Essentials of University Mathematics
Example 3.
Find the length of the vector PQ from the point P(3.-5. 2) to the
point QC-5.4.9)
Find a unit vector with the direction of PQ

Answers

Answer 1

Answer:

The length of the vector is of [tex]\sqrt{194}[/tex]

The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]

Step-by-step explanation:

Vector from point P(3,-5,2) to Q(-5,4,9)

The vector is:

[tex]PQ = Q - P = (-5-3, 4-(-5), 9-2) = (8,9,7)[/tex]

The length is:

[tex]\sqrt{8^2+9^2+7^2} = \sqrt{194}[/tex]

The length of the vector is of [tex]\sqrt{194}[/tex]

Find a unit vector with the direction of PQ

We divide each component of vector PQ by its length. So

[tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]

The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]


Related Questions

If a rectangle has an area of 48 cm², what would be the area of a similar rectangle if
the dimensions are doubled?
A) 2304 cm^2
B) 192 cm^2
C)96 cm^2
D)216 cm^2

Answers

Answer is
B)192cm^2
Step by step exploration

Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.

Answers

Answer:

t

Step-by-step explanation:

A circle can be circumscribed about the given quadrilateral, the answer is: A. True.

We know that,

To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.

Opposite angles of a circumscribed polygon are supplementary.

Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.

Learn more about circumscribed polygon on:

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Suzanne collected data on the weight of her classmates. She found that the range of the data she collected was 17
Which of the following BEST explains what a range of 17 indicates?
A
The average distance of each point from the mean is 17.
.
B
The distance between the minimum and the maximum is 17.
С
The distance between the lower quartile to the upper quartile is 17.
D
The distance between the mean and the median in a skewed data set is 17

Answers

Answer:

the answer is A.

Step-by-step explanation:

What is the median of 1, 3, 6, 8, 9, 9
Answer choices: A. 6
B. 7
C. 8
D. 9

Answers

Answer:

B

Step-by-step explanation:

The median is the middle value of the data arranged in ascending order. If there is no exact middle value then it is the average of the values either side of the middle.

1,  3,  6,  8,  9,  9

           ↑ middle

median = [tex]\frac{6+8}{2}[/tex] = [tex]\frac{14}{2}[/tex] = 7 → B

Answer:

B. 7

Step-by-step explanation:

(6 + 8) ÷ 2 = 7

I hope this is right if its not im sorry

Represent the greatest common factor of 36 and 8 using the distributive property
36 + 8 =
0 4x(9+2)
O2 x (18+4)
O 8x (5+2)
0 11 x (3+1)

Answers

36/4= 9, 8/4= 2 a is correct

36/2=18, 8/2= 4 b is correct however wrong because it is the simplest distribution

36/8= 4.5, 8/8= 1 c is incorrect

36/11= 3.27, 8/11= .73 d is incorrect.

Answer is 4x(9+2)

Let's say you have a 4 gallon and a 10 gallon pailHow can you measure exactly 2 gallons of water?

Answers

You can fill the 10 gallon pail all the way up. After that, you can pour the water from the 10 gallon pail, into the 4 gallon pail 2 times. That will leave you with 2 gallons in the 10 gallon pail.

Mrs Mills buys 4 packs of treats for her cats, Fluff and tigger
she gives Fluff 1/6 of a pack each day
She gives tigger 1/5 of a pack each day
for how many complete days will the 4 packs of treats last

Answers

Answer: 10 days

Step-by-step explanation:

1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)

4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)

So 10 complete days.

An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blends of gasoline:

88.5 98.8 89.6 92.2 92.7 91.8 91.0 91.0 94.7 88.3 90.4 83.4 87.9 88.4 87.5 90.9 84.3
90.4 91.6 91.0 93.0 92.6 87.8 89.9 90.1 91.2 90.7 88.2 94.4 93.7 88.3 91.8 89.0 90.6
88.6 88.5 90.4 96.5 89.2 89.7 89.8 92.2 88.3 93.3 91.2 84.3 92.3 92.2 91.6 87.7 94.2
87.4 91.2 93.2 88.9 90.3 91.1 85.3 91.1 86.7 88.6 89.8 90.0 86.7 90.1 90.5 94.2 88.7
92.7 91.5 93.4 89.3 100.3 90.8 92.7 93.3 89.9 96.1 91.1 87.6 90.1 89.3 86.7

Required:
Construct a stem-and-leaf display for these data. Calculate the median and quartiles of these data.

