find the total area of the composite figure

Step-by-step explanation:

the right answer is 1.714

Answer:

The basic sine and cosine functions have a period of 2π. The function sin x is odd, so its graph is symmetric about the origin. The function cos x is even, so its graph is symmetric about the y-axis. The graph of a sinusoidal function has the same general shape as a sine or cosine function.

They are the three x-intercepts, the maximum point, and the minimum point. All of these are on your unit circle. The values of sin x correspond to the y-values, so those key points are (angle, y-value) or (0,0), (π/2, 1), (π, 0), (3π/2, -1), (2π, 0).

Answer:

x ≤ 1/2

Step-by-step explanation:

Domain:  input values (x-values)

We cannot take a square root of a negative number, therefore

3 - 6x ≥ 0

Solving the inequality:

⇒ 3 - 6x ≥ 0

⇒ 3 ≥ 6x

⇒ 1/2 ≥ x

⇒ x ≤ 1/2

Therefore, the domain is x ≤ 1/2

Work Shown:

[tex]\displaystyle \lim_{x \to c}f(x) = -4\\\\\\\lim_{x \to c}g(x) = 1/5\\\\\\L = \lim_{x \to c}\frac{g(x)}{f(x)}\\\\\\L = \frac{\displaystyle \lim_{x \to c}(g(x))}{\displaystyle \lim_{x \to c}(f(x))}\\\\\\L = \frac{1/5}{-4}\\\\\\L = (1/5)*(-1/4)\\\\\\L = -1/20\\\\[/tex]

Put simply, we divide the two given values g(x) = 1/5 over f(x) = -4 to end up with -1/20

Answer:

Given, an isosceles right triangle has area 8 cm². We have to find the length of its hypotenuse. We know that in an isosceles triangle two sides are of equal length. Therefore, the length of the hypotenuse is √32 cm.

Answer:

radius = √35 mm or 5.916 mm

Explanation:

Here:

Solve for radius:

[tex]\rightarrow \sf \pi r^2 = 110[/tex]

[tex]\rightarrow \sf \dfrac{22}{7} r^2 = 110[/tex]

[tex]\rightarrow \sf r^2 = \dfrac{110(7)}{22} =35[/tex]

[tex]\rightarrow \sf r = \sqrt{35}[/tex]

Let's see

The measure of the three missing angles in the given rhombus are:

x = 122°

z = 58°

y = 122°

A rhombus is a quadrilateral with four interior angles. In a rhombus, the opposite angles are congruent while the adjacent angles are supplementary to each other.

x and 58° are adjacent angles and are therefore supplementary.

x = 180 - 58 = 122°

z = 58° (opposite angles)

y = x = 122° (opposite angles)

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Step-by-step explanation:

Answer:Mxy= [(Xa+Xb/2);(Ya+Yb/2)]

=(2+8/2);(3+9/2)

Midpoint= (5, 6)

Step-by-step explanation:

Answer:

(- 5, 4 )

Step-by-step explanation:

under a reflection in the line y = x

a point (x, y ) → (y, x ) , then

G (4, - 5 ) → G' (- 5, 4 )

The coordinates of the image of vertex G are (-5, 4)

When reflecting a figure in a line or in a point, the image is congruent to the pre image. A reflection maps every point of a figure to an image across a fixed line. The fixed line is called the line of reflection.

here, we have,

Let us revise some cases of reflection

If the point (x, y) reflected across the x-axis , then its image is (x, -y)

If the point (x, y) reflected across the y-axis , then its image is (-x, y)

If the point (x, y) reflected across the line y = x , then its image is (y, x)

If the point (x, y) reflected across the line y = -x , then its image is (-y, -x)

From the given figure

∵ The line of the reflection is y = x

→ That means we will switch the coordinates of the point to find its image

∵ The coordinates of vertex G are (4, -5)

∴ The x-coordinate = 4 and the y-coordinate = -5

→ Switch the two coordinates

∴ The coordinates of its image G' are (-5, 4)

∴ The coordinates of the image of vertex G are (-5, 4)

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Considering the given quadratic function, the correct statement is given by:

The airplane reaches its maximum height of 95 feet in 10 seconds.

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient. If a > 0, the vertex is a minimum point, and if a < 0 it is a maximum point.

In this problem, the function is:

h(t) = -(t - 10)² + 95.

Hence the vertex is (10, 95), and since a < 0, the correct statement is given by:

The airplane reaches its maximum height of 95 feet in 10 seconds.

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Answer:

While most Americans enjoyed relative prosperity for most of the 1920s, the Great Depression for the American farmer really began after World War I. Much of the Roaring '20s was a continual cycle of debt for the American farmer, stemming from falling farm prices and the need to purchase expensive machinery.<3

Step-by-step explanation:

Answer:

more difficult

Step-by-step explanation:

Answer:

284.3

Step-by-step explanation:

Trapezoid Formula:

A=a+b/2*h

plug in the numbers

The units on a base area calculations is  known to be cm² or  m² while units on your volume calculations is known to be m³ or cm³.

