -11
16. N= 15
Answer:
q12. [tex]x=6[/tex]
q14. [tex]b=-11[/tex]
q16. [tex]n=15[/tex]
Step-by-step explanation:
Q12.
[tex]-1=\frac{x}{-6}[/tex]
Flip the equation:
[tex]\frac{x}{-6} =-1[/tex]
Multiply both sides by 6/(-1)
[tex](\frac{6}{-1} )[/tex] × [tex](\frac{-1}{6}x )[/tex] = [tex](\frac{6}{-1} )[/tex] × [tex](-1)[/tex]
[tex]x=6[/tex]
Q14.
[tex]5b=-55[/tex]
[tex]b=\frac{-55}{5}[/tex]
[tex]b=-11[/tex]
Q16.
[tex]-3n=-45[/tex]
[tex]n=\frac{-45}{-3}[/tex]
[tex]n=15[/tex]
hope this helps.....
How many outcomes (sample points) for a deal of two cards from a 52-card deck are possible? Report your answer as an integer.
Answer:
1326
Step-by-step explanation:
[tex]{52\choose2}=\frac{52!}{(52-2)!2!}=\frac{52!}{50!*2!}=1326[/tex]
Which ratios are less than 8 to 10? Check all that apply.
6/20
3:5
50/100
13:15
9514 1404 393
Answer:
6/20, 3:5, 50/100 are all less than 8/10
Step-by-step explanation:
It can help to give all the ratios a common denominator. (We'll use 100, and fudge the last one a bit.)
8/10 = 80/100 . . . . our reference value
__
6/20 = 30/100 . . . less than 8/10
3/5 = 60/100 . . . . less than 8/10
50/100 . . . . . . . . . less than 8/10
13/15 ≈ 86.7/100 . . . more than 8/10
Joe's Auto Insurance Company customers sometimes have to wait a long time to speak to a
customer service representative when they call regarding disputed claims. A random sample
of 25 such calls yielded a mean waiting time of 22 minutes with a standard deviation of 6
minutes. Construct a 95% and 99% confidence interval for the population mean of such
waiting times. Explain what these interval means.
Answer:
The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.
The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0639
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.0639\frac{6}{\sqrt{25}} = 2.5[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 22 - 2.5 = 19.5 minutes
The upper end of the interval is the sample mean added to M. So it is 22 + 2.5 = 24.5 minutes
The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.797
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.797\frac{6}{\sqrt{25}} = 3.4[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 22 - 3.4 = 18.6 minutes
The upper end of the interval is the sample mean added to M. So it is 22 + 3.4 = 25.4 minutes
The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.
In 1980, the average cost of a pack of cigarettes was $0.88. In 2000, the average cost was $5.31 per pack.
What is the average rate of change of the cost of a pack of cigarettes? What is another name for the average rate of change?
Round your answer to the nearest cent.
Answer:
The average rate of change of the cost of a pack is 22 cents per year.
Another name for the average rate of change is slope.
Step-by-step explanation:
The average rate of change of the cost of a pack ([tex]r[/tex]), in monetary units per year, is equal to the change in the average cost of a pack ([tex]\Delta c[/tex]), in monetary units, divided by the change in time ([tex]\Delta t[/tex]), in years. Then, the average rate of change is:
[tex]r = \frac{\$\,5.31-\$\,0.88}{2000-1980}[/tex]
[tex]r = \$\,0.22\,\frac{1}{yr}[/tex]
The average rate of change of the cost of a pack is 22 cents per year.
Another name for the average rate of change is slope.
you have to find ABC and I'm not sure how to any help is appreciated
Hello,
Since (BD) bissects angle ABC,
18-x=26-3x
2x=8
x=4
18-x=18-4=14
m angle ABC=14°*2=28°
The mean temperature for the first 4 days in January was 1°C.
The mean temperature for the first 5 days in January was -1°C.
What was the temperature on the 5th day?
Answer:
The temperature on the 5th day was of -9ºC.
Step-by-step explanation:
Mean of a data-set
The mean of a data-set is the sum of all values in the data-set divided by the number of values.
The mean temperature for the first 4 days in January was 1°C.
This means that during the first 4 days, the sum of the temperatures was 4*1 = 4ºC.
The mean temperature for the first 5 days in January was -1°C.
First 4 days: Sum of 4º
5th day: Temperature of x.
The mean is -1, so:
[tex]-1 = \frac{4 + x}{5}[/tex]
[tex]x + 4 = -5[/tex]
[tex]x = -9[/tex]
The temperature on the 5th day was of -9ºC.
In a race competition the probability that Harry wins is 0.4, the probability that Krish wins is 0.2 and the probability that Jonny wins is 0.3.
Find the probability that Harry and Jonny wins
Harry or Krish or Jonny wins
Someone else wins.
Answer:
jonny is the winner.
Step-by-step explanation:
No. of wins harry has = 0.4
No. of wins krish has = 0.2
No. of wins jonny has = 0.3
To find the prbability of harry and jonny = 0.4 + 0.3
= 0.7
Now to see who wins we have to add krish's wins and harry's win, because harry has the greatest number of wins.
krish = 0.2
harry = 0.4
= 0.6
now we have all three's score, so we will now see which is the greatest number.
krish= 0.6
harry = 0.4
jonny = 0.7
The greatest number is 0.7.
Hence, jonny is the winner!
HOPE IT HELPS PLZ MARK ME BRAINLIEST :D
Find the length of the arc to 2 decimals places
Answer:
Step-by-step explanation:
The formula for arc length is
[tex]AL=\frac{\theta}{360}*2\pi r[/tex] where theta is the measure of the central angle and r is the radius. We have both of those pieces of info; filling in:
[tex]AL=\frac{30}{360}*2(3.14) (4)[/tex] and simplifying a bit:
[tex]AL=\frac{1}{12}(8)(3.14)[/tex] and a bit more:
[tex]AL=\frac{25.12}{12}[/tex] and finally, to
AL = 2.09 m
in an examination 30% of the candidates failed in English and 35% failed in general studies and 27% failed in both subjects.if310 candidates passed in both how many candidates appeared in the examination
Answer:
500
Step-by-step explanation:
find the value of...
Answer:
1
Step-by-step explanation:
tan(1)tan(2)....tan(89)=?
Recall tan(90-x)=cot(x) and cot(x)tan(x)=1.
tan(89)=tan(90-1)=cot(1)
tan(88)=tan(90-2)=cot(2)
tan(87)=tan(90-3)=cot(3)
...
tan(46)=tan(90-44)=cot(44)
tan(45)=tan(90-45)=cot(45)
So we can replace the last half of the factors with cotangent of the angles in the first half.
The only one that doesn't get a partner is the exact middle factor which is tan(45).
So this is whar we have:
tan(1)tan(2)tan(3)....tan(45)....cot(3)cot(2)cot(1)
So you should see that cot(1)tan(1)=1 and cot(2)tan(2)=1 and so on....
So the product equals tan(45) and tan(45)=1 using unit circle.
Please help I’m really stuck this is my last attempt
What is the mode for the set of data?
Ages
Stem Leaves
5 0, 4, 6
6 0, 2, 3, 4, 8, 8, 9
7 0, 2, 3, 4, 4, 4, 8, 9
8 4, 5, 6, 8
5|0 = 50 years old
33
68
4
74
Answer:
I THINK IT IS 74 NOT 4
I HOPE THIS HELPS!!!!!