Answer / Step-by-step explanation:
(300.500+40.60+8.2)=348.562
what’s the area of the base
Answer:
16 square units
Step-by-step explanation:
16 square units
Explain the difference between 2(7x-4) and (7x-4)^2
Answer:
2(7x-4) = 7x(2)-4(2) = 14x-8
but
(7x-4)^2 = (7x-4) (7x-4)
What is the value of x in the equation?
Answer:
What is the value of x in the equation?
Step-by-step explanation:
A rectangular piece of material with sides 150 cm and 100 cm is used to make a circular table cloth. the diameter of the completed cloth must be 0.9 m and 5 cm is provided for the hem. how much material is wasted?
The material wasted is 7915.375 sq cm.
What is area of rectangle?The product of its length and breadth.
Area = length* breadth
Given:
length= 150 ac, breadth = 100 cm
d= 0.9m 5cm
r= 47.5 cm
Area of rectangle,
= l * b
= 150*100
= 15000 sq. cm
Area of Circular cloth,
= πr²
=3.14*47.5*47.5
=7084.625 sq cm.
Hence, the wasted material is = 15000-7084.625
= 7915.375 sq cm
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A new amusement park presold discounted tickets for the opening day as well as upon arrival at the park. the opening day ticket sales for the park, including presales, is represented by this function, where is the number of tickets sold h hours after opening at 7:00 a.m. what is the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m.? a. tickets per hour b. tickets per hour c. tickets per hour d. tickets per hour
The approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour
How to determine the rate of change?The missing part of the question is represented by the following function:
[tex]T(h) = \frac{386 + 110h}{h}[/tex]
10:00 a.m is 3 hours after 7:00 am and 1:00 p.m is 6 hours after 7:00 am.
This means that:
h = 3 at 10:00 am
h = 6 at 1:00 pm
Next, we calculate T(3) and T(6)
[tex]T(3) = \frac{386 + 110*3}{3} =238.7[/tex]
[tex]T(6) = \frac{386 + 110*6}{6} =174.3[/tex]
The average rate of change is then calculated as:
[tex]T'(h) = \frac{T(3) - T(6)}{3 - 6}[/tex]
This gives
[tex]T'(h) = \frac{238.7 - 174.3}{-3}\\[/tex]
Evaluate
T'(h) = -21
This means that the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour
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i donnt know ..............
Answer:
7
Step-by-step explanation:
[tex]\dfrac 13(15+6)\\\\\\=\dfrac{21}3\\\\\\=7[/tex]
Slope of (-9,-2) and (-9,-6)
Answer:
Slope is undefined.
Step-by-step explanation:
Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6
Answer:
[tex]\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]
[tex]\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}[/tex]
[tex]\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}[/tex]
[tex]-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]
Answer:
3x-3
Step-by-step explanation:
use synthetic division
A light bulb consumes 1440 watt-hours per day. How long does it take to consume 6480 watt-hours?
The number of days it will take to consume the given power = 4.5 days
Calculation of energy consumptionThe amount of power consumed per day = 1440watt-hours
Therefore X days = 6480 watt-hours?
Make X the subject formula;
X = 1 × 6480/1440
X = 4.5 days
Therefore, The number of days it will take to consume the given power = 4.5 days.
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Find the equation
of the line
that goes through (-3,4) and
(6,7) in the form of y=mx+b.
Answer:
y = (1/3)*x + 5
Step-by-step explanation:
Step 1: determine slope or m
m = change in y-coordinates ÷ change in x-coordinates
m = (4-7)/(-3-6) = -3/-9 = 1/3
Step 2: determine y-intercept or b
y = m*x + b
y = (1/3)*x + b
4 = (1/3)*(-3) + b
4 = -1 + b
b = 5
Step 3: substitute values for m and b into the slope intercept equation
y = (1/3)*x + 5
Find the volume of this rectangular pyramid.
length =5cm
width =6cm
hight =7cm
PLEASE HURRY
Do you know the answer to this
Answer:
[tex] 4x^2y\sqrt[4]{3y} [/tex]
Step-by-step explanation:
[tex] \sqrt[4]{768x^8y^5} = [/tex]
[tex] = \sqrt[4]{256 \times 3(x^2)^4y^4y} [/tex]
[tex] = \sqrt[4]{4^4 \times 3(x^2)^4y^4y} [/tex]
[tex] = 4x^2y\sqrt[4]{3y} [/tex]
What is the equation of a line that passes through (-6,2) and has a slope of -(1)/(2)?
Answer:
y= -1/2x+5
Step-by-step explanation:
What is 95x9 divided by 14?