The unit above is used because in base area calculation, only 2 sides are calculated while in volume calculation, 3 sides are involved.

Note that in base area, square unit is often used in its calculations via the use of two dimensions length and breadth (cm² or  m² ).

In terms of volume, cubic unit is used in its calculations through the use of three dimensions length, breadth and height ( m³ or cm³.).

Note also that Area is seen as the space taken by a two dimensional flat object while volume is seen as the space taken by the three-dimensional object and as such The units on a base area calculations is  known to be cm² or  m² while units on your volume calculations is known to be m³ or cm³.

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Based on the calculations, the first three (3) iterations of the given function are 120, 96 and 76.8.

In this exercise, you're required to find the first three (3) iterations of the given function. Thus, we would substitute the value of x₀ into the function and then evaluate as follows:

First iteration:

f(x) = 0.80x

f(x₀) = 0.80x₀

f(150) = 0.80 × 150

f(150) = 120.

Second iteration:

f(x) = 0.80x

f(x₁) = 0.80x₁

f(120) = 0.80 × 120

f(120) = 96.

Third iteration:

f(x) = 0.80x

f(x₂) = 0.80x₂

f(96) = 0.80 × 96

f(120) = 76.8.

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The length and the width of the outside edge of the garden will be ( 6x + 12 ) and ( 9x + 6 ) respectively.

In mathematics, a scale factor is the proportion of related dimensions of an object to a description of that object.

Given that:-

The length and width of the outside edge will be:-

The sides are Dilated by factor 3 so the edges of the rectangle will be calculated as;-

Length = 3 ( 2x+4 ) = 6x + 12

Width   = 3 ( 3x+2 ) = 9x + 6

Therefore the length and the width of the outside edge of the garden will be ( 6x + 12 ) and ( 9x + 6 ) respectively.

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Answer:

x=-2

Step-by-step explanation:

Given equation:

8^x= 1/64

Ensure both sides of the equation are in power format by changing 1/64

1/64 = 64^-1

8^x = 64^-1

2^3(x) = 2^6(-1)

The bases will cancel out each other

3(x) = 6(-1)

3x = -6

x = -6/3

x = -2

Check

8^x = 1/64

x = -2

8^-2

= 1/8²

= 1/8*8

= 1/64

A function assigns the values. The function will be 8cos(2x-π)+4.

A function assigns the value of each element of one set to the other specific element of another set.

Given the maximum value is 12, while the minimum value is -4, therefore,

A = (Max-Min)/2 = 12-(-4)/2 = 8

D = (Max+Min)/2 = (12-4)/2 = 4

Period=π, but since x =-4 at 0 or π, therefore,

(2π/B) = π

B = 2π/π = 2

C/B = π/2, {∴At π/2 maximum}

C=π

Hence, the function will be 8cos(2x-π)+4.

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Answer:

The circumference of Pool B is greater than the circumference of Pool A by about 0.56 meters

Step-by-step explanation:

Identify the diameter of Pool A.

d = 2r

d = 2(18) Substitute 18 for r.

d = 36 ft

Convert from feet to meters. Use the ratio of 1 foot to 0.305 meters.

36 × 0.305 = 10.98

The diameter of Pool A is about 10.98 meters.

Use the formula to find the circumference of Pool A.

C = πd

C = π(10.98) Substitute 10.98 for d.

C ≈ 3.14(10.98) Substitute 3.14 for π.

C ≈ 34.48 Multiply. Round to the nearest hundredth.

The circumference of Pool A is about 34.48 meters.

Identify the diameter of Pool B.

d = 11.16 m

The diameter of Pool B is 11.16 meters.

Use the formula to find the circumference of Pool B.

C = πd

C = π(11.16) Substitute 11.16 for d.

C ≈ 3.14(11.16) Substitute 3.14 for π.

C ≈ 35.04 Multiply. Round to the nearest hundredth.

The circumference of Pool B is about 35.04 meters.

The circumference of Pool B is greater than the circumference of Pool A.

Find how much greater the circumference of Pool B is compared to the circumference of Pool A.

35.04 − 34.48 = 0.56

The circumference of Pool B is greater than the circumference of Pool A by about 0.56 meters.

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

The identity that relates the sine squared and the cosine squared of the angle, as follows:

[tex]\sin^{2}{\theta} + \cos^{2}{\theta} = 1[/tex]

In this problem, we have that the sine is given by:

[tex]\sin{\theta} = \frac{1}{3}[/tex]

Hence, applying the identity, the cosine is given as follows:

[tex]\cos^2{\theta} = 1 - \sin^2{\theta}[/tex]

[tex]\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2[/tex]

[tex]\cos^2{\theta} = 1 - \frac{1}{9}[/tex]

[tex]\cos^2{\theta} = \frac{8}{9}[/tex]

[tex]\cos{\theta} = \pm \sqrt{\frac{8}{9}}[/tex]

[tex]\cos{\theta} = \pm \frac{2\sqrt{2}}{3}[/tex]

The tangent is given by the sine divided by the cosine, hence:

[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]

[tex]\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}[/tex]

[tex]\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}[/tex]

[tex]\tan{\theta} = \pm \frac{\sqrt{2}}{4}[/tex]

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No, to be parallel the two given angles would need to be the same(corresponding angles)

The two lines are not parallel.

