Which of the following settings describes a displacement vs. time graph that
looks like this?
Displacement
Time
Check all that apply
O A. Constant velocity
OB. Increasing velocity
I C. Zero acceleration
O D. Decreasing acceleration
I NEED HELP ASAP
Answer:
c and a
Explanation:
ape x
Si un conductor tiene una longitud de 4 metros y una sección de 2 mm^2 calcule su resistencia, si su coeficiente de resistividad es de 0.10(Ωmm^2/m)
Answer:
R = 0.2 Ω
Explanation:
Para aplicar el concepto de resistencia de un conductor electrico, consideramos la siguiente formula:
R = ρ . l / S
Donde l es la longitud del conductor
S la superficie
y ρ el coeficiente de resistividad
Primero necestiamos hacer ciertas conversiones:
ρ = 0.10 ×10⁻⁶ (Ω . m²/m)
S = 2 mm² → 2 ×10⁻⁶ m²
R = 0.10 ×10⁻⁶ (Ω . m²/m) . 4m / 2 ×10⁻⁶ m²
Dentro de la formula simplificamos las unidades, los metros de ρ con la longitud y ambos m². De esa forma la unidad de R queda en Ω (ohmios).
Resolvemos:
R = 0.10 ×10⁻⁶ Ω . 4 / 2 ×10⁻⁶
R = 0.2 Ω
hello help me please :)
Answer: 75 N
Because we're finding the force, we need to use F = ma. M (Mass) = 25 and A (Acceleration) = 3. Multiply 25(3) to get 75. So, you're answer should be 75 N.
During which radioactive decay process does the mass number of a nucleus change?
A. Beta Decay (Electron)
B. Beta Decay (Positron)
C. Alpha Decay
D. Gamma Decay
Answer:
Alpha decay
Explanation:
Answer:
C
Explanation:
Alpha Decay
what instrument used measure
to volume of water
Answer: A Graduated Cylinder or A Beaker ?
Explanation:
NEED HELP The main difference between kinetic energy and potential energy is thatSingle choice.
(2 Points)
kinetic energy involves position, and potential energy involves motion.
kinetic energy involves motion, and potential energy involves position.
although both energies involve motion, only kinetic energy involves position.
although both energies involve position, only potential energy involves motion.
Answer:
kinetic energy involves motion, and potential energy involves position.although both energies involve position, only potential energy involves motion.hope it is helpful to you ☺️☺️✌️
please help me asap thankss
EXPLAIN WHY A POLYTHENE ROD GAINS A NEGATIVE CHARGE WHEN IT IS RUBBED WITH A CLOTH
Answer:
When a polythene rod is rubbed with a duster, the friction causes electrons to gain energy. Electrons gain enough energy to leave the atom and 'rub off' onto the polythene rod. The polythene rod has gained electrons, giving it a negative charge.
Explanation:
Hope it helps
Dos masas con valores de 8kg y 12kg cada una se encuentran separadas por una distancia de 1m. Determinar la fuerza de atraccion gravitacional entre ellas si se compara con el valor de sus pesos Como es este valor?
The question is: Two masses with values of 8kg and 12kg each are separated by a distance of 1m. Determine the force of gravitational attraction between them if compared with the value of their weights. What is this value?
Answer: The force of gravitational attraction between them if compared with the value of their weights is [tex]640.704 \times 10^{-11} N[/tex].
Explanation:
Given: [tex]m_{1}[/tex] = 8 kg, [tex]m_{2}[/tex] = 12 kg
Distance = 1 m
Formula used is as follows.
[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}[/tex]
where,
F = force of gravitational attraction
G = gravitational constant = [tex]6.674 \times 10^{-11} N m^{2}/kg^{2}[/tex]
[tex]m_{1}[/tex] = mass of object 1
[tex]m_{2}[/tex] = mass of object 2
r = distance between the centers of these two objects
Substitute the values into above formula as follows.
