Find the range of the data.

67, 63, 72, 62, 64, 79, 74, 66

Answers

Answer 1

Answer:

The range is 17

Step-by-step explanation:

67, 63, 72, 62, 64, 79, 74, 66

To find the range of the data, take the largest number and subtract the smallest number.

The largest number is 79

The smallest number is 62

79-62 = 17

The range is 17


Related Questions

Find the perimeter of the pentagon MNPQR with vertices ​M(2​, 4​), ​N(5​, 8​), ​P(​8, 4​), ​Q(8​, 1​), and ​R(2​, 1​)

Answers

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

[tex]p = MN + NP + PQ + QR + RM[/tex] (1)

[tex]p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}[/tex] (1b)

If we know that [tex]M(x,y) = (2,4)[/tex], [tex]N(x,y) = (5,8)[/tex], [tex]P(x,y) = (8,4)[/tex], [tex]Q(x,y) = (8,1)[/tex] and [tex]R(x,y) = (2,1)[/tex], then the perimeter of the pentagon MNPQR is:

[tex]p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}[/tex][tex]p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}[/tex]

[tex]p = 22[/tex]

The pentagon MNPQR has a perimeter of 22 units.

answer

The pentagon MNPQR has a perimeter of 22 units.

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

p = MN + NP + PQ + QR + RMp=MN+NP+PQ+QR+RM (1)

p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}p=

MN

MN

+

NP

NP

+

PQ

PQ

+

QR

QR

+

RM

RM

(1b)

If we know that M(x,y) = (2,4)M(x,y)=(2,4) , N(x,y) = (5,8)N(x,y)=(5,8) , P(x,y) = (8,4)P(x,y)=(8,4) , Q(x,y) = (8,1)Q(x,y)=(8,1) and R(x,y) = (2,1)R(x,y)=(2,1) , then the perimeter of the pentagon MNPQR is:

p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}p=

(5−2)

2

+(8−4)

2

+

(8−5)

2

+(4−8)

2

+

(8−8)

2

+(1−4)

2

+

(2−8)

2

+(1−1)

2

+

(2−2)

2

+(4−1)

2

p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}p=

3

2

+4

2

+

3

2

+(−4)

2

+

0

2

+(−3)

2

+

(−6)

2

+0

2

+

0

2

+3

2

p = 22p=22

The pentagon MNPQR has a perimeter of 22 units.


Find the area of the shaded sector of the circle. no links

Answers

Answer:

706.86m

Step-by-step explanation:

Square the radius, then multiply by pi.

This year, the price of a Christmas Cactus painting rose to $359. This is an increase of 15% more than last year’s price. What was the old selling price?

Answers

15 percent of 359 is 53.85
subtract 359 minus 53.85 and you get 305.15

What is the range of the following relation?
Oxso
all real numbers

Answers

Answer:

Step-by-step explanation:

The y values must be at or below the y axis, so C is the answer.

Find the midpoint of the segment with the following endpoints. (10, 7) and (5, 4)

Answers

Answer:

[tex]\frac{15}{2} , \frac{11}{2}[/tex]

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

[tex]\frac{x1 +x2}{2} , \frac{y1 + y2}{2}[/tex]

x1 = 10

x2 = 5

y1 = 7

y2 = 4

Substituting the values in the equation, we get:-

[tex]\frac{10+5}{2} , \frac{7+4}{2}[/tex]

Coordinates of the midpoint---> [tex]\frac{15}{2} , \frac{11}{2}[/tex]

can someone help me please

Answers

Answer:

3.5

Step-by-step explanation:

If you divide x from y on each row, you will always get 3.5

A student has taken three math tests so far this semester. His scores for the first three tests were 65​, 67​, and 69. Suppose his test scores continue to improve at the same rate. What will be his grade on the sixth​ (and final)​ test? What will be his total score for all six​ tests?

Answers

Answer:

75

Step-by-step explanation:

Scores for his first tests were 65, 67, 69.

Rate of change: +2

y=2x+63; 63 is the 0th test he took, his first test was 65, so 65-2=63. 2x is the rate of change, his tests scores increase by 2 each time.

x=6, 6th test score

y=2(6)+63

y=12+63

y=75

So, on his 6th test he will get a score of 75

In the parallelogram below,
z = [ ?]
124°
2z+16

Answers

2z+16=124
124-16=108
108/2=54

answer for brainliest and 10 points

Answers

Answer:

It is rational because 121 is a perfect square.

The ages of the U.S. Presidents that were inaugurated during the 1900s are given below. What is wrong with this histogram? Question 8 options: The bar for 50–54 is too short and the bar for 55–59 is too tall. The bar for 50–54 is too short. The bar for 55–59 is too tall. The bar for 40–44 is too short and the bar for 45–49 is too tall.

Answers

Hoyeaaaaa that’s the amsweer

17 and 18 please no links

Answers

Answer:

17) 135 degrees

Step-by-step explanation:

An octagon contains six triangle, or 1080 degrees, meaning each angle is 135 degrees.

Step-by-step explanation:

1. an octagon contain 6 triangles or 1080 degrees this means with 8 angles each angle is 135 degrees

I need help if you answer correct I will give brainiest

Answers

Answer:

Opaque

Step-by-step explanation:

Translucent materials, like greaseproof paper and frosted glass, let some but not all light through. They scatter or diffuse the light. Most materials do not allow light through at all and these are called opaque. (The second question is light)

Answer:

opaque, Radiant

Step-by-step explanation:

Opaque can not be seen through and radiant is an energy that can travel through space.

Find the smallest side of CDE?