Two methods Fred could use to solve the equation are

The solution for the function is x ≅ -0.7 OR x ≅ - 3.3

From the question, we are to solve the given quadratic equation

Two methods Fred could use to solve the equation are

The given quadratic function is

f(x) = 4x² + 16x+9

Now, we are to solve f(x) = 0 for x

That is,

4x² + 16x+9 = 0

Using the formula method to solve the equation

[tex]x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}[/tex]

In the equation,

a = 4, b = 16, and c = 9

∴ [tex]x =\frac{-16 \pm \sqrt{16^{2}-4(4)(9) } }{2(4)}[/tex]

[tex]x =\frac{-16 \pm \sqrt{256-144 } }{8}[/tex]

[tex]x =\frac{-16 \pm \sqrt{112 } }{8}[/tex]

[tex]x =\frac{-16 \pm 10.58 }{8}[/tex]

[tex]x =\frac{-16+ 10.58 }{8}[/tex] OR [tex]x =\frac{-16- 10.58 }{8}[/tex]

[tex]x =\frac{-5.42 }{8}[/tex] OR [tex]x =\frac{-26.58 }{8}[/tex]

x = -0.6771 OR x = - 3.3229

x ≅ -0.7 OR x ≅ - 3.3

Hence, the solution for the function is x ≅ -0.7 OR x ≅ - 3.3

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From the above function, it is clear that the value of f is never 0. Hence the statement that is true is (Option E), See explanation of same below.

Note that the function is related to Euler's number which is depicted as:
e ≈ 2.7182. The function is given as:

f(x) = 100 * [tex]e^{-x}[/tex]

Assuming x = -2, we'd have:

100 * 2.7182[tex]^{-2}[/tex]

= 271.82[tex]^{-2}[/tex]

= 0.00001353354

Hence, even when x tends < 0 the function f(x) thus, is never 0. See the attached graph for confirmation.

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Answer:

  (c)  Yes, +4 more

Step-by-step explanation:

The problem statement is telling you the available quantity in pounds. The answer choices are expressing the difference in terms of packets. A conversion of units of measure is needed.

__

Patel has 8 pounds of seed, and he puts it into 1/2-pound packets. Each pound will fill two (2) half-pound packets, so he has enough for ...

  (8 lb) × (2 packets/lb) = 16 packets

Patel has 12 people planting seed, so needs 12 of the 16 packets in order to give each team member one packet.

He has enough seed for this need, and enough for 16 -12 = 4 more packets than he needs.

Answer:

x = ± 10

Step-by-step explanation:

to solve the equation let y = 0 , that is

100 - x² = 0 ( add x² to both sides )

100 = x² ( take square root of both sides )

± [tex]\sqrt{100}[/tex] = x , that is

x = ± 10

Randy sells, in average, 460 vacuum cleaners per month.

First, we know that Janice sells 690 units per year.

There are 12 months in a year, so the amount that she sells, in average, per month is:

J = 690/12 = 57.5

This means that Janice sells, in average, 57.5 units per month. And Randy sells 8 times as many, then we can solve the product:

R = 8*57.5 = 460

This means that Randy sells 460 units per month.

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Answer:

linear equation is the equation having degree 1 like ax+by=c so option B is correct ..

y+7=5x will be treated as the linear function.  Thus, option B is correct.

Any formula with one or two variables and no exponents is said to be linear. On the coordinate plane, this property depicts a straight line. In order to maintain the same function's linear illness, extra variables in a function must be constant.

y+7=5x

This equation can be written in a proper form:

y=5x-7

As this equation does not have any power therefore this will be treated as a linear function.

Therefore, option B is correct.

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Answer: B'(-4, -4)

Given : A(1, 2), B(-1, -1), C(0, -2)

"Focusing on B coordinates"

If the points are dilated with a scale factor of 4

Then new coordinates : (-1, -1) × 4 = B'(-4, -4)

Answer:

B' = (-4, -4)

Step-by-step explanation:

Dilation:  A type of transformation that makes the pre-image larger or smaller without changing its shape.

Center of a dilation:  a fixed point about which all points are dilated.

Given:

For dilation when the center of dilation is the origin (0, 0), simply multiply the coordinates of the vertices of the pre-image by the given scale factor to find the image under dilation:

Therefore:

A' = (1 x 4, 2 x 4) = (4, 8)

B' = (-1 x 4, -1 x 4) = (-4, -4)

C' = (0 x 4, -2 x 4) = (0, -8)

Answer:

B.) No, because it fails the vertical line test.

Step-by-step explanation:

You can determine whether or not graphs represent functions by performing the vertical line test. This test states that to be a function, there must only be one output for every input. In other words, there must be only one "y" value per "x" value. As you can see, for some "x" values there is more than one "y" value.

The easiest way to perform this test is by placing your finger at the top of the graph and moving it downwards. If you cross the line twice, then it must not be a function.