[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\\= \frac{6.674 \times 10^{-11} Nm^{2}/kg^{2} \times 8 kg \times 12 kg}{(1 m)^{2}}\\= 640.704 \times 10^{-11} N[/tex]
Thus, we can conclude that the force of gravitational attraction between them if compared with the value of their weights is [tex]640.704 \times 10^{-11} N[/tex].
Question 1 (1 point)
All solid objects will deform when enough force is applied.
O True
False
Answer:
Solid objects will deform when adequate loads are applied to them; if the material is elastic, the object will return to its initial shape and size after removal. This is in contrast to plasticity, in which the object fails to do so and instead remains in its deformed state.
Explanation:
Answer:
It is false
Explanation:
because when it like a rolling ball it can deform no matter what unlesss you throw it at the ground really hard then it breaks but a soft or sometimes metal yeah it can deform but not all things solid deform.
How are wave properties and energy related?
give me examples
Answer:
They don’t ‘represent’ anything, they are properties of the wave.
Depending on the type of wave, we experience them as various phenomena. For example, with a sound wave we experience frequency (or wavelength, which is just another way to describe the same property) as the pitch of the sound. We experience amplitude as the loudness of the sound, although due to the characteristics of the ear, frequency also effects perceived loudness.
If the wave is a light wave, we experience the frequency (wavelength) as the colour of the light, and the amplitude as the brightness of the light.
For many waves, we don’t perceive them at all (e.g. radio waves).
For ocean waves, frequency is the time for each peak or trough to reach us, and amplitude is how tall the wave is.
The value of gravitational pull on the moon is 1.6 m/s/s. What is the weight of a 75 kg
astronaut on the moon?
Answer:
120N
Explanation:
Weight=mass x acceleration due to gravity (on the planet)
Mass of an astronaut is 75kg and value of acceleration due to gravity on moon is 1.6m/s2
Weight of astronaut on moon=mass of astronaut x value of acceleration due to gravity on moon
75kg x 1.6m/s2
=120N
What helps night vision? Answer fast please.
Answer:
Halos, blurriness, and night blindness causes night vision (symptoms) while vitamin-A,corrective lenses, such as eyeglasses or contacts, can improve or help night vision.
Explanation:
I bet you will get full Marks if you write it!!
(please note that you will have to mark me as brainliest if it helped you)£
A man is driving his 1100 kg car at 36 km/h on a straight freeway. After accelerating for 30 seconds, the car
has a speed of 108 km/h. How much work did the engine do during the 30 seconds?
Answer:
W = 439998 J = 439.99 KJ
Explanation:
First, we will calculate the acceleration of the car by using the first equation of motion:
[tex]v_f = v_i + at\\\\a = \frac{v_f-v_i}{t}[/tex]
where,
a = acceleration = ?
vf = final speed = [tex]108(\frac{km}{h})(\frac{1000\ m}{1\ km})(\frac{1\ h}{3600\ s})[/tex] = 30 m/s
vi = initial speed = [tex]36(\frac{km}{h})(\frac{1000\ m}{1\ km})(\frac{1\ h}{3600\ s})[/tex] = 10 m/s
t = time = 30 s
Therefore,
[tex]a = \frac{30\ m/s - 10\ m/s}{30\ s}[/tex]
a = 0.67 m/s²
Now, we will calculate the force applied by the engine:
F = ma
where,
F = force = ?
m = mass = 1100 kg
Therefore,
F = (1100 kg)(0.67 m/s²)
F = 733.3 N
Now, we will calculate the distance covered by the car by using the second equation of motion:
[tex]s = v_it+\frac{1}{2}at^2\\\\s = (10\ m/s)(30\ s)+\frac{1}{2} (0.67\ m/s^2)(30\ s)^2[/tex]
s = 600 m
Now, the work done (W) by engine can be calculated as follows:
W = Fs
W = (733.3 N)(600 m)
W = 439998 J = 439.99 KJ
Does a battery produce electric currents?