Answers

Answer:

[tex]Median = 90.4[/tex]

[tex]Q_1 = 88.6[/tex]

[tex]Q_3 = 92.2[/tex]

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

[tex]Smallest = 83.4[/tex]

[tex]Highest = 100.3[/tex]

Next, group each dataset base on common whole numbers.

So, we have:

[tex]83.4[/tex]

[tex]84.3\ 84.3[/tex]

[tex]85.3[/tex]

[tex]86.7\ 86.7\ 86.7[/tex]

[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]

[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]

[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]

[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]

[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]

[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]

[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]

[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]

[tex]96.1\ 96.5[/tex]

[tex]98.8[/tex]

[tex]100.3[/tex]

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]

  [tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]

From the above plot,

[tex]n = 83[/tex]

The median is calculated as:

[tex]Median = \frac{n+1}{2}th[/tex]

[tex]Median = \frac{83+1}{2}th[/tex]

[tex]Median = \frac{84}{2}th[/tex]

[tex]Median = 42nd[/tex]

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

[tex]Median = 90.4[/tex]

The lower quartile (Q) is calculated as:

[tex]Q_1 = \frac{n+1}{4}th[/tex]

[tex]Q_1 = \frac{83+1}{4}th[/tex]

[tex]Q_1 = \frac{84}{4}th[/tex]

[tex]Q_1 = 21st[/tex]

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

[tex]Q_1 = 88.6[/tex]

The upper quartile (Q3) is calculated as:

[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{84}{4}th[/tex]

[tex]Q_3 = 3 * 21th[/tex]

[tex]Q_3 = 63rd[/tex]

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

[tex]Q_3 = 92.2[/tex]

what is a easier way to solve fractions ​

Answers

Answer: hewo, there! I hope I Made it easier to Understand

the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27

Step-by-step explanation:

To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction

Hope this helps you!!

Have a great day!!!

Someone PLease help me

Answers

I’m pretty sure the answer is the last one. Playing football and soccer combined. If you look really closely you can see playing the piano takes up 1/4 of Brad’s time. And if you combine football and soccer you get about 1/4. Hope this helps

Rosalind made 969 donuts and put 8 donuts into each box. How many boxes of donuts were made

Answers

Answer:

121 donuts in each box

Step-by-step explanation:

969 divided by 8 = 121.125

(Ignore the remainder)

Step by step solution:

We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.

Step 1:

Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:

969/8 = x

Step 2:

Doing this, we can get 121.125, which leaves us with

121.125 = x

121.125 = 121.125

Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.

Checking our answer:

We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like

8 * 121.125 = x

969 = x

969 = 969

Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!

What is sec 0 when cot 0 = -4/2?

Answers

Answer:

[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]

Step-by-step explanation:

[tex]Cot0=-4\sqrt{2}[/tex]

[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]

[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]

[tex]=\frac{4\sqrt{66} }{32}[/tex]

[tex]=\frac{\sqrt{66} }{8}[/tex]

--------------------

hope it helps...

have a great day!!


Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?

Answers

Answer:

8x^2 - 26x - 10

Step-by-step explanation:

3(6x2 + 3x - 5 ) = 18x^2 + 9 -15

5(2x2 + 7x - 1) = 10x^2 + 35 - 5

18^2 - 10x^2 = 8x^2

9x - 35x = - 26x

-15 -(-5) = -10

final answer = 8x^2 - 26x - 10

Solve for x:
2x + 9 = 3

Answers

Answer:

x = -3

Step-by-step explanation:

2x + 9 = 3

2x = 3 - 9

2x = -6

x = -3

Answer:

- 3

Step-by-step explanation:

given

2x + 9 = 3

2x = 3 - 9

2x = - 6

x = - 6/2

x = - 3

hope it helps :)

I need to know the answer!

Answers

Answer:

As it says he is incorrect.