Answer:
213.75
Step-by-step explanation:
95×9=855
855÷4=213.75
1 soda + 1 cupcake+1popsicle=$22.00
1 soda +3cupcakes+3popsicle=$40.00
if a cupcake cost,$2:00 more than a popsicle,find the cost of the following
a)1 cupcake
b)1 popsicle
Answer:
a) 1 cupcake = $5.50
b) 1 Popsicle = $3.50
Step-by-step explanation:
Let s = cost of one soda
Let c = cost of one cupcake
Let p = cost of one Popsicle
From the given information we can create 3 equations:
Equation 1: s + c + p = 22Equation 2: s + 3c + 3p = 40Equation 3: c = p + 2Subtract Equation 1 from Equation 2 to eliminate the variable s:
s + 3c + 3p = 40
- s + c + p = 22
2c + 2p = 18
Substitute Equation 3 into this new equation and solve for p:
⇒ 2c + 2p = 18
⇒ 2(p + 2) + 2p = 18
⇒ 2p + 4 + 2p = 18
⇒ 4p = 14
⇒ p = 3.5
Substitute the found value of p into Equation 3 and solve for c:
⇒ c = p + 2
⇒ c = 3.5 + 2
⇒ c = 5.5
To find the cost of a soda (s), substitute the found values of p and c into Equation 1:
⇒ s + c + p = 22
⇒ s + 5.5 + 3.5 = 22
⇒ s = 13
Therefore,
1 soda costs $131 cupcake costs $5.501 Popsicle costs $3.50In a diving contest five judges score each dive. the highest and lowest scores are discarded and then the arithmetic average of the remaining scores is taken as the diver's score. if the five judges score a dive as 6.0, 6.3, 6.2, 6.8, and 6.1, then the diver's score is?
Using the given information, the diver's score is 6.2
Calculating average scoreFrom the question, we are to calculate the diver's score
From the given information,
The five judges score a dive as 6.0, 6.3, 6.2, 6.8, and 6.1.
Since the highest and lowest scores are discarded
Then, we will discard 6.8 and 6.0
The remaining scores are 6.1, 6.2, and 6.3
Now, the diver's score will be the average of the remaining scores
∴ The diver's score = (6.1 + 6.2 + 6.3) /3
The diver's score = 18.6 / 3
The diver's score = 6.2
Hence, the diver's score is 6.2
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Segment GH is shown on the graph.
What are the coordinates of the point that divides the
segment into a 3:2 ratio?
O (-7.5, 0.5)
O (0.5, -7.5)
O (-1.2,-2.2)
O (-2.2,-1.2)
The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)
How to determine the coordinate?The points are given as:
G = (-4,3)
H = (-1,-4)
Ratio, m : n = 3 : 2
The coordinate of the point is calculated using:
[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]
This gives
[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]
Evaluate
[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]
Evaluate the product
(x,y) = (-2.2, -1.2)
Hence, the coordinate of the point is (-2.2, -1.2)
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9=-7x+7x^2 Helppp please
Answer:
x= 0.21428571428 or x=0.2
Step-by-step explanation:
-7x+7x^2=9 1. simplify 7x^2
-7x+ 7x(7x)=9 2. combine like terms
-7x+49x=9 3. combine like terms
42x=9 4. /42 on both sides
x= 0.21428571428 or x=0.2
(4-x)/(x^2-5x+4)+(2)/(x-1)=1
show all steps please!!
Answer:
[tex]x = 2, 4[/tex]
Step-by-step explanation:
Given :
[tex]\frac{4-x}{x^{2} -5x+4} + \frac{2}{x-1} =1[/tex]
=============================================================
Factorize the denominator of the first term :
⇒ x² - 5x + 4
⇒ x² - x - 4x + 4
⇒ x(x - 1) - 4(x - 1)
⇒ (x - 4)(x - 1)
============================================================
Hence, the equation now is :
[tex]\frac{4-x}{(x-1)(x-4)} + \frac{2}{x-1} =1[/tex]
============================================================
Multiply the second term by (x - 4) in the numerator and denominator :
[tex]\frac{4-x}{(x-1)(x-4)} + \frac{2(x-4)}{x-1(x-4)} =1[/tex]
============================================================
Combine the numerator of both terms and bring the denominator to the other side :
[tex]\frac{4-x+2(x-4)}{(x-1)(x-4)} = 1[/tex]
[tex]4 - x+2x-8 = x^{2} - 5x + 4[/tex]
[tex]x - 4 = x^{2} - 5x + 4[/tex]
[tex]x^{2} -5x-x+4+4=0[/tex]
[tex]x^{2} -6x+8=0[/tex]
[tex](x-4)(x-2)=0[/tex]
[tex]x = 2, 4[/tex]
simplify the expression
4x(x + 1) (3x − 8) (x + 4)
Answer:
4×(x+1)(3x-8)(x+4)= (4x²+4)(3x-8)(x+4)= (12x³-32x²+12x²-32)(x+4)= (12x³-20x²-32)(x+4)= 12x⁴+48x³-20x³-80x²-32x²-128x= 12x⁴+28x³-112x²-128x
Please help me, greatly appreciate it!