Answer:
A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.
which feature is used to classify galaxies
age
color
shape
size
Answer:Shape
I took the quiz
Answer:shape
Explanation:
I took the quiz
A juggler is throwing balls up in the air and catching them. An observer in the crowd makes the statement that the potential and kinetic energy of the ball is the same when the ball is halfway down from its highest point. In one paragraph, using your own words, explain using the relationship of mechanical energy, potential energy, and kinetic energy why the observer is correct.
Answer:
do you have the answer?
Explanation:
if so whats the answer?
Elena puts her eggs in a cage made out of wood. The wood breaks during
the landing, but the eggs survive. Which would be the best reason to
explain why this prevented her eggs from breaking?"
O Directs the energy of the impact towards the egg
O Decreases the velocity of the egg before it starts slowing down
O Increases the time that the egg slows down
O Decreases the time that the egg slows down.
O Directs the energy of the impact away from the egg
O Increases the velocity of the egg before it starts slowing down
Answer:
I think the answer is Decreases the time that the egg slows down.
Explanation:
If not try it starts slowing down
O Increases the time that the egg slows down.
Define Acceleration.
Ty!
Answer:
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.
Which activities will help improve your flexibility? A. Yoga B. Dance C. Pilates D. All of the above
Answer: I believe that the answer is D.
Explanation:
Hope this helps and have a great day! :)
Answer:
D) all of the above
Explanation:
At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left is applied for 3seconds. What is the velocity at the end of the 3seconds ?
Answer:
v_f = -7.5 m / s
Explanation:
Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is
we assume that the direction to the right is positive
I = I₁ + I₂
I = F₁ Δt₁ - F₂ Δt₂
I = 3 1.5 - 4 3
I = -7.5 N s
now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)
I = Δp
I = m (v_f - v₀)
v_f = I / m
v_f = -7.5 / m
to finish the calculation we must assume a mass m = 1 kg
v_f = -7.5 m / s
the negative sign in the body is moving to the left
Starting circuit One battery. 2 light bulbs in parallel; switch What is the voltage across the battery? What is the voltage across light bulb 1? What is the voltage across light bulb 2?
Answer:
The voltage across light bulb 1 and light bulb 2 is the the same i.e V
Explanation:
In a parallel circuit, the Voltage is same across all the components of the circuit and the current flowing through each component is added to get the total current across the circuit.
Let us say, the voltage across the circuit is V. The voltage across light bulb 1 and light bulb 2 is the the same i.e V
What is the wavelength of sound wave in air that has a temperature of 24.6°C that has a frequency of 440.8 Hz?
A. 465.40 m
B. 0.78 m
C. 17.92 m
D. 0.75 m
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
An object with a mass of 1298 kg is accelerating at a rate of 17 m/s² when a net force is applied to it. What is the magnitude of the net force that is acting on the object?