Step-by-step explanation:

To start, if you were to multiply something such as 5*1, then you would get the same number. Another example would be 8*0. Anything multiplied by 0 IS zero. He does give some valid answers, but there are also ones with smaller numbers. That is why Jackson is incorrect.

the original piece of a book is $25. the book is on sale for 30% off. what percent are we paying? what is the price you will pay for the book

show work please and thank you :)

Answers

Answer:

$17.50

Step-by-step explanation:

multiply 25 and 30, the divide the answer by 100, the deduct that result from the original price

How can you isolate the variable in this equation? x + 6 = 13 A Add 6 to 13. B Add 6 to both sides. C Subtract x from both sides. D Subtract 6 from both sides.

Answers

Answer: D. Subtract 6 from both sides

Answer:

the answer is D, im doiing the flocab rn

Step-by-step explanation:

Which choice is the slope-intercept equation of the line shown below?
(1,2)

(0, -1)

A. y = 3x - 1
B. y = 2x-1
C. y = 2x + 1
D. y = 3x

Answers

Answer:

C is my answer

Step-by-step explanation:

14. On Monday, a work group eats at Ava's café,
where a lunch special is $8 and a dessert is
$2. The total is $108. On Friday, the group
eats at Bo's café, where a lunch special Is
$6 and a dessert is $3. The total is $90. Each
time, the group orders the same number of
lunches and the same number of desserts.
How many lunches and desserts are
ordered?
what the x and y value.

Answers

Answer:

no. who eat lunch special = 12

no. who eat dessert = 6

Step-by-step explanation:

Let x = no. who eat lunch special

y = no. who eat dessert

(1)    8x + 2y = 108             (2)    6x + 3y = 90

 Divide thru by 2                         Divide thru by 3

      4x + y = 54                          2x + y = 30

     -2x - y = -30

       2x = 24

         x = 12                               2(12) + y = 30

                                                    24 + y = 30

                                                            y = 6

                                                 

Meatball subs used to cost $5.40 at Mike's Sub Shop, but he just increased the price by $0.54.

How much do subs cost now?

Answers

Answer:

Step-by-step explanation: $5.40 + $0.54 now equals $5.94

Can you figure out the answer?​

Answers

she needs 1680 grams
Divide 480 by 4. That will give you how many grams per person. You will get 120 grams per person. Now multiply 120 by 14. That will give you the number of grams needed for 14 people. The answer will be: 1,680 grams

Sin 0= 8/17 determine the value of tan?

Answers

Answer:

tan theta = 8/15

Step-by-step explanation:

Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.

To find the value of the adjacent side from theta, use the Pythagorean Theorem.

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

Subtract 64.

b^2 = 225

Take the square root.

b = 15.

So that means:

the side opposite from theta is 8,

the side adjacent from theta is 15,

the hypotenuse is 17.

Now we take tan, opposite over adjacent, and use the values from the triangle.

tan = opposite / adjacent

tan = 8/15.

Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x

Answers

Answer:

[tex]Period = \pi[/tex]

Step-by-step explanation:

Given

[tex]y = -\frac{1}{3} * \sin(2x)[/tex]

Required

The period

A sine function is represented as:

[tex]y =A \sin(Bx + C) + D[/tex]

Where

[tex]Period = \frac{2\pi}{B}[/tex]

By comparing:

[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]

[tex]B = 2[/tex]

So, we have:

[tex]Period = \frac{2\pi}{2}[/tex]

[tex]Period = \pi[/tex]

Hence, the period of the function is [tex]\pi[/tex]

a clock chimes every 20mins
a light flashes every 8 mins
the clock chimes and the light flashes together at 8:00

how many times between 8:01 and 12:30 will the clock chime and the light flash together?
show your working (5marks)

Answers

Answer: 6 times

Step-by-step explanation:

it is a lowest common multiple question. So we list the multiples

20                   8

40                   16

60                   24

80                   32

                      40

40 is our lowest common multiple. Which means every 40 minutes they flash and chime together.

so if we add 40 minutes onto 08:00 we get 08:40 and if we add it again we get 09:20 and again we get 10:00 and again we get 10:40 and again we get 11:20 and again we get 12:00. We have to stop here as if we add 40 minutes again we will go over the given time of 12:30. If we count how many times it was added. this adds to 6. therefore the answer is 6.  

hope this helped.

The clock will chime and the light flashes together 6 times.

How many times the clock will chime and light flash together?