Answer: See the screenshots below
I'm answering in this format because the questions aren't numbered, so its hard to reference them consistently (so we're both on the same page).
All decimal values are approximate. I decided to round to 4 decimal places, but feel free to use another level of precision.
Help me please
calculate the value of x in the polygon
Answer:
122.5 degrees
Step-by-step explanation:
A six sided polygon's interior angles sum to
(n-2)(180) = (6-2) (180) = 720 degrees
then x + x + x + x+10 + 130 + 90 = 720
4x = 490 so x = 122.5 degrees
Explain how the expression 32 relates to the diver's depth
Answer:
See below
Step-by-step explanation:
Each 32 feet of depth is 1 more atmosphere of pressure on the diver
please help because I don’t know!!
Answer:
Step-by-step explanation:
Comment
There was a flat fee of 10 dollars
Each 1/4 hour brought in 3,75
The total charge was 55 dollars.
Equation
Charge = 10 + 4*3.75*x as an hourly rate,
Solution
55 = 10 + 4*3.75x Combine
55 = 10 + 15x Subtract 10 from both sides
55-10= 10-10 + 15x
45 = 15x Divide by 15
45/15 = 15x/15
x = 3 hours
Answer 3 hours
The temperatures for the summer in California are 105, 90, 85, 89, and 100.
What is the range of the temperature
Answer:
range is subtracting the highest number from the lowest number. so we want to find the difference
Step-by-step explanation:
all you do is 105-85 which is 15.
5 pts
Question 5
A model rocket is launched 25 feet from you. When the rocket is at height h, the
distance d between you and the rocket is given by d = √216 +h2 where h and d
are measured in feet. What is the rocket's height when the distance between you and
the rocket is 100 feet? Round to 3 decimal places
Question 6
5 pts
The rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet
How to determine the rock's height?The function is given as:
d = √216 +h²
At a distance of 100 feet, it means that:
d = 100
So, we have:
√216 +h² = 100
Take the square of both sides
216 +h² = 10000
Subtract 216 from both sides
h²= 9784
Take the square root of both sides
h = 98.9
Hence, the rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet
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Sherri solved the equatjon 1/5(x-20)=45. For each step, write the name of the property sherri used
Answer: The awnser is linear.
I hope this helped.
Step-by-step explanation:
♡♡♡ ▲ ▲ ▲ ▲ Ratio of hearts to triangles in simplest form.
3 hearts
4 triangle
H:T
3:4
So, ratio of hearts to triangles in simplest form is 3:4
(we can't simplify any further - HCF of 3 & 4 is 1)
Hope this helps!
Omar paid $8.64 for 5.4 pounds of grapes. what was the cost of 1 pound of grapes?
A cyclist set out from a town P on a bearing of to a town Q, 5 km away. He then moves on a bearing of to a town R, 6km from Q.
1. Represent the information on a diagram
Calculate, correct to two decimal places
2. the bearing of R from P
3. |PR|
The bearing of R from P is 019 and the distance |PR| is 8.75
The complete questionA cyclist set out from a town P on a bearing of 060 to a town Q, 5 km away. He then moves on a bearing of 345 to a town R, 6km from Q.
The diagram that represents the informationSee attachment
The bearing of R from PStart by calculating the distance PR using the following cosine ratio
PR² = PQ² + QR² - 2 * PQ * PR cos(Q)
Substitute known values
PR² = 5² + 6² - 2 * 5 * 6 cos(105)
Evaluate
PR² = 76.53
Take the square root of both sides
PR = 8.75
Next, calculate angle R using the following sine ratio
PQ/sin(R) = PR/sin(Q)
Substitute known values
5/sin(R) = 8.75/sin(105)
Evaluate the quotient
5/sin(R) = 9.06
Multiply both sides by sin(R)
9.06 * sin(R) = 5
Divide both sides by 9.06
sin(R) = 0.5519
Take the arc sin of both sides
R = sin⁻¹(0.5519)
Evaluate
R = 34
Calculate angle P using:
P = 180 - 34 - 105
P = 41
The bearing of R from P is then calculated as:
Bearing = 060 - 41
Evaluate
Bearing = 019
Hence, the bearing of R from P is 019
The distance |PR|In (b), we have:
PR = 8.75
Hence, the distance |PR| is 8.75
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