Answer:
Explanation:
This is a simple F = ma equation. We have the mass and we have the acceleration, so
F = 1298(17) and
F = 22066 which rounds correctly to
F = 22000N
The magnitude of the net force of object with a mass of 1298 kg is accelerating at a rate of 17 m/s² is 22066N
HOW TO CALCULATE NET FORCE:
The net force of a body can be calculated by multiplying the mass of the body by its acceleration. That is;Force (N) = mass (kg) × acceleration (m/s²)According to this question, an object with a mass of 1298 kg is accelerating at a rate of 17 m/s². The net force can be calculated as follows:F = 1298Kg × 17m/s²F = 22066NTherefore, the magnitude of the net force of object with a mass of 1298 kg is accelerating at a rate of 17 m/s² is 22066N.Learn more at: https://brainly.com/question/23245710?referrer=searchResults
Please select the word from the list that best fits the definition
Does not easily transfer electricity
conductor
insulator
circuit
current
Answer:
conductor
Does not easily transfer electricity
A very long cylindrical shell made of copper has an inner radius 2 cm and an outer radius of 3 cm. This shell concentrically surrounds a very long charged aluminum rod of radius 1 cm with a charge density of 4 pC/m. All charges on the aluminum rod reside at its surface. The inner surface of the copper shell has exactly opposite charge to that of the aluminum rod while the outer surface of the copper shell has the same charge as the aluminum rod. Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
Question:
Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
(a) 0.5 cm, (b) 1.5 cm, (c) 2.5 cm, (d) 3.5 cm, (e) 7.0 cm
Answer:
(a) 0
(b) 4.795 N/C
(c) 2.877 N/C
(d) 2.055 N/C
(e) 1.027 N/C
Explanation:
The given parameters are;
The inner radius of the copper = 2 cm
The outer radius of the copper - 3 cm
The radius of the aluminum rod, r = 1 cm
The radius of the aluminum rod = 4 pC/m
a) The charge at the 0.5 cm from the center of the aluminum rod, E = 0
There is no charge inside the rod given that the aluminum road is a conductor of electricity, having all the charge on its surface
b) At 1.5 cm, we have;
[tex]E = \dfrac{2 \cdot \lambda}{4 \cdot \pi \cdot r \cdot \epsilon_0}[/tex]
Where;
[tex]\dfrac{ \lambda}{4 \cdot \pi \cdot \epsilon_0} = 8.99 \times 10^9 \times 4 \times 10^{-12}[/tex]
r = 1.5 cm = 0.015 m
∴ E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.015 ≈ 4.795
The magnitude of the electric field, E = 4.795 N/C
The direction of the charge depends on the charge sign on the rod
c) At 2.5 cm, we have;
r = 2.5 cm = 0.025 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.025 ≈ 2.877
The magnitude of the electric field, E ≈ 2.877 N/C
d) At r = 3.5 cm, we have;
r = 3.5 cm = 0.035 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.035 ≈ 2.055
The magnitude of the electric field, E ≈ 2.055 N/C
e) At
r = 7.0 cm = 0.070 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.07 ≈ 1.027
The magnitude of the electric field, E ≈ 1.027 N/C
Below is a single strand of DNA, what is the complementary base pair for the strand?
AAG, GCA, TCA, GAT
True or False?
________________The fact that ocean crust is younger the farther away it is from an ocean ridge supports the theory of plate tectonics
Answer:
true is the answer of the question
differences between weightlessness in space and weightlessness in earth
Answer:
it depends on a person's own weight
Answer:
The gravity is roughly the same. The inverse square law applies to gravity and that means that being 60 miles above Earth is about the same as being on Earth. The thing is, they are going really fast in an orbit and thus falling around the Earth. The weightlessness comes from a sort of cancellation of gravity pulling them down and their going perpendicular to that force. The forces are cancelling and making them relatively “weightless”. It’s not really weightlessness but just an equilibrium reached between the two accelerations of gravity and their motion against the pull of the Earth.
Explanation:
Un cuerpo se mueve por una carretera que tiene rozamiento.¿Podríamos aplicar el principio de conservación de la energía mecánica? ¿Qué requisitos se han de cumplir para poder aplicarla?
Answer:
Sí se puede aplicar el Principio de Conservación de la Energía Mécanica siempre y cuando se considere los efectos de pérdida de energía a causa del rozamiento, de lo contrario, no se cumpliría el requisito de conservación derivado del citado principio de conservación.
Explanation:
Consideremos que el cuerpo representa nuestro sistema de estudio, el cual se desplaza por una carretera y experimenta rozamiento, significando cambios en la energía cinética y potencial gravitacional. La presencia de rozamiento indica una disipación de la energía del cuerpo, cuya energía mecánica total disminuye, significando un sistema no conservativo.
Sí se puede aplicar el Principio de Conservación de la Energía Mécanica siempre y cuando se considere los efectos de pérdida de energía a causa del rozamiento, de lo contrario, no se cumpliría el requisito de conservación derivado del citado principio de conservación.