Answers

side CE because it is across from the smallest degree.
It’s D because it is 56*

Help with this plz.
Solve the system of equations using the elimination method.​

Answers

Let's solve your system by elimination.

8x+y=−16;3x−y=5

8x+y=−16

3x−y=5

Add these equations to eliminate y:

11x=−11

Then solve: 11x=−11 for x:

11x=−11

11x

11

=

−11

11

(Divide both sides by 11)

x=−1

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+y=−16

Substitute: −1 for x in 8x+y=−16:

(8)(−1)+y=−16

y−8=−16(Simplify both sides of the equation)

y−8+8=−16+8(Add 8 to both sides)

y=−8

Answer:

x=−1 and y=−8

Answer:Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Subtract the second equation from the first.

Solve this new equation for y.

Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Step-by-step explanation:

WILL MAKE BRAINLIST only if you solve this

Answers

Answer:

18/18 is fractions

16/16 is fractions

Step-by-step explanation:

18/18x16/16=1

Theres your answer.

An arithmetic sequence is described by the formula f(n)=128+15(n−1). Find f(12).

Answers

Answer:

Step-by-step explanation:

Putting value of n = 12

f(12) = 128 + 15(12 - 1)

= 128 + 180 - 15

= 293

Timed test please help
Rectangles P and Q are similar. If the area of rectangle P is 80, what is the area of
rectangle Q?

Answers

10/7 =1.428 80/1.428=56.02

What the Sum of Adding the Polynomials.

Answers

Bbb hunk. Junk. Jensen the nonsense

Uhhh what?

A. 120
B. 30
C. 90
D. 45

Answers

C.90 bc it’s a right angle
The answer is c 90 degrees big daddy

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Answers

Answer:

The numbers are blurry on the graph

4 The rate of compound interest is 7.5%. How long will it take for an investment of $4500 to
be worth more than $7000?

Please use the compound interest formula for IGCSE:
[tex]p(1 + \frac{r}{100} ) {}^{t} [/tex]


Answers

Here is the result.....

Write the domain of
Y= x+1/
(x+2)(x+10)

Answers

(-∞,-10)∪(-10,-2)∪(-2,∞)

Or

[tex]\left\{x|x\ne-2,-10\right\}[/tex]

Both are correct.

Triangle theoroms, what is the value of x ?

Answers

Answer:

50.6

Step-by-step explanation:

MA=46.2-14=32.2

We have similar triangles.

That is, triangle MNP is similar to MAB.

This means, we have the following proportion to solve:

32.2/46.2=x/72.6

Multiply both sides by 72.6

32.2/46.2*72.6=x

50.6=x

select the inequality that is represented by the number line below
NO LINKS OR I WILL REPORT

Answers

The answer is choice A :)

Answer:

a) x<0

Step-by-step explanation:

the circle is not solid so it’s just a less than a sign and the arrow is going less than 0 so x is less than 0 is the answer

hope this helps :)

Use the following function rule to find f(3).

f(x) =
8
x

+ 9

f(3) =

Answers

Answer:

33

Step-by-step explanation:

f(3) = 8(3) + 9 = 24 + 9 = 33

Answer:

33 is the answer.

Step-by-step explanation:

# CarryOnLearning

The high temperatures for the last seven days are: High Temperatures: 81, 78, 83, 89, 80, 87, 78

Find the RANGE of the temperatures.

Answers

Answer:

78 is the range of high temperature

HELPPP PLS what is the circumference of 11 , 8 ,and 6 !

Answers

Answer:

C≈34.56, C≈25.13 and C≈18.85

Step-by-step explanation:

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·11≈34.55752

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·8≈25.13274

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·6≈18.84956

Which of the following represents the quadratic function f (x) = 5(x − 2)2 − 7 in standard form?

Answers

Answer:

f(x) = 10x - 27. I can't find the answer anywhere

Step-by-step explanation:

Choose the graph that represents the following system of inequalities:

y ≤ −3x + 1
y ≤ 1 over 2x + 3

In each graph, the area for f(x) is shaded and labeled A, the area for g(x) is shaded and labeled B, and the area where they have shading in common is labeled AB.

Graph of two intersecting lines. Both lines are solid. One line f of x passes through points negative 2, 2 and 0, 3 and is shaded above the line. The other line g of x passes through points 0, 1 and 1, negative 2 and is shaded above the line.
Graph of two lines intersecting lines. Both lines are solid. One line g of x passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line f of x passes through points 0, 1 and 1, negative 2 and is shaded above the line.
Graph of two intersecting lines. Both lines are solid. One line passes g of x through points negative 2, 2 and 0, 3 and is shaded below the line. The other line f of x passes through points 0, 1 and 1, negative 2 and is shaded below the line.
Graph of two intersecting lines. Both lines are solid. One line f of x passes through points negative 2, 2 and 0, 3 and is shaded above the line. The other line f of x passes through points 0, 1 and 1, negative 2 and is shaded below the line.

Answers

9514 1404 393

Answer:

  C

Step-by-step explanation:

Both inequalities have y ≤ ( ), so will be bounded by solid lines, and shaded below that line (where y-values are lower). The first inequality has a boundary line with a steeply negative slope; the second has a shallow positive slope.

Since both are shaded below, the doubly-shaded area (AB) will be in the bottom quadrant, below the point of intersection of the lines. The graph attached below shows the correct shading.

Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29 e) 2U + 8 = 10

Answers

Answer:

a) x = 3

b) z = 10

c) p = 2

d) x = 7

e) u = 1

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

x = 3

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

z = 10

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

p = 2

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

x = 7

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

x = 1

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

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