The Least Common Multiple (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.It is the lowest common multiple question. So we list the multiple

20                   8

40                   16

60                   24

80                   32

                     40

40 is our lowest common multiple. This means every 40 minutes they flash and chime together.

so if we add 40 minutes onto 08:00 we get 08:40 and if we add it again we get 09:20 and again we get 10:00

and again we get 10:40 and again we get 11:20 and again we get 12:00. We have to stop here as if we add 40 minutes again we will go over the given time of 12:30.

If we count how many times it was added. this adds to 6. therefore the answer is 6.  

Therefore the clock will chime and the light flashes together 6 times.

To know more about LCM follow

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choose the expression that represents the fraction as a product of a whole number and a unit fraction 4/10​

Answers

Answer:

69

Step-by-step explanation:

trust me

What is the solution to Three-fourths a greater-than negative 16?
a greater-than negative 21 and one-third
a less-than negative 21 and one-third
a greater-than 21 and one-third
a less-than 21 and one-third

Answers

Answer:

A

Step-by-step explanation:

Either A or D, this question made me lose braincells, you should get a new teacher

Answer:

A

Step-by-step explanation:

I did the test :)

Asking for help again

Answers

Answer:  D. (7, 0)

Step-by-step explanation:

[tex]4x+9y=28\\-4x-y=-28[/tex] The xs can already cancel since 4x is positive for the first equation, but negative on the second.Add the equations together8y=0Divide both sides by 8 y=0Plug y into one of the equations4x + 9(0)=28Distribute 04x=28Divide both sides by 4x= 7

So your answer is (7, 0)

A small country emits 130,000 kilotons of carbon dioxide per year. In
a recent global agreement, the country agreed to cut its carbon
emissions by 3.1% per year for the next 10 years. In the first year of the
agreement, the country will keep its emissions at 130,000 kilotons and
the emissions will decrease 3.1% in each successive year. How many
total kilotons of carbon dioxide would the country emit over the course
of the 10 year period, to the nearest whole number?

Answers

Answer:1132858

Step-by-step explanation:

The total carbon dioxide the country emit over the course of the 10 year period would be 1,132,858 kilotons.

What is rate of decrease?

The rate of decrease is a constant amount of deduction from a fixed or primary amount.

Here, the carbon dioxide emits by the country per year is 130,000 kilotons.

The rate of decrease of the carbon dioxide emission per year would be 3.1%.

In the 1st year, the carbon dioxide emission = 130,000 kilotons.

In the 2nd year, the carbon dioxide emission = 130,000 × (100-3.1)/ 100 kilotons = 125,970 kilotons.

In the 3rd year, the carbon dioxide emission = 125,970 × (100-3.1)/ 100 kilotons = 122,064.93 kilotons.

In the 4th year, the carbon dioxide emission = 122,064.93 × (100-3.1)/ 100 kilotons = 118,280.92 kilotons.

In the 5th year, the carbon dioxide emission = 118,280.92 × (100-3.1)/ 100 kilotons = 114,614.21 kilotons.

In the 6th year, the carbon dioxide emission = 114,614.21 × (100-3.1)/ 100 kilotons = 111,061.17 kilotons.

In the 7th year, the carbon dioxide emission = 111,061.17 × (100-3.1)/ 100 kilotons = 107,618.27 kilotons.

In the 8th year, the carbon dioxide emission = 107,618.27 × (100-3.1)/ 100 kilotons = 104,282.1 kilotons.

In the 9th year, the carbon dioxide emission = 104,282.1 × (100-3.1)/ 100 kilotons = 101,049.35 kilotons.

In the 10th year, the carbon dioxide emission = 101,049.35 × (100-3.1)/ 100 kilotons = 97,916.82 kilotons.

Hence, total carbon dioxide emission by that country over 10 years = (130,000 + 125,970 + 122,064.93 + 118,280.92 + 114,614.21 + 111,061.17 + 107,618.27 + 104,282.1 + 101,049.35 + 97,916.82) kilotons = 1,132,857.77 kilotons ≈ 1,132,858 kilotons.

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hey I need help with my coordinates ​

Answers

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

A dance studio is offering a ballroom dancing class. In order for the class to be held, a minimum of 20 people must sign up to take the class. The studio ballroom can accommodate up to 60 people at a time. Which inequality graph models the number of individuals that can be in the class?​

Answers

Answer:

B.

Step-by-step explanation:

The dance studio can have between 20 and 60 people. The holes are closed be 20 and 60 are included

Other Questions
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